The solution to an inequality is graphed on the number line. What is another way to represent this solution set? O {x | X 4.5) O x | x2 4.5) 5 -3 -2 -1 0 1 2 3 4 5​

Answer:

0 is a rational, whole, integer and real number.

Step-by-step explanation:

0 is a rational, whole, integer and real number.

Answer:

where's the question or the picture of the question

Answer:

B.

Step-by-step explanation:

Answer:

221

Step-by-step explanation:

2-1+5*4*11

2-1+20*11

2-1+220

1+220

221

Answer:

12x - 6 ≤ - 18

Step-by-step explanation:

We will call "a number" x so

Twelve times a number would be:

12x

Then minus 6

12x - 6

Now we add the less than or equal to sign.

12x - 6 ≤

This is equal to negative eighteen, so:

12x - 6 ≤ - 18

As a bonus we can also solve for x.

12x - 6 = - 18    Add 6 to each side.

12x - 6 + 6 = -18 + 6

12x = -18 + 6

12x = -12  Divide each side by 12

12x/12 = -12/12

x = -12/12

x = -1

So we can say when x ≤ -1 Then 12x - 6 ≤ -18

Answer: I think the answer is C

Answer:

yea i agree with kassidy

Answer:

The answer is 4

Step-by-step explanation:

Like the other person said

Number lines are used to represent numbers at regular and constant intervals

The point on the number line that represents -3 - (-7) is 4

The expression is given as:

-3 - (-7)

Open the bracket

-3 + 7

Evaluate the expression

4

Hence, the point on the number line that represents -3 - (-7) is 4

Read more about number lines at:

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Answer:

3/5 , .2, .19

Step-by-step explanation:

.2= 20/100

.19 = .19/100

3/5 = .6= 60/100

Complete the statements to verify that f(x) = 10x and g(x) = log10x are inverses of each other. f(g(x)) = 10log10x

The answer is given below in the image.

The laws apply to logarithms of any base but the identical base needs to be used at some point in a calculation. This regulation tells us a way to add logarithms collectively. Adding log A and log B results in the logarithm of the product of A and B, that is log AB. The same base, in this situation 10, is used throughout the calculation.

A logarithm of more than a few raised to a power is identical to the power expanded via the logarithm of the wide variety to the same base. that is, loga(mn) = nlogam.

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5/2 , √5 , 2¾ , 2.71 (bar)

am not really sure but i guess that is what I know.

Answer:

 [tex]2\frac{3}{4}, 2.71, \sqrt{5}, \frac{5}{2}[/tex]

Step-by-step explanation:

Just convert them all to a decimal, I'm too lazy to write it all out...

Answer:

35 counting yourself.........34 not

g(x) = f(x) - 5

We subtract 5 from f(x) because we are doing a vertical shift down 5 units.

Answer: A

Step-by-step explanation:

For this problem, you would need to analyze the graph.

If you notice, both lines look pretty identical with the exception of one lower than the other. As you can see, the blue line is the same as the red line, but shifted down by 5. Therefore, you would subtract f(x) by 5. That would make A our answer.

Answer:

8-p=-12-3p

8+12-p = -3p

20 = -3p + p

20 = -2p

20/-2 = p

-10 = p

ans. p = -10

...

The joint density equation is missing in the question. The equation is [tex]f(x,y)=\left\{\begin{matrix}2x^3, 0\leq x\leq 1,0\leq y\leq 2\\ 0, \text{ otherwise}\end{matrix}\right.[/tex]

Probability is 0.59

Step-by-step explanation:

We have

x -- denotes the annual claim health insurance

y -- denotes the annual claim life insurance

And joint density of x and y is given to us

[tex]f(x,y)=\left\{\begin{matrix}2x^3, 0\leq x\leq 1,0\leq y\leq 2\\ 0, \text{ otherwise}\end{matrix}\right.[/tex]

Event that the claim exceeds 0.5 but less than 2 can be written as 0.5≤ x+y ≤2

and claim of life insurance less than 1.5 can be written as 0 ≤ y ≤ 1.5

Required probability

= P( 0.5≤ x+y ≤2  ∩ 0 ≤ y ≤ 1.5 )

