THIS IS WORTH 30 POINTS

1. Point B is located at (-4, -6). Where is the location of B’ after a reflection over the y-axis?

Answers

Answer 1
It will be at (4,-6)
Answer 2

Answer:

your awnser would be [4, −6]

Step-by-step explanation:

hope this helps


Related Questions

Leia needs to make at least 40 necklaces to sell at a craft show. So far, she has made 7. Which inequality shows the
number of necklaces, n, that she still needs to make?


A). n - 7 less than or equal to 40

B) n - 7 greater than or equal to 40

C). n + 7 less than or equal to 40

D). n + 7 greater than or equal to 40

Answers

Answer:

The answer is D

Hope this helps!

Brainliest??

Answer:

D

Step-by-step explanation:

the answer is D because if she already made 7 she need to add n to 7 to get 40 or greater

In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association and independence should be performed. What is the expected frequency of West Campus and failed

Answers

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

Answer:

57.5

Step-by-step explanation:

Got it right on the test.

Ive been stuck on this problem for an hour, help pleaseee.

The graph of the function is given below. Give all y-intercepts and x-intercepts shown.

Answers

Answer:

y intercept: [tex]y = 1[/tex]

x intercept: [tex]x = -1[/tex] and [tex]x = -3[/tex]

Step-by-step explanation:

Given

The attached graph

Solving (a): The y intercepts

This is the point where [tex]x = 0[/tex]

From the attached graph, [tex]x = 0[/tex] when

[tex]y = 1[/tex]

Hence, the y intercept is 1

Solving (b): The x intercepts

This is the point where [tex]y = 0[/tex]

From the attached graph, [tex]y = 0[/tex] when

[tex]x = -1[/tex] and [tex]x = -3[/tex]

Hence, the x intercept are -1 and -3

What is perimeter of 300 315 55

Answers

Just add so it will be 670

Given the set of data below, which measure(s) will change if the outlier is removed? (Check all that apply.) 1,6,8,8,8
mean
range
median
mode​

Answers

The diameter of a circle measures 12 yd what is the Circumference some of the circle? Use 3.14 for n

The mean, range, and median will vary if the outlier is eliminated. Options A, B, and C are correct.

What is mean?

The arithmetic mean is a term used to describe the average. It's the ratio of the total number of observations to the sum of the observations.

The data set is;

1,6,8,8,8

Outliers in a dataset or graph are extreme values that stand out significantly from the main pattern of values.

There is an aberration in the graph below, on the far left. The value in January is much lower than the value in the other months.

If the outlier is removed mean, range, and median will changes.

Hence options A, B and C are correct.

To learn more about mean refer:

https://brainly.com/question/13451489

#SPJ2

Divide the following complex numbers:
(4-i)/(3+4i)
A.-8/7 + 19/7i
B. 16/25 - 19/25i
C. 8/25 - 19/25i
D. -16/7 + 19/7i

Answers

Answer:

C. 8/25 - 19/25i

Step-by-step explanation:

Given that:

[tex]\dfrac{4-i}{3+4i}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)} \\ \\ =\dfrac{12 -16i -3i+4i^2}{9 - 12i +12i -16i^2} \\ \\ = \dfrac{12-19i+4i^2}{9-16i^2} \\ \\ = \dfrac{8-19i}{25}[/tex]

[tex]=\dfrac{8}{25}- \dfrac{19i}{25}[/tex]

I neeeddddd help on this I’m failing

Answers

Answer:

AB = 9

Step-by-step explanation:

Here is a simple case of a proportion.

We see that:

3:4

x:12

what can we do to make 4 into 12?

we multiply it by 3

so we do the same to 3

3*3=9

Which of the following CANNOT be true for a triangle?

A. A triangle can be equilateral and obtuse at the same time.
B. A triangle can be equilateral and equiangular at the same time.
C. A triangle can be isosceles and right at the same time.
D. A triangle can be scalene and obtuse at the same time.

Answers

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

A distance of 400 km is represented in the map by 3 cm. What is the distance between two towns if they are 7.5 cm apart in the map?​

Answers

Answer:

The distance between the two towns is of 1000 km.

Step-by-step explanation:

This question is solved by proportions, using a rule of three.

We have that:

3 cm represents a distance of 400 km.

What is the distance represented by 7.5 cm?

