Answer:
Power
Explanation:
Power, by definition, is the rate of doing work (aka, work with respect to time).
arrange the values according to magnitude
1.8 X 10^5
4.3 X 10^-2
8.4 X 10^-6
9.0 X 10^-6
59000
Answer:
[tex]59000[/tex]
[tex]1.8\times 10^5[/tex]
[tex]4.3\times 10^{-2}[/tex]
[tex]9.0\times 10^{-6}[/tex]
[tex]8.4\times 10^{-6}[/tex]
Explanation:
The given numbers are
[tex]1.8\times 10^5=18000[/tex]
[tex]4.3\times 10^{-2}=0.043[/tex]
[tex]8.4\times 10^{-6}=0.0000084 [/tex]
[tex]9.0\times 10^{-6}=0.000009[/tex]
[tex]59000[/tex]
The arrangement of the numbers from largest to smallest is
[tex]59000[/tex]
[tex]1.8\times 10^5[/tex]
[tex]4.3\times 10^{-2}[/tex]
[tex]9.0\times 10^{-6}[/tex]
[tex]8.4\times 10^{-6}[/tex].
A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
the following using the energy/work formulae only:
1.The kinetic energy at the top of the cliff
2.The total mechanical energy at the top of the cliff
3.The kinetic energy of the Rock half way down 4.the speed of the Rock half way down
5.The speed of the Rock as it hits the ground
Answer:
this is the answer......
New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in the range of 30-300 GHz. What are the free-space wavelengths that correspond to this frequency range
Answer:
It corresponds to 1mm-10 mm range.
Explanation:
Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:[tex]v = \lambda * f (1)[/tex]
Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:[tex]\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)[/tex]
[tex]\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)[/tex]
What is an example of a secondary group?
A. the attendees of a video-gaming conference
B. the employees of Coca-Cola Corporation
C. the members of a family
D. the teachers from the science department
Answer:(D)The teachers from the science department
Explanation:I took the quiz
Two forces whose resultant is 100newton are perpendicular to each other. If one of them makes an angle of 60newton with the resultant. Calculate it magnitude
Answer:
100 N
Explanation:
Given that,
Two forces whose resultant is 100newton are perpendicular to each other.
If one of them makes an angle of 60newton with the resultant.
[tex]F_1=100\times \sin60=86.60\ N[/tex]
and
[tex]F_2=100\times \cos60=50\ N[/tex]
The magnitude of force,
[tex]F=\sqrt{F_1^2+F_2^2} \\\\F=\sqrt{86.6^2+50^2} \\\\F=99.99\ N[/tex]
or
F = 100 N
So, the magnitude of force is 100 N.
What is your average velocity after going 15 meters east followed by 20 meters
west in 10 seconds?
Answer:
0.5 m/s
Explanation:
Velocity = displacement/time taken
going 15 meters east and then 20 meters west gives a displacement of 5 meters.
Velocity v = 5/10
= 0.5 m/s
A tow truck applies a force of 2600 N on a 2100 Kg car for a period of 9 seconds. What is the magnitude of the change in the car’s momentum?
Answer:
P = 23400 [kg*m/s]
Explanation:
Momentum is defined as the product of force by the time of force duration. It can be determined by means of the following equation.
[tex]P=F*t[/tex]
where:
P = momentum [kg*m/s]
F = force = 2600 [N]
t = time = 9 [s]
Now replacing:
[tex]P=2600*9\\P=23400 [kg*m/s][/tex]
Which of the following is NOT an argument for showing that the Earth must be round: a. during an eclipse of the Moon, the shadow of the Earth is always seen to be round b. when ships travel a large distance away, we see their hulls disappear first and their masts disappear last c. the height of the North Star changes as we travel to different latitudes d. photographs of the Earth from space always show a round body e. the Sun is seen blocking different constellations in the course of a year Submit Your Answer
Answer: The correct option is option E (the Sun is seen blocking different constellations in the course of a year.
Explanation:
The earth, which is one of the planets of the solar system that supports life, is shperical in shape. The spherical ( round) shape of the earth is marked by the intervening highlands and oceans on its surface.
Evidence to show that the earth is shperical are:
--> The Lunar eclipse: During an eclipse of the Moon, the shadow of the Earth is always seen to be round.
--> Ships Visibility: When ships travel a large distance away, we see their hulls disappear first and their masts disappear last.
-->Altitude of Polaris (North Star): The height of the North Star changes as we travel to different latitudes. That is ,increases as you move toward the North pole, or decreases as you move toward the equator.
--> Aerial photographs: Photographs of the Earth from space always show a round body.
The statement that doesn't prove that the earth is spherical in shape is (the Sun is seen blocking different constellations in the course of a year). The sun is seen in front of stars blocking different constellation in a year because the earth orbits round the sun in a year and not that it is shperical in shape.
Which property of the wave makes it-(C)
the loudest? Choose the correct answer
Low amplitude o
High amplitude o
Low frequency O
High frequency O
Answer:
low amplitude hope it will help you
importance of choke coil?
Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.
Explanation:
6)
A flower pot weighing 42.0 N is hung above a window by three ropes, each
making an angle of 22.o with the vertical, as shown. What is the tension in
each rope supporting the flower pot?
220
Answert
Answer: 14.5 N
Explanation: NEED SCRATCH PAPER: A flower pot weighing 42.0 N (newtons) is hung above a window by three ropes, each making an angle of 15.0 degrees with the vertical. What is the tension in each rope supporting the flower pot?
✓ 14.5 N
found it on the internet?
if a object has a mass of 20g and a volume of 3.5cm3 what is the density
Answer:
5.71 g/cm^3
Explanation:
Recall that density is defined as:
density = mass/volume
therefore in our casewe have:
density = 20 g / 3.5 cm^3 = 5.71 g/cm^3
Which of the following is NOT a characteristic of noble gases? *
very reactive
colorless
odorless
unreactive
A woman lives on the eighth floor of an apartment building. She works in a high-rise office building 6.5 blocks away from her apartment on the same street. Her office is on the 14th floor. Assume each story of her apartment building is 4.0 m, each story of her office building is 5.5 m, and a block is 146.6 m long.
Required:
a. Sketch her path.
b. Estimate the distance she travels to work.
c. Find the magnitude of her displacement.
Answer:
b) d = 997.9 m , c) D = (952.9 i ^ +45 k ^) m , D = 953.6 m and θ = 2.7º
Explanation:
In this exercise we must add the distance traveled, remembering that the displacement is a vector and the distance a scalar.
a) The displacement scheme is the woman walks in her building A to descend to the lower floor 4.0 m, we assume that this includes the vertical displacement, until reaching the street level, the displacement is vertical in this part.
Being on the street, she travels the 6.5 blocks to reach the building where she works, they indicate that each block is 146.6 m, this movement is horizontal.
Upon reaching building B, she goes up to his office on the 14th floor where she travels 5.5m on each floor, it is assumed that the distance to go up to the upper floor is included, this displacement is vertical
b and c) Let's find the distance traveled and the displacement
in building A
Zₐ = 8 * 4.0
Zₐ = -32.0 m k ^
the vector k ^ indicates that the displacement is vertical and the negative sign that it is descending
on the street
[tex]X_{ab}[/tex] = 6.5 146.6
X_{ab} = 952.9 m i ^
the vector i ^ indicates that the displacement is the x-axis, we assume that the axis is in the direction of the displacement
in building B
[tex]Z_{b}[/tex] = 14 * 5.5
Z_{b} = 77 m k ^
displacement in the vertical axis and in the positive direction
now we calculate the distance traveled,
d = Zₐ + X_{ab} + Z_{b}
d = -32 + 952.9 + 77
d = 997.9 m
note that this value is a scalar
Let's calculate the displacement,
Z axis
[tex]Z_{total}[/tex] = Zₐ + Z_{b}
Z_{total} = -32 + 77
Z_{total} = 45 m k ^
X axis
X_{total} = X_{ab}
X_{total} = 952.9 m i ^
we can give the result in two ways
a) D = X_total i ^ + Z_total k ^
D = (952.9 i ^ +45 k ^) m
b) in module form and angles
Let's use the Pythagorean theorem
D² = [tex]X_{total}^2[/tex] + [tex]Z_{total}^2[/tex]
D = √(952.9² + 45²)
D = 953.6 m
We use trigonometry
tan θ = Z / X
θ = tan⁻¹ (Z / X)
θ = tan⁻¹ (45 / 952.9)
θ = 2.7º
this angle is measured from the positive side of the x axis towards the z axis
The average velocity of a tennis ball is measured during serving and found to be 216 km/hr.
