Answer:
There are different types of transformers
Audio-frequency transformers are used in audio distribution to loudspeakers and the to make record players and amplifiers compatible (matching), they are also used in telephone communication
Laminated core transformers are used as step-down transformers to lower the mains voltage from maybe 220 volts to 110 volts for equipment that uses 110 colts such as sound systems
Leakage transformers are used in arc welding machines to transmit voltage and as a magnetic ballast effect
A resonant transformer functions as tune able receiver and are used in radio receivers
Pulse transformers are able to transit rectangular pulses of electric current and are used in controllers of camera flash and telecom circuits
Ferrite core transformers for matching impedance are present in TV antennas
Output transformers are used to enable a low impedance speaker to work with the high load impedance valve
Loudspeaker transformers can power several speakers from a higher voltage source
Explanation:
Household appliances that have transformers are those that have a power pack such as dc fans, printers, laptop chargers, desktop computers, microwave ovens and air conditioners fans, power stabilizers and phones
When x = 10 ft, the crate has a speed of 20 ft/s which is increasing at 6 ft/s^2. Determine the direction of the crate's velocity and the magnitude of the crate's acceleration at this instant.
Answer:
The direction will be "39.8°". The further explanation is given below.
Explanation:
The equation will be:
⇒ [tex]y=\frac{x^2}{24}[/tex]
On differentiating the above, we get
⇒ [tex]\frac{dy}{dx}=\frac{2x}{24}[/tex]
[tex]=\frac{x}{12}[/tex]
On differentiating again, we get
⇒ [tex]\frac{d^2y}{dx^2}=\frac{1}{12}[/tex]
Demonstrate the radius of the path curvature .
⇒ [tex]\rho=\frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}}}{\left | \frac{d^2y}{dx^2} \right |}[/tex]
[tex]=\frac{[1+(\frac{x}{12} )^2]^{\frac{3}{2}}}{\left |\frac{1}{12} \right |}[/tex]
[tex]=\frac{[1+(\frac{10}{12})^2]^{\frac{3}{2}}}{\frac{1}{12} }[/tex]
[tex]=26.4 \ ft[/tex]
On calculating the acceleration's normal component, we get
⇒ [tex]a_{n}=\frac{v^2}{\rho}[/tex]
[tex]=\frac{20}{26.4}[/tex]
[tex]=15.15 \ ft/s^2[/tex]
Magnitude,
⇒ [tex]a=\sqrt{a_{n}^2+a_{t}^2}[/tex]
[tex]=\sqrt{(15.15)^2+(6)^2}[/tex]
[tex]=16.29 \ ft/s^2[/tex]
The direction of crate velocity will be:
⇒ [tex]\phi=tan^{-1}(\frac{dy}{dx} )[/tex]
On putting the values, we get
[tex]=tan^{-1}(\frac{x}{12})[/tex]
[tex]=tan^{-1}(\frac{10}{12} )[/tex]
[tex]=39.8^{\circ}[/tex]
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Engineering Design:Question 10
Which option describes the engineering design process?
Select one:
1. A series of steps engineers use to identify constraints.
2. A series of steps engineers use to decide which solution is best.
3. A series of steps engineers use to test what they build.
4. A series of steps engineers use to solve problems.
Answer:
4. A series of steps engineers use to solve problems.
Explanation:
The process of engineering design is a sequence of procedures that engineers pursue to arrive at a solution to a specific problem. Most times the solution includes creating a product such as a computer code, which fulfills certain conditions or performs a function. If the project in-hand includes designing, constructing, and testing it, then engineers probably adopt the design process. Steps of the process include defining the problem, doing background research, specifying requirements, brainstorming solutions, etc.