3 cm - 400 km

7.5 cm - x km

Applying cross multiplication:

[tex]3x = 400*7.5[/tex]

[tex]x = \frac{400*7.5}{3}[/tex]

[tex]x = 1000[/tex]

The distance between the two towns is of 1000 km.

Order the following units of a capacity families to greatest gallon paint cup quart

Answers

Answer:

7 yards

Step-by-step explanation:

Quadrilateral ABCD is inscribed. The measure of ∠A=67°. What is the measure of ∠C?

Answers

Answer:

angle C =113 degree

Step-by-step explanation:

angle A + angle C =180 degree

angle C = 180 degree - angle A  

angle C = 180 degree - 67 degree

=113 degree

1800=3×N
help asap plzzz

Answers

Okay first step is dividing by three on both sides.
1800/3 = 3/3 • N
now you have
600 = N
and you’re done!!! :)

An experimenter is studying the effects of temperature, pressure, and type of catalyst on yield from a certain chemical reaction. She considers 6 different temperatures, 5 different pressures, and 4 different catalysts are under consideration.

a. If any particular experimental run involves the use of a single temperature, pressure, and catalyst, how many experimental runs are possible?
b. How many experimental runs are there that involve use of the lowest temperature and two lowest pressures?
c. Suppose that five different experimental runs are to be made on the first day of experimentation. If the five are randomly selected from among all the possibilities, so that any group of five has the same probability of selection, what is the probability that a different catalyst is used on each run?

Answers

Answer:

a) 120 possible experimental runs

b) 8 possible experimental runs

c) 0

Step-by-step explanation:

a. For the experiment, there are 6 different temperatures (T), 5 different pressures (P), and 4 different catalysts (C). We can find the total number of combinations using the product rule.

N = T × P × C

N = 6 × 5 × 4 = 120

b) If we use only the lowest temperature, we have T = 1, and if we use the two lowest pressures, we have P = 2. We can find the total number of combinations using the product rule.

N = T × P × C

N = 1 × 2 × 4 = 8

c) If we perform 5 experimental runs with 4 possible catalysts, it is not possible to use a different catalyst each time. At least, 1 catalyst must be repeated twice. Then, the event "a different catalyst is used on each run" has a probability of 0.

Solve for x. Round to the nearest tenth, if necessary.
P.
х
50°
Q
R
4.2

Answers

Answer:

5.0 =x

Step-by-step explanation:

Since this is a right triangle

tan theta = opp side/ adjacent side

tan 50 = x / 4.2

4.2 tan 50 = x

5.005365089 =x

Rounding to the nearest tent

5.0 =x

1. How much salt and baking powder together is needed to make 36 cup cakes?

Answers

Answer:

too much salt will not bring taste to the cup cakes

Step-by-step explanation:

Answer nyo po to...Ang hirap(;-;)....pls. Lang po

Answers

The answer goes here,

a) We have to tell the time and day which simone has to tell her sister, for picking her up from airport.

b) We have given the day (monday), time(7:00 pm) and total time to reach the destination(18 hours).

c) No such formula will be used here, we will just use our mental ability to solve this question.

d) She will leave at 7:00 pm, day has 24 hours. So, she will be in the flight on monday:

= 24 - (12 + 7) ----------- [12 here means the time of rest of the day,(morning to noon)]

= 24 - 19

= 5 hours

So, she will complete 5 hours of her destination on monday,now the time left is:

= 18 - 5

= 13

= (12 + 1 )hours

So, on tuesday, she will be in the flight for 12 hours (noon) and then on 1:00 pm she will reach the airport, as she needs and extra hour to plane so, the final time is 1:30 pm. And finally, the time she should tell her sister is 1.30 pm.

A teacher is comparing the quarter grades between two of her classes. She takes a random sample of 8 students from each class and lists the grades as shown. Find the mean for Class A.
Class A: 80, 83, 74, 91, 76, 87, 93, 72
Class B: 90, 75, 82, 86, 73, 85, 79, 94

Answers

The mean for class A is 82

ellus
Find the surface area of the composite figure.
2 cm
7 cm
2 cm
12 cm
12 cm
7 cm
7 cm
SA = [?] cm2

Answers

Answer:

SA = 484 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)

✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 7 cm

H = 12 cm

S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²

✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 2 cm

H = 2 cm

S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²

✔️Base area of the smaller rectangular prism = L*W

L = 7 cm

W = 2 cm

Area = 7*2 = 14 cm²

✅Surface area of the composite figure = 434 + (64 - 14)

