the resistance of an object to change its dynamic state called​

Explanation:

We use Hooke's Law, which states that,

F=kx

F- is the force in newtons

k- is the spring constant

x- is the extension of the spring in meters

Solving for k we get k=F/x

k= 10N/0.50m

=100 N/m

Answer:

The mass of the copper is 3.00kg

Explanation:

Solution :

c). [tex]$\vec{F}_A = $[/tex] force applied by Abe

   [tex]$\vec{F}_B = $[/tex] force applied by Barry

   [tex]$\vec{F}_E = $[/tex] force applied by Eric

   [tex]$\vec{F}_R = $[/tex] Resultant force

[tex]$\vec{F}_A $[/tex]  in the vector form can be written as :

         [tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]

[tex]$\vec{F}_B $[/tex]  in the vector form can be written as :

         [tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]

The resultant,

[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]

     [tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]

    [tex]$=60 \hat i + 60 \hat j$[/tex]

[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

[tex]$|\vec F_E| = |\vec F_R|$[/tex]

[tex]$|\vec F_E| =84.853 \ N$[/tex]

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]

   [tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]

  = 45°  north east

The direction of the force E is  45° west or  45° south west.

I think The coastal areas were highly polluted

Answer:

i think its greenhouse gases may increase

Explanation:

Answer:

a survey

Explanation:

how kids like the playground or they do not like it at all

Suppose it takes at least 5 people to push a very heavy box up a 400-cm ramp. If there are actually 6 people there to help push, they could use ramp(s) = 480 cm to get the box moved.

According to newton if there is a object at rest then a physical or non physical thing acting on it and it helps him to move a bit that called the force. It is a vector quantity. It can be measured in newton, dyne.

To calculate the ramp we are using the formula,

s= s₁×(p₂/p₁)

Here we are given,

s₁= The initial length of the ramp. = 400m

p₂= The final number of people. = 6

p₁=The initial number of people. = 5

We have to calculate the final length of ramp.= s cm

Now we put the values in above equation, we get

s= s₁×(p₂/p₁)

Or, s= 400×(6/5)

Or, s=480 cm

From the above calculation we can say that, If there are actually 6 people there to help push, they could use ramp(s) = 480 cm to get the box moved.

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Explanation:

container, bottles, boxes, cups

Decay of Schizomycetes waste present in waste water leads to unpleasant smell.

These microorganisms, known as iron and sulfur bacteria, cause hydrogen sulfide to be found in water supplies. They include crenothrix and beggiatoa. Most often found in groundwater supplies, they produce an offensive odor of decaying matter. (I'm not sure)

The engine thermal efficiency is 50%

The engine does 200 joules of work per cycle

It exhausts 400 j

The thermal efficiency can be calculated as follows

= 200/400

= 0.5 × 100

= 50 %

Hence the engine thermal efficiency is 50%

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Answer:

37.5 J

Explanation:

With work done equation: W=Fs

W=75*0.50=37.5 J

or use mgh=(75)(0.5) which is the same

Answer:

The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].

Explanation:

Given that object has a constant mass in time, the force acting on the object ([tex]\vec F[/tex]), in newtons, is defined by following expression:

[tex]\vec F = m\cdot \vec a[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]\vec a[/tex] - Acceleration, in meters per square second.

By definition of acceleration, we know that:

[tex]\vec a = \frac{d}{dt} \vec v[/tex] (2)

Let suppose that given vector velocity is expressed in meters per second. If we know that [tex]m = 2\,kg[/tex], [tex]\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right][/tex] and [tex]t = 2\,s[/tex], then the force acting on the object is:

[tex]\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right][/tex]

[tex]\vec F = (4, 16\cdot t)\,[N][/tex]

[tex]\vec F = (4, 32)\,[N][/tex]

The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].

For the first hour, the slope is zero.

After that, the slope is -2 miles per hour.

Answer:

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

Answer:

USB-6000

Explanation:

For this strange exercise, you must take into account two fundamental aspects of the data acquisition cards;

* The resolution of the cards, which for a 12-bit card is 2.24mV =2.24 10⁻³V , for which a card of this resolution is sufficient

    In your case, the amplitude is 50 mv, which is why it is much higher than the resolution of the card.

* The sampling rate or the frequency in which the card can acquire the data, the typical frequencies go from 200 Khz to the MHz, in general a card that has more than double the frequency to be measured should be selected.

In this case the frequency of your wave is

           f = 1 / T

           f = 1/100 10⁻³

            f = 10 Hz

therefore a low frequency card is suitable.

- The third point is the requirement that it has a USB interface, most of the card do not have it

If you check the National Instruments catalog, there are low-cost cards for example: USB-6000 of 12bits and 10KS / s the latter is the samples taken per second

Answer:

E = 20 N/C

Explanation:

Given that,

Charge, q = 2 C

Force experience, F = 40 N

We need to find the electric field at that location.

The electric field in terms of electric force is given by :

F = qE

Where

E is the electric field

[tex]E=\dfrac{F}{q}\\\\E=\dfrac{40\ N}{2\ C}\\E=20\ N/C[/tex]

So, the electric field at that location is 20 N/C.

Answer:

573

Explanation:

totally not stealing previous answer cause I know it's right

The wavelength of the light is 578.45 nm.

Light passing through a double slit with separation is given as

d = 2.42 × 10⁻⁵ m.

Line number m = 2

Angle θ = 2.74°

     The distance between two sound waves i.e., crest and trough is called the wavelength.

To find the wavelength, here we use the formula as,

               sin θ = Line number × λ ÷ ( distance )

By substituting all the given values,

              Sin ( 2.74° ) = 2 × λ ÷ ( 2.42 × 10⁻⁵ )

Rearranging the equation,

                 λ= (Sin ( 2.74° ) ×  ( 2.42 × 10⁻⁵ ) ) ÷ (2)

                  λ = 578.45 nm.

Thus, wavelength λ of the light is 578.45 nm.

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Answer:

L = 2 J.s

Explanation:

The angular momentum of an object travelling in a horizontal circle is given by the following formula:

[tex]L = mvr[/tex]

where,

L = Angular momentum = ?

m = mass = 0.8 kg

v = linear speed = rω

r = radius of circular path = length of rope = 0.5 m

ω = Angular Speed = 10 rad/s

therefore,

[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]

L = 2 J.s

Answer:

Information from the leading mathematicians was considered "classified".

Answer:

acc to formula= F= G m1m2/rsq

mass of Uranus= F×r sq/G×m

M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21

=3×10^25-8×7614×7614/667×301×10^-2-11+21-2

=173918988×10^11/200767

=866×10^11(approx)

Answer:

I am joker if you are mad x_________-..............,,,,,,........ €£

Answer:

Density of body = 0.25g/cc

Explanation:

Given:

Volume submerged in water = 3/4

Find:

Density Of Body

Computation:

Density of body = fraction of body in liquid x density of water

Density of body = [1-3/4]1

Density of body = 0.25g/cc

Answer:

Neptune and Uranus

Explanation:

Did a quiz on this not to long ago

Answer:

B. Side-view mirrors on vehicles

C. Hallway safety mirrors

E. Lenses in sunglasses

Explanation:

Trust Me, Look At Attachment.

Answer:

2, 3, and 5 on Edge, 2022.

Explanation:

I had this question on Edge.

(See the attachment below.)

The rest of the answers are:

O Slide 8 - Sample Response: The image seems to be behind the mirror, but nothing is really there.

O Slide 9 - Concave

O Slide 10 - Same size

Answer:

How Urgent are we talking?

Explanation:

Answer: The dependent Variables include: Size and Types of trees.

The independent Variables include:

geographic elevations that is, valleys and the higher elevations.

Explanation:

The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.

Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the

geographic elevations that is, the valleys and the higher elevations.

Answer:

the answer is D

Explanation:

Answer:

1. M = 67,422,800,892,977.54 kg

2. r = 15 km

Explanation:

The diameter of the Comet Tempel 1, D = 9.0 km across

The speed with which the dust escapes = 1.0 m/s

1. The escape velocity, [tex]v_e[/tex], is given by the following formula

[tex]v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{R} }[/tex]

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

[tex]v_e[/tex] = The escape velocity of the debris = 1.0 m/s

M = The mass of the comet from where the debris escapes

From the escape velocity equation, we have;

[tex]M = \dfrac{v_e^2 \cdot R}{2 \cdot G}[/tex]

Plugging in the values for the variables, we get the mass of the comet, 'M', as follows;

[tex]M = \dfrac{1.0^2 \times 9,000}{2 \cdot 6.67430 \times 10^{-11}} \approx 67,422,800,892,977.54 \, kg[/tex]

The mass of the comet, M ≈ 67,422,800,892,977.54 kg

2. When the debris has lost 60% of its initial kinetic energy, we have;

[tex]60\% \, K.E. = 0.6\cdot K.E. = 0.6 \times \dfrac{1}{2} \times m \times v_e^2 = \dfrac{G \cdot M \cdot m}{r}[/tex]

[tex]\therefore \, The \ distance \ of \ debris \ from \ the \ center, \, r = \dfrac{G \cdot M }{0.6 \times \dfrac{1}{2} \times v_e^2 }[/tex]

[tex]r = \dfrac{6.67430 \times 10^{-11} \times 67,422,800,892,977.54}{0.6 \times \dfrac{1}{2} \times 1^2 } = 15,000[/tex]

When the debris has lost 60% of its initial kinetic energy, the distance the debris will be from the comet's center, r = 15,000 m = 15 km