Answer:
B. two atoms share or transfer electrons
Explanation:
for a chemical bond to occur there must be association of atoms into molecules,ions , crystals or other species that make up familiar substances
The empirical formula of a compound with 4 carbon atoms, 12 hydrogen atoms, and 2 oxygen atoms is
Answer:
c2h6o
Explanation:
find the hcf of the numbers and divide each number by the HCF eg
HCF of 4,12,2 -> 2
4÷2=2
12÷2=6
2÷2=1
therefore
c2h6o
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
PLS HELP ME PLZ AND THANKS
Answer:
q6= third option
q7= third option
Explanation:
kinetic molecular theory deals with temperature
pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
The normal boiling point of a certain liquid X is 130.9 °C, but when 19.9 g of urea (NH2) CO are dissolved in 200. g of X, it is found that the solution boils at 134.1 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer has the correct number of significant digits x 1 ℃.mol -kg
Answer:
K = 1.93 °C/m
Explanation:
This question can be solved by formula of elevation of boiling point.
Boiling T° of solution - Boiling T° of pure solvent = K . m . i
Our solute is urea.
Our solvent is X.
We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol
We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg
m = molality → moles of solute / kg of solvent
m = 0.331 mol / 0.2 kg = 1.66 m
As urea is an organic compound, no ions will be formed.
i = 1 (a non ionizing compound)
Let's replace data in formula:
134,1°C - 130.9°C = K . 1.66 m . 1
3.2 °C / 1.66 m = K
K = 1.93 °C/m
If the pH of a solution increases from 4.0 to 6.0, the hydronium ion concentration.
A) increases by a factor of 100.
B) decreases by a factor of a 100.
C) decreases by a factor of 1.5
D) increases by a factor of 1.5
Answer:
decrease by a factor of 1.5
Provide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate c.
Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.
Explanation:
Given values:
Initial moles of [tex]SO_3[/tex] = 0.700 moles
Volume of conatiner = 3.50 L
The given chemical equation follows:
[tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]
I: 0.700
C: -2x +2x x
E: 0.700-2x 2x x
Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles
Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]
Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]
Molarity is calculated by using the equation:
[tex]Molarity=\frac{Moles}{Volume}[/tex]
So,
[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]
[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]
[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]
Plugging values in above expression:
[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]
Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.
Select the correct answer.
Which value of Keq represents a scenario where the reactants of an equilibrium reaction are favored?
A.
Keq=1
B.
Keq = 6.0 x 10-2
O C.
Keq = 3.8 x 104
OD
Keq = 490.5
O E. Keq = 2.5
Answer:
B. Keq = 6.0 x 10-2.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:
[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]
Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B. Keq = 6.0 x 10-2.
Regards!
What is the product of the unbalanced equation below?
Ca(s) + O2(g)
A. CaO2(5)
B. Cao(s)
C. 2Ca(s) + O2(9)
D. Ca20(s)
Answer:
I think B
Explanation:
2Ca + O2 -> 2CaO
The product of the unbalanced equation: [tex]\rm Ca(s) + O_2(g)[/tex] is [tex]\rm CaO(s)[/tex]. The correct answer is option B.
A product is a material which arises from a chemical process. It is the end result of the reaction and is produced by the rearrangement of the atoms or molecules of the reactants.
This reaction's balanced chemical equation is:
[tex]\rm 2Ca(s) + O_2(g) \rightarrow 2CaO(s)[/tex]
The reaction begins by heating calcium metal in the presence of oxygen gas or by exposing calcium metal to oxygen-containing air. Calcium oxide [tex](\rm CaO)[/tex] is formed by the reaction of calcium metal (Ca) with oxygen gas[tex]\rm (O_2)[/tex].
In this equation, two atoms of calcium react with one molecule of oxygen gas to form two molecules of calcium oxide. The reaction is exothermic, meaning it releases heat energy.Therefore, the result of the stated chemical reaction is [tex]\rm CaO(s)[/tex]. Option B is the correct answer.
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How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
2Al + 6HCl → 2AlCl3 + 3H2
If 12 moles of Al completely react, how many moles of H2 are produced?
Answer:
18 moles of H₂.
Explanation:
The balanced equation for the reaction is given below:
2Al + 6HCl –> 2AlCl₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:
From the balanced equation above,
2 moles of Al reacted to produce 3 moles of H₂.
Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.
Thus, 18 moles of H₂ were obtained from the reaction.
