Answer:
1.403x10²⁴ molecules
Explanation:
In order to calculate how many molecules of CO₂ are there in 102.5 g of the compound, we first convert grams to moles using its molar mass:
102.5 g ÷ 44 g/mol = 2.330 mol CO₂Now we convert moles into molecules using Avogadro's number:
2.330 mol * 6.023x10²³ molecules/mol = 1.403x10²⁴ moleculesA formula unit made with Na and unknown nonmetal "Z" has the formula, NaZ. Which element does "Z" represent?
One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
and one mole of water. 5.00 g of the metallic oxide produces 2.32 g of the metal. What is the metallic
oxide? (Use molar masses)
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
[tex]M_2O+H_2\rightarrow 2M+H_2O[/tex]
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
[tex]\frac{10X}{(2X+16)}=2.32[/tex]
So we solve for x as shown below:
[tex]10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol[/tex]
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
Best regards!
A cook grabs the handle of the frying pan and their hand gets very warm. The cook's hand gets very warm because of?
a. conduction
b.radiation
c.convetion
After two half-lives, how much of the original material has decayed? 25 percent 50 percent 75 percent 100 percent
The original material has decayed 75%
Further explanationGiven
two half-life
Required
The decayed sample
Solution
General formulas used in decay:
[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t = 2 x t 1/2
Input the value :
[tex]\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%[/tex]
The amount of Nt = 25% No
After adding 20.0 mL of 5% NaOH solution into the remaining organic layer, followed by mixing and venting, the solution separated into two distinct layers. Match the following:
1. The top layer was the ______________ layer.
2. 9-fluorenone was most soluble in the ____________ layer.
3. Deprotonated chloroanilic acid was most soluble in the _____________ layer.
4. The bottom layer was the __________________ layer.
5. The organic layer was a ________________ colored solution.
6. The aqueous layer turned into a _____________ colored solution.
a. organic
b. aqueous
c. yellow
d. pink
Answer:
Explanation:
The objective of this experiment is to match the expected result with each of the propositions given after the experiment had been carried out.
1. The top layer was the organic layer. This is because all the organic compounds have lesser density than water except chloroform that will be formed when NaOH is added.
2. 9-fluorenone was most soluble in the organic layer. This is so as a result of its non-polar carbon structure.
3. Deprotonated chloroanilic acid was most soluble in the aqueous layer as a result of the formation of an electrovalent bond with water.
4. The bottom layer was the aqueous layer as a result of the huge amount of water density.
5. The organic layer was a yellow colored solution.
6. The aqueous layer turned into a pink colored solution.
How are acids and alkalis
similar?
Answer:h
Explanation:
Answer:
Acids and alkalis both contain ions. Acids contain lots of hydrogen ions, which have the symbol H+. Alkalis contain lots of hydroxide ions, symbol OH-. Water is neutral because the number of hydrogen ions is equal to the number of hydroxide ions.
Observation of balloon rub with cloth?
Answer:
When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.
Over an interval of 2.0 s the average rate of change of the concentration of C was measured to be 0.0540 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 2.000 M
Answer:
Explanation:
the average rate of change of the concentration =
( initial concentration - final concentration ) / time
Initial concentration = 2.000 M
the average rate of change of the concentration = .0540 M/s
time = 2 s
Putting the values
.0540 = (2.000 - X ) / 2
0.108 = 2.000 - X
X = 1.892 M .
Final concentration = 1.892 M .
Which of the following involves a reaction in which energy is absorbed?
O A. An instant cold pack
O B. A car's engine
C. A chemical hand-warmer
O D. A campfire
When an oxidant is present, vitamin C can be converted to a product described as (5R)-5-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxy-furan-2,3,4(5H)-trione, which retains the furan-based nomenclature of vitamin C and describes the hydrogen placement at atom 5 of the ring. Which of the following statements best describes this vitamin C derivative?A) Vitamin C is reduced to yield a furan ring with 4 carbonyl groups and no double bonds.B) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and 1 double bond.C) Vitamin C is reduced to yield a furan ring with 1 carbonyl group and no double bonds.D) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and no double bonds
Answer:
D) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and no double bonds
Explanation:
We can tell that the compound " (5R)-5-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxy-furan-2,3,4(5H)-trione " has 3 carbonyl groups due to it having "trione" in the name (and it lacking other carbonyl group names, like amide or carboxylic acid).
As there is no "-ene" part of the name referencing a double bond, the only option left is option D).
What is the percent oxygen in Rb2Cr2O7
Answer:
28.9452
Explanation:
Answer:
28.9452%
Explanation:
Rb-44.1781
Cr-26.8767
O-28.9452
The formation of tert-butanol is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.
Answer:
(CH3)3C^+ + OH^- --------> (CH3)3COH
Explanation:
This reaction has to do with SN1 reaction of alkyl halides. Here tert-butanol is formed from tert-butyl bromide.
The first step in the reaction is the formation of a carbocation. This is a unimolecular reaction. The rate of reaction depends on the concentration of the alkyl halide. This is a slow step and thus the rate determining step in the mechanism.
(CH3)3CBr -------> (CH3)3C^+ + Br^-
The second step is a fast step and it completes the reaction mechanism. It is a bimolecular reaction as follows;
(CH3)3C^+ + OH^- --------> (CH3)3COH
if a gas at 300k occupies 3.60 liters at a pressure of 1.00 atm, what will be it’s new pressure if the volume is compressed to 2.0 liters at a temperature of 450K?
Answer: The new pressure if the volume is compressed to 2.0 liters at a temperature of 450K is 2.7 atm
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 1.00 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 3.60 L
[tex]V_2[/tex] = final volume of gas = 2.0 L
[tex]T_1[/tex] = initial temperature of gas = [tex]300K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]450K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{1.00\times 3.60}{300}=\frac{P_2\times 2.0}{450}[/tex]
[tex]P_2=2.7atm[/tex]
The new pressure is 2.7 atm
Draw a mechanism for the reaction of methanol with sodium amide. In the box to the left, draw any necessary curved arrows. Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, check the box to indicate which side of the reaction is favored at equilibrium.
Answer:
See explanation
Explanation:
When sodamide reacts with methanol, the following equilibrium is set up;
CH3OH(aq) + NH2-(aq) ⇄ CH3O-(aq) + NH3(aq)
In the reaction, the sodamide acts as a base that abstracts a proton from methanol to yield the conjugate base of methanol which is the methoxide ion.
The forward reaction is favoured at equilibrium.
Indicate the type of solute-solvent interaction that should be most important in each of the following solutions.a. LiCl in waterb. NF3 in acetonitrile (CH3CN)c. CCl4 in benzene (C6H6)d. methylamine (CH3NH2) in watere. Dispersion forcesf. Dipole-dipole forcesg. Ion-dipole forcesh. Hydrogen bonding
Explanation:
a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.
b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.
c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.
d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.
The type of interactions in the following solutions are:
LiCl in water - Ion-dipole force[tex]\rm NF_3[/tex] in acetonitrile - Dipole-dipole force[tex]\rm CCl_4[/tex] in benzene - London Dispersion forceMethylamine in water - Hydrogen bondingIn a solution, the dissolution of solute molecules is driven by the interactions between the solute and solvent molecules.
Which interaction is present in solutions?The solute solvent interaction is based on the nature of the molecules. The interactions in the following solutions are:
LiCl in waterThe water is polar solvent and LiCl is an ionic molecule. The interaction between the molecules will be Ion-dipole force.
[tex]\rm NF_3[/tex] in acetonitrileThe acetronitrile and [tex]\rm NF_3[/tex] both are polar molecules. The force present in the interactions is Dipole-dipole force.
[tex]\rm CCl_4[/tex] in benzeneThe benzene and [tex]\rm CCl_4[/tex] both are nonpolar molecules. The type of interaction present in the solution is London Dispersion force.
Methylamine in waterThe water is a polar solvent, and Methylamine is an organic compound. The interaction in the solution is hydrogen bonding.
Learn more about solute-solvent interactions, here:
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From where do the placenta and umbilical cord develop?
Answer:
it develops from the womb
Answer:
outer cells of the blastocyst
Explanation:
on edg:)
According to the Bohr model of the atom, which particles are allowed to exist in any one of a number of energy levels?
Answer: the line-emission spectrum of an atom is caused by the energies released when electrons. releases energy of only certain values.
Which of the following substances contains MOSTLY ionic bonding? A) LIF B) CO2 C) AICI: D) BeCl2 E) Cu
Answer: [tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex]
Explanation:
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.
A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.
[tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex] contain ionic bonds as they aremade up of metals and non metals.
What is the definition of lava?
Answer:
Lava, magma (molten rock) emerging as a liquid onto Earth's surface. The term lava is also used for the solidified rock formed by the cooling of a molten lava flow.
Explanation:
How is a magnetic field produced?
O when an electromagnetic field interacts with a magnet
O when a current runs through a conductor
O when an object has an electric charge
O when electrons move through a circuit
Answer:
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.
Answer: when an electromagnetic field interacts with a magnet
Explanation:
When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.40 °C less than the freezi point of pure X. Calculate the mass of iron(III) nitrate (Fe(NO3)3 that must be dissolved in the same mass of X to produce the same depression in freezing point.
Answer:
21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.
Explanation:
Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.
Formula is: ΔT = Kf . m . i
Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:
ΔT = Freezing point of pure solvent - Freezing point of solution.
This data is known → 6.40°C
m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles
m = 0.351 mol / 0.5kg = 0.702 m
As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:
6.40°C = Kf . 0.702 m . 1
6.40°C /0.702m = 9.11 °C/m.
Let's go to the next question.
ΔT is the same → 6.40°C
But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ → 1Fe³⁺ + 3NO₃⁻
For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4
Let's replace data: 6.40°C = 9.11 °C/m . m . 4
6.40°C / (9.11 m/°C . 4) = 0.176 m
This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.
Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol
Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g
Which of the following represents C3H8?
Among the given options the compound with the formula C₃H₈ is option C. It is an organic compound under named as propane.
What is propane?
Propane is an organic compound classified as a hydrocarbon with saturated carbon - hydrogen bonds. It's formula is C₃H₈. It contains 3 carbons and 8 hydrogens.
The two end carbons contains 3 hydrogens each and the middle carbon contains 2 hydrogens. They are all bonded through sigma bonding. The compound in A is C₅H₁₂ and in B, it is C₆H₁₄.
The formula of the compound in option D is C₅H₁₀. Hence, the skeleton showing the compound with the formula of C₃H₈ is option C.
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Please answer this. List the three most abundant minerals in this bottle of mineral water.
When N,N-Dimethylaniline is treated with bromine, ortho and para products are observed. However, when N,N-Dimethylaniline is treated with a mixture of nitric and sulfuric acid, only the meta product is observed. Explain these results. (Hint: what can happen to the nitrogen atom in the presence of the strong acids
Answer:
See explanation below
Explanation:
To get a better understanding watch the picture attached.
In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.
In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.
Hope this helps.
Can someone help me with this
Answer:
a
b
d
c
Explanation:
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A sample consisting of 65.0 g of xenon is confined in a container at 2.00 atm and 298 K and then allowed to expand adiabatically (a) reversibly to 1.00 atm, (b) against a constant pressure of 1.00 atm. Calculate the final temperature and the expansion work at each case. Use the fact that xenon is a monoatomic gas.
Answer:
[a]. - 445.45J,
[b]. - 367.92 J
Explanation:
The following parameters are given in the question above. These information are used in solving this problem.
The mass of Xenon = 65.0 g of xenon, pressure = 2.00 atm, temperature = 298 K.
The number of moles of xenon = mass/ molar mass = 65g/ 131.293= 0.495.
The cp= 3/2 R, cp =3/2R + R = 5/2 R.
j = cp/cv = 3/2.
[a]. The final temperature,T2 = (2)^-2/3 × (298)^5/3 = T2^5/3.
Final temperature,T2 = 225.84K.
Expansion work = nCv [ T₂ - T₁] = 0.495 × 3/2 × 8.314 × [ 225.84 - 298] = - 445.45J.
(b). The final temperature can be Determine as;
3/2( T2 - 298k) = - 1 (T2 /1 - 298/2).
3/2(T2 - 298) = - T2 + 149K.
3T2 - 894 = - 2T2 +298K.
T2 = 238.4 K.
Workdone= nCv (T2 - T1) = 0.495 × 3/2 × 8.314 (238.4 - 298) = - 367.92 J.
This group of fungi forms spores in a round structure on the end of a hyphae
Answer:
Is zygote fungi an option??
Answer:
zygote fungi
Explanation:
i got the answer right
What is the energy of an electron in the third energy level of hydrogen?
Answer:
Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy.
...
Energy Levels of Electrons.
Energy Level Energy
1 -13.6 eV
2 -3.4 eV
3 -1.51 eV
4 -.85 eV
How many molecules in 4.10 mol H2O?
6.02×10^23
1.4×10^23
2.47×10^24
1.15×10^-23
Answer:
2,47 * [tex]10^{24}[/tex] (molecules)
Explanation:
Avogadro's number is a very important relationship: 1 mole = 6,02 * [tex]10^{23}[/tex] atoms, molecules, protons, etc.
To convert from moles to molecules, multiply the molar amount by Avogadro's number.
4,1 mol * 6,02 * [tex]10^{23}[/tex] ≈ 24,7 * [tex]10^{23}[/tex] = 2,47 * [tex]10^{24}[/tex] (molecules)
Therefore the third answer is correct
In which state of matter are the particles at rest (not moving at all)?
none of these
solid
liquid
gas
Answer:
Solids for sure
particles of solid cant flow.
Answer:
B)Solids
Solids have tightly packed particles unlike liquids and gases whose particles can move freely but rate of movement is highest in gas while compared to water