The tables represent the points earned in each game for a season by two football teams.


Eagles
3 24 14
27 10 13
10 21 24
17 27 7
40 37 55
Falcons
24 24 10
7 30 28
21 6 17
16 35 30
28 24 14


Which team had the best overall record for the season? Determine the best measure of center to compare, and explain your answer.
Eagles; they have a larger median value of 21 points
Falcons; they have a larger median value of 24 points
Eagles; they have a larger mean value of about 22 points
Falcons; they have a larger mean value of about 20.9 points

The correct statement regarding the zeros of the function is given as follows:

Hence the false statements are given as follows:

The zeros of a function are the values of the input x for which the output y of the function assumes a value of y.

Hence, on the graph of a function, the zeros of a function are the values of x for which the graph either touches or crosses the x-axis.

Thus the zeros of the graphed function are given as follows:

x = 0, x = 1 and x = 4.

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Based on the survey results, it can be concluded with 90% confidence that the proportion of students who prefer exercising outside over-exercising in a gym is between 0.8085 and 0.9296. This interval does not include the previously known proportion of 0.822, which suggests that there may have been a change in student preferences over time.

However, it should be noted that the sample size of 84 is relatively small and there may be some degree of sampling error present. Overall, the SRC should continue to monitor student preferences for exercising and consider offering a variety of options to accommodate different preferences.

In the Student Recreation Center, it was found that 73 out of 84 students preferred exercising outside over exercising in a gym. This gives us a sample proportion of 73/84 = 0.869. This proportion's 90% confidence interval is (0.8085, 0.9296).

Since the past data proportion of 0.822 falls within the 90% confidence interval, we can conclude that there is no significant difference between the past data and the current survey results regarding students' preferences for outdoor exercise over gym exercise.

Based on past data, the Student Recreation Center knew that the proportion of students who prefer exercising outside over-exercising in a gym was 0.822. To update their records, the SRC conducted a survey. Out of 84 students surveyed, 73 indicated that they preferred outdoor exercise over-exercising in a gym. The 90% confidence interval is ( 0.8085, 0.9296 ).

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Answer:

(a)  x = 6.71 cm (3 s.f.)

     θ = 30.8° (3 s.f.)

(b)  radius = 3.00 cm (3 s.f.)

Step-by-step explanation:

The given triangle is made up of two right triangles.

In the right triangle on the right side, the side labelled "x" is opposite angle 40° and the side labelled 8 cm is adjacent to angle 40°. Therefore, to find the length of side x, use the tangent trigonometric ratio.

[tex]\boxed{\begin{minipage}{7 cm}\underline{Tangent trigonometric ratio} \\\\$\sf \tan(\theta)=\dfrac{O}{A}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle. \\\phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle.\\\end{minipage}}[/tex]

Therefore, the values are:

Substitute the values into the equation and solve for x:

[tex]\implies \tan 40^{\circ}=\dfrac{x}{8}[/tex]

[tex]\implies 8 \cdot \tan 40^{\circ}=8 \cdot\dfrac{x}{8}[/tex]

[tex]\implies 8 \tan 40^{\circ}=x[/tex]

[tex]\implies x=8 \tan 40^{\circ}[/tex]

[tex]\implies x=6.71279704...[/tex]

[tex]\implies x=6.71\; \rm cm\;(3\;s.f.)[/tex]

Therefore, the length of side x is 6.71 cm (3 s.f.).

In the right triangle on the left side, the side labelled "x" is adjacent angle θ and the side labelled 4 cm is opposite to angle θ. Therefore, to find the size of angle θ, use the tangent trigonometric ratio.

Therefore, the values are:

Substitute the values into the equation and solve for x:

[tex]\implies \tan \theta=\dfrac{4}{x}[/tex]

[tex]\implies \tan \theta=\dfrac{4}{8 \tan 40^{\circ}}[/tex]

[tex]\implies \tan \theta=\dfrac{1}{2 \tan 40^{\circ}}[/tex]

[tex]\implies \theta=\tan^{-1}\left(\dfrac{1}{2 \tan 40^{\circ}}\right)[/tex]

[tex]\implies \theta=30.7897330...^{\circ}}[/tex]

[tex]\implies \theta=30.8^{\circ}}\; \rm (3\;s.f.)[/tex]

Therefore, the size of angle θ is 30.8° (3 s.f.).

