The time it takes me to wash the dishes is uniformly distributed between 11 minutes and 18 minutes. What is the probability that washing dishes tonight will take me between 14 and 15 minutes? Give your answer accurate to two decimal places.

Answer:

TRUE

Step-by-step explanation:

The circumcenter of a triangle is the center of the only circle that can be circumscribed about it

Answer:

False

Step-by-step explanation:

Answer:

8.51 seconds

Step-by-step explanation:

Time to reach maximum height

=( Usin90)/2g

= 32/2*9.81

= 32/19.62

= 1.63 s

Max height = U²Sin²tita/g

= 32²/9.81

= 1024/9.81

= 104.38ft

Total height=104.38 + 128= 232.38

Time to fall back to the ground using the formula

h = ut+(1/2)gt²

U= 0

H= 232.38

g = 9.81

(232.38 *2 )/9.81= t²

47.376= t²

t = 6.88 s

Total time taken to hit ground

= 6.88 + 1.63

= 8.51 seconds

Answer:

The quotient in polynomial form= 2x + 6

Step-by-step explanation:

In order to calculate the quotient in polynomial form of the following synthetic division we would have to make the following:

According to the given data we have the following:

-1|2 8 6

Therefore, quotient in polynomial form would be calculated as follows:

                                  -1 | 2  8  6

                                          -2 -6

                                       2   6  0

Therefore, quotient in polynomial form= 2x + 6

The quotient in polynomial form= 2x + 6

Answer:

the answer will be D

Step-by-step explanation:

Answer:

Height at t = 1 sec is 1144 ft

Step-by-step explanation:

Given:

Initial height of object = 1160 feet

Height of object after t seconds is given by the polynomial:

[tex]- 16t ^2+ 1160[/tex]

Let [tex]h(t)=- 16t ^2+ 1160[/tex]

Let us analyze the given equation once.

[tex]t^2[/tex] will always be positive.

and coefficient of [tex]t^2[/tex] is [tex]-16[/tex] i.e. negative value.

It means something is subtracted from 1160 ft (i.e. the initial height).

So, height will keep on decreasing with increasing value of t.

Also, given that the object is dropped from the top of a tower.

To find:

Height of object at t = 1 sec.

OR

[tex]h (1)[/tex] = ?

Solution:

Let us put t = 1 in the given equation: [tex]h(t)=- 16t ^2+ 1160[/tex]

[tex]h(1)=- 16\times 1 ^2+ 1160\\\Rightarrow h(1) = -16 + 1160\\\Rightarrow h(1) = 1144\ ft[/tex]

So, height of object at t = 1 sec is 1144 ft.

Answer:

2/7

Step-by-step explanation:

The numbers greater than 7 or less than 3 are 2 and 8.

2 numbers out of 7.

P(greater than 7 or less than 3) = 2/7

Answer:

2/7

Step-by-step explanation:

There are a total of 7 sample spaces also known as 2,3,4,5,6,7,8. Now we have to find a number greater than 7 and less than 3. 2 is less than 3, and 8 is greater than 7, so two numbers are selected. This would become 2/7 because out of all of the 7 outcomes, only two are selected.

Answer:

[tex]x^2-2x+1[/tex]

Step-by-step explanation:

=> (x-1)(x-1)

Using FOIL

=> [tex]x^2-x-x+1[/tex]

=> [tex]x^2-2x+1[/tex]

Answer:

[tex]\boxed{x^2-2x+1}[/tex]

Step-by-step explanation:

[tex](x-1)(x-1)[/tex]

Apply FOIL Method.

[tex]x(x-1)-1(x-1)[/tex]

[tex]x^2-x-x+1[/tex]

Combine like terms.

[tex]x^2-2x+1[/tex]

Answer:

3 packs of barrettes and 4 packs of ribbons.

Step-by-step explanation:

All we need to do here is to find the least common multiple between 12 and 9.

We can factor both of these numbers to do so.

12: 3*4: 3*2*2

9: 3*3

We can cancel out one 3 (since it appears in both prime factorizations) and multiply what we have left to find the LCM.

2*2*3*3=36

This means that she will be making 36 clips/needs 36 of each item.

36/12=3

3 packs of barretes.

36/9=4

4 packs of ribbons.

Answer:

There are 50 large boxes.

Step-by-step explanation:

First, "boxes of two sizes" means we can assign variables:

  Let x = number of large boxes

       y = number of small boxes

 "There are 115 boxes in all"    means    x + y = 115      [eq1]

Now, the pounds for each kind of box is:

    (pounds per box)*(number of boxes)

So,

  pounds for large boxes     +    pounds for small boxes      =    4125 pounds

                 "the truck is carrying a total of 4125 pounds in boxes"

        (50)*(x)                   +              (25)*(y)                  = 4125    [eq2]

It is important to find two equations so we can solve for two variables.

Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2.  Let's solve for x:

   x = 115 - y          [from eq1]

    50(115-y) + 25y = 4125             [from eq2]

     5750 - 50y  + 25y = 4125           [distribute]

     5750 - 25y = 4125

      -25y = -1625

         y = 65             [divide both sides by (-25)]

 There are 65 small boxes.

Put that value into either equation (now, which is easier?) to solve for x:

  x = 115 - y

  x = 115 - 65

  x = 50

Answer:

x=15

Step-by-step explanation:

165+x=180

180-165=15

Hope this helps!!

Answer:

Symmetric with respect to the polar axis in agreement with the second answer listed.

Step-by-step explanation:

This is the shape of a cardioid  [tex]14\,(1+cos(\theta))[/tex]  it contains the function cosine of the angle so it must be symmetric with respect to the polar axis, since the cosine function is also symmetric for positive and negative values of the angle.

Answer:

D

Step-by-step explanation:

We're looking for two numbers that have a sum of -9 and a product of 40. These 2 numbers are -4 and -5 so the answer is (x - 4)(x - 5).

Answer:

(x-4)(x-5)

Step-by-step explanation:

х^2 - 9х+ 20

What 2 numbers multiply to 20 and add to -9

-4*-5 = 20

-4+-5 = -9

(x-4)(x-5)

Answer: (3y - 10)*2÷4

Step-by-step explanation:

Because 10 less than 3 times a number, y, is done first, it is in parenthesis.  The 3 is there to represent the "three times" and the -10 is there to represent the "ten less".  The *2 is there to represent the "multiplied by two" and the ÷4 is there to represent the "divided by 4"

Hope it helps, and tyvm <3

Answer:

[tex]\displaystyle \frac{2(3y - 10)}{4}[/tex]

Step-by-step explanation:

10 less than 3 times y.

The variable y is multiplied by 3, 10 is subtracted from 3 × y.

The result 3y - 10 is then multiplied by 2.

2(3y - 10) is then divided by 4.

Steps to solve:

9(d - 93) = -36d

~Distribute

9d - 837 = -36d

~Subtract 9d to both sides

-837 = -45d

~Divide -45 to both sides

18.6 = d

Best of Luck!

Answer:

4m^11

Step-by-step explanation:

2m^4.2 you multiply powers in paranthesis

2m^8 result

2m^8.m^3

You add the exponents together because it is same base and put the 4 because 2 to the power of 2 is 4

4m^11

Answer: 4[tex]m^{11}[/tex]  

Step-by-step explanation:

(2m^4)^2 * m^3  

Expand

[tex]2^{2} * m^{8} *m^{3}[/tex]     add the exponents since they have the same base

[tex]4m^{11}[/tex]

Answer:

Domain is  

{

x

∈

R

;

x

≠

−

5

}

Range is  

{

y

∈

R

;

y

≠

0

}

Step-by-step explanation:

Explanation:

Domain: Denominator should not be  

0

∴

x

+

5

≠

0

or

x

≠

−

5

Domain is any real value except  

x

=

−

5

or  

{

x

∈

R

;

x

≠

−

5

}

Range is any real value except  

y

=

0

or  

{

y

∈

R

;

y

≠

0

}

graph{1/(x+5) [-10, 10, -5, 5]}

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

[tex]SI = \frac{P \times T \times R}{100}[/tex]

First account:[tex]SI=\frac{x \times 1 \times 12}{100}[/tex]

Second account : [tex]SI =\frac{(6000-x) \times 1 \times 7}{100}[/tex]

We are given that At the end of the first year he had earned $590 in interest.

So, [tex]\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400[/tex]

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

if there is any confusion then again ask me always with you

Answer:

d = 125

Step-by-step explanation:

E2020

pls mark Brainliest

Answer:

a). Y = y0e^-k(t)

b) Y = 19.4 Unit mass

Step-by-step explanation:

Y = y0e^-k(t)

Where y is amount present at the time

Y0 is initial amount present at t = 0

Y0 = 58.7

Half life = 5 hours

At half life , y = 58.7/2

At half life , y = 29.35

K = decaying constant.

Let's look fithe value of k

Y = y0e^-k(t)

29.35 = 58.7e^-k(5)

29.35/58.7 = e^-k(5)

0.5 = e^-k(5)

In 0.5 = -k(5)

-0.69314718 = -k(5)

0.138629436 = k

The value present in 8 hours will be

Y = y0e^-k(t)

Y = 58.7e-0.138629436(8)

Y = 58.7e-1.109035488

Y = 58.7(0.329876978)

Y= 19.36377861

To the nearest tenth

Y = 19.4 unit of mass

Answer:

[tex]\huge\boxed{x=\sqrt{66}}[/tex]

Step-by-step explanation:

ΔADC and ΔABD are similar (AAA)

Therefore the cooresponging sides are in proportion:

[tex]\dfrac{AD}{AC}=\dfrac{AB}{AD}[/tex]

Substitute

[tex]AD=x;\ AC=6+5=11;\ AB=6[/tex]

[tex]\dfrac{x}{11}=\dfrac{6}{x}[/tex]          cross multiply

[tex](x)(x)=(11)(6)\\\\x^2=66\to x=\sqrt{66}[/tex]

Answer:

0% probability of a random classmate getting a score more than 80

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation(which is the square root of the variance) [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 65, \sigma = \sqrt{12} = 3.4641[/tex]

What is the the probability of a random classmate getting a score more than 80?