= 434 + 50

= 484 cm²

What do the value of
(5 1/3)^3

Answers

Answer:

[tex] \frac{4096}{27} [/tex] or [tex]151 \frac{19}{27} [/tex]

Step-by-step explanation:

[tex](5 \frac{1}{3} {)}^{3} [/tex][tex](5 + \frac{1}{3} {)}^{3} [/tex][tex]( \frac{16}{3} {)}^{3} [/tex][tex] \frac{ {16}^{3} }{ {3}^{3} } [/tex][tex] \frac{4096}{27} [/tex][tex]151 \frac{19}{27} [/tex]Hope it is helpful....

10 points! If correct you get brainliest.
Which one's apply?

Answers

Answer:

The answer is C and E

Step-by-step explanation:

Complete all the problems.
1.
X - 6 = -24
Solve for x.

Answers

Answer:

x= -18

Step-by-step explanation:

x= -24 + 6

Add -24 and 6.

x= -18

Answer:

X = -18

Step-by-step explanation:

You want to isolate X by itself. To isolate X on one side of the = sign, use the addition property of equality (to undo the subtraction of 6 from x) by adding 6 to both sides of the equation. We use the addition property of equality because this is the inverse operation. It is important to add 6 to both sides of to maintain an equivalent equation.

1. Set up your equation

      X - 6  = -24

          +6     +6

2. Solve out

   X - 6  = -24

       +6     +6

       X    =  -18

Answer: -18

The regional transit authority for major metropolitan area wants to determine whether this relationship between the age of a bus and the annual maintenance cost. A sample of 10 buses resulted in the data located in the attached file above. Answer the following questions: Create a scatter chart using the data from the provided Excel file above. What does the scatter chart indicate about the relationship between age of a bus and annual maintenance cost

Answers

Answer Answer:

The scatter plot indicates that a positive linear relationship exists between the age of a car and its maintenance cost. This is depicted by the positive slope direction which indicates the maintainance cost of the car is will increase as the age of the car increases. If the correlation Coefficient of the data was calculated, a correlation Coefficient value of about 0.934 will be obtained.

Step-by-step explanation:

Check answer

What’s the measure of angle B? It’s not 64.

Answers

Answer:

65 degrees

Step-by-step explanation:

Angles in a triangle add to 180°.

Five classmates want to know how many of the 2688 students in their school prefer pop music. They each randomly survey 64 students. The table shows the results.
Use the results from each classmate to make an inference about the number of students in the school who prefer pop music.

Based on Shannon's results, the number is __
students.

Based on Trey's results, the number is __
students.

Based on Robert's results, the number is __
students.

Based on Callie's results, the number is __
students.

Based on Lani's results, the number is __
students.


Question 2
Describe the variation of the five inferences. Which one would you use to describe the number of students at the school who prefer pop music? Explain.
The greatest is __
students. The least is __
students. The median of the data is __
. The mode of the data is __
. So, use the inference of __
students to describe the number of students at the school who prefer pop music.

Answers

Answer:

Question 1

Shannon: 882/2688

Trey: 1008/2688

Robert: 798/2688

Callie: 882/2688

Lani: 840/2688

Question 2

The greatest is 1008/2688 students.

The least is 798/2688 students.

The median of the data is 882/2688 students.

The mode of the data is 882/2688 students.

So, use the inference of 882/2688 students to describe the number of students at the school who prefer pop music.

Step-by-step explanation

Question 1

Shannon: Because 21/64 in Shannon's survey stated they preferred pop music, we can apply it to the entire school of 2688 students. 2688 divided by 64, then multiplied by 21 gets us 882/2688 who might prefer pop music in the entire school without surveying all of the students.

Trey: Because 24/64 in Trey's survey stated they preferred pop music, we can apply it to the entire school of 2688 students. 2688 divided by 64, then multiplied by 24 gets us 1008/2688 who might prefer pop music in the entire school without surveying all of the students.

Robert: Because 19/64 in Robert's survey stated they preferred pop music, we can apply it to the entire school of 2688 students. 2688 divided by 64, then multiplied by 19 gets us 798/2688 who might prefer pop music in the entire school without surveying all of the students.

Callie: Because 21/64 in Callie's survey stated they preferred pop music, we can apply it to the entire school of 2688 students. 2688 divided by 64, then multiplied by 21 gets us 882/2688 who might prefer pop music in the entire school without surveying all of the students.

