The recipe calls for 4 cups of strawberries for every 2 cups of whipped cream. Write this comparison as a ratio. A. 4:2 B. 2:4 C. 4>2 D.

Answer:

20 liters

Explanation:

To find out how much jam Devon would jar if she spent four days making jam, we must first find out how much jam she makes in one day. In order to do that, we must divide how many liters of jam she makes in three days by the amount of days it took her to make it (three days).

15 liters ÷ 3 days = 5 liters per day

So, Devon jars 5 liters of jam per day.

Now that we found out how much jam she makes in a day, let's find out how much jam she makes in four days. To do that, we must multiply the amount of jam she makes in a day by four days.

5 liters × 4 days = 20 liters

Therefore, Devon will jar 20 liters of jam if she spends four days making jam.

Answer:

on ixl its 48.

Step-by-step explanation:

Answer:

Your x-intercepts are (1, 0) and (5, 0)

Step-by-step explanation:

Factor out the expression:

[tex]y =x^{2} -6x +5[/tex] factors out to [tex]y = (x-1) * (x-5)[/tex]

Because this factored out form is now in intercept form, we can solve that the two intercepts are (1, 0) and (5, 0).

Answer:

The coordinates are (5 ,0) and (1 ,0)

Answer is given below with explanations.

Step-by-step explanation:

[tex]to \: find \: the \: x \: intercepts \: of \: the \: parabola \: \\ defined \: by \: {x}^{2} - 6x + 5 = y \\ let \: y = 0 \\ then \\ {x}^{2} - 6x + 5 =0 \\ by \: factorization \\ (x - 5)(x - 1) = 0 \\ x - 5 = 0 \: \: (or )\: x - 1 = 0 \\ x = 5 \: \: ( or) \: x = 1[/tex]

We want ti express the intercepts as two ordered pairs (y = 0)

Then the coordinates are (5 ,0) and (1 ,0)

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

Answer:

b. 9h

Step-by-step explanation:

Volume of the cube = a*a*a

Volume of the cube = 3*3*h = 9h

But in reality for cube it should be 3*3*3= 27, because of the all edges of a cube are equal.

Answer: Conjecture

Step-by-step explanation:

An unproven statement which is based on only observations is a statement you believe is true based on inductive reasoning and you are able to draw a conclusion from it through a certain pattern. This is known as conjecture.

Conjecture is drawn from a personal opinion about something you notice in which you are able to draw a reasonable conclusion without experiment or without a proof.

So, the best option is conjecture.

Answer:

y=-1/2+2

Step-by-step explanation:

the y intercept is 2

Its negative because the slope is going down

1/2 because down 1 right 2

Answer: B

Step-by-step explanation:

You are given the function

p(x) = √5x+7

Let p(x) = y then,

Y = √5x+7

To find the inverse of a function, you need to interchange x and y and make y the subject of formula. That is,

X = √5y+7

Square both sides

X^2 = 5y + 7

Make y the subject of formula

5y = x^2 - 7

Y = ( x^2 - 7 ) / 5

the correct answer is B

Answer:

x = 30

Step-by-step explanation:

4x+2x=180

6x=180

x=30

The value of x is 30.

Angles are the figure formed by the intersection of two lines or rays by sharing a common point. This point is called the vertex of the angle.

Angles are usually measured in degrees or radians.

Given is a line EB where another line FA is intersected at the point A on the line EB.

Angles formed on a line is supplementary.

The angles EAF and BAF are the angles formed on a line.

∠EAF + ∠BAF = 180°

4x + 2x = 180°

6x = 180°

x = 180° / 6

x = 30

Hence the value of the x in 4x and 2x is x = 30.

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Answer:

Prime

Step-by-step explanation:

x^2 + 64 cannot be factored any further

It is prime because it cannot be factored further.

Prime numbers have two elements, themselves and 1, however, those are the trivial factors that every variety has. Due to the fact they can not be factored in every other manner, we are saying that they cannot be factored.

Prime factorization is a way of expressing a variety of as a made from its prime elements. A high wide variety is a number that has precisely two elements, 1 and the variety itself. For instance, if we take the range 30. We realize that 30 = 5 × 6, however, 6 isn't always a high wide variety.

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The approximate area of the unshaded region under the standard normal curve is 0.8641.

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics.

The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The degree to which something is likely to happen is basically what probability means.

We have to find the area under the standard normal curve equals the z probability.

So, P = 1 - P(1 < z <2)

P = 1 - [ P(z<2)- P(z<1)]

As, the standard normal probability

P (z<1)= 0.8413

P(z<2) = 0.9772

So,  P(1 < z <2)

= 0.9772 - 0.8413

= 0.1359

and, P = 1 - P(1 < z <2)

= 1 - 0.1359

= 0.8641

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Answer:

answer is B. 77 percent means 77/100

Have a great day

Step-by-step explanation:

brainliest please!!!!

Answer:

B

Step-by-step explanation:

Answer:

a)  f(x) = x² -9

function is an even function

b)  g(x) = |x -3|

function is an even function

c) f(x)= x / x²-1

function is  odd function

d) g(x) = x + x²

Given function is not an even not odd function

This function is neither even or odd

Step-by-step explanation:

Explanation:-

a) Given f(x) = x² -9

Even function

If f(-x) = f(x) , then the function is even function.

f(-x) = (-x)² -9

      =  x² -9

      = f(x)

f(-x) = f(x)

∴ Given function is an even function

b)

Given g(x) = |x -3|

Even function

If g(-x) = g(x) , then the function is even function.

g(-x) = |-(x-3)|

      = |x-3|

g(-x) = g(x)

∴ Given function is an even function

c)

odd function

If f(-x) =- f(x) , then the function is odd function.

f(-x) = [tex]f(-x) = \frac{-x}{(-x)^{2}+1 } = \frac{-x}{x^{2}+1 } = - f(x)[/tex]

      = -f(x)

f(-x) = -f(x)

∴ Given function is odd function

d)

If g(-x) = g(x) , then the function is even function.

g(x) = x + x²

g(-x) =  -x + (-x)²

     = - (x - x²)

This is not either even or odd function

∴ Given function is neither function

a)  f(x) = x² -9

function is an even function

b)  g(x) = |x -3|

function is an even function

c) f(x)= x / x²-1

function is  odd function

d) g(x) = x + x²

Given function is not an even not odd function

This function is neither even or odd

Here, we have,

a) Given f(x) = x² -9

Even function

If f(-x) = f(x) , then the function is even function.

f(-x) = (-x)² -9

     =  x² -9

     = f(x)

f(-x) = f(x)

∴ Given function is an even function

b)

Given g(x) = |x -3|

Even function

If g(-x) = g(x) , then the function is even function.

g(-x) = |-(x-3)|

     = |x-3|

g(-x) = g(x)

∴ Given function is an even function

c)

odd function

If f(-x) =- f(x) , then the function is odd function.

f(-x) = -x/(-x)²-1

     = -f(x)

f(-x) = -f(x)

∴ Given function is odd function

d)

If g(-x) = g(x) , then the function is even function.

g(x) = x + x²

g(-x) =  -x + (-x)²

    = - (x - x²)

This is not either even or odd function

∴ Given function is neither function.

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Answer:

The fifth term is 27

Step-by-step explanation:

Given:

[tex]T_1 = 1[/tex]

[tex]T_2 = 3[/tex]

Required

What is the fifth term?

Using the condition stated in the question;

[tex]T_5 = T_4 * T_3[/tex]

The values of [tex]T_4\ and\ T_3[/tex] are not known; so, we need to solve for both of them

[tex]T_3 = T_2 * T_1[/tex]

Substitute [tex]T_1 = 1[/tex] and [tex]T_2 = 3[/tex]

[tex]T_3 = 1 * 3[/tex]

[tex]T_3 = 3[/tex]

[tex]T_4 = T_2 * T_3[/tex]

Substitute [tex]T_2 = 3[/tex] and [tex]T_3 = 3[/tex]

[tex]T_4 = 3 * 3[/tex]

[tex]T_4 = 9[/tex]

Recall that

[tex]T_5 = T_4 * T_3[/tex]

[tex]T_5 =9* 3[/tex]

[tex]T_5 = 27[/tex]

Hence, the fifth term is 27

Answer:

I would say the 2-cup container is the best buy.

Step-by-step explanation:

Value for money and 2 cups are enough.

Answer:

Given

Hope it helps!

Step-by-step explanation:

Consider triangle ABD and CDB,

The congruent parts are:

AB= BC (given)

AD= CD (given)

BD= BD (common side)

Therefore the triangles are congruent by SSS (side side side) congruence rule.

The triangles are congruent by SSS (side side side) congruence postulate.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed. Then that means two triangles are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.

Given that AB = BC = CD = DA. we need to prove that triangle ADB is congruent to triangle CDB.

Let's Consider triangle ABD and CDB,

Here, Triangles ADB and CDB have a common side at BD.

The congruent parts are:

AB= BC (given)

AD= CD (given)

BD= BD (common side)

Since the three sides of the triangles are congruent.

Therefore, the triangles are congruent by SSS (side side side) congruence postulate.

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Answer:

median a= 65 b= 75 c=68

This shows the median of each fat content of each restaurant showing that restaurant c is closer to that of 'restaurant a ' than a is to 'restaurant b' and near to 1/7 lower than that of restaurant b which shows they are all highly skewed with each other upon their graph.

The measures of spread start with 55 to 72 for 'restaurant a' where the upper and lower quartiles  are 70-60 showing a distribution 10-17 into the whisker plot.

Compared to restaurant b which shows a measure of spread start with 65 to 90 for 'restaurant b' where the upper and lower quartiles are 85 - 68 into the whisker plot and show a spread of 3 in the left exterior and 5 spread in the right exterior to the upper quartile. So in comparison to restaurant a that restaurant b has a greater spread in the interquartile range = 15  where restaurant a =10.

For the outer quartile the comparison to restaurant a is twice as small meaning restaurant a is greater by over double and shown as   53 <a < 60 which when showing both outer quartiles we can use the amounts being 7 and 70<a<72 = 2

and show closed dots on equality line number line separately showing a<-7  and a>2 for each outer exterior quartile. For restaurant b this shows opposite similar equalities 65<b< 68 = b>-3 and   82<b<89 = b>7

So the differences are smaller for b for left side by 4 and larger for b by 5 up on the right side.

We compare both to restaurant c and find c =   60<c<61 = c>-1 and 70<c<71 = c>1 so the differences are that the outer quartile for c through the other quartiles = -2> c < -6 . This shows how smaller c is compared to a and b outer quartiles). We can also prove that while the outer quartiles are much more smaller for c than a and b we cna prove that c actually has an inner quartile more similar to c and closer distribution of b as the median is more closer for a and c where b has a greater output for median as restaurant b has the higher fat content and greater distribution within the inner quartiles over all.

Summary findings Restaurant c outer quartile is moderately skewed as they show -1 -0.5  on the left side and 1-0.5 on the right side. Restaurant a has a closer median inner quartile to c and closer distribution of inner distribution of c. It's output outer quartile distribiution is a distribution that is higher than b but a smaller inner quartile compared to b, when this happens then the distribution spread shows less range and fewer products to account for.

So i think restaurant b has the higher fat content to its menu.

Where restaurant a must be the healthiest as it holds the lowest range and larger gap is such range for healthier food.ie) when compared to the others. 

Meanings of what we are asked.

In a box and whisker plot: the ends of the box are the upper and lower quartiles, so the box spans the interquartile range. the median is marked by a vertical line inside the box. the whiskers are the two lines outside the box that extend to the highest and lowest observations.

Skewness refers to distortion or asymmetry in a symmetrical bell curve, or normal distribution, in a set of data. If the curve is shifted to the left or to the right, it is said to be skewed. Skewness can be quantified as a representation of the extent to which a given distribution varies from a normal distribution.

As a general rule of thumb:

If skewness is less than -1 or greater than 1, the distribution is highly skewed.

If skewness is between -1 and -0.5 or between 0.5 and 1, the distribution is moderately skewed.

If skewness is between -0.5 and 0.5, the distribution is approximately symmetric.

