the overall management of the availability, usability, integrity, and security of data used in an enterprise is called ?

Answers

Answer 1

Answer:

Data Governance

Explanation:

Data governance is a government organization which allows the users to access the shared data.

This is achieved as the Data governance involves the management, integrity, usability, availability and security.

Data governance plays an important role in IT industries and business practices so that business can work more efficiently. The governance involves selecting a team, discover data quality and data security.

Thus, Data governance is the correct answer.

Answer 2

Answer:

ate/kuya poca please

21. What is the best explanation of ATP utilization and production?

A. ATP is being recycled from the process glycolysis, undergo oxidation process and later it is being remade during

Krebs cycle

B. ATP is used to reduced carbon molecule to produce oxaloacetate and used for the bulk reproduction of ATP

during electron transport chain

C. ATP is used during energy investment phase to harvest the energy stored in the molecule 2,3 – carbon molecule

during the energy harvesting phase

D. ATP is adenosine triphosphate that has 3 phosphate groups attached and it is being reduced into Adenosine

diphosphate after losing one phosphate group in its molecule

22. The best description on the role of oxygen during respiration is ________.

A. Oxygen is used to phosphorylate ADP to ATP

B. Oxygen is used to oxidize carbon dioxide to form glucose

C. Oxygen is utilized to add carbon in carbon dioxide as a by-product of cellular respiration

D. Oxygen is used to oxidize glucose molecule to form ATP—the energy needed by the body

23. Where are the 36 ATP come from during cellular respiration?

A. 2 from glycolysis, 2 from oxidation of pyruvate and 32 from Krebs cycle

B. 2 from glycolysis, 2 from Krebs cycle and 32 from electron transport chain

C. 2 from glycolysis, 2 from oxidation of pyruvate and 32 from electron transport chain

D. 2 from oxidation of pyruvate, 2 from Krebs cycle and 32 from electron transport cha


Related Questions

The inception of cavitation​

Answers

Answer:

The overview of the given question is described in the explanation segment below.

Explanation:

Cavitation inception or emergence happens whenever the localized temperature decreases far enough underneath the saturated or dissolved vapor pressure, a quantity determined by the thermal strength or conductivity of the fluid beyond a certain point (temperature).To respond to induce cavitation emergence, the cavitation "bubbles" usually allow a layer on which they could be nucleated.

A completely reversible heat pump produces heat at a rate of 300 kW to warm a house maintained at 24°C. The exterior air, which is at 7°C, serves as the source. Calculate the rate of entropy change of the two reservoirs and determine if this heat pump satisfies the second law according to the increase of entropy principle

Answers

Answer:

Entropy generation rate of the two reservoirs is approximately zero ([tex]\dot S_{gen} = 9.318 \times 10^{-4}\,\frac{kW}{K}[/tex]) and system satisfies the Second Law of Thermodynamics.

Explanation:

Reversible heat pumps can be modelled by Inverse Carnot's Cycle, whose key indicator is the cooling Coefficient of Performance, which is the ratio of heat supplied to hot reservoir to input work to keep the system working. That is:

[tex]COP_{H} = \frac{\dot Q_{H}}{\dot W}[/tex]

The following simplification can be used in the case of reversible heat pumps:

[tex]COP_{H,rev} = \frac{T_{H}}{T_{H} - T_{L}}[/tex]

Where temperature must written at absolute scale, that is, Kelvin scale for SI Units:

[tex]COP_{H, rev} = \frac{297.15\,K}{297.15\,K-280.15\,K}[/tex]

[tex]COP_{H, rev} = 17.479[/tex]

Then, input power needed for the heat pump is:

[tex]\dot W = \frac{\dot Q}{COP_{H,rev}}[/tex]

[tex]\dot W = \frac{300\,kW}{17.749}[/tex]

[tex]\dot W = 16.902\,kW[/tex]

By the First Law of Thermodynamics, heat pump works at steady state and likewise, the heat released from cold reservoir is now computed:

[tex]-\dot Q_{H} + \dot W + \dot Q_{L} = 0[/tex]

[tex]\dot Q_{L} = \dot Q_{H} - \dot W[/tex]

[tex]\dot Q_{L} = 300\,kW - 16.902\,kW[/tex]

[tex]\dot Q_{L} = 283.098\,kW[/tex]

According to the Second Law of Thermodynamics, a reversible heat pump should have an entropy generation rate equal to zero. The Second-Law model for the system is:

[tex]\dot S_{in} - \dot S_{out} - \dot S_{gen} = 0[/tex]

[tex]\dot S_{gen} = \dot S_{in} - \dot S_{out}[/tex]

[tex]\dot S_{gen} = \frac{\dot Q_{L}}{T_{L}} - \frac{\dot Q_{H}}{T_{H}}[/tex]

[tex]\dot S_{gen} = \frac{283.098\,kW}{280.15\,K} - \frac{300\,kW}{297.15\,K}[/tex]

[tex]\dot S_{gen} = 9.318 \times 10^{-4}\,\frac{kW}{K}[/tex]

Albeit entropy generation rate is positive, it is also really insignificant and therefore means that such heat pump satisfies the Second Law of Thermodynamics. Furthermore, [tex]\dot S_{in} = \dot S_{out}[/tex].

The rate of entropy change of the two reservoirs is; 9.318 * 10⁻⁴ kW/K and it satisfies second law of thermodynamics

What is the rate of entropy?

The formula for Coefficient of Performance is;

COP = T_H/(T_H - T_L)

Where;

T_H = 24°C = 297.15 K

T_L = 7°C = 280.15 K

Thus;

COP = 297.15/(297.15 - 280.15)

COP = 17.479

Input power is;

Input power needed for the heat pump is:

W' = Q'/COP

We are given; Q' = 300 kW

Thus;

W' = 300/17.479

W' = 16.902 kW

From first law of thermodynamics, we can deduce that;

Q_L = Q_H - W'

Thus;

Q_L = 300 - 16.902

Q_L = 283.098 kW

From second law of thermodynamics, the rate of entropy generation is;

S_gen = (Q_L/T_L) - (Q_H/T_H)

S_gen = (283.098/280.15) - (300/297.15)

S_gen = 9.318 * 10⁻⁴ kW/K

Read more about Entropy at; https://brainly.com/question/15022152

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