If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?
Answer:
3200kg
Explanation:
F=ma
16000=5m
m=3200kg
Hope this helps!
The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.
It is given that:
If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons
As we know,
Newton's second law:
F = ma
Here F is the force acting on an object.
m is the mass of the object
a is the acceleration of the object.
a = 5 m/s²
F = 16,000 N
m = 3200kg
16000 = 5m
3200 kg
Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
Learn more about the mass here:
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A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?
Whoever answers will get the Brainliest.
Answer:
Explanation:
Given height of lamp from the ceiling = 2.6m
mass of the lamp = 3.8kg
acceleration due to gravity = 9.81m/s²
As the body falls to the ground, it falls under the influence of gravity.
Gravitational potential energy = mass*acc due to gravity * height
Gravitational potential energy = 3.8*2.6*9.81
Gravitational potential energy = 96.923 Joules
b) Kinetic energy = 1/2 mv²
m = mass of the body (in kg)
v = velocity of the body (in m/s²)
To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]
[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]
Since mass = 3.8kg
[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]
c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s
A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car's average velocity?
Answer:
v = -4 m / s
Explanation:
The average speed of a body is defined by the distance traveled in a given time interval
v = (x₂ -x₁) / (t₂ -t₁)
in this case the end point is x₂ = -10 m and the start point is x₁ = 10 m, the negative sign is because the point is below the reference that can be considered as zero point
let's calculate
v = (-10 - 10) / 5
v = -20 / 5
v = -4 m / s