The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
Fe2O3(s) + 3C0(9) - 2Fe(s) + 3CO (9)
How many grams of Fe2O3 are required to produce 4.65g Fe? You must show your work to receive full credit.
Answer:
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
Explanation:
The balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe₂O₃: 1 moleCO: 3 molesFe: 2 molesCO₂: 3 molesThe molar mass of each compound is:
Fe₂O₃: 159.7 g/moleCO: 28 g/molFe: 55.85 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 gramsCO: 3 moles* 28 g/mol= 84 gramsFe: 2 moles* 55.85 g/mole= 111.7 gramsCO₂: 3 moles* 44 g/mole= 132 gramsThen you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?
[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]
mass of Fe₂O₃= 6.65 grams
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
significant figures.
Answer:
37.5 g NaCl
Explanation:
Step 1: Given data
Concentration of NaCl: 15.0% m/mMass of the solution: 250.0 gStep 2: Calculate how many grams of NaCl are in 250.0 g of solution
The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.
250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl
1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl
Answer:
Moles of NaNO2 = 0.158
Moles of HNO2 final = 0.098
Explanation:
Given
Moles of HCl = 12
Moles of HNO2 = 0.11
Moles of NaNO2 = 0.170
HCl +NaNO2 --> HNO2 + NaCl
1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2
Moles of NaNO2 = 0.17 - 0.012 = 0.158
Moles of HNO2 final = 0.11 - 0.012 = 0.098
HELP!!!! if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?
Answer: 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.
Explanation:
We are given:
Moles of sodium hydroxide = 3.50 moles
The given chemical equation follows:
[tex]Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)[/tex]
By stoichiometry of the reaction:
If 2 moles of NaOH produces 1 mole of [tex]Pb(OH)_2[/tex]
So, 3 moles of NaOH will produce = [tex]\frac{1}{2}\times 3=1.5mol[/tex] of [tex]Pb(OH)_2[/tex]
Hence, 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.
How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?
Answer:
63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid
I'm sorry if it's wrong, I tried.
Explanation:
Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey and need to neutralize 15.0 mL of stomach acid, how many grams of calcium carbonate would you need to take
Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution
[tex]pH=-\log [H^+][/tex] .....(1)
Given value of pH = 1.5
Putting values in equation 1:
[tex]1.5=-\log[H^+][/tex]
[tex][H^+]=10^{(-1.5)}=0.0316M[/tex]
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(2)
We are given:
Volume of solution = 15.0 mL
Molarity of HCl = 0.0316 M
Putting values in equation 2:
[tex]0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol[/tex]
The chemical equation for the reaction of HCl and calcium carbonate follows:
[tex]2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2[/tex]
By the stoichiometry of the reaction:
2 moles of HCl reacts with 1 mole of calcium carbonate
So, [tex]4.74\times 10^{-4}mol[/tex] of HCl will react with = [tex]\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol[/tex] of calcium carbonate
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Moles of calcium carbonate = [tex]2.37\times 10^{-4}mol[/tex]
Molar mass of calcium carbonate = 100.01 g/mol
Putting values in the above equation:
[tex]\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g[/tex]
Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl
Calculate the molality of a solution that contains 75.0-grams of methyl alcohol, CH3OH, dissolved in 600.0-grams of
water.
Answer:
[tex]m=3.90mol/kg[/tex]
Explanation:
Hello there!
In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:
[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]
Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:
[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]
Regards!
How would the accuracy of your determined Keq change if all of your volume measurements were made with graduated cylinders rather than pipets
Answer:
Accuracy decreases
Explanation:
All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.
The accuracy is how close is the measurement to the real value.
If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.
The accuracy of the determined value decreases if all measurement is done with graduated cylinders.
What is Accuracy?The accuracy is the measurement of how close the calculated value is to the real value.
When a student measures the volume with a graduated cylinder the chances of error increase.
Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.
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Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-
Answer:
F₂ + At⁻
Explanation:
Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.
Which bodies of water in the list are found to the west of the Philippines?
Answer:
South China sea
Explanation:
To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
Suppose one was doing this experiment in the real world and the stockroom ran out of NaCl solutions. Which other solutions of similar concentration could be used in place of NaCl(aq)
Answer:
Polyethylene glycol
Explanation:
Because of the corrosive nature of Brine solution (solution of NaCl) , we can use organic liquid polyethylene glycol .
which of the following can cause muscle fatigue ?
