To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. In order to compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different.To determine the organic material in a dried lake ted, the percent carbon by mass is measured at two different locations. In order to compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location1(%C) Location2(%C)1 10.40 10.102 10.20 10.903 10.30 10.204 10.40 10.705 10.20 10.40a-1. Far each location, calculate the standard deviation and report it.- location 1: _____- location 2: _____a-2. What is the calculated F value for comparing the standard deviation?b. Are the two standard deviations for the locations significantly different at the 95% confidence level?A. yes.B. No.c. What is the calculated t value used to compare the means of these two locations?d. Are the means for the two different locations significantly different at the 95% confidence level?A. yes.B. No.

Answer:

F statistic = 11.3 ;

-1.02

Step-by-step explanation:

____Location1(%C) ____ Location2(%C)

1 ______ 10.40 _________ 10.10

2 _____ 10.20 _________ 10.90

3 ______10.30 _________ 10.20

4 ______10.40 _________ 10.70

5 ______10.20 _________ 10.40

F = larger sample variance / smaller sample variance

Using calculator :

Sample standard deviation (s)

s1² = 0.01

s2² = 0.113

F = s2² / s1²

F = 0.113 / 0.01

F = 11.3

Yes, the two standard deviations for the locations are significantly different at the 95% confidence level.

B.)

Tvalue

x1 = 10.3 ; x2 = 10.46

μ1 = 10.30 ; μ2 = 10.46

(10.30 - 10.46) / sqrt[(0.01/5) + (0.113/5)]

-0.16 / 0.1568438

-1.02

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