Answer:
It is not moving with uniform velocity
Explanation:
The velocity of the car is 10 m/s after 10 seconds.
Assuming the initial velocity is 0 m/s.
[tex]a=\frac{v-u}{t}[/tex]
[tex]a=acceleration\\v=final \: velocity \\ u=initial \: velocity \\ t=time[/tex]
[tex]a=\frac{10-0}{10}[/tex]
[tex]a=\frac{10}{10}[/tex]
[tex]a=1[/tex]
The acceleration is 1 m/s².
The acceleration of a body moving with a uniform velocity is 0 m/s².
Therefore the car is not moving with uniform velocity.
No , a car is not moving with uniform velocity because its acceleration is 1 m/s^2.
What is acceleration?Acceleration is a rate of change in velocity.Acceleration a = ΔV / ΔTHere ΔV = difference between final and initial velocity V2 - V1 and ΔT = time difference T2 - T1So , a = V2 - V1 / T2 - T1How to calculate acceleration of a car?
The car is having initial velocity V1 = 0 at the time T1 = 0 , at T2 = 10 seconds the final velocity of a car is V2 = 10 m/s.
So, acceleration a = V2 - V1 / T2 - T1
∴ a = 10 - 0 / 10 - 0
∴ a = 1 m/s^2
Therefore acceleration of a car is 1 m/s^2, it means the car has a acceleration of 1 m/s^2 so the velocity of a car is not uniform.
Learn more about acceleration here -
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Velocity is a description of an object’s blank
Answer:
Average speed
Explanation:
There is no explanation its written in the definition. Hope this helps.
Answer:
speed and direction of motion
Explanation:
velocity is a description of an objects speed and direction of motion
a body of mass 5 kg undergoes a change in speed from 20 m/s to 0.20m/s. find the momentum
Answer:
99kg m/s
Explanation:
[tex]p=m\Delta v \\\\\Delta v=20-0.20=19.8m/s \\\\p=5(19.8)=99[/tex]
Hope this helps!
Answer:
99 kg m/sSolution,
Initial speed(u)=20 m/s
final speed(v)=0.20 m/s
change in momentum∆P=m(v-u)
∆P=5(0.20-20)
∆P=5*19.8
∆P=99 kg m/s
Momentum of the body is decreased by 99 kg m/s
hope this helps...
Good luck on your assignment...
One of the hazards facing humans in space is space radiation: high-energy charged particles emitted by the sun. during a solar flare, the intensity of this radiation can reach lethal levels. one proposed method of protection for astronauts on the surface of the moon or mars is an array of large, electrically charged spheres placed high above areas where people live and work. the spheres would produce a strong electric field e⃗ to deflect the charged particles that make up space radiation. the spheres would be similar in construction to a mylar balloon, with a thin, electrically conducting layer on the outside surface on which a net positive or negative charge would be placed. a typical sphere might be 5 m in diameter. suppose that to repel electrons in the radiation from a solar flare, each sphere must produce an electric field e⃗ of magnitude 1 × 106 n/c at 25 m from the center of the sphere. what is the magnitude of e just outside the surface of such a sphere
Answer:
[tex]1\times 10^{8} N/C[/tex]
Explanation:
According to the gauss law
As we know that
Electric field is
[tex]E = -k\frac{q}{r^2}[/tex]
where,
k = column constant = [tex]9 \times 10 ^{9}\ N. \frac{m^2}{c^2}[/tex]
q = charge
r = distance from the sphere center
For computing the magnitude of e first we have to need to find out the charge outside of sphere which is
[tex]q = -\frac{Er^2}{k}[/tex]
[tex]q = -\frac{1 \times 10^{6} \frac{N}{C} (25m)^2}{9 \times 10 ^{9}\ N. \frac{m^2}{c^2}}[/tex]
q = -0.07 C
Now we have to find the electric field
[tex]E = k\frac{q}{r^2}[/tex]
The r is 2.5m but in question it is given 5m
So,
Electric field is
[tex]E = 9 \times 10^{9} N . \frac{m^2 \times 0.07 C}{C^2 (2.5 m)^2}[/tex]
[tex]E = 9 \times 10^{9} N. \frac{m^2 \times 0.07 C} {C^2 (2.5m)^2}[/tex]
[tex]= 1\times 10^{8} N/C[/tex]
I NEED HELP!! PLEASE HELP ME
Answer:
but I can tomorrow if you have time can you come to the meeting tonight but yyyy the person who is this and what
Explanation:
gyyyyyyyyyyyyyyyyy the number of the person who is this and what is the
Please help ASAP. There are 3 question it would be a big help if you can answer any.
