There are 50 deer in a particular
forest. The population is increasing
at a rate of 15% per year. Write an
exponential growth function that
represents the number y of deer in
that forest after x months. Round
to the nearest thousandth.

Answers

Answer 1

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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents

the number of deer y in that forest after x months? Round to the nearest thousandth.

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Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

Answer 2

The exponential growth function that represents the number y of deer in that forest after x months is 50 × [tex](1.013)^{x}[/tex].

What is exponential growth function?

An exponential function is a nonlinear function that has the form of

y=[tex]ab^{x}[/tex],wherea≠0,b>0. An exponential function with a > 0 and b > 1, like the one above, represents an exponential growth and the graph of an exponential growth function rises from left to right.

There are 50 deer in a particular forest.

The population is  increasing at a rate of 15% per year.

Assuming that the number of deer is 'y' and the number of month is 'x' then after the first month the number of deer is

y(x) = 50 × [tex]1+(\frac{0.15}{12} )[/tex]

= 50 × 1.0125

= 50.625

y(2) = y(1) × (1.0125)

= y(0) × [tex](1.0125)^{2}[/tex]

= 51.258

y(3) = y(2) × (1.0125)

= y(0) × [tex](1.0125)^{2}[/tex]

= 51.898

y(x) = 50 × [tex](1-\frac{0.15}{12} )^{x}[/tex]

= 50 × [tex](1.013)^{x}[/tex]

Hence, the exponential growth function that represents the number y of deer in that forest after x months is 50 × [tex](1.013)^{x}[/tex].

Find out more information about exponential growth function here

https://brainly.com/question/11487261

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