Lets plot this, to find the common region

For common region

when 0≤ x ≤ 0.5, then 0.5 ≤ y ≤ 1.5  ---- for region I

when 0.5≤ x ≤ 1, then 0 ≤ y ≤ 2-x  ---- for region II

The required probability

= [tex]\int_{0}^{0.5} \int_{0.5-x}^{1.5}2x^3 dy dx+\int_{0.5}^{1} \int_{0}^{2-x}2x^3 dy dx[/tex]

= [tex]\int_{0}^{0.5} 2x^3[\int_{0.5-x}^{1.5}dy] dx+\int_{0.5}^{1} 2x^3[\int_{0}^{2-x}dy] dx[/tex]

= [tex]\int_{0}^{0.5} 2x^3(1.5-0.5+x) dx+\int_{0.5}^{1} 2x^3 (2-x) dx[/tex]

= [tex]\int_{0}^{0.5}2x^3 dx+\int_{0}^{0.5}2x^4 dx+\int_{0.5}^{1}4x^3 dx-\int_{0.5}^{1}2x^4[/tex]

= [tex][\frac{2x^4}{4}]_0^{0.5}+[\frac{2x^5}{5}]_0^{0.5}+[\frac{4x^4}{4}]_{0.5}^1-[\frac{2x^5}{5}]_{0.5}^1[/tex]

= [tex]$\frac{1}{32}+\frac{1}{80}+\frac{1}{16}-\frac{31}{20}$[/tex]

= 19/32

=0.59    

answer

4 pairs

Step-by-step explanation:

total is $175

when you buy three pairs of pants you have wasted $90

175-90 equals 85

Answer:

2(L+w) = 190ft (Perimeter)

L + W = 95ft (190 divided by 2)

L = W + 43ft (Given)

W + 43 + W = 95ft

2W + 43 = 95ft

2W = 52ft

W = 26ft

L = 26ft + 43 = 69ft

Answer: The feild is 69ft by 26ft

Hope this helps!!!

- Jarrett Lane

Answer:

2.1 < x <2.5

Step-by-step explanation:

i’m taking the test rn i’m not sure if it’s correct i’ll lyk!

Answer:

B on Edge

Step-by-step explanation:

Here, Angle 1 and angle 2, Angle 4 and angle 3 and Angle 7 and angle 5 are supplementary angles.

We need to identify which angle pairs are supplementary.

Supplementary angles are two angles with a sum of 180°.

Here, Angle 1 and angle 2, Angle 4 and angle 3 and Angle 7 and angle 5 are supplementary angles.

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Answer:

5(5(-1)-7)

-25-35

-60

Step-by-step explanation:

Answer: -60

Step-by-step explanation:

Image!!

Answer:

y=3.364

x=4

Step-by-step explanation:

hope this helps

Step-by-step explanation:

10x2-10x+2

20-10x+2

22-10x

8x2+7-7

16+0

16

I'm confused so I add together cuz why not?

16+22-10x

28-10x

Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

Step-by-step explanation:

1)         First       and        Second         and         Third

  [tex]\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}[/tex]

2)         First       and          Second

   [tex]\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}[/tex]

[tex]3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}[/tex]

[tex]4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}[/tex]

Answer:100 chocolates

Step-by-step explanation:

20 chocolate in each box so 20 time 5 is 100 so 20 time 11 is 220

Points A′, B′, and D′ are shown, but the line of reflection and point C′ are not . coordinates of C from the graph = (4,2) If the coordinates of C'=(6,2) we can see that value of y isn't change with reflection therefore the line of reflection would be x= ordinate of C'+ ordinate of C divided by 2=6+4 divided by 2=10 divided by 2=5. Therefore, the line of reflection must be x=5.

Answer:

A) (2x − 7) (4x² + 14x + 49)

C) (3x + 5) (9x² − 15x + 25)

Step-by-step explanation:

Sums and differences of cubes factor as:

a³ + b³ = (a + b) (a² − ab + b²)

a³ − b³ = (a − b) (a² + ab + b²)

8x³ − 343 is a difference of cubes.

(2x)³ − 7³

(2x − 7) (4x² + 14x + 49)

27x³ + 125 is a sum of cubes.

(3x)³ + 5³

(3x + 5) (9x² − 15x + 25)

Answer:

45ans

Step-by-step explanation:

p=?

m=15kg

v=3m/s

now,

p=m*v

p=15*3

p=45 ans

In this expression, the constant would be 12.

A constant is simply a term that has no variable next to it.

Answer:

the anwser is 7 buddy hope it helps