Answer:
CB=CA
FD and FG
Verticies
Step-by-step explanation:
Answer:
B,A,C
Step-by-step explanation:
because Place the compass center at C and set the radius to
the length of CB. Because
he needs to
set the compass radius only once.
Keeping the compass width the same, move the
compass center to F and draw arcs to intersect
segments
The points where the arcs intersect the segments are
the of the triangle. Construct segments to
form the remaining sides of the triangle
pls helppppp with my math
Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
Answer:
Step-by-step explanation:
[tex]\frac{5}{6}-\frac{2}{3}=\frac{5}{6}-\frac{2*2}{3*2}\\\\=\frac{5}{6}-\frac{4}{6}\\\\=\frac{5-4}{6}\\\\=\frac{1}{6}[/tex]
There is more than one integer greater than 1 which leaves a reminder of1 when divided by each of the four smallest primes
Answer:
210
Complete question found at brainly(ID): 18678557 is stated below.
There is more than one integer, greater than 1, which leaves a remainder of 1 when divided by each of the four smallest primes. What is the difference between the two smallest such integers?
Step-by-step explanation:
Prime numbers are numbers that can only be divided by itself and 1
The smallest of the prime numbers we have = 2, 3, 5, 7
Since the integers greater than 1 are said to be divided by the four smallest prime numbers, we would assume the number of integers are 4 in total.
Let the integers be T
From the question:
Integer/(prime number) = quotient + (remainder/prime number)
Integer/(prime number) = Q + R/P
Let the different quotients derived from all 4 prime number = w, x, y, z
For prime 2:
T/2 = w + 1/2
T/2 - 1/2 = w
(T-1)/2 = w
T = 2w + 1
T-1 = 2w
Following the above solution
For prime 3:
T = 3x + 1
T-1 = 3x
For prime 5:
T = 5y + 1
T-1 = 5y
For prime 7:
T = 7z + 1
T-1 = 7z
T-1= T-1 = T-1 = T-1
2w = 3x = 5y = 7z
T-1 = LCM of all the prime numbers
T- 1 = 2×3×5×7
T-1 = 210
T = 210+1 = 211
T = 211
The smallest of the integer greater than 1 that leaves a remainder of 1 = 1(T-1) + 1 = 211
The next after the smallest number: 2(T-1) +1= 2(210) + 1 = 421
The two smallest number = 1(T-1) + 1 and 2(T-1) +1 respectively
The difference between the two smallest such integers = 421-211 = 210
The assembly time for a product is uniformly distributed between 8 and 12 minutes.The mean and the variance of the assembly time are: a.4 minutes and 16 (minute)2 b.8 minutes and 12 (minute)2 c.12 minutes and 1.33 (minute)2 d.10 minutes and 1.33 (minute)2
Answer:
d. 10 minutes and 1.33 minutes.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The mean of the uniform distribution is:
[tex]M = \frac{a + b}{2}[/tex]
The variance of the uniform distribution is given by:
[tex]V = \frac{(b-a)^{2}}{12}[/tex]
The assembly time for a product is uniformly distributed between 8 and 12 minutes.
This means that [tex]a = 8, b = 12[/tex].
Mean:
[tex]M = \frac{8 + 12}{2} = 10[/tex]
Variance:
[tex]V = \frac{(12-8)^{2}}{12} = 1.33[/tex]
So the correct answer is:
d. 10 minutes and 1.33 minutes.
what is the slope of the line that is parallel to the line y= 3/4x + 2
Answer:
3/4
Step-by-step explanation:
Answer:
3/4
Step-by-step
Since they are parallel they will have the same slope but not the same intercept
4
What is tan 11pi/6
Answer:
[tex]tan(\frac{11\pi}{6}) =-\frac{\sqrt{3} }{3}[/tex]
Step-by-step explanation:
Notice that [tex]\frac{11\pi}{6}[/tex] is an angle in the fourth quadrant (where the tangent is negative), and the angle is in fact equivalent to [tex]-\frac{\pi}{6}[/tex]. This is one of the special angles for which the sine and cosine functions, as well as the tangent function have well know values:
Recall that the tangent is defined as
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
and for this angle ( [tex]\frac{11\pi}{6}[/tex] ) the value of the sine and cosine functions are well known:
[tex]sin (\frac{11\pi}{6}) =-\frac{1}{2} \\cos( \frac{11\pi}{6}) =\frac{\sqrt{3} }{2}[/tex]
Then, the tangent would be:
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\tan(\frac{11\pi}{6}) = \frac{-\frac{1}{2} }{\frac{\sqrt{3} }{2} } \\tan(\frac{11\pi}{6}) =-\frac{1}{\sqrt{3} } \\tan(\frac{11\pi}{6}) =-\frac{\sqrt{3} }{3}[/tex]
HELP ASAP GIVING BRANLIST!!
Answer:
Question 1: 3 - 5 hours.
Question 2: 0 - 1 hour
Step-by-step explanation:
Question 1: As you can see in the diagram, the guy is moving really slowly and is almost stuck, therefore, it is 3 - 5 hours.
Question 2: In hours 0 - 1, you can see that the graph is the closest to vertical as it gets.
You are dealt one card from a 52 card deck. Then the card is replaced in the deck, the deck is shuffled, and you draw again. Find the probability of getting a picture card the first time and a club the second time. Express the probability as a simplified fraction. Group of answer choices
Answer:
3/52
Step-by-step explanation:
The picture card are j,q k and there are 4 of each so there are 12 picture cards
P( picture card) = picture card/ total
12/52 = 3/13
Then replace the card
There are 13 clubs
P( club) = club/ total
13/52 = 1/4
P(picture,replace,club) = 3/13*1/4 = 3/52
Consider random samples selected from the population of all female college soccer players in the United States. Assume the mean height of female college soccer players in the United States is 66 inches and the standard deviation is 3.5 inches. Which do you expect to have less variability (spread): a sampling distribution with sample size n
Answer:
Option C is correct.
The sampling distribution with sample size n=100 will have less variability.
Step-by-step explanation:
Complete Question
Consider random samples selected from the population of all female college soccer players in the United States. Assume the mean height of female college soccer players in the United States is 66 inches and the standard deviation is 3.5 inches. Which do you expect to have less variability (spread): a sampling distribution with sample size n = 100 or a sample size of n = 20.
A. Both sampling distributions will have the same variability.
B.The sampling distribution with sample size n=20 will have less variability
C. The sampling distribution with sample size n =100 will have less variability
Solution
The central limit theorem allows us to say that as long as
- the sample is randomly selected from the population distribution with each variable independent of each other and with the sample having an adequate enough sample size.
- the random sample is normal or almost normal which is guaranteed if the population distribution that the random sample was extracted from is normal or approximately normal,
1) The mean of sampling distribution (μₓ) is approximately equal to the population mean (μ)
μₓ = μ = 66 inches
2) The standard deviation of the sampling distribution or the standard error of the sample mean is related to the population standard deviation through
σₓ = (σ/√N)
where σ = population standard deviation = 3.5 inches
N = Sample size
And the measure of variability for a sampling distribution is the magnitude of the standard deviation of the sampling distribution.
For sampling distribution with sample size n = 100
σₓ = (3.5/√100) = 0.35 inch
For sampling distribution with sample size n = 20
σₓ = (3.5/√20) = 0.7826 inch
The standard deviation of the sampling distribution with sample size n = 20 is more than double that of the sampling distribution with sample size n = 100, hence, it is evident that the bigger the sample size, the lesser the standard deviation of the sampling distribution and the lesser the variability that the sampling distribution shows.
Hope this Helps!!!
Researchers want to determine if caffeine affects reaction time. They divide a sample of 150 people into 3 groups. Group 1 gets a regular drink with no caffeine, group 2 gets a drink with 95 mg of caffeine, and group 3 gets a drink with 250 mg of caffeine. Each group is then given a test to gauge their reaction time. What is the appropriate test to use?
Answer:
One-way ANOVA
Step-by-step explanation:
One-way ANOVA(analysis of variance) a testing method in statistics that is used to compare the means of two or more independent samples, to check if the differences are statistically significant.
In this case, we have three groups which their various reaction time to caffeine is to be tested using the same testing method (amount of caffeine). Hence the appropriate test to use here is the one-way ANOVA
Arc CD is Two-thirds of the circumference of a circle. What is the radian measure of the central angle? StartFraction 2 pi Over 3 EndFraction radians StartFraction 3 pi Over 4 EndFraction radians StartFraction 4 pi Over 3 EndFraction radians StartFraction 3 pi Over 2 EndFraction radians CAN YOU SHOW WORK PLEASE
Answer:
[tex]\theta = \frac{4\pi}{3}[/tex]
Step-by-step explanation:
Given
Let A represent the Length of Arc CD and C, represents the circumference
[tex]A = \frac{2}{3} C[/tex]
Required
Find the central angle (in radians)
The length of arc CD in radians is as follows;
[tex]A = r\theta[/tex]
Where r is the radius and [tex]\theta[/tex] is the measure of central angle
The circumference of a circle is calculated as thus;
[tex]C = 2\pi r[/tex]
From the question, it was stated that the arc length is 2-3rd of the circumference;
This means that
[tex]A = \frac{2}{3} C[/tex]
Substitute [tex]2\pi r[/tex] for C and [tex]r\theta[/tex] for A
[tex]A = \frac{2}{3} C[/tex] becomes
[tex]r\theta = \frac{2}{3} * 2\pi r[/tex]
[tex]r\theta = \frac{4\pi r}{3}[/tex]
Divide both sides by r
[tex]\frac{r\theta}{r} = \frac{4\pi r}{3}/r[/tex]
[tex]\frac{r\theta}{r} = \frac{4\pi r}{3} * \frac{1}{r}[/tex]
[tex]\theta = \frac{4\pi r}{3} * \frac{1}{r}[/tex]
[tex]\theta = \frac{4\pi}{3}[/tex]
Hence, the measure of the central angle; [tex]\theta = \frac{4\pi}{3}[/tex]
Answer:
The answer is C on Edge 2020
Step-by-step explanation:
I did the assignment
The World Issues club has decided to donate 60% of all their fundraising activities this year to Stephen Lewis Foundation. This foundation was created to help ease the pain of HIV/AIDS in Africa. Lewis, a Canadian, works for the United Nations trying to determine ways to stop the spread of this deadly disease from crippling an entire continent. Choose a variable to represent the money earned during fundraising activities and the revenue generated for the foundation Use these variables to create an equation that will determine the amount of money the foundation will receive. In their latest bake sale, the club raised $72. Calculate the amount the foundation will receive. At the end of the year, the World Issues Club mailed a cheque to the foundation for $850. How much money did they fundraise in total?
Answer:
$43.20$1416.67Step-by-step explanation:
Let the money earned during fundraising activities =x
Since the World Issues club has decided to donate 60% of all their fundraising activities this year to Stephen Lewis Foundation.
The amount of money the foundation will receive
=60% of x
= 0.6x
In the bake sale, the club raised $72.
Therefore, the amount the foundation will receive =0.6*72=$43.20
At the end of the year, the World Issues Club mailed a cheque to the foundation for $850.
Therefore:
0.6x=850
x=850/0.6
x=$1416.67
The total amount of money the club raised is $1416.67.
Please answer this correctly
Answer:
47
Step-by-step explanation:
The probability for tails to land is 1/2 when you flip 1 coin.
When you flip 94 times, 1/2 × 94
= 47
Develop a 3-week moving average for the following time series Time PeriodTime Series Value 19 22 39 416 511 62 77 Find the value for MSE. Round your calculations to 2 decimal places.
Answer:
MSE = 198.18 / 3 = 66.06
Step-by-step explanation:
Time period : Time series value
1 : 9
2 : 2
3 : 9
4 : 16
5 : 11
6 : 2
7 : 7
3 weeks moving average
F4 = average of weeks 1-3 = ( 9 + 2 + 9 ) / 3 = 20 / 3 = 6.67
F4 = average of weeks 2-4 = ( 2 + 9 + 16 ) / 3 = 27 / 3 = 9
F4 = average of weeks 3-5 = ( 9 + 16 + 11 ) / 3 = 36 / 3 = 12
F4 = average of weeks 4 - 6 = ( 16 + 11 + 2 ) / 3 = 9.67
attached is the table showing the development of the 3-week moving average
PLEASE ANSWER FAST !!!
What is the range of the function g for given domain ?
Answer:
The answer is B
Step-by-step explanation:
Hope this helps.. if not im sorry :(
Please answer this correctly
Solve the equation and express each solution in a+bi form x^4-7x^2-8=0
Answer:
x = ±2√2, ±i
Step-by-step explanation:
Step 1: Factor
(x² - 8)(x² + 1)
Step 2: Find roots
x² - 8 = 0
x² = 8
x = ±2√2
x² + 1 = 0
x² = -1
x = ±i
Answer:
The answer is B
Step-by-step explanation:
The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsightly blemishes often appear because of improper mixtures or other problems. A worker counted the number of blemishes on each door. Most doors had no blemishes; a few had one; a very few had two; and so on. The average number was 0.5 per door. The distribution of blemishes followed the Poisson distribution. Out of 10,000 doors painted, about how many would have no blemishes
Answer:
The numbers of doors that will have no blemishes will be about 6065 doors
Step-by-step explanation:
Let the number of counts by the worker of each blemishes on the door be (X)
The distribution of blemishes followed the Poisson distribution with parameter [tex]\lambda =0.5[/tex] / door
The probability mass function on of a poisson distribution Is:
[tex]P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}[/tex]
[tex]P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}[/tex]
The probability that no blemishes occur is :
[tex]P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}[/tex]
[tex]P(X=0) = 0.60653[/tex]
P(X=0) = 0.6065
Assume the number of paints on the door by q = 10000
Hence; the number of doors that have no blemishes is = qp
=10,000(0.6065)
= 6065
Expand (2 + a)9 using Pascal’s triangle.
Answer:
Step-by-step explanation:
The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.
1 [tex](A + B) ^ 0[/tex] = 1
1 1 [tex](A +B ) ^ 1 = 1A + 1B[/tex]
1 2 1 [tex](A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2[/tex]
By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is
1 9 36 84 126 126 84 36 9 1
Now, fill in AB in the gaps.
1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB
Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is
[tex]1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B[/tex]
Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B
[tex]1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9[/tex]
The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.
[tex]A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9[/tex]
Hope you can learn the method
What is the surface area of the pyramid? 12ft 10ft 10ft
Answer:
2h x (l+b)
2x10 X (12+10)
20 X 22
44 cm cube is your answer...
I need help PLEASE help mee
Answer:
Step-by-step explanation:
In order to convert 0.0004578, which is in decimal, to scientific notation, all we need to do in this case is to move our decimal point to the right till we arrive at the first number that is not a zero, and then eliminate all the zero.
In this case, we will have to move the decimal point 4 spaces to our right, which would mean our exponent would be negative. The number of decimal spaces we moved to our right would be the value of our exponent, which is -4 in this case.
Thus, we have:
[tex] 4.578 * 10^{-4} [/tex]
NEED GEOMETRY HELP ASAP (12 POINTS)
Answer:
HJ > PK
Step-by-step explanation:
Notice that the side PL in one triangle has the same length as side GJ in the other, and side GH has the same size as side LK of the other triangle. Now what is different is the angle subtended between these sides in the case of the triangle on the lower left, the subtended angle is [tex]90^o[/tex] , which is larger angle than that subtended between equal sides on the other triangle ([tex]85^o[/tex])
Therefore, if the angle subtended by the equivalent sides in the triangle on the left is larger than the angle subtended on the right hand side triangle, then the sides associated with such angle aperture must keep the inequality. That is:
Since [tex]\angle\,G\,\,\,>\,\,\,\angle \,L[/tex], then HJ > PK
Find the following measure for this figure.
Volume =
Answer:
91 2/3 pi cubic units
Step-by-step explanation:
The formula for the volume of cone is [tex]\dfrac{1}{3}\pi r^2 h[/tex]. Plugging in the given numbers, you get:
[tex]\dfrac{1}{3}\cdot \pi \cdot 5^2 \cdot 11= 91 \ 2/3 \pi[/tex]
Hope this helps!