A.A build up of lactic acid
b.an inadequate supply of oxygen
C.an inadequate supply of glycogen
D.all of the above
Answer:
The correct answer is -all of the above.
Explanation:
Muscle fatigue is a reduced ability in work capacity caused by work itself. It is known that altering oxygen is contracting skeletal muscle affects performance. Reduced O2 supply increases the rate of muscle fatigue.
The lactic acid is accumulated as it forms rapidly but the breaking of the lactic acid is slow down, which causes muscle fatigue. Less ATP and glycogen in muscle results in fatigue as the muscle is not able to generate energy to power contractions and therefore contributes to muscle fatigue.
If the distance the pepper flakes moved were a measure of the strength of the intermolecular force, would you say the effect was stronger or weaker in hand sanitizer compared to soap
Answer:
In the given case, the pepper flakes are considered virus particles. One of the applications of the principle of "like dissolves like" is the behavior of hand sanitizers and soaps. The polar molecules like alcohols comprise -OH as the functional groups, which are fascinated towards the water, thus, producing robust intermolecular associations. In comparison, the nonpolar molecules like fats and oils, proteins comprise hydrocarbon groups, which are hydrophobic to water.
The active constituents of both hand sanitizers and soaps show the features of both nonpolar and polar regions in their molecular compositions. As a consequence, part of the molecule is fascinated by water, while some parts are attracted towards organic molecules like fats and proteins.
The virus particles are enveloped with different kinds of proteins and fats, so when soaps and hand sanitizers come in contact with the virus, the nonpolar regions of sanitizers and soaps get fascinated towards the coating, and efficiently pulls apart the virus composition.
In the given case, one can model the principle by assuming pepper flakes as virus particles, which are coated with fats and proteins, and thus are insoluble in water. After this, one can simultaneously see the effect of soaps and sanitizers by using them one by one.
What is 0.29km in mm
Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the second the heat of combustion of the carcinogenic substance benzene (C6H6). a. In the first experiment, the temperature rises from 22.37 o C to 24.68 o C when the calorimeter absorbs 5682 J of heat. Determine the heat capacity of the calorimeter. Page 3 of 4 b. In the second experiment, the combustion of 0.258 g of benzene increases the temperature from 22.37 o C to 26.77 o C. Determine the heat of combustion for 1 mol of benzene.
Answer:
The right solution is:
(a) 2459.74 J/degree C
(b) 3271.769 KJ/moles
Explanation:
According to the question,
(a)
The heat capacity of the calorimeter will be:
= [tex]\frac{5682}{24.68-22.37}[/tex]
= [tex]\frac{5682}{2.31}[/tex]
= [tex]2459.74 \ J/degree \ C[/tex]
(b)
The change in temperature will be:
= [tex]26.77-22.37[/tex]
= [tex]4.4 \ Degree \ C[/tex]
The amount of heat released will be:
= [tex]2459.74\times 4.4[/tex]
= [tex]10822 \ Joules[/tex]
or,
= [tex]10.822 \ KJ[/tex]
Moles of benzene combusted will be:
= [tex]\frac{0.258}{78}[/tex]
= [tex]0.00330 \ Moles[/tex]
hence,
The heat combustion for 1 mol of benzene will be:
= [tex]\frac{10.822}{0.00330}[/tex]
= [tex]3271.769 \ KJ/moles[/tex]
2
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
Two atoms interact with each other as shown by the equation. Complete the equation by filling in the missing parts.
1
2
3
4
5
5
H
le
Li
?H + He -
+
TH
H
Reset
Next
Answer:
4 on the top
He in the middle
2 on the bottom
Explanation:
Correct on plato
The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
What is interaction of the two atoms?The two atoms interact with each other as shown by the equation below;
[tex]^4_2He[/tex]
where;
He is Helium atom4 is the mass number of the helium atom2 is the atomic number of the helium atom.Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.
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Se prepara una solución agregando sal en 500 g de agua. Calcular la masa de sal, cuando se tiene una solución al 6,4 % en masa
Answer:
x~ 34.19 grams del sal o ~ 34 grams!
Explanation:
el porcentaje de masa se escribe como
% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%
aquí, el disolvente se da como 500 g de agua.
usa x en lugar de masa de sal y resuelve usando álgebra
6.4 = x / (x+ 500) * 100
0.064 = x / (x+500)
0.064 x + 32 = x
32 = x-0.064x
32 = 0.936 x
x~ 34.19 grams del sal o ~ 34 grams!