The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver's seat. Part A If the car goes over a bump, what will be the frequency of oscillations

Answer:

D

Explanation:

D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.

Answer:

Waning Crescent

Answer: waxing crescent

Explanation:

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

Learn more about Place Value here:

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Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

[tex]\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s[/tex]

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

Answer:

The right solution is:

(a) 89.455 m/s

(b) 44.73 m/s

Explanation:

The given values are:

Mass,

m = 200 lbs

or,

   = [tex]\frac{200}{2.205} \ kg[/tex]

   = [tex]90.7 \ kg[/tex]

Air's density,

[tex]\delta = 1.225 \ kg/m^3[/tex]

Drag coefficient,

[tex]C_d=0.325[/tex]

When body is straight, area,

[tex]A_1=6 \ ft^2[/tex]

As we know,

Terminal velocity,

⇒  [tex]V_t=\sqrt{\frac{2W}{C_d \delta A} }[/tex]

or,

⇒      [tex]=\sqrt{\frac{2mg}{C_d \delta A} }[/tex]

At straight orientation,

⇒ [tex]V_t'=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558} }[/tex]

⇒      [tex]=\sqrt{\frac{1777.72}{0.223}}[/tex]

⇒      [tex]=89.455 \ m/s[/tex]

When belly flat,

⇒  [tex]V_t''=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558\times 4} }[/tex]

⇒        [tex]=\sqrt{\frac{1777.72}{0.889} }[/tex]

⇒        [tex]=44.73 \ m/s[/tex]

Answer:

2 m/s

Explanation:

...........................

Answer:

A:2 m/s

Explanation:

Plato

Answer:

I would need to see the part a to be more specific but this may help:

resources like solar, water, wind are considered renewable because they will never run out, they can be replenished over and over again. There will always be a sun (and if there wasn't then we'd have bigger conserns than renewable energy) and the wind will always blow. It can never run out because you use too much unlike coal and fossil fuels.

Hope this helps!

Answer:

D 2N

Explanation:

these are opposite forces so one becomes negative and the other positive that is

-3+5=2 or 5-3=2

Answer:

Explanation:

2500 rpm = 2500 / 60 rps ( revolution per second )

= 41.67 rps .

power output = 500 kW

thermal efficiency = 20 %

power input = (100 /20) x 500 kW

= 2500 kW .

work done per second = 2500 kJ

work done per cycle = 2500 / 41.67

= 60 kJ .

We have that the  workdone per cycle is mathematically given as

Wc=12.00KJ

Question Parameters:

The power output of a car engine running at 2500 rpm is 500 kW

Generally the work done per cycle  is mathematically given as

Wc=500*1/41.666

Where

=2500rev/60sec

=41.666

Meaning one cycle takes 1/41.666

Hence

Wc=500*1/41.666

Wc=12.00KJ

For more information on work

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Answer:

Condensation and Melting

Explanation:

Gas to liquid = Condensation

Solid to liquid = Melting

Answer:

radiation

Explanation:

Answer:

independent and the second one with the (-8, 1, -3)

Answer:

s = 0.3 m

Explanation:

In order to calculate the distance traveled by the person, we will use the second equation of motion:

[tex]s = v_it + \frac{1}{2}at^2[/tex]

where,

s = distance traveled = ?

vi = initial speed = 0 m/s

t = time = 32 ms = 0.032 s

a = acceleration = 60g = (60)(9.81 m/s²) = 588.6 m/s²

Therefore,

[tex]s = (0\ m/s)(0.032\ s)+\frac{1}{2}(588.6\ m/s^2)(0.032\ s)^2[/tex]

s = 0.3 m

Answer:

The FITT principles are an exercise prescription to help participants understand how long and how hard they should exercise. FITT is acronym that stands for Frequency, Intensity, Time, and Type. FITT can be applied to exercise in general or specific components of exercise.

Explanation:

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

Answer:

I think so too

Explanation:

:*

Answer:

The answer is D. Here is proof . Plz mark brainliest

Explanation:

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

Answer:

I think its B

Explanation:

Answer:

The correct answer is "1080 W".

