The products of a reaction are NaCl and H2O. What does the law of conservation of matter reveal about the reactants in the reaction? A. At least some of the reactants will include NaCl and H2O. B. The reactants will contain only Na, Cl, O, and H in some amounts. C. Na, Cl, O, H, and three other elements were the reactant elements. D. The reactants will have one Na, one Cl, one O, and two H atoms.

Answer:

3.5 g CO2

Explanation:

A hummingbird emits up to 3.5 grams of CO2 a day.

Equation:7.9 x 10‒2mol CO2x (44.01 g CO2/ 1 mol CO2)

=3.5 grams

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Answer:

FROM the magnetic point of view, phosphorus is an extremely interesting

substance because of its allotropic modifications. The ordinary forms are

the yellow (or white) and the red varieties. X-ray investigations indicate

that probably yellow phosphorus is analogous with the cubic forms of antimony and arsenic; and red phosphorus with monoclinic antimony and

arsenic (Mellor, 1928). The conclusions of different workers on the structure of red phosphorus are not in agreement. There is also Bridgman's black

phosphorus which is probably hexagonal (Linck and lung, 1925). Natta

and Passerini (1930) have studied the crystal structure of white phosphorus.

This substance when condensed at the temperature of liquid ammonia is

cubic. Atomic positions however are yet undetermined. Another and noncubic form is obtained by condensation at liquid-air temperatures. It is

thus clear that most likely white phosphorus is cubic in structure with a

probable superposition of another lattice.

The evidence from Raman effect also points to the same conclusion.

Bhagavantam (1930) investigated the Raman effect of white phosphorus in

the solid state. The characteristic frequencies obtained by him are 607, 468

and 374. Since the phosphorus molecule is known to contain 4 atoms,

Bhagavantam (1930) has shown that the tetrahedral structure fits the results

satisfactorily since such a structure would give only three frequencies. But

for the particular law of forces adopted, the frequencies should have the

ratio 2: 2: 1 but the observed frequencies deviate considerably.

Phosphorus is a really intriguing element. because of the allotropic changes to the material.

Red phosphorus is likely akin to monoclinic antimony, while yellow phosphorus is probably similar to the cubic forms of antimony and arsenic.

There is disagreement among the findings of many researchers regarding the structure of red phosphorus. Additionally, Bridgman's black It is presumably hexagonal, phosphorous (Linck and lung, 1925). Natta and Passerini (1930) have investigated the white phosphorus crystal structure.

Condensed from this material at liquid ammonia temperature is cubic. However, the locations of the atoms are still unknown. Condensation at liquid air temperatures yields a different, noncubic shape.

Therefore, Phosphorus is a really intriguing element. because of the allotropic changes to the material.

To learn more about phosphorus, refer to the link:

https://brainly.com/question/4622631

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Answer:

Jeweler B = more accurate

Jeweler A = more precise

Error:

0.008, 0

% error :

0.934% ; 0

Explanation:

Given that:

True mass of nugget = 0.856

Jeweler A: 0.863 g, 0.869 g, 0.859 g

Jeweler B: 0.875 g, 0.834 g, 0.858 g

Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864

Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556

Accuracy = closeness of a measurement to the true value

Accuracy = true value - official measurement

Jeweler A's accuracy :

0.856 - 0.864 = - 0.008

Jeweler B's accuracy :

0.856 - 0.856 = 0.00

Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.

However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.

Error:

Jeweler A's error :

0.864 - 0.856 = 0.008

% error =( error / true value) × 100

% error = (0.008/0.856) × 100% = 0.934%

Jeweler B's error :

0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)

% error = 0%

Answer:

To find the number of molecules first find the number of moles.

number of moles (n) = mass / molar mass (M)

then use the formula

N = n × L

where n = number of moles

N = number of entities

L = Avogadro's constant = 6.02 × 10^23entities to find the number of molecules

A. 4.9 g H2O

m = 4.9g

M = (2*1)+(16×1) = 2 + 16 = 18g/mol

n = 4.9/18 = 0.272mol

N = 0.272 × 6.02 × 10^23

= 1.6374*10^23 molecules of H2O

B. 54.4g of N2

m = 54.4g

M(N2) = 14×2 = 28g/mol

n = 54.4/28 = 1.942mol

N = 1.942 * 6.02*10^23

= 1.1690*10^24 molecules of N2

C. 89 g CCI4

m = 89g

M(CCl4) = 12 + (35.5 × 4) = 154g/mol

n = 89/154 = 0.577mol

N = 0.577 × 6.02 × 10^23

= 3.473*10^23 molecules of CCl4

D. 11 g C6H12O6

m = 11g

M(C6H12O6) = (12×6)+(12×1)+(16×6) =

180g/mol

n = 11/180 = 0.0611mol

N = 0.0611 × 6.02×10^23

= 3.678*10^22 molecules of C6H12O6

Hope this helps