trig please help, thanks

Answer:

20%

Step-by-step explanation:

Answer:

x= -1, y=1

Step-by-step explanation:

First label the 2 equations.

7x +6y= -1 -----(1)

-x +2y= 3 -----(2)

Then choose which term you would like to eliminate. To eliminate the y term, multiply equation (2) by 3 such that the coefficient of y is 6.

(2) ×3:

-3x +6y= 9 -----(3)

Since the coefficient of y is positive 6 in both equations, subtract one equation from the other.

(3) -(1):

-3x +6y -(7x +6y)= 9 -(-1)

Expand:

-3x +6y -7x -6y= 9 +1

-10x= 10

x= 10 ÷(-10)

x= -1

Substitute x= -1 into (2):

-(-1) +2y= 3

1 +2y= 3

2y= 3 -1

2y= 2

y= 2 ÷2

y= 1

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2nd method: eliminating the x term

(2) ×7:

-7x +14y= 21 -----(3)

Since the coefficient of y in equation (1) is a positive 7, while that in equation (3) is a negative 7, add the 2 equations together to eliminate the x term.

(1) +(3):

7x +6y -7x +14y= -1 +21

20y= 20

y= 20 ÷20

y= 1

Substitute y= 1 into (2):

-x +2(1)= 3

-x +2= 3

-x= 3 -2

-x= 1

x= -1

Answer:

18.

Step-by-step explanation:

3*12 = 36

36/2 = 18

18*3 = 54

54/3 = 18

Answer:

18

Step-by-step explanation:

3 x 12 is 36,

36 divided by 2 is 18,

18 x 3 is 54,

54 divided by 3 is 18

Answer:

11 and -11

Step-by-step explanation:

Answer:

C. y = x + 2

Step-by-step explanation:

2 is being added onto both sides

Answer:

16x-30

Step-by-step explanation:

distribute 2/5 by 40x and then 75

2/5(40x) - 2/5(75)

16x - 30

Answer: A^2

Step-by-step explanation:

Angle C + Angle B = Angle A

ok so

leave y^2 alone

so you need to get 2 factors that when added equal 11 so 9x2=18

and 9+2=11

so it would be (y+9)(y+2)

hope this helps

Answer:

Step-by-step explanation:

(x + 9 ) ( x + 2 )

Answer:

∠C=39°

Step-by-step explanation:

The interior angles of a triangle will always have a sum of 180°.

∠A+∠B+∠C=180°

78°+63°+∠C=180°

∠C=180°-78°-63°

∠C=39°

Answer:

39 degrees

Step-by-step explanation:

All triangles will add up to 180 degrees. So, you know that angle C added with angles A and B will equal 180. if you take 180, minus 78, minus 63, you get the answer 39.

Answer:

50%

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Answer:

the person is correct b

Step-by-step explanation:

Answer:

A. 850 cubic feet

Step-by-step explanation:

Have a good day :)

Answer:

So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.

Step-by-step explanation:

please mark this answer as brainliest

The equation in standard form for the circle with radius 6 centered at the origin will be x² + y² = 36.

It is the close curve of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

Let r be the radius of the circle and the location of the center of the circle be (h, k).

Then the equation of the circle is given as,

(x - h)² + (y - k)² = r²

The radius of the circle is 6 units and has a center at the origin. Then the equation is given as,

(x - 0)² + (y - 0)² = 6²

x² + y² = 36

The equation in standard form for the circle with radius 6 centered at the origin will be x² + y² = 36.

More about the equation of the circle link is given below.

https://brainly.com/question/10618691

#SPJ2

Answer:

70°

Step-by-step explanation:

In the context it says that Franklin St. is parallel to Washington St.

The 110° formed by Franklin St. and Mulberry St. is a supplementary angle to Angle x.

Supplementary angles are angles that add up to each other to make 180°

So lets subtract:

180 - 110 = 70°

Angle x = 70°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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Answer:

height

Step-by-step explanation:

you can just look these questions up

Answer:

Okay well if you need to find mph she is going 10 mph

Step-by-step explanation:

1/2+1/2= 1 mile in 10 min, multiply both sides by 6 and you get 1 mile = 60min

Answer:

10,000 × .08 = 800.

Step-by-step explanation:

2400 interest in 3 yrs

Answer: C is the answer for first picture

             F is the answer for second picture

            C is the answer for number one on 3rd picture

            F is the answer for number 2 on 3rd picture  

Step-by-step explanation:

Answer:

look below

Step-by-step explanation:

for the first picture, the answer to the first problem is C

for the first picture, the answer to the second problem is G

for the second picture, the answer is F

for the third picture, the answer to the first problem is C

for the third picture, the answer to the second problem is G

have a nice day!

