The school band collected $3,240 for 380 tickets sold to their spring concert. Adult tickets were $12 each and student tickets were $6 each. How many adult tickets were sold?

Answers

Answer 1

160 adult tickets were sold

How to determine how many adult tickets were sold?

Word problems are sentences describing a 'real-life' situation where a problem needs to be solved by way of a mathematical calculation.

Set up equations to represent the problem.

Let the A and S represent the number of adult and student ticket respectively. So we can write:

12A + 6S = 3,240 --- (1)

A + S = 380  --- (2)

From (2):

S = 380 - A ---- (3)

Put (3) in (1):

12A + 6S = 3,240

12A + 6 (380 - A) = 3,240

12A + 2280 -6A = 3,240

6A = 3,240 - 2280

6A = 960

A = 960/6

A = 160 tickets

Thus, the number of adult ticket sold is 160

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Related Questions

What is the number based on the list of factors? 1,3,7, __
Please help

Answers

Answer:

21 I think, might be wrong.

YOU HAVE SAVED $5000 AND INVESTED IT AT A RATE 3.2% FOR 5 YEARS. WRITE AN EXPONENTIAL FUNCTION TO REPRESENT THIS SITUATION. HOW MUCH WILL VOU KAVE AFTER YEARS? HOW MUCH WILL A BILLIONAIRE HAVE IF HE INVESTS $1,000,000,000 AT THE SAME RATE FOR THE SAME AMOUNT OF TIME?

Answers

Answer:

5852.86 = 5000 (1+ .032)^5

1170572956 = 1,000,000,000(1+ .032)^5

Step-by-step explanation:

Two possible floor plans for a new bathroom are shown.
Is there a value for x for which the perimeters are equal?
What is the linear equations?

Answers

Answer:

Hope it works for u

Step-by-step explanation:

As we have given two shapes bathroom

square and rectangle

Parameter of square= sum of all the sides   ( : In square all sides are equal

Parameter of square= 4*L  = 4*(x+3)       (:L=x+3

similarly,

In rectangle opposites sides  are equal hence

Perimeter of rectangle= 2*length+2*width  ( : length=x+4,width can't be seen clearly so I assume and take it width=x+1  hope this is equal to the width of ur question otherwise do the calculation by ur self).

Perimeter of rectangle= 2*(x+4)+2(x+1)

so now we have to find the value of "x" for which both perimeter are equal, so

perimeter of square= perimeter of rectangle

4*(x+3)=2*(x+4)+2(x+1)  we can also write as

2(x+3)+2(x+3)=2(x+4)+2(x+1)This is the linear equation requirednow to find value of "x"simplify both sides, we get4x+12=4x+100≠2 so that not true and also there is no value of "x"

for which both parameters become equal

so from my side "b" option is correct

Please brain-list it if u find it help-full it requires effort!

Answer: B option is correct. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle.

explanation: I hope that was helpful!

2+4x=2(2x+1)
Which statements are true?

Select each correct answer.


There is no value for x that will make the equation true.

The equation is an identity,

The solution is 2.

There are infinitely many solutions.

The equation is a contradiction.

There are no solutions.

The equation is true for all values of x.

Answers

Correct answers:
1. There is no value of X that will make the equation true
2. The equation is an identity
4. There are infinite many solutions
5. The equation a contradiction

I need help ASAP no rocky

Answers

Answer:

no rocky

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

I think it's C and I am always right so it is C! You're welcome!

Which graph represents this system? 2x-5v=-5 y=-3x+1​

Answers

Answer:

Please check the attached graph.

Step-by-step explanation:

The slope-intercept form of the line equation

[tex]y = mx+b[/tex]

where

m is the slopeb is the y-intercept

Given the system of equations

2x - 5y = -5    --- [Equation 1]

y = -3x + 1​      --- [Equation 2]

converting the equation 1 in the slope-intercept form

2x - 5y = -5

5y = 2x+5

divide both sides by 5

y = 2/5x + 1

Thus, the y-intercept  = 1

Now, please check the attached graph below.

The red line represents the equation  2x - 5y = -5

From the graph, it is clear that the red line has the y-intercept y = 1.

