this better?just help with riddle

The match of the responses to the letters gives the solution of the riddle

as; IT HAS THE EDGE

1. The volume of a cone is; [tex]V = \mathbf{\frac{1}{3} \cdot \pi \cdot r^2 \cdot h}[/tex]

Therefore;

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times3.14 \times 7^2 \times 14 \approx \mathbf{718 \, u^3}[/tex]

718 u³ is equivalent to S

2. Diameter of the cone, d = 24

Therefore;

Radius of the cone = 12

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times3.14 \times 12^2 \times 28 \approx \mathbf{4220.2\, u^3}[/tex]

4220.2 u³ is equivalent to E

3. d = 11, and h = 12

Therefore;

r = 5.5

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 5.5^2 \times 12\approx \mathbf{379.9\, u^3}[/tex]

379.9 u³ is equivalent to T

4. r = 3.2, and h = 10

Therefore;

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 3.2^2 \times 10\approx \mathbf{107.2\, u^3}[/tex]

107.2 u³ is equivalent to G

5. r = 9, h = 15

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 9^2 \times 15\approx \mathbf{1271.7\, u^3}[/tex]

1,271.7 u³ is equivalent to D

6. d = 4, and h = 6

Therefore;

r = 2

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 2^2 \times 6\approx \mathbf{25.1 \, u^3}[/tex]

25.1 u³ is equivalent to A

7. r = 1.5, and h = 3

Therefore;

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 1.5^2 \times 3\approx \mathbf{7.1\, u^3}[/tex]

7.1 u³ is equivalent to E

8. d = 30, and h = 34

Therefore;

r = 15

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 15^2 \times 34\approx \mathbf{8,007\, u^3}[/tex]

8,007 u³ is equivalent to I

9. r = 5, and h = 8

[tex]Volume \ of \ the \ cone \approx \frac{1}{3} \times 3.14 \times 5^2 \times 8\approx \mathbf{209.3\, u^3}[/tex]

209.3 u³ is equivalent to H

83 961 392 7542 gives; IT HAS THE EDGE

Learn more about calculating the volume of a cone here:

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