Hence, in answering the stated question, we may say that As a result, cylinder Kendra has approximately 1.45 pounds more freeze pop than Luke.
what is cylinder?The cylinder, which is frequently a three-dimensional solid, is one of the most basic curved geometric forms. In elementary geometry, it is called a prism with a circle as its basis. A cylinder is also defined as an infinitely curved surface in several modern domains of geometry and topology. A "cylinder" is a three-dimensional object with curved sides and round tops and bottoms. A cylinder is a three-dimensional solid figure with two identical circle bases linked by a curving surface at the cylinder's height, which is determined by the distance between the bases from the centre. Cold beverage cans and toilet paper wicks are both examples of cylinders.
1.5 cubic inches = 1/3 * 2.25 * 2
1.5 * 0.8 = 1.2 lbs.
* radius2 * height = * 12 * 4 = 4 cubic in.
Kendra's freeze pop has the following mass:
4 * 0.2 = 0.8 lbs.
The volume for Luke's freeze pop is:
*1.52 x 3 = 6.75 cubic inches
And the majority is:
6.75 * 0.05 = 0.3375 lbs
1.2 pound Benjamin
Kendra weighs 0.8 2.51 pounds.
Luke: 0.3375 1.06 lbs.
As a result, Kendra is consuming the most freeze pop, weighing around 2.51 pounds.
We may deduct Luke's mass from Kendra's to figure out how many more pounds of freeze pop Kendra has than Luke:
2.51 - 1.06 1.45 lbs.
As a result, Kendra has approximately 1.45 pounds more freeze pop than Luke.
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A clothing store has an inventory of at least $6200 in women's coats. A suede coat costs $150 and a cotton
coat costs $69. Write the system of inequalities that represents this situation.
Step-by-step explanation:
Let x be the number of suede coats and y be the number of cotton coats. Then, the system of inequalities representing the situation is:
150x + 69y ≥ 6200 (the total cost of the women's coats must be at least $6200)
x ≥ 0, y ≥ 0 (the number of coats cannot be negative)
Note that this system assumes that the store only sells suede and cotton coats for women, and that there are no other costs associated with these coats (such as shipping or storage costs).
The acceleration of a rocket fired vertically upwards t seconds after launch is 20+4???? m????−2 (as a rocket burns fuel it becomes lighter, so accelerates more quickly). What is the second order differential equation for the height of the rocket. ℎ′′= ___________
What is the general solution? (Please use A as the first constant of integration and B as the second):
General solution: ℎ = ___________
Use the fact that at t = 0 the rocket was on the ground and not moving to find the particular solution that gives the height of the rocket. How high was the rocket after 10 seconds? How fast was it moving then? (hint: acceleration is the rate of change of velocity. The velocity of the rocket is the rate of change of what?)
Height = ______ meters
Velocity = _______ meters/second
For the second order differential equation, we find that Height = 1333.33 meters, Velocity = 240 meters/second.
The acceleration of a rocket fired vertically upwards t seconds after launch is given by a = 20 + 4t m/s². The second order differential equation for the height of the rocket is given by ℎ′′ = a.
The initial conditions for the rocket are:
ℎ(0) = 0 (the rocket starts from the ground) and ℎ′(0) = 0 (the rocket is not moving initially). For the differential equation, we integrate the acceleration once to obtain the velocity, and then integrate the velocity to obtain the height.
Integrating a = 20 + 4t gives v = 20t + 2t² + C1, where C1 is a constant of integration. Using the initial condition v(0) = 0, we get C1 = 0. Integrating v = 20t + 2t² gives ℎ = 10t² + 2/3 t³ + C2, where C2 is another constant of integration. Using the initial condition ℎ(0) = 0, we getC2 = 0.
Therefore, the general solution for the height of the rocket is ℎ = 10t² + 2/3 t³.The velocity of the rocket is given by v = ℎ′.
At t = 10 s, the height of the rocket is ℎ(10) = 10 × 100 + 2/3 × 1000 = 1333.33 m. The velocity of the rocket at t = 10 s is v(10) = ℎ′(10) = 20 × 10 + 2 × 10² = 240 m/s.
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What type of graph would you make if you asked “What is your favorite vacation spot?”
Group of answer choices
Bar Graph
Line Plot
Line Graph
Pie Chart
Answer:
its bar graph
Step-by-step explanation:
thanks for the question
please mark me brainless
The respοnses fοr favοurite vacatiοn spοt can be described best by a pie chart.
What is a pie chart?One sοrt οf graph that illustrates the infοrmatiοn in the circular graph is a pie chart. It is a sοrt οf graphical representatiοn οf data where the slices οf pie depict the relative sizes οf the data. A list οf numerical and categοrical variables is necessary fοr a pie chart. Pie in this cοntext refers tο the entire thing, and slices tο its cοmpοnent pοrtiοns.
If yοu asked "What is yοur favοrite vacatiοn spοt?" tο a grοup οf peοple, the mοst apprοpriate type οf graph tο represent the respοnses wοuld be a pie chart.
A pie chart is a circular chart that is divided intο slices tο represent the prοpοrtiοn οf each categοry in a dataset.
In this case, each slice οf the pie chart wοuld represent a different vacatiοn spοt, and the size οf each slice wοuld cοrrespοnd tο the prοpοrtiοn οf respοndents whο selected that vacatiοn spοt as their favοrite.
Pie charts are useful fοr displaying categοrical data, where the categοries are mutually exclusive and add up tο 100%.
They are easy tο read and understand, and can quickly shοw the distributiοn οf respοnses amοng the different categοries.
On the οther hand, a bar graph οr a line graph wοuld nοt be apprοpriate fοr this type οf data since the respοnses are nοt numerical οr cοntinuοus.
A line plοt wοuld alsο nοt be apprοpriate since it is used tο display a series οf data pοints, and in this case, there is οnly οne data pοint per categοry.
Therefοre, a pie chart is the best chοice.
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what is the root of 45
Answer:
The square root of 45 is approximately 6.708203932.
You have 7 1/2 minutes to complete 3 rock climbing walls.you normally climb each wall in 155 seconds do you have enough time to climb all 3 walls
The answer is no, you do not have enough time to climb all 3 walls within 7 1/2 minutes.
What is the conversion of the unit?
A conversion factor is a fraction equal to ' 1 '. It has the same quantity in the numerator and denominator, but they're in different units. You use it to convert a number from one unit to another unit.
There are different ways to approach this problem, but one possible method is to convert everything to a common unit, such as seconds.
First, convert 7 1/2 minutes to seconds by multiplying by 60:
7.5 minutes x 60 seconds/minute = 450 seconds
Next, multiply the time it takes to climb each wall by 3 to find the total time needed:
3 walls x 155 seconds/wall = 465 seconds
Comparing the total time needed (465 seconds) to the available time (450 seconds), we see that there is not enough time to climb all three walls.
Therefore, the answer is no, you do not have enough time to climb all 3 walls within 7 1/2 minutes.
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Assume that the download times for a two-hour movie are uniformly distributed between 16 and 23 minutes. Find the following probabilities. a. What is the probability that the download time will be less than 17 minutes? b. What is the probability that the download time will be more than 22 minutes? c. What is the probability that the download time will be between 18 and 20 minutes? d. What are the mean and standard deviation of the download times? .
a) The probability is equal to the proportion of the range that lies below 17 minutes.P(X< 17) = (17 - 16) / (23 - 16) = 1/7
b) The probability is equal to the proportion of the range that lies above 22 minutes.P(X > 22) = (23 - 22) / (23 - 16) = 1/7
c) The probability is equal to the proportion of the range that lies between 18 and 20 minutes.P(18 ≤ X ≤ 20) = (20 - 18) / (23 - 16) = 2/7
d) The mean and standard deviation of the download times are 19.5 and 1.4 minutes, respectively.