Now, considerng the equation 2

y = -3x + 1​  

comparing with the slope-intercept form of line equation

The y-intercept b = 1

Hence, the y-intercept of the line y = -3x + 1​ is y = 1

The green line represents the equation  y = -3x + 1​  

From the graph, it is clear that the green line has the y-intercept y = 1.

Point of Intersection:

It is clear from the graph:

The red line represents the equation  2x - 5y = -5.The green line represents the equation  y = -3x + 1​.

As both lines meet or intersect at the point (0, 1).

Therefore, the point of intersection of both the lines is:

(x, y) = (0, 1)

As we know that the point of intersection of both the lines represents the solution to the system of equations.

Therefore, (0, 1) on the graph represents the solution to the system of equations.

The graph is attached below.

Certain pieces made by an automatic lathe are subject to three kinds of defects X, Y, Z. A sample of 1000 pieces was inspected with the following results: 2.1% had type X defect. 24% had type Y defect. 2.8% had type Z defect. 0.3% had both type X and type Y defects. 04% had both type X and type Z defects. 0.6% had both type Y and type Z defects. 0.1% had type X, type Y, and type Z defects. Draw a Venn Diagram, then find:
(a) What percent had none of these defects?
(b) What percent had at least one of these defects?
(c) What percent were free of type X and/or type Y defects?
(d) What percent had not more than one of these defects?

Answers

Answer:

a) % age of samples containing none of these defects = 93.9%

b)% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect = 98.9%

Step-by-step explanation:

Data Given:

Number of Samples = 1000

Type X defect = 2.1% = 21 samples

Type Y defect = 2.4% = 24 samples

Type Z defect = 2.8% = 28 samples

Both Type X and Y defect = 0.3% = 3 samples

Both Type X and Z defect = 0.4% = 4 samples

Both Type Y and Z defect = 0.6% = 6 samples

Type X and Y and Z defect = 0.1%  = 1 sample

Venn Diagram is attached in the attachment below. Please refer to attachment for the Venn Diagram.

a) % age of samples containing none of these defects.

Solution:

Number of samples containing none of these defects = Total - Samples with defects

Number of samples containing none of these defects = 1000 - { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

 Number of samples containing none of these defects = 1000 - { (21) + (24) +(28) - (3) -(4) - (6) + (1) }

Number of samples containing none of these defects = 1000 - 61

Number of samples containing none of these defects = 939

% age of samples containing none of these defects = 939/1000 x 100

% age of samples containing none of these defects = 93.9%

b) % age of samples containing at least one of these defects:

We have already calculated this above, number of samples containing at least on of these defects:

number of samples containing at least on of these defects = { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

number of samples containing at least on of these defects = { (21) + (24) +(28) - (3) -(4) - (6) + (1) }  

number of samples containing at least on of these defects = 61

% age of samples containing at least one of these defects = 61/1000 x 100

% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects.

For this find, we need to find the samples with only Z Type defect.

Number of Samples with Only Z type defects = { (Type Z) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

Number of Samples with Only Z type defects = { (28)  -(4) - (6) + (1) }

Number of Samples with Only Z type defects = 19

Now, we also know the number of samples without any defects = 939

Now,

The number of samples free of type X and/or type Y defect = Sum of Number of Samples with Only Z type defects and number of samples without any defects

The number of samples free of type X and/or type Y defect = 19+939

The number of samples free of type X and/or type Y defect = 958

% age of samples free of type X and/or type Y defects = 958/1000 x 100

% age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect:

For this find, we need to find number of samples with only X type and with only type Y and with only type Z.

We have already found the number of samples with only Z type defect = 19

Now,

number of samples with only X type defect = { (Type X) - (Both X and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only X type defect =  { (21)  -(4) - (3) + (1) }

number of samples with only X type defect =  15

Similarly,

number of samples with only Y type defect =  { (Type Y) - (Both Y and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only Y type defect =  { (24)  -(6) - (3) + (1) }

number of samples with only Y type defect =  16

For,

samples with not more than 1 defect = number of samples with only Y type defect + number of samples with only X type defect + number of samples with only z type defect + number of samples without any defects

samples with not more than 1 defect = 939 + 16 + 15 + 19

samples with not more than 1 defect = 989

%age of samples with not more than 1 defect = 989/1000 x 100

%age of samples with not more than 1 defect = 98.9%

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