[tex]\hrulefill[/tex]

The formula for the volume of a cylinder is:

[tex]\boxed{V=\pi r^2 h}[/tex]

where:

Given values:

Substitute the given values into the formula and solve for r:

[tex]\implies \pi \cdot r^2 \cdot 5.3 = 150[/tex]

[tex]\implies r^2=\dfrac{150}{5.3\pi}[/tex]

[tex]\implies \sqrt{r^2}=\sqrt{\dfrac{150}{5.3\pi}}[/tex]

[tex]\implies r=\sqrt{9.00877036...}[/tex]

[tex]\implies r=3.00146137...[/tex]

[tex]\implies r=3.00\; \rm cm\;(3\;s.f.)[/tex]

Therefore, the radius of the cylinder is 3.00 cm (3 s.f.)

The values of the variables x and y are 12 and 3 respectively, while the measure of angles m∠A and m∠B are 36° and 126° respectively

1). m∠A and m∠D are complementary angles so their sum is equal to 90°

3x + (4x + 6)° = 90°

7x = 90° - 6°

x = 84/7

x = 12

2). m∠A = 3(12) = 36°

3). m∠B and m∠C are on a straight line and their sum is equal to 180° {also called supplementary angles}.

18y + 42y = 180°

60y = 180°

y = 180°/60°

y = 3

4). m∠C = 42(3) = 126°

In conclusion, the values of the variables x and y are 12 and 3 respectively, while the measure of angles m∠A and m∠B are 36° and 126° respectively

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Answer:

Alike: Whole number's

Different: 29 is odd, 92 is even; 29 is a prime number, 92 is not.

a. The coefficient of determination, r squared, is 0.669. Interpretation: The value of r squared indicates that 66.9% of the variation in box office gross can be explained by the variation in online trailer views.

b. The standard error of the estimate is 16.74.

c. The regression model is somewhat useful for predicting opening weekend box office gross because the coefficient of determination is closer to 1 than it is to 0.

d. Other variables that might explain the variation in opening weekend box office gross include: the amount spent on advertising, the timing of the release of the movie, and the type of movie.
a. To find the coefficient of determination (r^2), you will need to perform a linear regression analysis on the given data. Since we don't have the actual data values, we cannot calculate r^2 directly. However, once you calculate r^2 using the data, you can interpret its meaning as follows:

The value of r^2 indicates that ___% of the variation in box office gross can be explained by the variation in online trailer views. (Fill in the blank with the calculated r^2 value, rounded to one decimal place.)

b. Similarly, without the actual data values, we cannot calculate the standard error of the estimate (Syx). Once you have the data, you can calculate Syx using regression analysis.

c. The usefulness of the regression model depends on the calculated r^2 value. Choose the most appropriate answer based on the calculated r^2:

A. It is not useful for predicting box office gross because the coefficient of determination is close to 0.
B. It is not useful for predicting box office gross because the coefficient of determination is close to 1.
C. It is very useful for predicting box office gross because the coefficient of determination is very close to 1.
D. It is somewhat useful for predicting box office gross because the coefficient of determination is closer to 1 than it is to 0.

d. Other variables that might explain the variation in opening weekend box office gross are:

A. The amount spent on advertising might explain the variation in opening weekend box office gross because viewers are probably more likely to watch a movie that has been advertised heavily.
B. The timing of the release of the movie might explain the variation in opening weekend box office gross because a movie released at the same time as multiple other major movies may get crowded out.
C. The type of movie might explain the variation in opening weekend box office gross since some genres are more heavily attended than others.

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1. [tex]dy/dt = ky[/tex] 2. [tex]dy/dt = -ky[/tex] 3. [tex]ln|y| = kt + C1[/tex] are solutions for the differential equation.

1. The differential equation for an animal whose weight is increasing at a rate proportional to its weight can be represented as:

[tex]dy/dt = ky[/tex]

where dy/dt is the rate of change of weight with respect to time, k is the proportionality constant, and y is the weight of the animal.

2. The differential equation for a bacteria population that is shrinking at a rate proportional to its population size can also be represented as:
[tex]dy/dt = -ky[/tex]

Here, dy/dt is the rate of change of population with respect to time, k is the proportionality constant, and y is the population size. The negative sign indicates that the population is shrinking.

3. To solve the differential equation dy/dt = ky using separation of variables, follow these steps:

Step 1: Separate the variables, with y terms on one side and t terms on the other:

[tex](dy/y) = k(dt)[/tex]

Step 2: Integrate both sides of the equation:

[tex]∫(1/y) dy = ∫k dt[/tex]

Step 3: After integrating, you'll get:

[tex]ln|y| = kt + C1[/tex]

where C1 is the constant of integration.

Step 4: To solve for y, take the exponent of both sides:

[tex]y(t) = e^(kt + C1) = e^(kt) * e^C1[/tex]

Since e^C1 is a constant, we can replace it with another constant, C:

[tex]y(t) = Ce^(kt)[/tex]

This is the general solution to the differential equation [tex]dy/dt = ky[/tex], where C is the integration constant, and it can be determined using initial conditions if provided.

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The probability of Event 1 is 5/36 and the probability of Event 2 is 1/2.

Comparing the results of the roll of two fair die yields the probability of each of the following events:

There are 6 × 6 = 36 outcomes that could occur.

Event 1: The total exceeds eight.

There are five outcomes where the total exceeds eight.

P(Event 1)=5/36

Event 2: The sum can be divided by two.

Where the total is divisible by 2, there are 18 possible results.

The likelihood of this occurrence is:

P(Event 2) =18/36

P(Event 2) equals 1/2

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Probabilistic data refers to data that involves uncertain or random events.

it is typically analyzed using probability theory or statistical methods. Examples of probabilistic data include the outcomes of a coin toss, the probability of a person having a certain genetic trait, or the likelihood of an event occurring given certain conditions. The formula P(A) x P(B) = P(A and B) is a probability formula that applies to probability theory and statistics, which deal with random events and their likelihoods. Therefore, it is related to probabilistic data

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Answer:

Step-by-step explanation:

The denominators are not 4!!! The denominator is 11 everywhere

Answer: H

Step-by-step explanation:

The cost of $5 has not meaning for what we want.  The are only trying to figure out the number each bought so that was thrown in to throw you off.

you know they  bought 14 total DVDs

n+L=14   the number norma bought + number Lauretta bought is 14

Th next key sentence is Norma purchased two and a half times as Luaretta

In the sentence:

Norma is n  

purchased is your = sign  (usually in word problems "is" "costs" etc is =

Two and 1 half  [tex]2\frac{1}{2}[/tex] = [tex]\frac{5}{2}[/tex]

times is * (multiplied)

Lauretta is l

Substitute each symbol for each work

Norma(n) purchase(=) two and a half [tex]\frac{5}{2}[/tex] times* L

n= [tex]\frac{5}{2}[/tex]L

n+L=14    these are your 2 equations  H

Answer:

To solve the quadratic equation x^2 + 9x +25 = 5 by factoring, we first rearrange the equation to get:

x^2 + 9x +20 = 0

Next, we need to find two numbers that multiply by 20 and add to 9, the coefficient of x. The two numbers are 4 and 5.

So, we can factor the quadratic as:

(x + 4)(x + 5) = 0

Setting each factor to zero and solving for x, we get:

x + 4 = 0 or x + 5 = 0

Solving for x in each equation, we get:

x = -4 or x = -5

Therefore, the solutions to the quadratic equation x^2 + 9x +25 = 5 are x = -4 and x = -5.

In the context of data patterns and variations in a time series, cyclical patterns are characterized by repeatable periods of ups and downs over short periods of time. The answer is: a. cyclical patterns.

Cyclical patterns refer to fluctuations that occur over an extended period of time, usually several years or more, and are often related to economic or business cycles. These patterns are not as predictable as seasonal patterns, as they may vary in amplitude and duration from cycle to cycle. Cyclical patterns can also be influenced by a variety of factors, including changes in consumer behavior, technological innovations, and geopolitical events.

Irregular variations, on the other hand, refer to unexpected, random fluctuations in the data that cannot be attributed to any known factors. Random variations are also unpredictable, but they are not necessarily cyclical in nature.

Seasonal patterns refer to regular, predictable fluctuations in the data that occur within a single year. These patterns are often related to seasonal changes in weather, holidays, or other seasonal factors that affect consumer behavior.

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To find the length of the curve r(t) = (5t, 3 cos t, 3 sin t), -4 ≤ t ≤ 4, we can use the formula for arc length: L = ∫√(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt
Applying this formula to r(t),

we get: L = ∫_(-4)^(4) √(25 + 9sin^2t + 9cos^2t) dt Simplifying the expression under the square root, we get: L = ∫_(-4)^(4) √34 dt
Evaluating the integral, we get: L = 8√34

Therefore, the length of the curve is 8√34, To find the length of the curve √2ti + e^tj + e^-tk, 0 ≤ t ≤ 2, we can use the same formula: L = ∫√(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt.

Applying this formula to the given curve, we get:
L = ∫_0^(2) √(2^2 + e^(2t) + e^(-2t)) dt, Simplifying the expression under the square root, we get: L = ∫_0^(2) √(e^(2t) + 2 + e^(-2t)) dt
Making a substitution u = e^t + e^(-t),

we get: L = 1/2 ∫_2^(e^2 + e^(-2)) √(u^2 - 4) du Making another substitution v = u/2, we get:
L = ∫_√2^(√(e^2 + e^(-2))/2) √(v^2 - 1) dv
Using a trigonometric substitution v = sec θ, we get:
L = ∫_(π/4)^(π/2) sec θ dθ
Evaluating the integral, we get:
L = ln(1 + √2) + ln(√(e^2 + e^(-2)) + 1)
Therefore, the length of the curve is ln(1 + √2) + ln(√(e^2 + e^(-2)) + 1).

To reparametrize the curve r(t) = 3ti + (6 - 4t)j + (8 + 2t)k with respect to arc length measured from the point where t = 0 in the direction of increasing t, we can use the formula for arc length:
s = ∫√(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt.

We first find the arc length of the curve from t = 0 to some arbitrary value t: s = ∫_0^t √(9 + 16 + 4) dt
Simplifying, we get:
s = 3√29 t
Solving for t in terms of s, we get:
t = s/(3√29)
Substituting this expression into the given curve, we get:
r(s) = 3(s/(3√29))i + (6 - 4(s/(3√29)))j + (8 + 2(s/(3√29)))k
Simplifying,

we get: r(s) = si/√29 + (6 - 4s/(3√29))j + (8 + 2s/(3√29))k
Therefore, the reparametrized curve is r(s) = si/√29 + (6 - 4s/(3√29))j + (8 + 2s/(3√29))k.

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Yes, the function C is a piecewise function.

The domain of C is the set of non-negative integers (0, 1, 2, 3, ...),

The range of C is the set of non-negative real numbers

(0, 8, 16, 24, ..., 40),

We have,

The function C is a piecewise function.

When a passholder watches between 1 and 5 movies, the cost is $8 per movie, so the total cost C is:

C(n) = 8n

When a passholder watches more than 5 movies, but not more than 15 movies, the cost is a fixed price of $40 for the first 5 movies plus additional movies watched for free.

Therefore, the total cost C is:

C(n) = 40, for 5 < n ≤ 15

When a passholder watches more than 15 movies, the cost is undefined since the maximum number of movies allowed is 15.

The domain of C is the set of non-negative integers (0, 1, 2, 3, ...), since you cannot watch a negative or fractional number of movies.

However, since the maximum number of movies allowed is 15, the domain is restricted to integers between 0 and 15, inclusive.

The range of C is the set of non-negative real numbers (0, 8, 16, 24, ..., 40), since the cost per movie is $8 and the cost for watching between 6 and 15 movies is a fixed price of $40.

The minimum cost is 0 (if no movies are watched) and the maximum cost is 40 (if 15 or more movies are watched).

Thus,

The domain of C is the set of non-negative integers (0, 1, 2, 3, ...),

The range of C is the set of non-negative real numbers

(0, 8, 16, 24, ..., 40),

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The probability that the mean weekly wage of these 57 workers will be greater than $750 is approximately 9%.

To find the probability that the mean weekly wage of the 57 randomly chosen office workers will be greater than $750, we'll use the Central Limit Theorem and z-score formula.

1. Find the standard error (SE) by dividing the standard deviation ($151) by the square root of the sample size (57):
SE = $151 / √57 ≈ $20.03

2. Calculate the z-score:
z = (sample mean - population mean) / SE
z = ($750 - $723) / $20.03 ≈ 1.35

3. Look up the z-score in a standard normal distribution table or use a calculator to find the probability. For a z-score of 1.35, the area to the left is approximately 0.9115. Since we want the probability of the mean wage being greater than $750, we'll calculate the area to the right:
P(z > 1.35) = 1 - 0.9115 ≈ 0.0885

4. Convert the probability to a percentage and round to a whole number:
0.0885 × 100 ≈ 9%

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This statistics is an example of the "interference theory" in motor learning.

Interference theory suggests that when individuals learn multiple skills or movements in a random order, they perform better in retention and transfer tests compared to those who learn the same skills or movements in a blocked or constant order. The random practice group in this scenario was able to better transfer their knot-tying skills to new situations because they learned the knots in a more varied and unpredictable way, which helped them develop more adaptable and flexible motor patterns.

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The statement true about the rectangle and scale factor is

A scale factor of 2.5 was applied to create the enlargement

Given data ,

A rectangle with a long side of 3 and an arrow points to a larger rectangle with a long side of 7.5

Now , the long side of the original rectangle is 3 units, and the long side of the enlarged rectangle is 7.5 units.

And , the ratio of the long sides is 7.5/3 = 2.5, which indicates that the rectangle was enlarged by a factor of 2.5.

Hence , the scale factor of dilation is d = 2.5

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The probability is approximately 0.9429. Rounded to four decimal places, the probability is 0.9429. Therefore, the probability that the sample mean would be less than 107.81 liters is about 0.9429 or 94.29%.

To solve this problem, we can use the central limit theorem, which states that the distribution of sample means will be approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

First, we need to calculate the standard error of the mean, which is the standard deviation of the sampling distribution of the mean:

standard error = standard deviation / square root of sample size
standard error = 26 / sqrt(220)
standard error ≈ 1.756

Next, we can standardize the sample mean using the formula for z-scores:

z = (sample mean - population mean) / standard error
z = (107.81 - 105) / 1.756
z ≈ 1.574

Finally, we can use a standard normal distribution table or calculator to find the probability of getting a z-score less than 1.574.

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Answer: 9/4

Step-by-step explanation:

since each cube measure 1/2 of a centimeter on one side, the dimension is calculated first

length = 2 x 1/2 cm

width = 3 x 1/2 cm

height = 3 x 1/2 cm

The probability that the coin lands heads up and the cube lands on a composite number is 1/3 or approximately 0.333.

To find the probability that the coin lands heads up and the cube lands on a composite number, we need to first determine the number of outcomes in the sample space that satisfy these conditions, and then divide that by the total number of possible outcomes.

There are two possible outcomes for the coin flip: heads or tails. There are six possible outcomes for rolling the number cube: 1, 2, 3, 4, 5, or 6. To determine the number of outcomes in the sample space that satisfy the given conditions, we need to identify the composite numbers among the possible outcomes for rolling the number cube.

The composite numbers are 4, 6, and they occur two times each. Therefore, there are four outcomes that satisfy the given conditions: (heads, 4), (heads, 6), (tails, 4), and (tails, 6).

The total number of possible outcomes is the product of the number of outcomes for the coin flip and the number of outcomes for rolling the number cube, which is:

2 x 6 = 12

So the probability of the coin landing heads up and the cube landing on a composite number is:

4 / 12 = 1/3

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d. A paired t-test is a statistical test used to determine if there is a significant difference between the means of two related or paired samples.

It is used when two numeric variables are measured on the same or very similar units and the goal is to test for the mean of the differences between those variables. For example, it could be used to test whether a new drug treatment is significantly more effective than a placebo treatment, by measuring the difference in response between the same individuals receiving the two treatments. The paired t-test is also sometimes called a dependent samples t-test or a matched pairs t-test.

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Answer: False.

Explanation: In a sequential search algorithm, the boolean variable used as a flag is typically initialized to be false. This is because the flag is used to indicate whether a search item has been found or not. If the flag is set to false, it means the item has not been found yet.

False. In a sequential search algorithm, the boolean variable used as a flag is initialized to false. This flag is set to true if the search key is found in the sequence.

False. In a sequential search algorithm, the boolean variable used as a flag is usually initialized to false. The flag is set to true only when the desired element is found during the search process.

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Answer:Let's call the two numbers we are trying to find "x" and "y".

We know that the sum of these two numbers is 16, so we can write the equation:

x + y = 16

We also know that the difference between these two numbers is 27, so we can write the equation:

x - y = 27

Now we have two equations and two unknowns. We can use substitution or elimination to solve for x and y.

Using the substitution method, we can solve for y in the first equation:

y = 16 - x

Now we can substitute this expression for y into the second equation:

x - (16 - x) = 27

Simplifying this equation, we get:

2x - 16 = 27

Adding 16 to both sides, we get:

2x = 43

Dividing both sides by 2, we get:

x = 21.5

Now we can substitute this value for x into either of the original equations to solve for y:

y = 16 - x = 16 - 21.5 = -5.5

So the two numbers are 21.5 and -5.5.

Step-by-step explanation:

The inequality is represented as;

x/2 - 4 ≤  10

x  ≤ 28

Inequalities are described as the relation such that make an uneven comparison between two numbers, expressions or even variables.

The different signs of inequality are;

From the information given, we have that;

four less than the quotient of a number and two is no more than ten what is the number

Let the number be x

This can then be represented as;

x/2 - 4 ≤  10

x/2 ≤  10 + 4

x/2  ≤  14

x  ≤ 28

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The statements that must be true based on the histogram are as follows:

A. The range of the data set is 50 min.

C. The most common amount of exercise is 0 to 9 min.

E. The distribution is skewed right.

You can say that the distribution of a histogram is skewed right if the highest point in the distribution lies towards the left-hand side of the graph.

The graph above is an example of a distribution that is skewed right. Also, the range of the dataset is between 0 to 50 and the most common amount of exercise engaged in by the students is 0 to 9 min.

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In a polynomial function of the lowest degree with rational coefficients that have the given numbers as some of its zeros, we can use the fact that if a number "a" is a zero of a polynomial function, then (x-a) is a factor of the function.

Therefore, we can start by multiplying together (x-a) for each given zero, and then simplify the resulting expression to get the polynomial function in standard form with rational coefficients.

For example, if the given zeros are 2, -1, and 1/2, we would start by multiplying (x-2)(x+1)(x-1/2), which gives:

(x-2)(x+1)(2x-1)

Expanding this expression, we get:

2x^3 - 3x^2 - 5x + 2

This is a polynomial function of degree 3 (highest exponent is 3) with rational coefficients (all coefficients are integers or fractions). Note that this is the lowest degree possible for a polynomial with these zeros, since there are three distinct zeros.

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True. Seasonality refers to a regular, repeating pattern in the data that takes longer than one year to complete. It can occur in various forms such as monthly, quarterly, or even weekly patterns.

These patterns are usually associated with external factors such as weather, holidays, or other events that influence consumer behavior. By identifying seasonality in the data, businesses can use it to predict future trends and adjust their strategies accordingly. This information can be valuable in a range of industries such as retail, tourism, and agriculture.

Overall, understanding the repeating patterns in data is essential for making informed decisions and staying ahead of the competition.

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The two positive integers that satisfy the conditions and minimize the sum of their squares are 4 and 4.

We can use the method of Lagrange multipliers to solve this problem. Let x and y be the two positive integers we want to find, then we want to minimize the function [tex]f(x,y) = x^2 + y^2[/tex] subject to the constraint g(x,y) = x + y - 16 = 0.

The Lagrange function is L(x,y,λ) = f(x,y) - λg(x,y) =[tex]x^2 + y^2[/tex] - λ(x + y - 16).

Taking partial derivatives of L with respect to x, y, and λ, we get:

dL/dx = 2x - λ = 0

dL/dy = 2y - λ = 0

dL/dλ = x + y - 16 = 0

Solving for λ in the first two equations, we get λ = 2x = 2y. Substituting this into the third equation, we get 4x = 16, or x = 4. Then y = 4 as well, since λ = 2x = 2y.

Therefore, the two positive integers that satisfy the conditions and minimize the sum of their squares are 4 and 4.

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