there were 7,000 raffle tickets sold at the school carnival. Each ticket cost $0.25. How much money did the school raise by selling raffle tickets

Answer: 2x²+4x+6

Step-by-step explanation:

[tex]\displaystyle\\\frac{2x^3-2x-12}{x-2} =\\\\\frac{2(x^3-x-6)}{x-2}=\\\\ \frac{2(x^2-8+8-x-6)}{x-2} =\\\\\frac{2(x^3-2^3-x+2)}{x-2} =\\\\\frac{2((x^3-2^3)-(x-2))}{x-2}=\\\\\frac{2((x-2)(x^2+2x+2^2)-(x-2))}{x-2} =\\\\\frac{2(x-2)(x^2+2x+4-1)}{x-2}=\\\\2(x^2+2x+3)=\\\\2x^2+4x+6[/tex]

Answer:=

Step-by-step explanation:

As the LCM of 5, 8, and 12, which is 60 so it is the smallest length that can be divided exactly into equal sections of length 5 m, 8 m, and 12 m.

The acronym LCM stands for the least common multiple or factor of any two or more specified integers. The least common multiple for the numbers 16 and 20 is 80, hence the LCM of those two numbers will be, for instance, 2 x 2 x 2 x 2 x 5 = 80.

8 is the LCM of 4 and 8. The LCM is the number that can be divided by the provided numbers equally. You can discover the least common multiple of 4 and 8 by looking at the common multiples. 4 is a multiple of 8, 12, 16, 20, 24, etc.

finding prime factors of the given numbers by repeated division method in order to find the LCM;

2 | 5,8,12

5 | 5,4,6

2 | 1,4,6

2 | 1,2,3

3 | 1,1,3

0 | 1,1,1

so we get 2x5x3x2=60

As the LCM of 5, 8, and 12, which is 60 so it is the smallest length that can be divided exactly into equal sections of length 5 m, 8 m, and 12 m.

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The shortest length which can be split into equal segments of length 5 meters, 8 meters, or 12 meters is 120.

Your form may be divided into sections with the help of sections, as the name suggests. This enables your users to input responses that might be categorized. The fact that sections divide your form into distinct screens is another significant benefit. For instance, a first screen shows section 1. When concealed lines in external views cannot adequately represent a part's inner design, sections are employed. The internal components can be viewed more clearly by imagining cutting through the thing and removing a section of it.

Finding the LCM by repeatedly dividing the supplied integers to get their prime components:

2 | 5,8,12

2 | 5,4,6

2 | 5,2,3

3 | 5,1,3

5 | 5,1,1

1 | 1,1,1

So we get 2*2*2*3*5*1 = 120

The lowest length that could be divided into precisely equal segments in lengths 5 m, 8 m, and 12 m is 120, which equals the LCM of 5, 8, & 12.

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I believe the answer must be 96x-160

Because we have to multiply 8x12 which is 96. and there is x next to it. so keep the x as it is.

and next to it is minus ( - ) sign so keep it as it is.

now we have to multiply 8x20 which is 160.

so if we write it together it will be:

so if we write it together it will be:96x - 160.

Thank you

Answer:

I think the answer is 1/2. Given the first die was odd, you rolled either a 1,3, or 5. Now on the second roll only a 6,4, or a 2 will give you a sum of 7. Given that is half of the sample space of the second die, it is 1/2?

Step-by-step explanation:

Area of the parallelogram is 882 square units

the solution of the inequality is plotted in the last number line

area o the glass window is 144π cm²

the second number line is the correct plot

the water left after the serving is 2 gallons 3 quart 1 pint

Area of a parallelogram is given by the formula

= base *  height

= 63 * 14

= 882 square units

The solution of the number line is b/2 ≥  4

= b ≥  8

the last option is correct

Area of circle is solved by

= πd² / 4

= π * 24² / 4

= 144π cm²

The inequality 4 > -y

= -4 < y

The second option is correct

total fluid ounces used

= 68 * 4 = 272 ounces

272 ounces = 2.125gallons

5 - 2.125 = 2.825 gallons

2.875 gallons

0.875 gallons = 3.5 quart

2 gallons 3.5quart

0.5 quart = 1 pint

2 gallons 3 quart 1 pint

Water left in the cooler is 2 gallons 3 quart 1 pint

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Answer:

do the butterfly method if you don't know how to do that comment and I'll show you a screenshot

Answer:

Step-by-step explanation:

Question: Determine the equation of the parabola that opens up, has vertex (7,7), and a focal diameter of 16 . This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.