The probability that the download time will be less than 17 minutes.The probability is equal to the proportion of the range that lies below 17 minutes.P(X< 17) = (17 - 16) / (23 - 16) = 1/7
The probability that the download time will be more than 22 minutes.The probability is equal to the proportion of the range that lies above 22 minutes.P(X > 22) = (23 - 22) / (23 - 16) = 1/7
The probability that the download time will be between 18 and 20 minutes.The probability is equal to the proportion of the range that lies between 18 and 20 minutes.P(18 ≤ X ≤ 20) = (20 - 18) / (23 - 16) = 2/7
The mean and standard deviation of the download times.Using the formula for the mean and standard deviation for a uniform distribution with a range of [a, b],μ = (a + b) / 2 = (16 + 23) / 2 = 19.5σ = (b - a) / sqrt(12) = (23 - 16) / sqrt(12) ≈ 1.4 Therefore, the mean and standard deviation of the download times are 19.5 and 1.4 minutes, respectively.
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Twenty students were surveyed to find out how many hours of TV they watch during a school week. The results are shown to the right. Answer the following questions and round your answers to the nearest half hour. The mode of the data is COMPLETE The range of the data is hours.
Mode: The mode of this data is 8 hours. This is because 8 hours was the most frequently reported amount of time that the students watched TV during a school week.
Amount is a quantitative expression of magnitude, size, or degree of a particular quantity. It is typically used to describe an object, person, or an event. Amount is used to quantify something, to describe its size, duration, or extent. It can be used to measure a wide range of physical and abstract entities, such as money, time, energy, resources, and emotions. For example, you might say “there was a large amount of people at the event” or “I have a certain amount of money saved up.”
Range: The range of this data is 8 hours. This is because the difference between the highest amount of time reported (16 hours) and the lowest amount of time reported (8 hours) is 8 hours.
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1. The number of people with the flu during an epidemic is a function, f, of the number of days, d, since the
epidemic began. The equation f(d) = 50- () defines f.
a. How many people had the flu at the beginning of the epidemic? Explain how you know.
b. How quickly is the flu spreading? Explain how you can tell from the equation.
c. What does f(1) mean in this situation?
d. Does f(3.5) make sense in this situation?
if () is not defined for non-integer values of d, then f (3.5) would not make sense.
What is inequality?In mathematics, an inequality is a statement that compares two values or expressions using a relational operator, such as less than (<), greater than (>), less than or equal to (≤), greater than or equal to (≥), or not equal to (≠). The values being compared can be numbers, variables, or expressions.
by the question.
a. At the beginning of the epidemic, the number of days since the epidemic began is 0. Therefore, substituting d = 0 in the equation f(d) = 50- () gives f (0) = 50 - 0 = 50. So, there were 50 people with the flu at the beginning of the epidemic.
b. The rate at which the flu is spreading can be determined by examining the coefficient of d in the equation f(d) = 50- (). Specifically, if the coefficient is positive, then the flu is spreading at an increasing rate, and if the coefficient is negative, then the flu is spreading at a decreasing rate. Additionally, the magnitude of the coefficient gives an indication of how quickly the flu is spreading. However, since the expression in the parentheses is not given in the question, it is not possible to determine the rate at which the flu is spreading.
c. f(1) represents the number of people with the flu after one day since the epidemic began. Substituting d = 1 in the equation f(d) = 50- (), we get f(1) = 50 - (). Therefore, f (1) depends on the value of ().
d. It is not possible to determine whether f(3.5) makes sense in this situation without knowing the value of (). If () is defined for non-integer values of d, then f(3.5) would make sense and represent the number of people with the flu after 3.5 days since the epidemic began.
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10yd 10yd 4yd 4yd find the area
Answer:
Step-by-step explanation:
Create the smallest pyramid possible with the tool, and record the values of the base length, base width, height, and volume (in terms of π). Then scale the original pyramid by the given scale factors, and record the resulting volumes (in terms of π), to verify that the formula V' = V × k3 holds true for a pyramid
The volume of small pyramid with base length 2, base width 2, and height 2. Its volume was 8/3π. We then scaled it by a factor of 2 and verified the formula V' = V × k3 holds true.
To create the smallest pyramid possible, we will use a tool such as a ruler or protractor to measure and construct the pyramid. Let's assume that we are using a ruler and that the smallest pyramid we can construct has a base length of 2 units, a base width of 2 units, and a height of 2 units.