Answer:
number 1 is falling freely number 2 I think the 2nd option number 3 3rd option
1). If you're standing on a scale in an elevator, and the scale reads much less than your real weight, then the elevator must be accelerating downward.
(Think of the extreme limit: If the elevator is in free-fall, accelerating down at 9.8 m/s², then you'll apear to be weightless ... the scale will read zero.)
2). A 100 kg man is standing in an elevator, accelerating up at 2.0 m/s².
The net force acting on him is F = m·a = (100 kg) x (2.0 m/s²) = 200 N up.
The forces acting on him are:
-- gravity, m·g = (100 kg) x (9.8 m/s²) = 980 N down
-- elevator floor force . . . EF up
Net force = (980N down) + (EF up)
(200N up) = (980N down) + (EF up)
Add (980N up) to each side:
(200N up + 980N up) = EF up
Elevator force = 1180N up.
Pick the second choice: 1.2 x 10³ N up
3). My computer is resting on my desk.
There are many forces acting on my computer, and they are all balanced.
That means the NET force acting on my computer is zero.
If the net force were NOT zero, then my computer would be accelerating in the direction of the net force. But it's at rest. So the net force must be zero.
find the gravitational force of attraction between two elephants, one mass 1.00 * 10kg and the other of mass 8.00 * 10 square kg, when they are separated by 5.0m
Answer:
F=2.135706 * 10^-8 N
Explanation:
[tex]F=G\frac{m_{1} m_{2} }{r^{2} } \\\\G=6.67408*10^{-11}\\m_{1}=10kg\\m_{2}=8*10^{2}kg\\r=5m\\\\=> F=6.67408*10^{-11}*\frac{10*(8*10^{2})}{5^{2} }\\F=2.135706*10^{-8}N[/tex]
describe briefly one problem caused by the expansion of metals.
Answer:
The expansion and contraction of materials can also cause problems. For example, bridges expand in the summer heat and need special joints to stop them bending out of shape.A bimetallic strip has two metal strips glued together. One of these metals expands more for each degree temperature rise than that other.
What net force is required to cause a 12,000 kg airplane to accelerate at a
rate of 5.0 m/s^2?
Answer:
60000 N
Explanation:
Neglecting air resistance,
Using equation Net force = mass x acceleration (F=ma),
F = 12000 x 5
F = 60000 N
In a container of negligible heat capacity, mix 6kg of ice at -40 ° C with 3kg of steam at 120 ° C, determine the equilibrium temperature.
Answer:
100°C
Explanation:
The heat gained by the ice equals the heat lost by the steam, so the total heat transfer equals 0.
Heat lost by the steam as it cools to 100°C:
q = mCΔT
q = (3 kg) (2.00 kJ/kg/K) (100°C − 120°C)
q = -120 kJ
Total heat so far is negative.
Heat lost by the steam as it condenses:
q = -mL
q = -(3 kg) (2256 kJ/kg)
q = -6768 kJ
Heat absorbed by the ice as it warms to 0°C:
q = mCΔT
q = (6 kg) (2.11 kJ/kg/K) (0°C − (-40°C))
q = 506.4 kJ
Heat absorbed by the ice as it melts:
q = mL
q = (6 kg) (335 kJ/kg)
q = 2010 kJ
Heat absorbed by the water as it warms to 100°C:
q = mCΔT
q = (6 kg) (4.18 kJ/kg/K) (100°C − 0°C)
q = 2508 kJ
The total heat absorbed by the ice by heating it to 100°C is 5024.4 kJ.
If the steam is fully condensed, it loses a total of -6888 kJ.
Therefore, the steam does not fully condense. The equilibrium temperature is therefore 100°C
Electrons that are free to move in metals
Answer:
Brainliest please
Explanation:
I will start by saying that Metals by their very nature are conductors of electricity. Now metals exhibit “metallic bonding” which holds its structure together. Unlike other materials which exhibit covalent bonding, it's atoms are not bonded by “electron sharing”. Rather they are bonded by the availability of valence electrons. Now within a metals atomic structure, the metal atoms lose the electrons in thier outermost shell (valence electrons), thus becoming positively charged ions (cations )
A football is kicked at ground level with a speed of 18.6 m/s at an angle of 44.9 to the horizontal.
How much later does it hit the ground ?
Answer:
t = 3.79 s
Explanation:
We have,
A football is kicked at ground level with a speed of 18.6 m/s at an angle of 44.9 to the horizontal.
It means that,
Initial speed of a football, u = 18.6 m/s
Final speed of a football, v = 0 (when it hits the ground)
It would under the action of gravity. Let t is the time of motion. So, using equation of kinematics to find it.
v=u+at
a=-g
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{0-18.6}{-9.8}\\\\t=1.89\ s[/tex]
The total time before the ball hits the ground is the sum of time taken to come down and time taken to go up. So, total time is 2×1.89 = 3.79 s
A Ray of light in air makes an angle of 45 degree at the surface of a sheet of ice . the ray is refracted within the Ice at an angle of 30 degree . a) what is the critical angle for the Ice? b) A speck of dirt is embedded 2CM below the surface of the Ice . what is the Apparent depth when viewed at normal incidence
Answer:
Explanation:
a )
Refractive index of ice = sini / sin r where i is angle of incidence and r is angle of refraction
angle of incidence = 90 - 45 = 45
angle of refraction = 30
refractive index of ice μ = sin 45 / sin 30
= 2/ √2
μ = √2 = 1.414
μ = 1 / sin C where C is critical angle for ice - air interface
sinC = 1 / μ
= 1 / 1.414
= .70
C = 44 .42° .
b )
real depth / apparent depth = refractive index
2 / apparent depth = 1.414
apparent depth = 2 / 1.414
= 1.414 cm .
n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic energy is small compared with the gain in gravitational potential energy on even small hills.) To demonstrate this, find the final speed and the time taken for a skier who skies 70.0 m along a 30â slope neglecting friction: (a) Starting from rest. (b) Starting with an initial speed of 2.50 m/s. (c) Does the answer surprise you? Discuss why it is still advantageous to get a running start in very competitive events.
Answer:
Explanation:
a ) starting from rest , so u = o and initial kinetic energy = 0 .
Let mass of the skier = m
Kinetic energy gained = potential energy lost
= mgh = mg l sinθ
= m x 9.8 x 70 x sin 30
= 343 m
Total kinetic energy at the base = 343 m + 0 = 343 m .
b )
In this case initial kinetic energy = 1/2 m v²
= .5 x m x 2.5²
= 3.125 m
Total kinetic energy at the base
= 3.125 m + 343 m
= 346.125 m
c ) It is not surprising as energy gained due to gravitational force by the earth is enormous . So component of energy gained due to gravitational force far exceeds the initial kinetic energy . Still in a competitive event , the fractional initial kinetic energy may be the deciding factor .
A rifle is used during the biathlon event in the Olympics. The rifle has a mass
of 3 kg and the bullet has a mass of 0.015 kg. After it is shot, the bullet travels
at a speed of 450 m/s. What is the total momentum of the rifle bullet system
after the bullet is shot?
A. 1350 kg-m/s
OB. 0 kg-m/s
O C. 6.75 kg-m/s
D. 1365 kg-m/s
Answer:
0 kg m/s
Explanation:
before the bullet is shot the velocity of the gun & the bullet is 0.
Answer:
0 kg-m/s
just did it ;D
Explanation:
One sprinter has a stride of 120cm, another 75cm. How many steps do they each take if they run a 100m race?
Explanation:
100 m / (1.20 m) = 83.3
100 m / (0.75 m) = 133.3
Rounded up, the first sprinter takes 84 steps, and the second sprinter takes 134 steps.
Which quantities are equal to total of the individual values within a circuit?