Answer: ((x2)−14x+87)/16

Step-by-step explanation:

  focal diameter = 16,

  4a=16;

  a=4.

(h,v)=(7,7-a)

==> (h,v)=(7,3)

the equation of the parabola =  ((x-7)^2)=16(y-3)

                                                => y = ((x^2)-14x+87)/16.

Answer: $5400

Step-by-step explanation:

x =  amount raised so far

13500 - x = amt. still needed

x/3 = (13500 - x)/2

2x = 3(13500 - x)

2x = 40500 - 3x

5x = 40500

x = 40500/5 = 8100 (amt. raised so far)

13500 - 8100 = 5400 (amt. still needed)

Answer:

√122

Step-by-step explanation:

first we have to find the missing side with x on the 5 and 9 triangle by using the theorem

a^2+b^2=c^2

9^2+5^2=c^2

81+25=c^2

106=c^2

√106=c

and now we can use this as a side to find x

4^2+√106^2=x^2

16+106=x^2

122=x^2

√122=x

Hopes this helps please mark brainliest

Answer:  -2

Step-by-step explanation:

4y/4 = -8/4

     y = -2

Answer:

Step-by-step explanation:

Answer is -2

Answer:

1

Step-by-step explanation:

g(f(11))

It says in the problem that f(11) = -9

So:

g(-9)

It says again in the problem that g(-9) = 1

So the answer is 1

The answer is 1,200

First you need to add . + . to get 1.5M and then you need to subtract the rest ( 1.5M - one million four hundred ninety-eight thousand eight hundred )

So then you get 1,200

Hope this helped!

Answer:

2

Step-by-step explanation:

Answer:

.20

Step-by-step explanation:

because customers are always right

The Maclaurin series of xcos(-x) up to n = 3 is

[tex]m(x)= xcos(-x)= x-\frac{1}{2}x^3+\frac{1}{24}x^5-\frac{1}{720}x^7+\frac{1}{40320}x^9+\ldots \:[/tex]

The function is given in the question as

m(x) = xcos(-x)

Taylor (Maclaurin) series of xcos(x) up to n=5

A Maclaurin series is given by  f(x),

[tex]f\left(x\right)=f\left(a\right)+\frac{f^'\left(a\right)}{1!}\left(x-a\right)+\frac{f^{''}\left(a\right)}{2!}\left(x-a\right)^2+\frac{f^{'''}\left(a\right)}{3!}\left(x-a\right)^3+\ldots[/tex]

[tex]f\left(x\right)=f\left(0\right)+\frac{f^'\left(0\right)}{1!}\left(x\right)+\frac{f^{''}\left(0\right)}{2!}\left(x\right)^2+\frac{f^{'''}\left(0\right)}{3!}\left(x\right)^3+\ldots[/tex]

We need to do to get the desired polynomial is to calculate the derivatives, evaluate them at the given point, and plug the results into the given formula.

f⁽⁰⁾(x) = f(x) = xcos(x)

Evaluate the function at the point: f(0)=0

1st derivative: f(1)(x)=(f(0)(x))′=(xcos(x))′=−xsin(x)+cos(x)

1st derivative at the given point: (f(0))′=1

2nd derivative: f(2)(x)=(f(1)(x))′=(−xsin(x)+cos(x))′=−xcos(x)−2sin(x)

Evaluate the 2nd derivative at the given point: (f(0))′′=0

3rd derivative: f(3)(x)=(f(2)(x))′=(−xcos(x)−2sin(x))′=xsin(x)−3cos(x)

Evaluate the 3rd derivative at the given point: (f(0))′′′=−3

Now, use the calculated values to get a polynomial:

[tex]m(x)=0+\frac{1}{1!}x+\frac{0}{2!}x^2+\frac{-3}{3!}x^3+.....[/tex]

[tex]m(x)=x-\frac{1}{2}x^3+\frac{1}{24}x^5-\frac{1}{720}x^7+\frac{1}{40320}x^9+\ldots \:[/tex]

Thus, the Maclaurin series of xcos(-x) up to n = 3 is

[tex]m(x)= xcos(-x)= x-\frac{1}{2}x^3+\frac{1}{24}x^5-\frac{1}{720}x^7+\frac{1}{40320}x^9+\ldots \:[/tex]

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By Trigonometric formula - Tan(∅) =  [tex]\frac{opposite}{adjacent}[/tex] , we got that answer - x= 10.4 yard (On rounding to tenth place)

An equation containing one or more trigonometric ratios of unknown angles is known as a trigonometric equation. In terms of angles, it is written as ratios of the sine, cosine, tangent, secant, and cotangent angles. A trigonometric equation is, for instance, cos2 x + 5 sin x = 0.

For angle 30 degrees adjacent side is 18 yard and opposite side is x.

=>  Tan(∅) =  [tex]\frac{opposite}{adjacent}[/tex]

=>  Tan(30) = [tex]\frac{x}{18}[/tex]

=>  x=Tan 30 (18)

=>  x= 10.39

=>  x= 10.4 yard (On rounding to tenth place)

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Step-by-step explanation:

8b-10

hope it helps. please mark brainliest

Answer:  The correct answer is (8*b) - 10

Step-by-step explanation:

When translating word problems into equations, the term "product" denotes multiplication, and "less than" denotes subtraction.

This wording "10 less than the product of 8 and b" tells us to multiply 8 and b, then subtract 10:

(8*b) - 10

Answer:

m=10

Step-by-step explanation:

m/3-6=4

30/3=10

10-6=4

Answer: It is 12 kilometers per minute

Step-by-step explanation:

in the problem that you'll need to simplify your answer and write it as a proper fraction, mixed number, or whole number so I can confirm this is 100% correct.

Step-by-step explanation:

Answer:

7 and 1/24

Step-by-step explanation:

4 7/8 + 2 1/6

First when adding fractions, we want to have a common denominator. To do that, we must multiply the fractions until we get a desired denominator. We can find LCM.

The LCM of 6 and 8 is 24, so we must multiply accordingly.

We can put this into improper fraction form:

39/8 + 13/6

Then multiply accordingly. Multiply by 3 on both sides for the first fraction, and multiply by 4 on both sides for the second to get a denominator of 24.

117/24 + 52/24

Now, we can add the fractions.

169/24

Simplify

7 and 1/24

Step-by-step explanation:

The image point of the transformation is (-1, 6)

The coordinate of the point is given as

(2, -3)

The transformations are given as

The rotation is around the point (1,-2)

So, the point becomes

Point = (2 - 1, -3 + 2)

Evaluate

Point = (1, -1)

The 270 degrees rotation has the algebraic rule of its rotation to be changed from (x, y) to (-y, x) i.e.  (x, y) => (-y, x)

So, we have

(x, y) = (1, 1) after the rotation

The translation is given as

(x - 2, y + 5)

So, we have

(x, y) = (1 - 2, 1 + 5)

Evaluate

(x, y) = (-1, 6)

Hence, the coordinates of the image is (-1, 6)

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The transformation of System A into System B is:

Equation [A2]+ Equation [A 1] → Equation [B 1]"

The correct answer choice is option D

To transform System A into System B as 1 × Equation [A2] + Equation [A1]→ Equation [B1] and 1 × Equation [A2] → Equation [B2].

System A:

-3x + 4y = -23 [A1]

7x - 2y = -5 [A2]

Multiply equation [A2] by 2

14x - 4y = -10

Add the equation to equation [A1]

14x - 4y = -10

-3x + 4y = -23 [A1]

11x = -33 [B1]

Multiply equation [A2] by 1

7x - 2y = -5 ....[B2]

So therefore, it can be deduced from the step by step explanation above that System A is ultimately transformed into System B as 1 × Equation [A2] + Equation [A1]→ Equation [B1] and 1 × Equation [A2] → Equation [B2].

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Step-by-step explanation:

here is your answer hope it helps you plaz mark me as brainlist

The required three angle is 55 , 55 and 70

What is an angle ?

An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. The meeting of two planes also creates angles. We refer to these as dihedral angles.

When two straight lines or rays intersect at a single endpoint, an angle is created. The vertex of an angle is the location where two points come together. The Latin word "angulus," which means "corner," is where the term "angle" originates.

Let each of the base angle of isosceles triangle = x

Vertex angle = (x+15)

Sum of the angle = 180

x + x + (x + 15) = 180

3x + 15 = 180

3x = 180 - 15

x = 165 / 3

x = 55

Each base angel = 55

Vertex angle = x + 15

                      = 55 + 15

                      = 70

Required three angles = 55 , 55 and 70

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Answer:

uh let's see

Step-by-step explanation:

2,4 and -3,-6

y2-y1/

x2-x1

-6-4

-3-2

-10/-5 = 2

slope is 2

u do the rest I'm tired