The quotient of y and 3

Answer:

49.8 nautical miles

Step-by-step explanation:

Recall that speed = distance/time

Time = 2hours

Speed = 12knots and 16 knots respectively

D = speed×time

D1 = 12×2 = 24

D2 = 16×2 = 32

Using the 'cosine rule' we have:

a^2 = b^2+c^2-2bc cos Θ

Where a =?

b =24

c = 32

Θ = 125°

a² = 24² + 32² - 2(24)(32)cos125°

a^2 = 576+1024 - 1536cos125°

a² = 1600 - 1536(-0.57357)

a² = 1600+881.0134

a² = 2481.0134

Then, a² = 2481.013406

a =√2481.013406

Hence, a = 49.8 nautical miles

In this exercise we must use the knowledge about triangles to calculate the distance that a ship will travel, in this way we find that:

49.8 nautical miles

First, remember the formula for distance, which is:

[tex]Speed = distance/time[/tex]

And knowing that the data reported in the exercise are:

So putting the values ​​informed in the distance formula, we have:

[tex]D = speed*time\\D_1 = 12*2 = 24\\D_2 = 16*2 = 32[/tex]

Using the 'cosine rule' we have:

[tex]a^2 = b^2+c^2-2bc cos \theta[/tex]

Find the a, will have:

[tex]b =24 \ \ \ c = 32 \ \ \ \theta = 125\\a^2 = 24^2 + 32^2 - 2(24)(32)cos125\\a^2 = 576+1024 - 1536cos125\\a^2 = 1600 - 1536(-0.57357)\\a^2 = 1600+881.0134\\a^2 = 2481.0134\\a=49.8[/tex]

See more about triangles at brainly.com/question/25813512

Answer:

A.50-n=44, 6 shorts borrowed

Step-by-step explanation:

If her sister borrowed n shorts, that means Shelly now has n less shorts. Since her amount of shorts is 50, then 50-n must equal how many shorts she has now, meaning 50-n=44. Solving the equation we get n=6. This means that her sister borrowed 6 shorts.

Answer:

A

Step-by-step explanation:

50 minus the shorts Shawnie borrowed (n) equal to 44

Answer:

0.1/4-3/20=1/40-6/40=-1/8 200% of this is -1/4

Step-by-step explanation:

This shows that  200 percent of (0.020(5/4) + 3 ((1/5) - (1/4))) is -2.75

Given the expression as shown in the question:

[tex]200\% \ of \ [0.020(\frac{5}{4} )+3(\frac{1}{5}- \frac{1}{4} )][/tex]

Expand the expression in the square bracket using the distribution law as shown:

[tex]=200\% \ of \ [0.020(\frac{5}{4} )+3(\frac{4-5}{20} )]\\=200\% \ of \ [0.020(\frac{5}{4} )+3(\frac{-1}{20} )]\\=200\% \ of \ [0.020(\frac{5}{4} )-(\frac{3}{20} )]\\=200\% \ of \ [0.020(1.25 )-\frac{3}{20}]\\=\frac{200}{100} \times [0.025-0.15]\\=2 \times [-0.125]\\=-2.75[/tex]

Hence the correct answer to the expression is -2.75.

Learn more here: https://brainly.com/question/19383460.

Using the Pythagorean theorem

Hypotenuse = sqrt( 11^2 + 7^2)

= sqrt( 121 + 39)

= sqrt( 160)

= 12.694

Answer:

[tex]\boxed{\sf \ \ x=6 \ \ }[/tex]

Step-by-step explanation:

Hello,

BMN and NPC are two similar triangles so

[tex]\dfrac{BM}{MN}=\dfrac{NP}{PC}\\\\ \dfrac{10-x}{x}=\dfrac{x}{15-x}\\\\<=>(15-x)(10-x)=x^2\\\\<=>150-25x+x^2=x^2\\\\<=>25x=150\\\\<=>x=6[/tex]

espero que esto ayude

Answer: See bolded below

Step-by-step explanation:

With the given f(x) and g(x) given, we can directly plug them in to solve. The inverse is to replace the y with x and x with y, then solve for y.

A. f(g(-4))=143

g(-4)=3(-4)+1

g(-4)=-12+1

g(-4)=-11

With g(-4), we plug that into f(x) to find f(g(-4)).

f(-11)=(-11)²-2(-11)

f(-11)=121+22

f(-11)=143

------------------------------------------------------------------------------------

B. 9x²-1

(3x+1)²-2(3x+1)

(9x²+6x+1)-6x-2

9x²-1

------------------------------------------------------------------------------------

C. g⁻¹(x)=(x-1)/3

x=3y+1

x-1=3y

(x-1)/3=y

Answer:

Step-by-step explanation:

y + 8 = 0(x - 0)

y + 8 = 0

y = -8

Answer:

Option B

Step-by-step explanation:

The null hypothesis for a chi-square goodness of fit test states that the data are consistent with a specified distribution.

While the alternative hypothesis states that the data are not consistent with a specified distribution.

In this case study, the test is for a nose distribution. Thus the null hypothesis would be that the population has a normal distribution.

Answer:

(x + 2) ^2 (x - 2) ^ 2 so A is the answer.

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

[tex]-\frac{8}{3}[/tex]

Step-by-step explanation:

Given

[tex]\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}[/tex]

Required

Simpify

The very first step is to take LCM of the given expression

[tex]\frac{-10 -4 - 2}{6}[/tex]

Perform arithmetic operations o the numerator

[tex]-\frac{16}{6}[/tex]

Divide the numerator and denominator by 2

[tex]-\frac{16/2}{6/2}[/tex]

[tex]-\frac{8}{3}[/tex]

The expression can't be further simplified;

Hence, [tex]\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}[/tex] = [tex]-\frac{8}{3}[/tex]

Answer:

the slope is 8

Step-by-step explanation:

The coefficient of x,  "m"  is the slope in the slope-intercept form:

y = mx + b

Answer: option D on edge 2020

Step-by-step explanation:

if you reverse the formula for mean, then you just insert the numbers and you have your answer

Answer:

30x - 18

Step-by-step explanation:

6(5x - 3)

Apply the distributive property.

6(5x) + 6(-3)

30x + - 18

Answer:

30x - 18 is your final answer

Answer:

3

Step-by-step explanation:

To begin with notice that  

        [tex]\displaymode{ \tan(x) = \frac{30}{10 + 30\cot(y)} }[/tex]

From that equation you get that

10 tan(x)  +  30tan(x) cot(x) = 30

therefore

tan(x) + 3 tan(x) cot(x) = 3

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.214, 3.386)

95% confidence interval for the population mean PEF for children in LPG households

= (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

Significance level for 95% confidence interval

= (100% - 95%)/2 = 2.5% = 0.025

z (0.025) = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.30

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 755

σₓ = (1.20/√755) = 0.0436724715 = 0.04367

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.30 ± (1.960 × 0.04367)

CI = 3.30 ± 0.085598

95% CI = (3.214402, 3.385598)

95% Confidence interval = (3.214, 3.386)

For the children in the LPG households

Sample mean = 4.25

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.75

N = sample size = 750

σₓ = (1.75/√750) = 0.063900965 = 0.063901

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.25 ± (1.960 × 0.063901)

CI = 4.25 ± 0.125246

95% CI = (4.12475404, 4.37524596)

95% Confidence interval = (4.125, 4.375)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.30

n₁ = 755

s₁ = 1.20

μ₂ = 4.25

n₂ = 750

s₂ = 1.75

σ = √[(1.20²/755) + (1.75²/750)] = 0.07740

z = (3.30 - 4.25) ÷ 0.07740 = -12.27

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -12.27, at 0.01 significance level, with a one tailed condition) = < 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 755

σₓ = (0.5/√755) = 0.0182

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.0182)

CI = 2.30 ± 0.03567

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.375)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

Answer:

The answer is option D.

Hope this helps you

Answer:

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

2¹³

13 x 13

Step-by-step explanation:

We simply find numbers that can multiply to 26 and write out the multiplication to get our answer.

Answer:

B) (x^2-2x)/(2x+6)

Step-by-step explanation:

When dividing fractions, it's just like multiplying the reciprocal of the second fraction : x/y divided by z/w = x/y * w/z.

We use that and we get (x-2)/(x+3) * x/2. we simplify and get x(x-2)/2(x+3). So Our answer is B

Answer:

Step-by-step explanation:

The vertex can be located most easily by completing the square of

f(x) = -X^2 - 2x - 1 (which is equivalent to -(x^2 + 2x + 1).  The latter expression can be rewritten as -(x + 1)^2, which indicates that the x-coordinate of the vertex is -1.  The corresponding y-value is 0.  Vertex is at (-1, 0).

The function is increasing for x < -1 and decreasing for x > -1.

The domain of the function is "all real numbers."

The range is (-infinity, 0)

Answer:

620 comic books

2480 / 4 is 620.

620 x 3 is 1860.

1860 + 620 is 2480.

Done!

Answer:

2.26 repeating

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

hope this helpes

be sure to give brainliest

Answer: [tex]2\sqrt{1+tant}+C[/tex]

Step-by-step explanation:

To integrate means to find the antiderivative of the function. For this problem, we can use u-substitution.

[tex]\int\limits {\frac{dt}{cos^2t\sqrt{1+tant} } } \[/tex]

Let's first use our identities to rewrite the function. Since [tex]\frac{1}{cosx} =secx[/tex], we can use this identity.

[tex]\int\limits {\frac{sec^2t}{\sqrt{1+tant} } } \,[/tex]

[tex]u=\sqrt{1+tant}[/tex]

[tex]du=\frac{sec^2t}{2\sqrt{1+tant} } dt[/tex]

Now that we have u and du, we can plug them back in.

[tex]\int\limits {2} \, du[/tex]

[tex]\int\limits{2} \, du=2u[/tex]

Since we know u, we can plug that in.

[tex]2\sqrt{1+tant}[/tex]

This may seem like the correct answer, but we forgot to add the constant.

[tex]2\sqrt{1+tant}+C[/tex]

Answer:

Yeah, you got the answer right.

Step-by-step explanation:

Answer:

one side is [tex]\sqrt{10}[/tex] and other 3[tex]\sqrt{10}[/tex]

in decimal one side = 3.16

other side =  9.48

Step-by-step explanation:

In right angle

if two sides containing right angle is a and b and h is hypotenuse then

by Pythagoras theorem

a^2 + b^2 = h^2

__________________________________

let one side be x

given

One of the triangle’s legs is 3  times the length of the other leg

then other leg = 3x

given h = 10 cm

applying Pythagoras theorem

[tex]a^2 + b^2 = h^2\\x^2 + (3x)^2 = 10^2\\x^2 + 9x^2 = 100\\10x^2 = 100\\x^2 = 100/10 = 10\\x = \sqrt{10}[/tex]

Thus, one side is [tex]\sqrt{10}[/tex] and other 3[tex]\sqrt{10}[/tex]

[tex]\sqrt{10} = 3.16\\[/tex]

thus, in decimal one side = 3.16

other side = 3.16*3 = 9.48

Answer:

  (f-g)(x) = -x² +4x +6

Step-by-step explanation:

We assume you want to find (f -g)(x).

 [tex](f-g)(x)=f(x)-g(x)=(4x+1)-(x^2-5)\\\\\boxed{(f-g)(x)=-x^2+4x+6}[/tex]

Answer:

P(Chase) > P(Ava)

700 > 587

Therefore, Ava's claim is wrong!

On day 14, Chase's bacteria population will be greater than Ava's bacteria population.

Step-by-step explanation:

Please refer to the attached image.

Ava's bacteria population is modeled by the following equation.

[tex]$ b(t) = 200(1+0.08)^t $[/tex]

Where t is time in days and b(t) is the population of the bacteria after t days.

The graph represents the population of Chase's bacteria.

Ava claims that on day 14, she will have more bacteria than Chase.

Let us compare the population of both bacteria.

Chase bacteria population when t = 14 days:

From the graph, the population is approximately 700 at t = 14 days

P(Chase) ≈ 700

Ava bacteria population when t = 14 days:

at t = 14 days

[tex]b(t) = 200(1+0.08)^t \\\\ b(14) = 200(1.08)^{14} \\\\ b(14) = 200 (2.93719)\\\\ b(14) = 587.44[/tex]

So, the population is approximately 587 at t = 14 days

P(Ava) ≈ 587

P(Chase) > P(Ava)

700 > 587

Therefore, Ava's claim is wrong!

On day 14, Chase's bacteria population will be greater than Ava's bacteria population.

Answer:

D

Step-by-step explanation:

Trust

Answer:

Yup P is the right one having 62.26%

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

We can set it up as

P = 33/53

Q = 20/48

R = 54/90

S = 44/83

This is because we are calculating the percent of yellow birds in the total amt. of birds in a specified park.

Now we calculate =>

P = 33/53 = around 0.62

Q = 20/48 = around 0.416

R = 54/90 = 0.6

S = 44/83 = around 0.53

We find that Park P has the greatest percentage and -->

Thus, Park P is our answer and yes, you are correct.

Answer:

Step-by-step explanation:

We would apply the future value which is expressed as

FV = C × [{(1 + r)^n - 1}/r]

Where

C represents the yearly payments of the young professional.

FV represents the amount of money

in your account at the end of 40 years.

r represents the annual rate.

n represents number of years or period.

From the information given,

r = 4% = 4/100 = 0.04

C = $76000

n = 40 years

Therefore,

FV = 76000 × [{(1 + 0.04)^40 - 1}/0.04]

FV = 76000 × [{4.8 - 1}/0.04]

FV = 76000 × 95

FV = P7220000