the rectangle below consists of 8 unit squares. what fraction of the rectangle is shaded?

The height of the hat is 9.0 inches.

A party hat is in the shape of a cone with dimensions shown . Therefore, the height of the cone can be found as follows:

The radius of the cone is 4.3 inches and the slanted height of the cone is 10 inches.

Therefore, Pythagoras's theorem can be used to find the height of the cone. The radius and the slanted height of the cone forms a right angle triangle.

Therefore,

10² - 4.3² = h²

h² = 100 - 18.49

h² = 81.51

square both sides

h = √81.51

h = 9.02828887442

h = 9.0 inches

Therefore,

height of the hat = 9.0 inches

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Yes, the formula z = -b± √(b²-4ac)/2a is used to find the solutions (or roots) of a quadratic equation of the form az² + bz + c = 0. This is known as the Quadratic Formula.

What is the Quadratic Equation?

A quadratic equation is a type of polynomial equation of degree 2 in one variable (x), which can be written in the form of ax² + bx + c = 0, where a, b, and c are real numbers, and a is not equal to zero. The solutions or roots of this equation can be found by using the Quadratic Formula which is z = -b ± √(b²-4ac) / 2a.

The Quadratic formula is valid for any quadratic equation in standard form (ax² + bx + c = 0), where a, b, and c are real numbers, and a is not equal to zero. The two solutions are given by the formula are the roots of the equation, and they are always real and distinct, unless the discriminant b² - 4ac is negative, in which case the roots are complex numbers.

Hence, Yes, the formula z = -b± √(b²-4ac)/2a is used to find the solutions (or roots) of a quadratic equation of the form az² + bz + c = 0. This is known as the Quadratic Formula.

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The answer is -There are no outliers.

According to the question, there are no outliers in the Global Unemployment Rates. From the given data, no outliers are observed.

An outlier is an observation that lies an abnormal distance from other values in a sample from a population. In a sense, this explanation leaves it up to the analyst to decide what will be considered abnormal.

An outlier is a single data point that goes far outside the average value of a set of statistics. Outliers may be exceptions that stand outside individual samples of populations.

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Answer/Step-by-step explanation:

Starting with:

8r + 5p + 7



There are three terms. 8r is a term; 5p is a term; 7 is a term. See how the terms are separated by + or -

r and p are variables. Most often the variable is a letter, that way it can stand for an unknown value. It can vary.

5 is the coefficient of p. Its the number right next to the p. (They are multiplied together)

7 is the constant. Constant means unchanging, right? So 7 is a plain old number, it doesn't change like a variable can. A plain number with no variable is a constant.

Answer: 12y+168

Step-by-step explanation:

Basically, multiply each of the numbers that are in the parenthesis by the number outside the parenthesis (12). So 12·y=12y and 12·14=168. Therfore the answer is 12y+168 .

The complete implementation of the function 'same diff ints' is written italic below.

Below is the implementation for the function same_diff_ints in Python:

def same_diff_ints(ints):

   for i in range(1, len(ints)):

       for j in range(i, len(ints)):

           if abs(ints[j] - ints[j-i]) == i:

               return True

   return False

The function takes in a list of integers as input and iterates through the list using nested for loops. The outer for loop iterates through the list starting at index 1, and the inner for loop iterates through the list starting at the outer loop's current index.

The function compares the absolute difference between the two elements at index j and j-i with the value of i. If the absolute difference between the two elements is equal to i, the function returns True. If no such pair of elements is found, the function returns False.

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The given pair of linear equations is consistent.

What are Linear Equations?

An equation is said to be linear if the maximum power of the variable is consistent. Another name for it is a one-degree equation.

Equations are declarations of equality between two mathematical expressions containing one or more variables. A linear equation is one in which the maximum power of the variable is one. a real number equation of the form ax+by+c = 0, with real numbers a, b, and c with the highest power one variable x and y.

In our question, we can see:

a1 = -3 and a2 = 4

b1 = 3 and b2 = 4

c1 = 21 and c2 = 60

a1/a2 = -¾

b1/b2 = ¾

c1/c2 = 7/20

Since a1/a2 is not equal to b1/b2, therefore our pair of liner equation is consistent.

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A matrix is in the row-echelon form if:

1. The first nonzero element of each nonzero row (called the leading entry) is to the right of the leading entry of the row above it.

2. Each leading entry is 1 (also called a pivot).

3. Each element above and below a pivot is 0.

A matrix is in the reduced row-echelon form if it is in row-echelon form and also:

4. Each pivot is the only nonzero element in its column.

A matrix is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns. The numbers, symbols, or expressions in a matrix are called its entries or elements. Matrices are often used in linear algebra, a branch of mathematics that deals with vector spaces and linear transformations.

They can be used to represent systems of linear equations, perform operations such as matrix addition and multiplication, and solve systems of linear equations.

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Answer:(a) To find the net cost equivalent, we can use the formula:

Net Cost Equivalent = Original Cost / (1 - (Discount Rate / 100))

Using this formula, the net cost equivalent for a series discount of 5/10/12 is:

Net Cost Equivalent = Original Cost / (1 - (5/100)) / (1 - (10/100)) / (1 - (12/100))

(b) To find the single discount equivalent for a series discount of 5/10/12, we can use the formula:

Single Discount Equivalent = (1 - (1 - (Discount Rate1 / 100)) x (1 - (Discount Rate2 / 100)) x ... x (1 - (Discount RateN / 100))) x 100

Using this formula, the single discount equivalent for a series discount of 5/10/12 is:

Single Discount Equivalent = (1 - (1 - (5/100)) x (1 - (10/100)) x (1 - (12/100))) x 100

Answer:

75,000

Step-by-step explanation:

We have to round up to nearest thousand ,so we need to check hundred place ...

If hundred place is equal or greater than 5 ,we need to add +1 to the number which is in thousand place , If it is less than 5 we don't need to do so ....

The percent of increase from 5.5 feet to 6 feet is 9.1%

Percentage is a way to express a number as a fraction of 100.

It is often used to express a proportion or rate in a convenient and understandable way.

To calculate percentage, you can use the formula: (part/whole) x 100.

For example, if you scored 80 out of 100 on a test, your percentage score would be 80%.

Percentage is often used in many fields such as finance, statistics, and education.

It can be used to express the increase or decrease between two values or to compare the parts of a whole.

You can use the following calculation to determine the percentage increase from 5.5 feet to 6 feet:

Old Value * 100 / (New Value - Old Value) = Percent Increase

In this case:

(6 - 5.5) / 5.5 * 100 = 9.090909090909091%

You can round this to the nearest tenth, which would be 9.1%.

Therefore, the percent of increase from 5.5 feet to 6 feet is 9.1%.

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Answer:

Let's look at each number separately. Look in the tens place to determine which way to round.

4,070 will round up since there's a 7. However, it will only round up to 4,100 so this is not the right answer.

4,617 will round down since there's a 1. However, it will only round down to 4,600 so this is not the right answer.

4,681 will round up since there's an 8. This number will round up to 4,700 so this is the correct answer.

4,797 will round up since there's a 9. However, it will only round up to 4,800 so this is not the right answer.

The correct answer is 4,681.

A set S spans R^2 if any element of R^2 can be written as linear combination of elements of S the set S spans R2.

(a) Given that S={ (1,-1),(2,1) }

Let (x,y) be the any element in R^2.

(x,y) = C1(1,-1)+C2(2,1)

(x,y) = (c1+2c2,-c1+c2)

x  =  c1+2c2

y  = -c1+c2

x+y = 3c2

c2= {x+y}/{3}

c1 = c2-y

= {x+y}/{3}-y

={x-2y}/{3}

So for any element (x,y) in R^{2} we have the constants c_1,c_2 so that (x,y) can be written as,

(x,y)= {(x-2y)}/{3}(1,-1) + {(x+y)}/{3}(2,1)

So S= { (1,-1),(2,1) } spans R^2.

(b) Given that S = { (1,1) }

Let (x,y) be the any element in R^2.

(x,y)=c_1(1,1)

(x,y)=(c_1,c_1)

x=c_1,y=c_1

If x,y are distinct then do not get a value of c_1 so that (x,y) = c_1(1,1).

So set S= { (1,1) } does not span R^2.

(c) Given that S= { (0,2),(1,4) }

Let (x,y) be the any element in R^2.

(x,y)=c_1(0,2)+c_2(1,4)

(x,y)=(c_2,2c_1+4c_2)

x=c_2

y=2c_1+4c_2

c_1={y-4c_2} / {2}

={y-4x} / {2}

So (x,y)= {(y-4x)}/{2}(0,2)+x(1,4)

So any element of R^2 can be written as written as linear combination of elements of Set S.

Hence set S={ (0,2),(1,4) } spans R^2.

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The probability that the student got a a a given that the student was in the afternoon class is 25/57

In math the term probability is defined as based on the possible chances of something to happen

Here we have given that  a test to a group of students, the grades by the two different classes are summarized.

and it can be written like the following;

                                a             b               c                   Total

Morning class         4             20              8                    32

Evening Class         13              5               7                   25

Total                        17             25              15                  57

Here we know that the total number of students is obtained as

=> 57

And the number of students who have been taking the afternoon class is calculated as,

=> 25

Then the probability the student got a a a given that the student was in the afternoon class is written as,

=> 25/57

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This given series [tex]\displaystyle \sum_{n=1}^{\infty} \frac{1}{n!}[/tex] diverges.

The ratio can be defined as the number that can be used to represent one quantity as a percentage of another. Only when the two numbers in a ratio have the same unit can they be compared. Ratios are used to compare two objects.

Given a series, [tex]\displaystyle \sum_{n=1}^{\infty} \frac{1}{n!}[/tex] we need to see if the series converges or not.

the ratio test will fail if [tex]\displaystyle \lim_{n\to \infty} \left |\frac{a_{n+1}}{a_n} \right | =1[/tex]. Otherwise, the series converges absolutely if  [tex]\displaystyle \lim_{n\to \infty} \left |\frac{a_{n+1}}{a_n} \right | < 1[/tex] and diverges if [tex]\displaystyle \lim_{n\to \infty} \left |\frac{a_{n+1}}{a_n} \right | > 1[/tex]

Testing for the series  [tex]\displaystyle \sum_{n=1}^{\infty} \frac{1}{n!}\\[/tex],

=> [tex]\displaystyle \lim_{n\to \infty} \left |\frac{a_{n+1}}{a_n} \right |[/tex]

=>  [tex]\displaystyle \lim_{n\to \infty} \left |\frac{(n+1)!}{n!} \right | \\[/tex]

=> [tex]\lim_{n \to \infty} (n + 1)[/tex]

This value will always be greater than 1 for any positive value of n.

Therefore, This given series [tex]\displaystyle \sum_{n=1}^{\infty} \frac{1}{n!}[/tex] does not converge.

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All variables must be greater than or equal to 0, indicating that no shipping is allowed if the cost is negative.

The network representation of the Herman Company distribution system is as follows:

Plants (P1, P2, P3) -> Warehouses (W1, W2) -> Customers (C1, C2, C3, C4).

A linear programming model of the problem can be formulated as:

Minimize Z = 2x14 + 3x15 + 4x24 + 5x25 + 6x34 + 7x35 + 8x46 + 9x47 + 10x48 + 11x49 + 12x56 + 13x57 + 14x58 + 15x59

Subject to:

x14 + x15 ≤ 2

x24 + x25 ≤ 3

x34 + x35 ≤ 4

x46 + x47 + x48 + x49 ≤ 5

x14 + x24 + x34 ≤ 6

x15 + x25 + x35 ≤ 7

x46 + x56 + x66 ≤ 8

x47 + x57 + x67 ≤ 9

x48 + x58 + x68 ≤ 10

x49 + x59 + x69 ≤ 11

All variables ≥ 0

The objective of this problem is to minimize the total shipping cost from plants to warehouses and warehouses to customers. The constraints represent the limited capacities of each plant, warehouse and customer and the maximum number of units that can be shipped from each plant to each warehouse or each warehouse to each customer. All variables must be greater than or equal to 0, indicating that no shipping is allowed if the cost is negative.

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The number of cans to be added to 18 gallon tank is given by equation

A = 2.25 cans

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of cans for 18 gallon tank be A

Now , the equation will be

The number of cans per 8 gallons = 1 can

So , the number of cans for 1 gallon = number of cans per 8 gallons / 8

On simplifying the equation , we get

The number of cans for 1 gallon = 1/8

The number of cans for 1 gallon = 0.125 can

And ,

The number of cans for 18 gallons A = 18 x number of cans for 1 gallon

Substituting the values in the equation , we get

The number of cans for 18 gallons A = 18 x 0.125

The number of cans for 18 gallons A = 2.25 cans

Hence , the number of cans is 2.25 cans

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The probability of successful region is  =241/2500 Option b is correct.

Since √x=12, 12 ≤√x<13 and thus 144 ≤ x  < 169.
The successful region is when 120 ≤ 10√x < 121 in which case 12 ≤√x< 12.1
Thus, the successful region is when
144 ≤ x < 146.41

The successful region consists of a 2.41 long segment, while the total possibilities region is 25 wide. Thus, the probability is
=2.41/25
=241/2500 (B)  


In mathematics, a real number is a quantity that can be expressed as an infinite decimal expansion. In contrast to the natural numbers 1, 2, 3,..., which are derived from counting, real numbers are used in measurements of continuously varying quantities such as size and time.
               

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The price of the ABC bond on the previous day is $104 3/4

From the question, we have the following parameters that can be used in our computation:

Rate = $10 per day

Current price = $114 3/4

Using the above as a guide, we have the following:

Previous price = Current price - Rate

Substitute the known values in the above equation, so, we have the following representation

Previous price = $114 3/4 = $10

Evaluate the difference

Previous price = $104 3/4

Hence, the previous price is $104 3/4

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Complete question

ABC bond increase by $10 everyday. If the price on a given is $114 3/4, what was the price of the ABC bond on the previous day?

As per the given confidence interval, the proportion of all city residents who would respond very supportive or somewhat supportive of the proposal is 336 ± 0.197

The term confidence interval is defined as the statistical measure used to indicate the range of estimates within which an unknown statistical parameter is likely to fall.

Here we have given that the random sample of 1,018 city residents were asked to rate their level of support for a proposal being considered by the city council.

Here we have also know that the percent of confidence interval is 95%.

Here we also identified the following values,

Total population = 1,018

Very supportive population = 336

Somewhat supportive population = 387

Not supportive population= 295

Then the value of confidence interval is calculated as,

Proportion of positive results = P = x/N = 0.3301

Lower bound = 0.3012

Upper bound = 0.3599

Therefore, it can be written as,

=> 336 ± 0.197

Complete Question:

A random sample of 1,018 city residents were asked to rate their level of support for a proposal being considered by the city council. Based on the responses, which of the following is a 95% confidence interval for the proportion of all city residents who would respond very supportive of somewhat supportive of the proposal?

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The expression of the fraction 256^-3/4 in the form of a / b is equal to     1 / 64 where highest common factor between 1 and 64 is 1.

Expression of the fraction 256^-3/4 in the form a /b .

Where 'a' and 'b' are positive integers .

'a' and 'b' have no common factor than 1.

256^-3/4

= ( 1 / 256^3/4 )

= 1 / 2^ (8 × 3/4 )

= 1 / 2 ^ ( 2 × 3 )

= 1 / 2^6

= 1 / 2⁶

= 1 / 64 in the form of ( a / b )

Greatest common factor between 1 and 64 is equal to 1.

1 and 64 are positive integers.

Therefore, the expression of 256^-3/4 in the a/b fraction form is equal to 1/64.

The given question is incomplete, I answer the question in general according to my knowledge:

Express 256^-3/4 as a fraction. Write the fraction in the form a/b, where a and b are positive integers with no common factor greater than 1 .

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Answer:  I don't have the capability to draw images. However, I can explain how to graph the equation y = x² for the interval -3≤x≤4.

To graph the equation, we can plot a set of points by substituting values of x from the given interval into the equation and solving for y.

For example:

when x = -3, y = (-3)² = 9

when x = -2, y = (-2)² = 4

when x = -1, y = (-1)² = 1

when x = 0, y = (0)² = 0

when x = 1, y = (1)² = 1

when x = 2, y = (2)² = 4

when x = 3, y = (3)² = 9

when x = 4, y = (4)² = 16

We can plot these points on a coordinate plane, and then connect them with a smooth curve.

The graph of y = x² for the interval -3≤x≤4 will be a parabola that opens upward and its vertex is located at (0,0) point.

The x-coordinates of the vertex are in the center of the inte

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

the slope is Δy/Δx

0-(-5) =5

6-5 =1

slope is 5

If the x-intercepts of a function are 2 and 5, then f(2) = ____0___. and f(5) = ____0____. The x-intercepts, 2 and 5, are called the _zeros_ of the function.

The x-intercepts of a function y = f(x) are the values of x such that the graph of the function intercepts the x-axis, that means that are the values of x such that f(x)= 0

Then if 2 and 5 are x-intercepts of the function, then:

f(2) = 0

f(5)  =0

The x-intercepts are allso called the zeros of the function.