This is 1 subtracted by the pvalue of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 65}{3.4641}[/tex]

[tex]Z = 4.33[/tex]

[tex]Z = 4.33[/tex] has a pvalue of 1

1 - 1 = 0

0% probability of a random classmate getting a score more than 80

Answer:

Step-by-step explanation:

Using the formula

p +/- (z* √[p(1-p) /n]

Where p is sample proportion = 120/400= 0.3 z*= 1.96 (z score for 95% confidence) and n is 400.

0.3 + (1.96 √[0.3(1-0.3) / 400])

0.3 + (1.96 √[(0.3*0.7)/400

0.3 + (1.96√ (0.21/400))

0.3 + (1.96 √0.000525)

0.3 + (1.96* 0.023)

0.3 + (0.045)

= 0.345 ~ 35%

For the lower interview

0.3 - (0.045)

= 0.255 ~ 26%

Thus, a 95% confidence interval for this study is between 26% and 35%

Answer:

B

Step-by-step explanation:

The answer is B because in order for the square root of a number to be equal to another number, the answer squared should be the number under the square root.

B. [tex](-4)^2\neq -16[/tex].

Hope this helps.

Answer:

4

Step-by-step explanation:

1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4

Arrange the numbers from smallest to largest

0,1, 1,2,2, 3,3, 4, 4,4,4,4,4 , 4, 5, 6, 6,   7, 8, 9,

There are 20 numbers

The middle number is between 10 and 11

0,1, 1,2,2, 3,3, 4, 4,4   ,4,4,4 , 4, 5, 6, 6,   7, 8, 9,

The median is 4

Solution,

Arranging the data in ascending order:

0,1,1,2,2,3,3,4,4,4,4,4,4,4,5,6,6,7,8,9

N(total number of items)= 20

Now,

Median:

[tex] (\frac{n + 1}{2)} ) ^{th \: item} \\ = (\frac{20 + 1}{2} ) ^{th \: item} \\ = \frac{21}{2} \\ = 10.5 \: th \: \: item[/tex]

Again,

Median:

[tex] \frac{10 \: th \: item + 11 \: th \: item}{2} \\ = \frac{4 + 4}{2} \\ = \frac{8}{2} \\ = 4[/tex]

Answer:

3/10

Step-by-step explanation:

We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:

Ambitious

First we have to do is that the denominator is the same.

in the case of 5/6 it would be 25/30

and for 8/15 it would be 16/30

Now if we can do the subtraction and it would be:

25/30 - 16/30 = 9/30 or what equals 3/10

3/10 was the amount of wood he burned in the winter

Answer:

D) 3/10 row

Step-by-step explanation:

Answer:

The answer is explained below

Step-by-step explanation:

Given that, the equation H*x = c is inconsistent for some c in R^n, we can say that the equation A*x = b has at least one solution for each b in R^n of IMT (Inverse Matrix Theorem) is not fulfilled.

Thanks to this we can say that by equivalence of theorem statement, the equation H*x = 0 will not have only the trivial solution. It will have non-trivial solutions too.

Answer:

False, there are actually infinite solutions as these are parallel lines.

Step-by-step explanation:

Answer:

a. The volume of Pyramid A is double that of Pyramid B.

b. The new volume of B is equal to the volume of A.

Step-by-step explanation:

The base of pyramid A is a rectangle with length 10 meters and width 20 meters.

The base of pyramid B is a square of side length 10 meter.

Both pyramids have the same height, h.

The volume of a pyramid is given as:

V = lwh / 3

where l = length

w = width

h = height

The volume of Pyramid A is:

V = (10 * 20 * h) / 3 = 66.7h cubic metres

The volume of Pyramid B is:

V = (10 * 10 * h) / 3 = 33.3h cubic metres

By comparing their values, the volume of Pyramid A is double that of Pyramid B.

If the height of B increases to 2h, its new volume is:

V = (10 * 10 * 2h) / 3 = 66.7h cubic metres

The new volume of B is equal to the volume of A.

Answer:

$1850 per month

Step-by-step explanation

There are two types of chocolates that can be produced milk chocolate and strawberry covered chocolate. To find the profit we make following equation,

P = $2.25 SC + $2.50 WC

where SC is strawberry chocolate and WC is White milk chocolate.

The maximum production level can be 800 boxes per month and white chocolates can not exceed the 200 boxes per month so we assume making 600 boxes of Strawberry covered chocolates and 200 boxes of white chocolates.

Profit = 2.25 * 600 + 2.50 * 200

Profit = $1850

This is the maximum profit that can be earned after making combination of two types of chocolates.