Answer:
[tex]Volume=\frac{1}{3} \,275\,\pi[/tex] cubic units
Notice that this answer doesn't agree with any of the first three in the list provided via the screenshot
Step-by-step explanation:
Recall the formula for the volume of a cone:
[tex]Volume=\frac{1}{3} Base\,*\,Height[/tex]
In this case the Height is 11 units, and they also give us the radius of the circular base (5 units) from which we can find the circle's base area:
[tex]Area_{circle} = \pi\,R^2\\Area_{circle}=\pi\,(5)^2\\Area_{circle}=25 \pi[/tex]
therefore the total volume becomes:
[tex]Volume=\frac{1}{3} Base\,*\,Height\\Volume=\frac{1}{3} 25\,\pi\,*\,11\\\\Volume=\frac{1}{3} \,275\,\pi[/tex]
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the distance of a focus from the center. Because a>c, it follows that e<1. Write a brief paragraph about the general shape of each of the following ellipses. Be sure to justify your conclusions. (a) Eccentricity close to 0 (b) Eccentricity=5 (c) Eccentricity close to 1
Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as [tex]e=\frac{c}{a}[/tex]
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)
[tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)[/tex]
b) Eccentricity =5
[tex]5=\frac{c}{a} \:c=5a[/tex]
An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:
[tex]If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0[/tex]
c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.
[tex]a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)[/tex]
[tex]Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1[/tex]
Please answer this question I give brainliest thank you! Number 8
Answer:
The third options
Step-by-step explanation:
Counting we can see that 10 students went to two or less states, and 10 went to three or more
A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00. The 95% confidence interval for the average hourly wage (in $) of all information system managers is
Answer:
The 95% confidence interval for the average hourly wage of all information system managers is (39.14,42.36)
Step-by-step explanation:
In order to calculate the 95% confidence interval for the average hourly wage we would have to calculate first the margin of error as follows:
ME=t0.05/2,n-1s/√n
for n=75, t0.025,74=1.993
Therefore, ME=1.993*7/√75
ME=1.61
Therefore, the 95% confidence interval for the average hourly income of all syatem manager would be as follows:
(X-ME,X+ME)=(40.75-1.61,40.75+1.61)
=(39.14,42.36)
I need help with this
Answer:
Volume = 14.5 cm³
Step-by-step explanation:
Volume of cone = [tex]\pi r^2\frac{h}{3}[/tex]
Where r = 2 and h = 3.46
Volume = [tex](3.14)(2)^2\frac{3.46}{3}[/tex]
Volume = (3.14)(4)(1.15)
Volume = 14.5 cm³
A research organization keeps track of what citizens think is the most important problem facing the country today. They randomly sampled a number of people in 2003 and again in 2009 using a different random sample of people in 2009 than in 2003 and asked them to choose the most important problem facing the country today from the following choices, war, economy, health care, or other. Which of the following is the correct test to use to determine if the distribution of "problem facing this countrytoday" is different between the two different years?
A.
Use a chi-square test of homogeneity.
B.
Use a paired t-test.
C.
Use a two-sample z-test for proportions.
D.
Use a chi-square goodness-of-fit test.
Answer:
Step-by-step explanation:
From the information given, the population is divided into sub groups. Each group would consist of citizens picking a particular choice as the most important problem facing the country. The choices are the different categories. In this case, the null hypothesis would state that the distribution of proportions for all categories is the same in each population. The alternative hypothesis would state that the distributions is different. Therefore, the correct test to use to determine if the distribution of "problem facing this country today" is different between the two different years is
A) Use a chi-square test of homogeneity.
help plz!!!! 30 points!!!!!!!!!! i will mark brainliest for who answers first! anveer bought 0.7 pounds of sliced ham at his local deli. If the deli charged $6.79 per pound, how much did Tanveer pay? A. $2.04 B. $4.75 C. $7.49 D. $9.70
Answer:
B
Step-by-step explanation:
[tex]6.79 \times 0.7[/tex]
[tex]=4.753[/tex]
Answer:
The correct answer would be $4.75
Step-by-step explanation:
6.79 × 0.7
=$4.75
Hope that was helpful.Thank you!!!
Suppose that four microchips in a production run of sixty are defective. A sample of six is to be selected to be checked for defects. (a) How many different samples can be chosen
Answer:
50,063,860 different samples can be chosen
Step-by-step explanation:
The order in which the microchips are chosen is not important. So we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
How many different samples can be chosen
We choose 6 microchips from a set of 60. So
[tex]C_{60,6} = \frac{60!}{6!(60-6)!} = 50063860[/tex]
50,063,860 different samples can be chosen
Nicola runs a small pottery cafe. Customers choose from a range of ceramics which they paint and personalise.
Nicola wants to make as much profit as possible on the sale of ceramic plates. She pays £1.28 for each plate. What is the most profit Nicola can make on one plate.
Answer:
Bb
Step-by-step explanation: