The world’s largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds.
What is the velocity for one of the blades?
(THIS IS PHYSICS, CIRCULAR MOTION)

Answers

Answer 1

Answer:

88.14 m/s

Explanation:

From the question given above, the following data were obtained:

Radius (r) = length of blade = 80 m

Revolution (rev) = 1

Time (t) = 5.7 s

Velocity (v) =?

The velocity of the blade can be obtained by using the following formula:

v = (rev × 2πr) / t

NOTE: Pi (π) = 3.14

v = (1 × 2 × 3.14 × 80) / 5.7

v = 502.4 / 5.7

v = 88.14 m/s

Therefore, the velocity of the blade is 88.14 m/s


Related Questions

Describe how electric potential energy, kinetic energy, and work change when two charges of opposite sign are placed near each other.

Answers

Answer:

As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.  

Explanation:

Why are stars considered to be the building blocks of the universe?
A. Stars are found throughout the galaxy
B. Stars become novas, supernovas, and Black Holes
C. Nuclear fusion within stars creates needed elements for he universe
D. The sun is a star

Answers

The answer for that would be C
The answer to this question is C

"When the ball leaves the ramp at Point B, students measure the horizontal" distance traveled. They repeat the experiment five times, being careful to release the ball from the same starting Point A and find the average horizontal distance traveled to be 2.0 m. One student suggests they use a stopwatch to find the time the ball is in the air whereas another student suggests they use a meter stick. Given these materials, describe the procedure students should follow to minimize error and calculate the speed of the ball as it leaves the ramp.

Answers

Answer:

Speed of ball as it leaves ramp is 2 m/s

Explanation:

From the question it is given that the average distance traveled by ball from point A to B is 2.0 m and the time taken is 1sec

one student is using stopwatch to calculate the time taken by ball and another student is using meter stick to calculate the distance traveled

since speed of ball is given by v = [tex]\frac{distance}{time}[/tex]  thus,

the speed = 2 m/s

now for minimizing the error of speed it is necessary to record the readings by single students at-least 5 times and take average

by doing this, the error of speed calculation will be minimum as the it decreases the error due to random error of system caused by taking the reading  by different students

Unit Test
Active
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TIME REMAININO
01:47:35
Which best describes the energy of a sound wave as it travels through a medium?
It increases
It decreases
It remains the same
It depends on the medium

Answers

Answer:

It depends on the medium is answer.

Explanation:

I hope it's helpful!

The energy of sound waves depends on the nature of medium it travels through. As the speed of the wave increases in the medium its energy increases. Hence, option d is correct.

What are sound waves ?

Sound waves are type of mechanical waves passing through a medium. Sound waves are longitudinal waves hence, the oscillation of particles is in the same direction of of the wave propagation.

The energy of a wave is directly proportional to the frequency of the wave and inversely proportional to the wavelength. As the density of the medium increases, the speed of the wave decreases and thereby energy too.

Sound waves travels with higher speed through solids. As their energy increases, the waves moves with higher speed. Hence, the energy of sound waves depends on the nature of the medium.

Find more on sound waves:

https://brainly.com/question/11797560

#SPJ7

A guitar player can change the frequency of a string by "bending" it-pushing it along a fret that is perpendicular to its length. This stretches the string, increasing its tension and its frequency. The B string on a guitar is 64 cm long and has a tension of 74 N. The guitarist pushes this string down against a fret located at the center of the string, which gives it a frequency of 494 Hz. He then bends the string, pushing with a force of 4.0 N so that it moves 8.0 mm along the fret.

* What is the new frequency?

Answers

Answer:

[tex]f'=504hz[/tex]

Explanation:

From the question we are told that

The B string on a guitar is 64 cm long

The B string tension tension of 74 N.

Frequency of 494 Hz

Pushed with a Force of 4.0 N

It moves 8.0 mm along the fret.

Generally the equation for frequency of ring under tension is mathematically given as

 [tex]2Lf=\sqrt{x\frac{T}{\mu} }[/tex]

 [tex]2*(64/100)*494=\sqrt{\frac{74}{m/0.64}[/tex]

 [tex](632.32)^2={\frac{74}{m/0.64}[/tex]

 [tex](632.32)^2=74*{\frac{0.64}{m}[/tex]

 [tex](632.32)^2={\frac{47.36}{m}[/tex]

 [tex]m=1.18450761*10^-^4[/tex]

Therefore finding the New frequency f'

 

  [tex]f'=\frac{(\sqrt{\frac{74+11}{(\frac{1.18450761*10^-^4}{0.642})}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{74+11}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{85}{1})*(\frac{0.642}{1.18450761*10^-^4}})}{2*0.642}[/tex]

  [tex]f'=\frac{(\sqrt{(\frac{54.57}{1.18450761*10^-^4}})}{2*0.642}[/tex]

 [tex]f'=\frac{678.7471973}{2*0.642}[/tex]

 [tex]f'=572.9111096hz[/tex]

 

 

In class, Kelsey stops paying attention to the lesson and begins to focus on tapping her pencil on her desk. Her teacher slowly walks to Kelsey’s desk and gently takes her pencil from her. How would behaviorist B.F. Skinner MOST likely describe this response?

Answers

Answer:

I think it might be negative reinforcement.

Explanation:

Answer:

negative reinforcement

Explanation:

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