To calculate the volume of the pyramid, we use the formula:
V = (1/3) × base area × height
The base area of the pyramid is:
A = base length × base width = 2 × 2 = 4 square units
Therefore, the volume of the pyramid is:
V = (1/3) × 4 × 2 = 8/3 cubic units (in terms of π, this is 8/3π cubic units)
Now, let's scale the original pyramid by a factor of k = 2. To find the new dimensions of the scaled pyramid, we multiply each dimension of the original pyramid by the scale factor k:
Base length = 2 × 2 = 4 units
Base width = 2 × 2 = 4 units
Height = 2 × 2 = 4 units
The base area of the scaled pyramid is:
A' = base length × base width = 4 × 4 = 16 square units
The volume of the scaled pyramid is:
V' = (1/3) × A' × height = (1/3) × 16 × 4 = 64/3 cubic units (in terms of π, this is 64/3π cubic units)
Now, we can verify that the formula V' = V × k3 holds true for the scaled pyramid:
V' = 64/3 cubic units
V = 8/3 cubic units
k = 2
V' = V × k3
64/3 = (8/3) × 23
64/3 = 8/3 × 8
64/3 = 64/3
Therefore, the formula V' = V × k3 holds true for a pyramid, and we have successfully verified it using the scaled pyramid.
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Vince has ½ ton of gravel to spread equally in 8 square yards for his driveway. How many tons of gravel will be spread in each square yard?
Given:
Vince has 1/2 ton of gravel.
It is to be spread equally in 8 square yards.
To find:
How many tons of gravel will be spread in each square yard?
Solution:
Total gravel = 1/2 ton
To be spread equally in 8 square yards.
No. of tons of gravel will be spread in each square yard = (1/2) / 8 = 1/16 tons.
Therefore, 1/16 tons of gravel will be spread in each square yard.
Answer:
Given:
Vince has 1/2 ton of gravel.
It is to be spread equally in 8 square yards.
To find:
How many tons of gravel will be spread in each square yard?
Solution:
Total gravel = 1/2 ton
To be spread equally in 8 square yards.
No. of tons of gravel will be spread in each square yard = (1/2) / 8 = 1/16 tons.
Therefore, 1/16 tons of gravel will be spread in each square yard.
Step-by-step explanation:
Let W be the set of all vectors [x y x + y] with x and y real. Determine whether each of the following vectors is in W. v = [- 2 - 2 2] v = [6 - 1 - 3]
First vector v = [- 2 - 2 2] is in W and the second vector v = [6 - 1 - 3] is not in W.
W be the set of all vectors [x y x + y] with x and y real. To find: Whether each of the following vectors is in W. Let's check each vector whether it is in W or not: v = [- 2 - 2 2] To check the given vector is in W or not, we need to find the values of x and y such that the third component equals 2.So, x + y = 2 ⇒ y = 2 - x
The given vector can be written as v = [x y x + y]= [x, 2 - x, 2] Thus, given vector v is in W. v = [6 - 1 - 3]. To check the given vector is in W or not, we need to find the values of x and y such that the third component equals -3. So, x + y = -3 ⇒ y = -3 - x The given vector can be written as v = [x y x + y]= [x, -3 - x, -3]Thus, given vector v is not in W.
Moreover, Vectors, in Maths, are objects which have both, magnitude and direction. Magnitude defines the size of the vector. It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.
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Find all real solutions of this equation to answer the question.
(6 – 2x)(3 – 2x)x = 40
Yes. Because is a root, you can cut squares with sides of in. to make the box
No. This equation has no real solutions.
No. The only real solution is x = 4. It is not possible to cut squares of this size.
The solution to the equation is (c) No, because there is only one real solution and the value is x = 4
What is the method for figuring out the answer to the equation?The given equation is
(6 – 2x)(3 – 2x)x = 40
Next, we answer the question from the numbers given from the list of options
In option (c), we have
x = 4
By substitution, the equation becomes
(6 - 2 * 4)(3 - 2 * 4) * 4 = 40
Evaluate the product expression
40 = 40
The above equation is true
Hence, the solution is (c)
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as the Earth revolves around the Sun it travels at a rate of approximately 18 miles per second convert this rate to kilometers per second. at this rate how many kilometers will the Earth travel in 10 seconds? in your computions assume that one mile is equal to 1.6 km. do not round your answer
Aproximate speed of the Earth's rotation around the Sun is 18.5 miles per second (30 km per second). 110,000 kilometers per hour is equal to 30 kilometers per second.