Answer:

[tex]19.5\:\mathrm{m^3}[/tex]

Step-by-step explanation:

The volume of a square pyramid is given by [tex]V=\frac{1}{3}\cdot s^2\cdot h[/tex], where [tex]s[/tex] is the base edge and [tex]h[/tex] is the height. Since the base area ([tex]s^2[/tex]) is already given to us, we can substitute directly in to our equation.

Solving for [tex]V[/tex]:

[tex]V=\frac{1}{3}\cdot 6.8\cdot 8.6\approx \boxed{19.5\:\mathrm{m^3}}[/tex]

The answer on deltamath is

19.5m^3

Answer:

lol get a life

Step-by-step explanation:

Answer:

1 / 2704

Step-by-step explanation:

Number of cards in a deck = 52

9 of clubs in a deck = 1

10 of clubs in a deck = 1

Probability = required outcome / Total possible outcomes

P(9 of club) = 1 / 52

With replacement ;

Then ;

P(10 of club) = 1 / 52

Hence,

P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704

Step-by-step explanation:

60+5x+5=180 (being angle of straight line)

5x+65=180

5x=180-65

5x=115

x=23

Answer:

27.04 per dress

Step-by-step explanation:

120 - 11.84 = 108.16

108.16 ÷ 4 = 27.04

Answer:

140 drops

Step-by-step explanation:

Length of the pool = 24 feet

Width of the pool = 14 feet

Depth of the pool = 5 feet

Volume of the pool = length × width × depth

= 24 ft * 14 ft * 5 ft

= 1,750 ft³

Volume of the pool = 1,750 ft³

He needs to add 4 drops of chlorine for every 50 cubic feet in his pool.

Number of 50 cubic feet in the volume of the pool = Volume of the pool / 50 ft³

= 1,750 ft³ / 50 ft³

= 35

Number of 50 cubic feet in the volume of the pool = 35

How many drops of chlorine should Jorge use to chlorinate his pool properly?

Number of drops of chlorine Jorge should use = number of drops per 50 ft³ × Number of 50 cubic feet in the volume of the pool

= 4 × 35

= 140 drops

Number of drops of chlorine Jorge should use = 140 drops

Answer:

a) The coordinates of the rest stop is [tex]C(x,y) = \left(5, \frac{5}{2} \right)[/tex].

b) The approximate distance between the high school and the stadium is 32 miles.

Step-by-step explanation:

a) The rest stop is located in the midpoint of the line segment between the high school and the stadium. Vectorially speaking, we use the following formula:

[tex]C(x,y) = \frac{1}{2}\cdot A(x,y) + \frac{1}{2}\cdot B(x,y)[/tex] (1)

Where:

[tex]A(x,y)[/tex] - Coordinates of the high school.

[tex]B(x,y)[/tex] - Coordinates of the stadium.

[tex]C(x,y)[/tex] - Coordinates of the rest stop.

If we know that [tex]A(x,y) = (3, 4)[/tex] and [tex]B(x,y) = (7,1)[/tex], then the coordinates of the rest stop are, respectively:

[tex]C(x,y) = \frac{1}{2}\cdot (3, 4) + \frac{1}{2}\cdot (7, 1)[/tex]

[tex]C(x,y) = \left(\frac{3}{2}, 2 \right) + \left(\frac{7}{2}, \frac{1}{2} \right)[/tex]

[tex]C(x,y) = \left(5, \frac{5}{2} \right)[/tex]

The coordinates of the rest stop is [tex]C(x,y) = \left(5, \frac{5}{2} \right)[/tex].

b) The approximate distance between the high school and the stadium ([tex]d[/tex]), in miles, is the product of the Length Equation of the Line Segment and the scale factor:

[tex]d = r\cdot \sqrt{(\Delta x)^{2} + (\Delta y)^{2}}[/tex] (2)

Where:

[tex]r[/tex] - Scale factor, in miles.

[tex]\Delta x[/tex], [tex]\Delta y[/tex] - Horizontal and vertical distances between the high school and the stadium, no unit.

If we know that [tex]r = 6.4\,mi[/tex], [tex]\Delta x = 4[/tex] and [tex]\Delta y = -3[/tex], then the distance between the high school and the stadium is:

[tex]d = r\cdot \sqrt{(\Delta x)^{2} + (\Delta y)^{2}}[/tex]

[tex]d = (6.4\,mi)\cdot \sqrt{4^{2}+(-3)^{2}}[/tex]

[tex]d = 32\,mi[/tex]

The approximate distance between the high school and the stadium is 32 miles.