Answer:
a. the current in a parallel circuit and the voltage in a series circuit
b. the resistance in a parallel circuit and the current in a series circuit
c. the resistance in a parallel circuit and the voltage in a series circuit
d. the voltage in a parallel circuit and the resistance in a series circuit
Answer:
A. the current in a parallel circuit and the voltage in a series circuit
Explanation:
on edg
the most common mineral group is broken into the subgroups of ferromagnesium and nonferromagnesium
Answer:
They're made of silicon and oxygen.
Explanation:
Which term describes the amount of energy that is used in a circuit each
second?
O A. Voltage
O B. Power
O c. Current
O D. Resistance
Answer:
The correct answer is power
Three 15.0-W resistors are connected in parallel across a 30.0-V battery. Please show all work.
a) Find the current through each branch of the circuit.
b) Find the equivalent resistance of the circuit.
c) Find the current through the battery.
Answer:
Part A)
Since all of the resistors have equal resistance, hence for finding even only 1 branch It will be fine because current will be the same for all branches.
=> [tex]I = \frac{V}{R_{1} }[/tex]
=> [tex]I = \frac{30}{15}[/tex]
=> I = 2 A
Part B)
Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.
=> [tex]\frac{1}{R} = \frac{1}{R_{1}}+\frac{1}{R_{2}} +\frac{1}{R_{3}}[/tex]
=> [tex]\frac{1}{R} = \frac{1}{15}+ \frac{1}{15}+\frac{1}{15}[/tex]
=> [tex]\frac{1}{R} = \frac{3}{15}[/tex]
=> R = 15/3
=> R = 5 ohms
Part C)
I = V/R
Where I is current, V is voltage and R is the equivalent resistance
=> I = 30/5
=> I = 6 A
In which of the following situation is light most likely to be a reflection
Answer:
when the reflecting surface is plain and without even small hurdles that are not the visible by our naked eyes. Eg : plain mirror
Explanation:
A motorcycle together with its Rider with 150 kg how much work is needed to set its movement at 15 metre per second.
Answer:
W = 16875 J
Explanation:
We have,
Mass of a motorcycle together with its rider is 150 kg
It is required to find the work is needed to set its movement at 15 metre per second. The work done is given by :
[tex]W=\dfrac{1}{2}mv^2[/tex]
Plugging all the values in above formula such that :
[tex]W=\dfrac{1}{2}\times 150\times (15)^2\\\\W=16875\ J[/tex]
So, the work of 16875 J is needed.
PLEASE I NEED HELP WITH THIS ASAP
A student finds a rock on the way to school. In the laboratory he determines that the volume of the rock by placing the rock in a graduated cylinder with 50 cm3 of water and watched the water rise to 72.7 cm3. The student determined the mass is 39.943 g through the use of a triple beam balance. What is the density of the rock?
With step by step explanation
Answer:
density=mass/volume
39.943/22.7=1.75
Explanation:
Suppose the current is changing with time according to I = a + bt, where a and b are constants. Determine the magnitude of the emf (in V) that is induced in the loop if b = 14.0 A/s, h = 1.00 cm, w = 15.0 cm, and L = 1.05 m.
Answer:
[tex]emf=81.51\times 10^{-7} Volt[/tex]
Explanation:
Given that
I = a + b t
b = 14 A/s , h= 1 cm , w= 15 cm , L= 1.05 m
The magnitude of induced emf is given as follows
[tex]emf=\dfrac{d\phi}{dt}[/tex]
[tex]emf=\dfrac{\mu_o\times L}{2\times \pi}\times ln\dfrac{h+w}{h}\times \dfrac{dI}{dt}[/tex]
I = a + b t
[tex]\dfrac{dI}{dt}= b[/tex]
Now by putting the values in the above equation we get
[tex]emf=\dfrac{4\times \pi \times 10^{-7}\times 1.05}{2\times \pi}\times ln\dfrac{1+15}{1}\times 14[/tex]
[tex]emf=81.51\times 10^{-7} Volt[/tex]
Thus the induce emf will be
[tex]emf=81.51\times 10^{-7} Volt[/tex]
outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and compresses it 6.5 cm before the spring expands and shoots the box back out. How fast was the box going when it hit the spring?
Answer:
v = 0.489 m/s
Explanation:
It is given that,
Mass of a box, m = 1.5 kg
The compression in the spring, x = 6.5 cm = 0.065 m
Let the spring constant of the spring is 85 N/m
We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.
[tex]\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2[/tex]
[tex]v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s[/tex]
So, the speed of the box is 0.489 m/s.
Explain the science behind the following statement: Magnetic heating may replace surgery to cure some infections. Is the method of alternating magnetic fields to cure internal infections in people a proven method? Explain why or why not?
Answer:
can you attach photo
Explanation:
Magnetosomes are also used to induce magnetic hyperthermia (using magnets to heat cells that have ingested magnetosomes). Scientists were able to kill the pathogenic bacterial cells of Staphylococcus aureus, a common cause of infection, by pumping them full of magnetosomes and applying magnetic heat.
What does a magnet do to heal your interior?studies show that magnets increase amino acid production and have a positive effect on the whole body. In other words, magnets speed up metabolism and help the body function properly. They ensure that oxygen and nutrients arrive at the site of injury as soon as possible in order to repair the injury.
Magnetic Resonance Imaging (MRI) uses a very strong magnetic field and is much stronger than a household magnet can produce, but MRI does not directly affect the patient's health (MRI is a diagnostic tool). Works indirectly as).
Learn more about magnetic fields here: https://brainly.com/question/14411049
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Radium-226 emits alpha (α), beta (β) and gamma (γ) radiation.
Explain how the properties of alpha (α), beta (β) and gamma (γ) radiation affect the level of the hazard at different distances.
Answer:
Explanation:
alpha
Alpha Radiation (α): A large, unstable nucleus decays to produce a smaller, more stable nucleus and an alpha particle (identical to a helium nucleus, ⁴₂He or ⁴₂α).
It has a very high ionizing energy and low penetrating power. It can be stopped by paper skin
Beta Radiation (β): A neutron in an unstable nucleus decays, forming a proton and emitting a beta (β) particle (identical to an electron, ⁰₋₁e or ⁰₋₁b) and resulting in a more stable nucleus.
It has high ionizing energy and penetrating power. It can be stopped by aluminium sheet
Gamma Radiation (γ): An unstable nucleus releases energy in the form of a high energy photon (no mass)to become more stable; this often accompanies other forms of radioactivity.
It has very high penetrating power and very low ionizing energy. It can be stopped by lead block.
long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder.
Answer:
the magnitude of the electric field = 27.1058 V/m
≈ 27 V/m
Explanation:
given
R(radius enclosed) = 12 cm = 0.12 m
ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³
r(radius from the axis) = 15 cm = 0.15 m
using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.
attached is the calculation of the question, using Gauss law of electrostatics
A boy is twirling a model airplane on a string 4 feet long. if he twirls the plane at 0.25 revolutions per minute, how far does the plane travel in 4 minutes? round to the nearest tenth.
Answer:
25.13 ft
Explanation:
r = 4 feet
ω=0.25 revolution per minute
=1 revolution in 4 minutes
total number of revolution N = 1 (in 4 minutes )
v=rω
distance traveled = 2×N×π×r
=2×1×π×4
=8π
= 25.13ft in 4mins
If mass of the planet is 10% less than that of
the earth and radius of the planet is 20%
greater than that of the earth then the weight
of 40kg person on that planet is
Answer:
25kg
Explanation:
The formula for acceleration due to gravity is:
[tex]g=\dfrac{GM}{r^2}[/tex]
Here, G represents a constant and M represents the mass of the object. We don't need to know the actual values to solve this, then: We can just multiply by the amount they are multiplied relative to earth.
[tex]g=\dfrac{G(0.9M)}{(1.2r)^2}=0.625g[/tex]
Multiplying this by the weight of the person on Earth of 40kg, you get 0.625*40=25kg.
Hope this helps!
as a motorcycle takes a sharp turn the type of motion that occurs is called ——— motion
Answer:
circular motion
Explanation:
hope this helps you :)
Answer:
Centripetal motion
Explanation:
As a motorcycle takes a sharp turn the type of motion that occurs is called centripetal motion