Lani: Because 20/64 in Lani's survey stated they preferred pop music, we can apply it to the entire school of 2688 students. 2688 divided by 64, then multiplied by 20 gets us 840/2688 who might prefer pop music in the entire school without surveying all of the students.

Question 2

Using Shannon's or Callie's survey would best describe the number of students in the entire school because their individual results (21/64) is the average of all of the individual results of the 5 students. If you decide to use any of the other individual survey results, you will not get the closest answer to the actual amount of students who prefer pop music in the entire school.

Using the individual survey results to estimate the number of students who prefer pop music in the entire school:

The greatest was Trey's results, which estimated about 1008 out of 2688 students in the entire school who would prefer pop music.

The least was Robert's results, which estimated about 798 out of 2688 students in the entire school who would prefer pop music.

The median of the data was 882 out of 2688 students in the entire school who would prefer pop music, as shown in Shannon's and Callie's individual survey results.

To find the median, list the results least to greatest, then look at the number that is in the exact middle. If there is no middle, but instead two middle numbers, find the average of the two.

The mode of the data was Shannon's or Callie's results, which estimated about 882 out of 2688 students in the entire school who would prefer pop music.

To find the mode, look for the number or result that it repeated the most (Ex: the result of 21/64 students who preferred pop music was found twice compared to the other individual survey results which did not repeat more than once).

So, in the end using Shannon's or Callie's individual survey results to estimate the amount of students in the entire school who prefer pop music is the best way to do so.

Please comment if you think I made a mistake, misunderstood, or missed something.

320% of 69 is what number?

Answers

Answer:

220.8

Step-by-step explanation:

I believe 220.8

sorry if I am wrong.

Answer:

320×69÷100

answer * number is 220

brainliest for answer

Answers

Answer:

what is the question?

Step-by-step explanation:

Answer:

i answered

Step-by-step explanation:

The time spent waiting in the line is approximately normally distributed. The mean waiting time is 55 minutes and the variance of the waiting time is 11. Find the probability that a person will wait for more than 33 minutes. Round your answer to four decimal places.

Answers

Answer:

1 = 100% probability that a person will wait for more than 33 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean waiting time is 55 minutes and the variance of the waiting time is 11.

This means that [tex]\mu = 55, \sigma = \sqrt{11}[/tex]

Find the probability that a person will wait for more than 33 minutes.

This is 1 subtracted by the p-value of Z when X = 33. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{33 - 55}{\sqrt{11}}[/tex]

[tex]Z = -6.63[/tex]

[tex]Z = -6.63[/tex] has a p-value of 0.

1 - 0 = 1

1 = 100% probability that a person will wait for more than 33 minutes.

In a small metropolitan area, annual losses due to storm, fire, andtheft are assumed to be independent, exponentially distributed random variableswith respective means 1.0, 1.5, 2.4. Determine the probability that the maximumof these losses exceeds 3.

Answers

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

2. Suppose over several years of offering AP Statistics, a high school finds that final exam scores are normally distributed with a mean of 78 and a standard deviation of 6. A. What are the mean, standard deviation, and shape of the distribution of x-bar for n

Answers

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is [tex]s = \frac{6}{\sqrt{n}}[/tex] and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 78 and a standard deviation of 6

This means that [tex]\mu = 78, \sigma = 6[/tex]

Samples of n:

This means that the standard deviation is:

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{n}}[/tex]

What are the mean, standard deviation, and shape of the distribution of x-bar for n?

By the Central Limit Theorem, the mean is 78, the standard deviation is [tex]s = \frac{6}{\sqrt{n}}[/tex] and the shape is approximately normal.

Sum of 4x^3+6x^2+2x^2-3 and 3x^3+3x^2-5x-5 is

Answers

9514 1404 393

Answer:

  7x^3 +11x^2 -5x -8

Step-by-step explanation:

Combine like terms.

  (4x^3+6x^2+2x^2-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +2 +3)x^2 +(-5)x + (-3 -5)

  = 7x^3 +11x^2 -5x -8

_____

Noting that the first expression contains two x^2 terms, we wonder if you actually want the sum ...

  (4x^3+6x^2+2x-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +3)x^2 +(2 -5)x +(-3 -5)

  = 7x^3 +9x^2 -3x -8

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