What is unitary method?"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."
We always count the unit or amount value first and then calculate the more or less amount value.
For this reason, this procedure is called a unified procedure.
Many set values are found by multiplying the set value by the number of sets.
A set value is obtained by dividing many set values by the number of sets.
Hence, Aproximate speed of the Earth's rotation around the Sun is 18.5 miles per second (30 km per second). 110,000 kilometers per hour is equal to 30 kilometers per second.
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a zipline drops 30 feet from one treetop to a second treetop. if the angle of inclination from the shorter tree to the taller tree is 10 degrees, how long is the zip;ine?
167.7 feet is the length of the zipline.
The angle of inclination is the angle formed between a horizontal line and a line or surface that is sloping or inclined. It is a measure of the steepness or slope of the line or surface and is typically expressed in degrees or as a trigonometric ratio.
We have a zipline that drops 30 feet from one treetop to a second treetop.
If the angle of inclination from the shorter tree to the taller tree is 10 degrees.
Let AB be the distance between two trees and BC be the drop in height from A to C. Then,
We have BC/AB = tan(θ)
Where θ = 10 degrees
We know BC = 30 feet.
So,
AB = BC/tan(θ) = 30/tan(10°) = 167.7 feet (rounded to one decimal place)
Therefore, the length of the zipline is 167.7 feet.
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Please help!!! I need the answer
Answer: 8
Step-by-step explanation:
Using SOHCAHTOA, we need TOA as we have the opposite (1) and the adjacent (7)
θ = [tex]tan^{-1}(\frac{1}{7} )[/tex] = 8.13 = 8
Simplify the following algebric expressionX^2-x-12/x^2-4
Simplified form of the algebraic expression (x^2 - x - 12) / (x^2 - 4) = (x + 3) / (x - 2)
To simplify the given algebraic expression (x^2 - x - 12) / (x^2 - 4), we first need to factor both the numerator and denominator as much as possible.
We can factor the numerator using the product-sum method or the quadratic formula, which yields:
x^2 - x - 12 = (x - 4)(x + 3)
Similarly, we can factor the denominator as a difference of squares, which gives:
x^2 - 4 = (x - 2)(x + 2)
Now, we can substitute these factorizations into the original expression:
(x^2 - x - 12) / (x^2 - 4) = [(x - 4)(x + 3)] / [(x - 2)(x + 2)]
At this point, we can simplify the expression by canceling out the factors that appear in both the numerator and denominator. Specifically, we can see that (x - 4) and (x + 2) appear in both the numerator and denominator, so they cancel out:
[(x - 4)(x + 3)] / [(x - 2)(x + 2)] = (x + 3) / (x - 2)
So the simplified expression is (x + 3) / (x - 2).
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from the sum of 3x+ 5y -2 and 2x-3y +1 subtract the sum of 4x -8y +3 and -5x + 6y +7
Answer:
First, let's simplify both sums by combining like terms:
3x + 5y - 2 + 2x - 3y + 1 = 5x + 2y - 1
4x - 8y + 3 - 5x + 6y + 7 = -x - 2y + 10
Now we can subtract the second sum from the first:
(5x + 2y - 1) - (-x - 2y + 10) = 5x + 2y - 1 + x + 2y - 10
Simplifying this expression, we get: 6x + 4y - 11
a firm is experiencing theft problems at its warehouse. a consultant to the firm believes that the dollar loss from theft each week (t) depends on the number of security guards (g) and on the unemployment rate in the county where the warehouse is located (u measured as a percent). in order to test this hypothesis, the consultant estimated the regression equation t = a + bg + cu and obtained the following results: dependent variable: t r-square f-ratio p-value on f observations: 27 0.7793 42.38 0.0001 variable parameter estimate standard error t-ratio p-value intercept 5150.43 1740.72 2.96 0.0068 g -480.92 130.66 -3.68 0.0012 u 211.0 75.0 2.81 0.0096 based on the information in the table, which of the following is correct at the 1% level of significance?