Calculate the time elapsed between hitting the ball and meeting the ground if the distance covered by the ball during that interval is 20m
PLEASE ANSWER WITH EXPLANATION :)
Answer:
The time between hitting the ball and meeting the ground is [tex]t=0.33\: s[/tex]
Explanation:
We have a semi parabolic motion here. We know that the initial speed 216 km/h or 60 m/s in the x-direction.
So we can use the following equation:
[tex]v=\frac{\Delta x}{\Delta t}[/tex]
[tex]60=\frac{20}{t}[/tex]
[tex]t=\frac{20}{60}[/tex]
[tex]t=0.33\: s[/tex]
hope it helps you!
Which of the moon's properties prevents it from being pulled inward by Earth?
O gravity
O inertia
O shape
O structure
Answer:
O inertia
Explanation:
The moon's property that prevents it from being pulled inward by the Earth is called it's inertia.
Every object in the universal space have gravitational force of attraction to one another due to their masses.
An inertia is the reluctant of a body to move or the tendency of it to remain in constant motion.
Inertia entails the property of objects to remain at rest or continue in uniform motion.
As the force of gravity acts between the earth and the moon, inertia keeps a body in constant position.
Tim’s cow is anemic. The cow is lacking which type of nutrient?
Answer:
Iron deficiency
Explanation:
or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.
What are homophones?
words that are spelled incorrectly several times in one paper
words that are spelled exactly as they sound
words that have different meanings depending on how they are used
words that have the same sound but different spellings and meaning
Answer:
words that have the same sound but different spellings and meaning
Explanation:
Homophones are generally words that sound the same but have different spellings and even meaning.
For example the words new and knew are homophones.
They have the same sound when pronouncing but their meaning is different.
Also, the words bawl and ball are homophones.
We see that both words have very similar pronunciation but their meanings are completely different.
A 25 kg box on a horizontal frictionless surface is moving to the right at a speed of 5.0 m s. The box hits and remains attached to one end of a spring of negligible mass whose other end is attached to a wall. As a result, the spring compresses a maximum distance of 0.60 m. (a) i. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maximum compression. Indicate whether the work done by the spring is positive, negative, or zero.
Answer:
Explanation:
Work done by the spring is negative .
Work done by force F creating displacement d is given by the following expression .
Work = F x d
Both force and displacement are vector quantity .
When direction of force and direction of displacement is same , work is positive . When direction of force and direction of displacement is opposite , work is negative .
When spring is compressed , it exerts a restoring or opposing force in a direction opposite to the direction of displacement of box . Hence here force is opposite to displacement . Restoring force acts opposite to displacement . Hence work done by spring on box is negative .
what is phyical quantity
Answer:
physical quantity
Explanation:
All quantity in term of which laws of physics are described and can be measured is called physical quantity
PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
The first person with the right answer gets to be a brainlest
In the attachment there is a density column where there is colour
Question: tell me why is the red at the bottom of the density column if it is the least dense
Explanation: That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.
58) Two balls, A and B are simultaneously projected from the top
of a building at 10 mis upwards & 20 m/s downwards respectively. Find
out the separation btwn them 3 sec after projection.
Answer:
90 m
Explanation:
For ball A::
The equation of a ball moving upwards is given by the formula:
s = ut - (1/2)gt²
where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) - (1/2) * 10 * 3²
s = 30 - 45
s = -15 m
The negative sign means the object travels in the opposite direction. Hence s = 15 m
For ball B::
The equation of a ball falling downwards is given by the formula:
s = ut + (1/2)gt²
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) + (1/2) * 10 * 3²
s = 30 + 45
s = 75 m
Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m
An electric eel develops a 450 V potential difference between its head and tail. The eel can stun a fish or other prey by using this potential difference to drive a 0.80 A current pulse for 1.0 ms. What are (a) the energy delivered by this pulse and (b) the total charge that flows
Answer:
(a) The energy delivered by the pulse is 0.36 J
(b) the total charge that flows is 0.8 mC
Explanation:
Given;
potential difference of the electric eel, V = 450 V
current flow, I = 0.8 A
time of current flow, t = 1.0 ms = 1.0 x 10⁻³ s
(a) The energy delivered by the pulse is calculated as;
E = Pt
where;
t is time
P is power developed = IV
E = (IV)t
E = IVt
where;
I is the current
V is the potential difference
E = 0.8 x 450 x 1.0 x 10⁻³
E = 0.36 J
(b) the total charge that flows is calculated as;
Q = It
where;
I is the current
t is the time
Q = 0.8 x 1.0 x 10⁻³
Q = 0.0008 C
Q = 0.8 mC.
Which observation is the best evidence that some colors of visible light are
being absorbed in this photo?
A. The man's head is distorted under the water.
B. The top of the man's head appears disconnected.
C. The shape of the man's arm is clearly seen underwater.
D. The snorkel in the man's mouth appears yellow.
Answer:
D-The snorkel in the mans mouth appears yellow
Explanation:
Answer D is the only example related visible light being absorbed.
What is my name?:
I am a god
I am a guardian of the sun
I am used to measure heat.
Answer:
Apllo?
Explanation:
3.7. A dog searching for a bone walks 3.50 m south, then 8.20 m at an angle 23.1 degrees north of east, and finally 15.0 m west. (a) What is the magnitude of the dog’s total displacement? (b) What is the direction of the dog’s total displacement where directly east is taken as zero degrees and counter-clockwise is positive?
Answer:
Explanation:
We shall represent displacement of dog in vector form , in terms of i , j , i representing east and j representing north .
Dog travels 3.5 m south .
Displacement D₁ = - 3.5 j
then dog travels 8.2 m , 23.1 degree north of east
Displacement D₂ = 8.2 cos23.1 i + 8.2 sin23 j
D₂ = 8.2 cos23.1 i + 8.2 sin23.1 j
= 7.54 i + 3.22 j
Third displacement
D₃ = - 15i
Total displacement = D₁ + D₂ + D₃
= - 3.5 j + 7.54 i + 3.22 j -15i
= - 7.46 i - 0.28 j
Magnitude of displacement = √ ( 7.46² + .28²)
= √(55.65 + .08 )
= 7.46 m
b ) Direction of displacement
If Ф be angle , displacement makes with west direction
TanФ = .08 / 55.65 = .00143
Ф = .082 degree south of west or almost west .
From east , this angle = 180 + .082 = 180.082 , counterclockwise .
can someone give me a 5 day fitness plan with all the reps and sets for 3 only and 4 exercises a day
Answer:
Classic 5 Day Split
Day 1 – Chest
Day 2 – Legs
Day 3 – Rest
Day 4 – Back
Day 5 – Arms
Day 6 – Shoulders
Day 7 – Rest
Upper Lower Push Pull Legs
Day 1 – Upper
Day 2 – Lower
Day 3 – Rest
Day 4 – Push
Day 5 – Pull
Day 6 – Legs
Day 7 – Rest
5 Day Split Variation
Day 1 – Chest
Day 2 – Legs & Shoulders
Day 3 – Back
Day 4 – Biceps & Triceps
Day 5 – Core & Cardio
Day 6 – Rest
Day 7 – Rest
Explanation:
Which of the following is a pure substance?
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radial component of the acceleration (in m/s2) on the edge the wheel?
Answer:
[tex]a=368.97\ m/s^2[/tex]
Explanation:
Given that,
Initial angular velocity, [tex]\omega=0[/tex]
Acceleration of the wheel, [tex]\alpha =7\ rad/s^2[/tex]
Rotation, [tex]\theta=14\ rotation=14\times 2\pi =87.96\ rad[/tex]
Let t is the time. Using second equation of kinematics can be calculated using time.
[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s[/tex]
Let [tex]\omega_f[/tex] is the final angular velocity and a is the radial component of acceleration.
[tex]\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s[/tex]
Radial component of acceleration,
[tex]a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2[/tex]
So, the required acceleration on the edge of the wheel is [tex]368.97\ m/s^2[/tex].
The radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s²
Using ω² = ω₀² + 2αθ, we find the final angular speed after 14 revolutions, ω where
ω₀ = initial angular speed = 0 rad/s (since the wheel starts from rest), α = angular acceleration = 7 rad/s and θ = number of revolutions = 14 = 14 rev × 2π rad/rev = 87.965 rad.So, substituting the values of the variables into the equation, we have
ω² = ω₀² + 2αθ,
ω² = (0 rad/s)² + 2 × 7 rad/s² × 87.965 rad.
ω² = 0 rad²/s² + 1231.504 rad²/s²
ω² = 1231.504 rad²/s²
ω = √(1231.504 rad²/s²)
ω = 35.09 rad/s
We know that the radial acceleration a = rω² where
r = radius of wheel = diameter of wheel/2 = 60 cm/2 = 30 cm = 0.30 m and ω = final angular acceleration of wheel = 35.09 rad/s.So, substituting the values of the variables into the equation, we have
a = rω²
a = 0.30 m × (35.09 rad/s)²
a = 0.30 m × 1231.504 rad²/s²
a = 369.45 m/s²
So, the radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s².
Learn more about radial acceleration here:
https://brainly.com/question/25243603
What are the 4 basic skills of Badminton. Explain.
Answer:
As the service marks the start of every rally and subsequently dictates its flow, it is a crucial aspect of the game to get right in badminton.
These are the four main types of services in badminton and most can be executed with either your forehand or backhand.
1. Low serve
This low serve is almost a gentle tap over the net with the shuttle, with the aim of flying just over the net, yet falling just over the front line of his service court. It must not be too high or predictable, otherwise it would be easy for your opponent to do an outright smash or net kill.
2. High serve
The high serve is a powerful strike upwards with the shuttle, that aims to travel a great distance upwards and fall deep at the rear end of the court.
Although it is a strong serve and the popular choice of beginner players, its a serve that isn't so easy to disguise especially since you're using a forehand grip. Your opponent will already expect the shuttlecock to land at the back of the court.
Do remember that shuttlecocks have to fall within the corresponding service areas and this is different in singles and doubles.
3. Flick serve
This flick serve is also played upwards but at a much lesser altitude. It is most common for players to use their backhand to execute the flick serve and the trajectory is lower as this grip has less power.
The whole point of the backhand flick serve is deception, by mixing your serves up and making it look like you're doing a low serve. For this reason, serving with your backhand is thus very popular with competitive players.
It becomes hard for your opponent to predict if you are going to do a flick or a low serve as your stroke will look exactly the same until the point of contact.
4. Drive Serve
This is an attacking serve that is used by top badminton players like Lin Dan. The idea is to hit the shuttle directly at your opponent, limiting their return options and catching them off guard, winning you easy points. It's a good change of pace but it is also risky as if your opponent is prepared, he could just smash the shuttlecock back at you.
This serve is executed with your forehand through underarm action and following through. The shuttle should be dropped a bit sideways rather than in front of your body and hit flatter.
Now that you've determined the type of serve you want to make, here are a four tips on how to execute these serves well.
1. Keep your feet still
During the service, some part of both your feet must be in contact with the ground for it to be a legal serve.
2. Disguise your shots
Make sure your stroke is the same up to the point of contact with the shuttle. This will make your serve possible to predict only at the last possible second. Advanced players can try to trick their opponent by making it deliberately look like you're leaning back and about to do a high serve when you're really going to do a low serve.
3. Observe your opponents position
Is your opponent leaning towards the back already anticipating a high serve to the rear-court? In that case, you may want to execute a low serve to catch him off-guard. Always be aware of the position of your opponent. Try to imagine what he's expecting and do the opposite to gain an advantage.
4. Mix up your serves
Using just one type of service will make you too easy to predict. Make sure you incorporate at least two types of serves into your play. Once you've mastered the basic high and low serves, you can learn the flick and drive serves to add more dimension to your play.
In a nutshell, executing a service well allows you to start the rally strong and dictate its flow.
Explanation:
I hope it's help