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Step-by-Step Explanation:

3rd term (a3) = -6

12th term (a12) = -3

We know, nth term of an AP = a1 + (n - 1)d, where d = common difference

a3 = a + (3-1)d = a + 2d = -6...(I)

a12 = a + (12-1)d = a + 11d = -3..(II)

Subtracting (II) from (I), we have

2d - 11d = -6 + 3

=> -9d = -3

=> d = 1/3

Therefore, a + 2×1/3 = -6

=> a + 2/3 = -6

=> a = -6-2/3 = -20/3

Therefore, 18th term

= a + (18-1)d

= -20/3 + 17/3

= -3/3

= -1

Answer:

-1

Hope it helps.

If you have any query, feel free to ask.

Answer:

there is no value of v that makes quadrilateral PQRS a parallelogram.

Step-by-step explanation:

Hopefully this helps, may be wrong so...

A quadrilateral is a parallelogram if and only if opposite angles are equal. Therefore, in order for quadrilateral PQRS to be a parallelogram, angle P must be equal to angle S, and angle Q must be equal to angle R. From the given information, we know that:

angle P = v + 38°

angle S = 8v - 56°

angle Q = v + 98°

angle R = 6v - 72°

To find the value of v that makes quadrilateral PQRS a parallelogram, we must set angle P equal to angle S and angle Q equal to angle R:

v + 38° = 8v - 56°

v + 98° = 6v - 72°

Solving for v in the first equation:

v + 38° = 8v - 56°

-7v = -94°

v = 13.428571428571429

Solving for v in the second equation:

v + 98° = 6v - 72°

-5v = -170°

v = 34

We can see that both values of v do not match, therefore there is no value of v that makes quadrilateral PQRS a parallelogram.

A quadrilateral is a parallelogram if and only if the opposite angles are equal. In this case, the opposite angles are P and S, and Q and R.

Therefore, for the quadrilateral PQRS to be a parallelogram, we must have:

v+38° = 8v-56° and v+98° = 6v–72°

Solving the first equation for v:

v+38° = 8v-56°

38 = 7v

v = 38/7

Now we use this value of v to check if the second equation is true:

v+98° = 6v–72°

(38/7) +98 = 6(38/7) - 72

98 = -34

As we can see, the second equation is not true, so the value of v = 38/7 doesn't make quadrilateral PQRS a parallelogram.

No value of v exists that would make quadrilateral PQRS a parallelogram, as the opposite angles are not equal in this case.

In a parallelogram, opposite sides are equal in length, which can be used to calculate the length of AE. AB is equal to 26 and BD is equal to 20, so AE is equal to 6.

In contrast to a parallelogram, which has equal sides on both sides and diagonals that bisect each other, a rhombus has equal sides on all four sides and diagonals that cross at 90 degrees.

The length of each side is the same. A rhombus has equal opposite angles. At a 90° angle, the diagonals split in half.

In a parallelogram, opposite sides are equal in length. Therefore, we can use this fact to calculate the length of AE in the given parallelogram.

Since AB is equal to 26 and BD is equal to 20, we can set up the equation:

26 = AE + 20

Subtract 20 from both sides of the equation to solve for the length of AE:

26 - 20 = AE

6 = AE

Therefore, AE is equal to 6.

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Step-by-step explanation:

given = y = 6x-6 .

therefore ,

=) -3(6x-6)+8x=18 - ( from given ) .

=) -18x+18+8x=18 .

=) -10x=18-18 .

=) -10x = 0 .

=) x = 0/10 = 0.

therefore ,

y=6(0)-6 .

= -6 .

therefore , x = 0 & y = -6 .

[ it takes so much time to write and solve so plzzz => ]

Answer: s squared.s2.sigma i think

Step-by-step explanation:

No, the data provided in the link does not allow us to infer that the mean number of commercials watched during the game is different from 16.

To test the hypothesis that the mean number of commercials watched is different from 16, we would need to perform a statistical hypothesis test. The level of significance (10%) would be used to determine the critical value(s) for the test statistic, which would then be used to make a decision about the null hypothesis (that the mean number of commercials watched is equal to 16).

Without the results of such a test, it is not possible to make a conclusion about the difference between the mean number of commercials watched and 16.

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