Explanation:

Given:

Current,

I = 9.0 A

Potential difference,

V = 120 volt

As we know,

⇒ [tex]Power=IV[/tex]

On substituting the values, we get

⇒             [tex]=120\times 9.0[/tex]

⇒             [tex]=1080 \ W[/tex]

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

Answer:

Fuerza, F = 0.001 Newton

Explanation:

Dados los siguientes datos;

Intensidad del campo eléctrico = 5 * 10² N/C

Carga = 2 microculombios = 2 * 10^{-6} culombios

Para encontrar la fuerza que actúa sobre la carga;

Matemáticamente, la intensidad del campo eléctrico viene dada por la fórmula;

Intensidad del campo eléctrico = fuerza/carga

F = E * Q

F = 5 * 10² * 2 * 10^{-6}

Fuerza, F = 0.001 Newton

Answer:

14.9 mm

Explanation:

We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m

Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m

So, sinθ = mλ/d

Since θ is small, sinθ ≅ tanθ

So,

mλ/d = L/D

d = mλD/L

Substituting the values of the variables into the equation, we have

d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m

d = 2448 × 10⁻⁹ m²/0.017 m

d = 144000 × 10⁻⁹ m

d = 1.44 × 10⁻⁴ m

d = 0.144 × 10⁻³ m

d = 0.144 mm

Now, for the second-order maximum, m' of the 670 nm wavelength of light,

m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m

So, L' = m'λ'D/d

So, substituting the values of the variables into the equation, we have

L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m

L' = 2144  × 10⁻⁹ m²/0.144 × 10⁻³ m

L' = 14888.89 × 10⁻⁶ m

L' = 0.01488 m

L' ≅ 0.0149 m

L' = 14.9 mm

Answer:

the researcher say hi for us the best pa the best of us are going out to eat that I can get my money toward a little bit but the best of luck to be at work by then and we will see what the status

Answer:

[tex]81:256[/tex].

Explanation:

Let [tex]T[/tex] denote the absolute temperature of this object.

Calculate the value of [tex]T[/tex] before and after heating:

[tex]T(\text{before}) = 27 + 273 = 300\; \rm K[/tex].

[tex]T(\text{after}) = 127 + 273 = 400\; \rm K[/tex].

By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to [tex]T^4[/tex].

Ratio between the absolute temperature of this object before and after heating:

[tex]\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}[/tex].

Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:

[tex]\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}[/tex].

Answer:

Spring constant = 63.77 N/m

Explanation:

Given the following data;

Force = 44 N

Extension = 0.69 m

To find the spring constant;

Force = spring constant * extension

Substituting into the formula, we have;

44 = spring constant * 0.69

Spring constant = 44/0.69

Spring constant = 63.77 N/m

Answer:

d = 1,029 m

Explanation:

When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.

To calculate the distance let's use the uniform motion relationships

        v = d / t

        d = v t

As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,

         t = to / 2

         t = 6/2

         t = 3 s

         d = 343 3

         d = 1,029 m

Answer:

8 days

Explanation:

Answer:

An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.

Answer:

[tex]\frac{K.E_t}{K.E_r} = 1[/tex]

Explanation:

The translational kinetic energy of the hoop is given as:

[tex]K.E_t = \frac{1}{2} mv^2[/tex]      ---------------------- equation (1)

where,

[tex]K.E_t[/tex] = translational kinetic energy

m = mass of hoop

v = linear speed of hoop

The rotational kinetic energy of the hoop is given as:

[tex]K.E_r = \frac{1}{2} I\omega^2[/tex]

where,

[tex]K.E_r[/tex] = rotational kinetic energy of the hoop

I = Moment of Inertia of the hoop = mr²

r = radius of the hoop

ω = angular speed of hoop = [tex]\frac{v}{r}[/tex]

Therefore,

[tex]K.E_r = \frac{1}{2} (mr^2)(\frac{v}{r} )^2\\\\K.E_r = \frac{1}{2} mv^2[/tex]------------------- equation (2)

dividing equation (1) and equation (2), we get:

[tex]\frac{K.E_t}{K.E_r} = \frac{\frac{1}{2}mv^2 }{\frac{1}{2}mv^2 }\\\\\frac{K.E_t}{K.E_r} = 1[/tex]