Step-by-step explanation:

check the photo and if u feel I made any mistakes pls do let me know

Answer:

Step-by-step explanation:

Given the expression [tex]\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }[/tex]for x ≠ 0, y ≠ 0 to get the equivalent expression we will have to simplify the given expression.

[tex]\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\[/tex]

The correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Answer:

It’s b

Step-by-step explanation:

Answer:

m = 15    OR      m = 0

Step-by-step explanation:

=> [tex]m^2 - 15m = 0[/tex]

=> Taking m common

=> [tex]m(m-15) = 0[/tex]

Either,

m = 0    OR     m = 15

Answer:

m₁ = 0

m₂ = 15

Step-by-step explanation:

m² - 15m = 0

m(m - 15) = 0

m₁ = 0

m - 15 = 0 => m₂ = 15

Answer: 55.9% appex

Step-by-step explanation:

The probability that a data value is between 55 and 63 is 54.7%.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

We can use the standard normal distribution to solve this problem by standardizing the values of 55 and 63:

z1 = (55 - 62) / 4 = -1.75

z2 = (63 - 62) / 4 = 0.25

Using a standard normal distribution table (or a calculator), we can find the area under the curve between z1 and z2:

P(-1.75 < z < 0.25) = 0.5466

Rounding to the nearest tenth of a percent, we get:

0.5466 ≈ 54.7%

Therefore,

The probability that a data value is between 55 and 63 is 54.7%.

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1)Obtuse Triangle: A triangle with one obtuse angle.

2)Acute Triangle: A triangle where all three angles are acute.

3)Equiangular Triangle: A triangle where all the angles are congruent.

4)Isosceles Triangle: A triangle with at least two congruent sides.

5)Equilateral Triangle: A triangle with three congruent sides

Answer:

Option d is the answer

(X + 8)(x2 – 3)

Step-by-step explanation:

x3 + 8x2 – 3x – 24

= (X + 8)(x2 – 3)

Check all the options by expansion

(a)

(x-8)(x2 - 3)

=x3-3x-8x2+24

(b)

(X + 8)(x2 + 3)

=X3+3x+8x2-24

(c)

(x-8)(x2 + 3)

=X3+3x-8x2-24

(d)

(X + 8)(x2 – 3)

=X3-3x+8x2-24

Answer:

b

Step-by-step explanation:

Answer:

(4,-1)

Step-by-step explanation:

I took the quiz

Answer:

4

Step-by-step explanation:

A and B meet at G which is 50 moving up the degree ould still stay 50

Answer:sit and reach test

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

Attached below is the graph of [tex]x\geq 2[/tex]. Since x=2 is a vertical line, everything shaded are the x values larger or equal to 2. Hope this helps!

Answer:

a=-18

b=7

c=27

Step-by-step explanation:

Answer:

230 - 151 + 180 + (43 - 12) = 290

Step-by-step explanation:

Use PEMDAS.

Evaluate the expression in the parentheses:

230 - 151 + 180 + (43 - 12)

43 - 12 = 31

230 - 151 + 180 + 31

Add and Subtract From Left to Right:

230 - 151 + 180 + 31

79 + 180 + 31

259 + 31

290

None of the given options are correct.

Answer:

18

Step-by-step explanation:

Evaluate the expression: 23^(0) - 15^(1) + 18^(0) + (43 - 12) = 18

Answer:

[tex]a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\[/tex]

Step-by-step explanation:

We are to factorize the expression [tex]a^{3y} + 1[/tex] completely. To do this, we will apply the expression below;

The expression can be rewritten as [tex]a^{3y} + 1^{3}[/tex]

To factorize the expression, we need to first factorize [tex](a^{y}+1 )^{3}[/tex] first

[tex](a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\[/tex]

The we will make [tex]a^{3y} + 1^{3}[/tex] the subject of the formula as shown;

[tex](a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3} = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\[/tex]

[tex](a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\[/tex]

[tex]a^{3y} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\[/tex]

[tex]a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\[/tex]

This last result gives the expansion of the expression

Answer:

The x-int.s are (2, 0) and (4, 0) so the midpoint will be (3, 0).

Answer:

Step-by-step explanation: