Engineering College

The velocity in a channel that is 3 m deep is 1 m/s. What is the Froude number in a 1/6 scale model of that channel that satisfies dynamic similarity?a. 1.b. 0.45.c. 0.18.d. 5.4.e. 0.08.

Answers

Answer 1

Answer:

c. 0.18

Explanation:

The Formula for Froude Number is given as follows:

Froude No. = Inertial Forces/Gravity Forces

Froude No. = v/√(gD)

where,

v = velocity = 1 m/s

g = 9.8 m/s²

D = Depth of channel = 3 m

Therefore,

Froude No. = (1 m/s)/√[(9.8 m/s²)(3 m)]

Froude No. = 0.18

hence, the correct option will be:

c. 0.18

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A wet electrode can cause arc blow ?

Answers

Answer:

yes it can

Explanation:

35 points and brainiest. A, B, C, D
Which of the following identifies what carbide-tipped bits, lines on machine bolts, and lock washers all have in common?

A. All are very expensive items.
B. All are very recent inventions.
C. All are rather outdated inventions.
D. All provide an added level of strength.

Answers

Answer:c

Explanation:

List the three main phases of photo interpretation in photogrammetry

Answers

Answer:

Stages of Interpretation and Mapping

Selection of photographs. Whenever possible, all photographs of a site or small area should be assessed for fitness of purpose. ...

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Transformation.

Explanation:

simple Brayton cycle using air as the working fluid has a pressure ratio of 10. The minimum and maximum temperatures in the cycle are 295 and 1240 K. Assuming an isentropic efficiency of 83 percent for the compressor and 87 percent for the turbine, determine (a) the air temperature at the turbine exit, (b) the net work output, and (c) the thermal efficiency.

Answers

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) [tex](\frac{783.05-778.18}{800.13-778.18} )[/tex] = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

Determine the force in members FD and DB of the frame. Also, find the horizontal and vertical components of reaction the pin at C exerts on member ABC and member EDC.

Answers

Answer:  

A.

Explanation:

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