the temperatures at midday on march 1st in five cities are shown in the bar chart below. What is the difference in temperature between rome and munich?
Answers
The difference in temperature between Rome and Munich is given as follows:
6ºC.
How to obtain the difference in temperatures?The difference in temperature between Rome and Munich is given by the subtraction of Rome's temperature by Munich's temperature.
The bar graph in the context of this problem gives the temperature for each town.
From the bar graph given by the image presented at the end of the answer, the temperatures for Rome and Munich are given as follows:
Rome: 11 ºC.Munich: 5 ºC.Hence the difference in temperature between Rome and Munich is given as follows:
11 - 5 = 6ºC.
Missing InformationThe graph is given by the image presented at the end of the answer.
More can be learned about difference of two amounts at https://brainly.com/question/17301989
#SPJ1
Related Questions
Instructions: Find the missing probability.
P(B)=1/2P(A|B)=11/25P(AandB)=
Answers
P(A and B) = P(B) x P(A|B)
We are given:
P(B) = 1/2
P(A|B) = 11/25
Substituting these values into the formula, we get:
P(A and B) = (1/2) x (11/25) = 11/50
Therefore, P(A and B) = 11/50.
Out of 1000 students who appeared in an examination,60% passed the examination.60% of the failing students failed in mathematics and 50% of the failing students failed in English.If the students failed in English and Mathematics only, find the number of students who failed in both subjects.
Answers
The value of number of students who failed in both mathematics and English is 40.
Since, Given that;
60% of the 1000 students passed the examination,
Hence, we can calculate the number of students who passed the exam as follows:
60/100 x 1000 = 600
So, 600 students passed the examination.
Now, let's find the number of students who failed the examination.
Since 60% of the students passed, the remaining 40% must have failed. Therefore, the number of students who failed the examination is:
40/100 x 1000 = 400
Of the 400 failing students, we know that 60% failed in mathematics.
So, the number of students who failed in mathematics is:
60/100 x 400 = 240
Similarly, we know that 50% of the failing students failed in English.
So, the number of students who failed in English is:
50/100 x 400 = 200
Now, we need to find the number of students who failed in both subjects.
We can use the formula:
Total = A + B - Both
Where A is the number of students who failed in mathematics, B is the number of students who failed in English, and Both is the number of students who failed in both subjects.
Substituting the values we have, we get:
400 = 240 + 200 - Both
Solving for Both, we get:
Both = 240 + 200 - 400
Both = 40
Therefore, the number of students who failed in both mathematics and English is 40.
Learn more about the subtraction visit:
https://brainly.com/question/17301989
#SPJ1
Please help. Is the answer even there?
Answers
The critical values t₀ for a two-sample t-test is ± 2.0.6
To find the critical values t₀ for a two-sample t-test to test the claim that the population means are equal (i.e., µ₁ = µ₂), we need to use the following formula:
t₀ = ± t_(α/2, df)
where t_(α/2, df) is the critical t-value with α/2 area in the right tail and df degrees of freedom.
The degrees of freedom are calculated as:
df = (s₁²/n₁ + s₂²/n₂)² / [(s₁²/n₁)²/(n₁-1) + (s₂²/n₂)²/(n₂-1)]
n₁ = 14, n₂ = 12, X₁ = 6,X₂ = 7, s₁ = 2.5 and s₂ = 2.8
α = 0.05 (two-tailed)
First, we need to calculate the degrees of freedom:
df = (s₁²/n₁ + s₂²/n₂)² / [(s₁²/n₁)²/(n₁-1) + (s₂²/n₂)²/(n₂-1)]
= (2.5²/14 + 2.8²/12)² / [(2.5²/14)²/13 + (2.8²/12)²/11]
= 24.27
Since this is a two-tailed test with α = 0.05, we need to find the t-value with an area of 0.025 in each tail and df = 24.27.
From a t-distribution table, we find:
t_(0.025, 24.27) = 2.0639 (rounded to four decimal places)
Finally, we can calculate the critical values t₀:
t₀ = ± t_(α/2, df) = ± 2.0639
To learn more on Statistics click:
https://brainly.com/question/30218856
#SPJ1