At the 1% level of significance, both the number of security guards (g) and the unemployment rate (u) have a significant effect on the dollar loss from theft each week (t). This is indicated by the p-values for both variables, which are both less than 0.01 (0.0012 for g and 0.0096 for u).
This means that there is less than a 1% chance that the observed relationship between these variables and the dependent variable (t) is due to chance. Therefore, we can reject the null hypothesis that there is no relationship between these variables and the dependent variable, and conclude that they have a significant effect on the dollar loss from theft each week.
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If the two shortest sides of a triangle measure 16 cm and 30 cm, what does the longest side need to
measure in order to prove that it is a right triangle?
___________ cm
Answer:
34
Step-by-step explanation:
In all right triangles, the two shortest sides squared equals the longest side squared, given by the equation [tex]a^2+b^2=c^2[/tex].
We know the two shortest sides, so we can plug in
[tex]16^2+30^2=c^2\\256+900=c^2\\1156=c^2\\c=\sqrt{1156} \\c=34[/tex]
HELP ASAP
What are all the zeros of the polynomial function?
[tex]f(x)=x^{4} -2x^{3} -8x^{2} +10x+15[/tex]
Answer:
The zeros of the polynomial function f(x) = x^4 - 2x^3 - 8x^2 + 10x + 15 are x = -1, x = 3 + √29/2, x = 3 - √29/2, and x = -0.4495 (approximately).
Step-by-step explanation:
To find all the zeros of the polynomial function f(x) = x^4 - 2x^3 - 8x^2 + 10x + 15, we can use the Rational Root Theorem and synthetic division.
Write the polynomial function in descending order of degree: f(x) = x^4 - 2x^3 - 8x^2 + 10x + 15.
Use the Rational Root Theorem to generate a list of possible rational zeros: ±1, ±3, ±5, ±15.
Use synthetic division to test each possible zero. We start with x = 1:
1 │ 1 -2 -8 10 15
│ 1 -1 -9 1
└───────────────
1 -1 -9 1 16
x = 1 is not a zero of the polynomial function.
We continue testing the remaining possible zeros:
-1 │ 1 -2 -8 10 15
│ -1 3 5 -15
└───────────────
1 -3 -3 15 0
Since the remainder is zero, we have found a zero of the polynomial function at x = -1.
We can use synthetic division to factor the polynomial function:
(x + 1)(x^3 - 3x^2 - 6x + 15)
Now we can solve for the remaining zeros of the polynomial function by factoring the cubic equation using the Rational Root Theorem and synthetic division:
3 │ 1 -3 -6 15
│ 3 0 -18
└─────────────
1 0 -6 -3
x = 3 is not a zero of the polynomial function.
-3 │ 1 -3 -6 15
│ -3 18 -36
└────────────
1 -6 12 -21
x = -3 is not a zero of the polynomial function.
The only remaining possible rational zeros are ±1/2 and ±5/2, but testing these values using synthetic division does not yield any more zeros.
However, we can see that the polynomial function can be factored as follows:
(x + 1)(x - 3)(x^2 - 3x - 5)
We can solve for the remaining zeros of the polynomial function by factoring the quadratic equation using the quadratic formula or factoring by grouping. Either way, we find that the remaining zeros are approximately x = (3 + √(29))/2 and x = (3 - √(29))/2.
Therefore, the zeros of the polynomial function f(x) = x^4 - 2x^3 - 8x^2 + 10x + 15 are x = -1, x = 3 + √29/2, x = 3 - √29/2, and x = -0.4495 (approximately).
Hopefully this helps, if not I'm sorry! If you need more help, you may ask me! :]
$30 for bike rental
$125 for cost of food and camp for each biker
$700 for van rental
$350 of income earned for each biker
a. Write an equation for the total expenses E for n bikers.
b. Write an equation for the total income I for n bikers.
c. Write an equation for the profit P for n bikers
Answer: a. The equation for the total expenses E for n bikers is:
E = 30n + 125n + 700
b. The equation for the total income I for n bikers is:
I = 350n
c. The equation for the profit P for n bikers is:
P = I - E = 350n - (30n + 125n + 700) = 195n - 700
The distance, d, in inches of a weight attached to a spring from its equilibrium as a function of time, t, in seconds can be modeled by the graph below. Which equation is represented in the graph below?
On a coordinate plane, a curve crosses the y-axis at (0, negative 5). It increases to (1, 5) and then decreases to (2, negative 5). 5 cycles are shown.
d = negative 10 cosine (StartFraction pi Over 2 EndFraction t)
d = negative 10 cosine (pi t)
d = negative 5 cosine (StartFraction pi Over 2 EndFraction t)
d = negative 5 cosine (pi t)
Answer:
d = negative 5 cosine (StartFraction pi Over 2 EndFraction t) [y=-5*cos(π/2)]
Step-by-step explanation:
See the attached graph for the explanation. Desmos graphing software was used to plot the 4 equation options (using x in place of t and y in place of d).
The given points were added to see which of the graphed lines they best match. We can see that the third option, y=-5*cos(π/2), intersects all four points.
Two of the options (1st and 3rd) lie too close to y=0 to see their difference on the scale of the graph, so we can eliminate them. (Options 1 and 3)
Option 2 has an amplitude higher than the given points, so it can also be eliminated.
y=-5*cos(π/2) best represents the given points.
lf A is equal to 0.5 (a+bh) express h in terms of A, and b
The required expression can express h in terms of A and b as [tex]$ h = \frac{2A - a}{b} $$[/tex]
What is expression?Mathematical expressions consist of at least two numbers or variables, at least one math procedure, and a sentence. It's possible to multiply, divide, add, or subtract with this mathematical procedure. An expression's form is as follows: Expression: (Math Operator, Number/Variable, Math Operator)
According to question:First, we can start by isolating the term that contains h on one side of the equation. To do this, we will first distribute the 0.5 term to get:
A = 0.5a + 0.5bh
Then, we can subtract 0.5a from both sides to get:
A - 0.5a = 0.5bh
Next, we can divide both sides by 0.5b to isolate h:
[tex]$ \frac{A - 0.5a}{0.5b} = h $$[/tex]
Simplifying the expression further, we can see that:
[tex]$$ \boxed{h = \frac{2A - a}{b}} $$[/tex]
Therefore, we can express h in terms of A and b as:
[tex]$ h = \frac{2A - a}{b} $$[/tex]
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Drag the points to create two different cylinders with the same volume.
What is the volume of one cylinder?
one is circle 3 and 8,
two is circle is 6 and 4.
Help please....
Answer:
u multiply 3 with 8 then u get ur answer the u do the same method which is multiplication with 6 with 4 to get ur answer
What number is 3% larger than 600?
Answer:
3% of 600 is (3/100) x 600 = 18.
So, a number that is 3% larger than 600 would be:
600 + 18 = 618.
Therefore, the number that is 3% larger than 600 is 618
Answer:
618
Step-by-step explanation:
Let us first see what is 3% of the 600
3/100 x 600 = 18
a number that is 3% larger than 600 is 600+18 = 618.
7+5x=-3
solve for x.
(0)
The endpoints of a diameter of a circle are (2,4) and (-14,-8).
1). Write an equation of the circle in standard form.
2). Graph the circle.
3). An equation of the circle in standard form is ?
The radius is half that distance.r = 1/2(d) where d = distance between the endpoints of the diameter.
1. Writing the equation of the circle in standard formWe know that the endpoints of a diameter are (2,4) and (-14,-8) respectively, and that the midpoint of the diameter is the center of the circle. Therefore, let's begin by calculating the midpoint of the diameter using the midpoint formula:x = (x1 + x2)/2y = (y1 + y2)/2x = (2 + (-14))/2 = -6y = (4 + (-8))/2 = -2So, the midpoint is (-6,-2) which is the center of the circle. Now, we can use the distance formula to calculate the radius. Recall that the diameter is the distance between the two endpoints of the diameter, so the radius is half that distance.r = 1/2(d) where d = distance between the endpoints of the diameter.So, d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]d = sqrt[(-14 - 2)^2 + (-8 - 4)^2]d = sqrt[(-16)^2 + (-12)^2]d = sqrt[256 + 144]d = sqrt[400] = 20So, r = 20/2 = 10. Now that we have the center and radius, we can use the standard form equation of a circle which is:(x - h)^2 + (y - k)^2 = r^2where (h,k) is the center and r is the radius.Substituting our values into the equation, we have:(x + 6)^2 + (y + 2)^2 = 100Expanding and simplifying, we can write the equation of the circle in standard form as:x^2 + 12x + y^2 + 4y + 20 = 0This is the equation in standard form.2. Graphing the circleTo graph the circle, we need to plot the center which is (-6,-2) and then draw the circle with radius 10 units. The circle will be a curve that is equidistant from all points on it to the center. Here's a sketch of the circle.
3. An equation of the circle in standard form is x² + 12x + y² + 4y + 20 = 0.
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9. A taxi service charges $3 for the first mile and then $2. 25 for every mile after that. The
farthest the taxi will travel is 35 miles. If x represents the number of miles traveled, and y
represents the total cost of the taxi ride, what is the most appropriate domain for the
situation?
a) 2. 25
b) 0
c) 3 < x < 81. 75
d) 2. 25 < x < 81. 75
The domain can be written as 3 <x < 81.75, which includes all x values that are feasible and fit within the constraints of the issue.
The most appropriate domain for this situation is (c) 3 < x < 81.75.
The reason for this is that the taxi charges $3 for the first mile, so x must be greater than 1. After that, the taxi charges $2.25 for every mile after the first, so the domain must exclude x = 0. Additionally, the problem states that the farthest the taxi will travel is 35 miles, so the domain must also include x < 35.
Therefore, the domain can be expressed as 3 < x < 81.75, which allows for all possible values of x that fall within the given parameters of the problem.
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If bolt thread length is normally distributed, what is theprobability that the thread length of a randomly selected boltis
a) Within 1.5 SDs of its mean value
b)Farther than 2.5 SDs from its mean value
c)Between 1 and 2 SDs from its mean value
Probability that the thread length of a randomly selected bolt is within 1.5 SDs of its mean value is 0.8664, is farther than 2.5 SDs from its mean value is 0.0124 and between 1 and 2 SDs from its mean value is 0.2728.
Probability that the thread length of a randomly selected bolt is within 1.5 SDs of its mean value P (μ - 1.5σ < X < μ + 1.5σ)= P(Z < 1.5) - P(Z < -1.5)Here, Z is the standard normal variable P(Z < 1.5) = 0.9332 (from standard normal table)P(Z < -1.5) = 0.0668 (from standard normal table) So, P (μ - 1.5σ < X < μ + 1.5σ) = 0.9332 - 0.0668= 0.8664
Thus, probability that the thread length of a randomly selected bolt is within 1.5 SDs of its mean value is 0.8664. Probability that the thread length of a randomly selected bolt is farther than 2.5 SDs from its mean value P (X < μ - 2.5σ) + P (X > μ + 2.5σ) = P (Z < -2.5) + P (Z > 2.5)P (Z < -2.5) = 0.0062 (from standard normal table)P (Z > 2.5) = 0.0062 (from standard normal table)
So, P (X < μ - 2.5σ) + P (X > μ + 2.5σ) = 0.0062 + 0.0062 = 0.0124 Probability that the thread length of a randomly selected bolt is between 1 and 2 SDs from its mean value P (μ - 2σ < X < μ - 1σ) = P (Z < -1) - P (Z < -2) + P (Z < 1) - P (Z < 2)P (Z < -1) = 0.1587 (from standard normal table)
P (Z < -2) = 0.0228 (from standard normal table)P (Z < 1) = 0.8413 (from standard normal table)P (Z < 2) = 0.9772 (from standard normal table) So, P (μ - 2σ < X < μ - 1σ) = 0.1587 - 0.0228 + 0.9772 - 0.8413= 0.2728
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