Answer:
(a) the frequency of the lowest note the piccolo can sound is 571.7 Hz
(b) the distance between adjacent antinodes is 5.72 cm
Explanation:
(a)
Given;
length of piccolo, L = 30 cm = 0.3 m
the speed of sound in air is 343 m/s
The wavelength of a pipe open at both ends, for the first harmonic is given;
L = A → N + N → A
L = λ / 4 + λ / 4
L = λ / 2
λ = 2L
λ = 2 x 0.3 = 0.6 m
The fundamental frequency (lowest frequency) is given by;
f₀ = v / λ
f₀ = (343 / 0.6)
f₀ = 571.7 Hz
(b)
Given;
highest note, f = 3000 Hz
the distance between adjacent antinodes is given by;
[tex]d = \frac{v}{2f}\\\\ d = \frac{343}{2*3000}\\\\ d = 0.0572 \ m\\\\d = 5.72 \ cm[/tex]
In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 36 μA current, due to the flow of electrons. Part A What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?
Answer:
n = 2.25 x 10¹⁴ electrons/s
Explanation:
The amount of electric current is defined as the electric charge passing through an area per unit time. Hence:
I = q/t
where,
I = Current
q = amount of charge
t = time interval
but,
q = ne
therefore,
I = ne/t
where,
n = no. of electrons
e = charge on single electron = 1.6 x 10⁻¹⁹ C
t = 1 s (for electrons passing per second)
I = Current = 36 μA = 3.6 x 10⁻⁵ A
Therefore,
3.6 x 10⁻⁵ A = n(1.6 x 10⁻¹⁹ C)/1 s
n = (3.6 x 10⁻⁵ A)/(1.6 x 10⁻¹⁹ C)
n = 2.25 x 10¹⁴ electrons/s
An unstrained horizontal spring has a length of 0.34 m and a spring constant of 180 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.024 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges. g
Answer:
a
[tex]q_1 = -1.389 *10^{-5} \ C [/tex] , [tex]q_2 = -1.389 *10^{-5} \ C [/tex]
OR
[tex]q_1 = 1.389 *10^{-5} \ C [/tex] , [tex]q_2 = 1.389 *10^{-5} \ C [/tex]
b
[tex]q_1 = 1.389 *10^{-5} \ C [/tex] and [tex]q_2 = 1.389 *10^{-5} \ C [/tex]
Explanation:
Generally the force exerted on the string is mathematically represented as
[tex]F = k * e[/tex]
substituting values 180 N/m for k and 0.024 m for e
[tex]F = 180 * 0.024[/tex]
[tex]F = 4.32 \ N[/tex]
This force can also equivalent to the electrostatic force between the charges i.e
[tex]F = k * \frac{q^2}{ r^2}[/tex]
substituting [tex]9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex] for k and ( 0.34 + 0.024 = 0.364 m) for r we have
[tex] 4.32= 9*10^{9} * \frac{q^2}{ (0.364)^2}[/tex]
[tex]q = \sqrt{1.929 *10^{-10}}[/tex]
[tex]q = 1.389 *10^{-5} \ C [/tex]
Given the spring was stretched it means that the force between the charges is a repulsive for which tell us that both charge are of the same sign thus the possible algebraic signs of the charges are
[tex]q_1 = -1.389 *10^{-5} \ C [/tex] , [tex]q_2 = -1.389 *10^{-5} \ C [/tex]
OR
[tex]q_1 = 1.389 *10^{-5} \ C [/tex] , [tex]q_2 = 1.389 *10^{-5} \ C [/tex]
half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value after
Answer:
44 years
Explanation:
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is time,
and T is the half life.
0.25 A₀ = A₀ (½)^(t / 22)
0.25 = (½)^(t / 22)
t / 22 = 2
t = 44
44 sec is half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value.
What is half-life?The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. A given radioactive isotope's half-life is constant; it is unaffected by external factors and independent of the isotope's starting concentration.
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is time,
and T is the half life.
0.25 A₀ = A₀ (½)^(t / 22)
0.25 = (½)^(t / 22)
t / 22 = 2
t = 44 sec
44 sec is half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value.
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what does Aristotle say about the good life?Does it still stand contemporary world?
Answer:
Explanation:
Aristotle was a philosopher and a scientist who believed good life for humans is ultimately about happiness and this happiness can be achieved by virtue or high moral standards.
In the contemporary world, generally, everyone's ultimate goal is still to be happy but achieving this feat by being virtuous or having a high moral standard is fading away in our contemporary world as people just want to be happy by any means possible. Some amass wealth illegally just to be happy while others do things that are considered immoral (by the society) to be happy hence people still want a good life but not a way described by Aristotle.
Aristotle stated that a good life is about happiness and this can only be achieved through high moral standards.
The statement that a good life is about happiness and this can only be achieved through high moral standards doesn't stand anymore in the contemporary world. People now engage in immoral things as long as it brings them happiness. Even though the ultimate goal of people is to be happy, there are different ways that people go about in achieving this. There are some people who get their wealth illegally just to ensure that they are happy. This source of happiness is gotten through vices.In conclusion, Aristotle's statement about the good life is not applicable in the contemporary world anymore.
Read related link on:
https://brainly.com/question/21792802
what is machinery
............
What does this picture show?
A. Good accuracy, poor precision
B. Poor accuracy, good precision
C. Good accuracy, good precision
D. Poor accuracy, poor precision
Suppose that a certain battery produces a voltage of 1.55V without a load connected (open circuit) and a current of 500mA when shorted. According to these specifications, if we were to model this as an ideal voltage source in series with a source resistance, what should the source voltage and internal resistance be? Justify your answer
Answer:
Explanation:
Let the internal resistance be r .
Since in open circuit the volt is 1.55 V , this will be the source voltage .
Source voltage = 1.55
If external resistance be R .
1.55 / (R + r ) = .500
R + r = 3.1 ohm
So sum of internal resistance and external resistance will be 3.1 ohm.
Which term describes the tendency of an object to resist changes in motion?
A) reaction
B) force
C) inertia
D) acceleration
Answer:
inertia
Explanation:
It is easier to open the lid of a can using a spoon why?
Answer:
It depends on how you use the spoon...
if you are keeping one end of the spoon and pressing other end, the force you provide is supported by the force due to gravity... Hence it is easy to open this way :)
F + G ... Where F is the force you provide and G is the force due to gravity.
How does deploying slats or slots on an airfoil affect CL max and Stall AOA?
a) Stall AOA increases, CL max increases.
b) Stall AOA decreases, CL max increases.
c) Stall AOA increases, CL max decreases.
d) Stall AOA decreases, CL max decreases.
Answer: a. Stall AOA increases, CL max increases.
Explanation:
Deploying slats or slots on an airfoil affect CL max and Stall AOA by increasing Stall AOA and also increasing CL max.
It should be noted that the coefficient of lift CL would rise through the use of slots due to increase in boundary later energy. The slots also leads to delay of stall by through increase in AOA.
When a gas undergoes an isothermal process, there is
(A) no heat added to the gas.
(B) no work done by (or on) the gas.
(C) no change in the temperature of the gas.
(D) no change in the volume of the gas.
(E) no change in the pressure of the gas.
Answer:
(C) no change in the temperature of the gas.
Explanation:
isothermal process of a gas, can result to compression of the gas or expansion of the gas at a constant temperature (ΔT = 0).
For isothermal gas expansion, work is done in reducing the pressure of the gas by increasing its volume at a constant temperature. The change in the internal energy of this process is zero (ΔU = 0).
For isothermal gas compression, work is done in decreasing the volume of the gas by increasing its pressure at a constant temperature. The change in the internal energy of this process is also zero (ΔU = 0).
Therefore, when a gas undergoes an isothermal process, there is no change in the temperature of the gas.
a) How long (in ns) does it take light to travel 1.0 m in a vacuum?
b) What distance does light travel in water, glass, cubic zirconia during the time it travels in 1.0 m vacuum?
Answer:
a
[tex]t = 3.33 \ ns[/tex]
b
i [tex]D_w =0.75 \ m [/tex]
ii [tex]D_g =0.67 \ m [/tex]
iii [tex]D_c =0.46 \ m [/tex]
Explanation:
Generally the time taken to travel 1 m in a vacuum is mathematically represented as
[tex]t = \frac{1}{c}[/tex]
Here c is the speed of light with value [tex]c = 3.0*10^{8} \ m/s[/tex]
So
[tex]t = \frac{1}{3.0*10^{8}}[/tex]
[tex]t = 3.33*10^{-9} \ s[/tex]
[tex]t = 3.33 \ ns[/tex]
The distance light travels in water is mathematically represented as
[tex]D_w = \frac{c}{n_w} * t[/tex]
Here n_w is the refractive index of water with value 1.333
So
[tex]D_w = \frac{3.0*10^{8}}{1.333} * 3.33*10^{-9}[/tex]
[tex]D_w =0.75 \ m [/tex]
The distance light travels in glass is mathematically represented as
[tex]D_g = \frac{c}{n_g} * t[/tex]
Here n_g is the refractive index of glass with value 1.5
So
[tex]D_g = \frac{3.0*10^{8}}{1.5} * 3.33*10^{-9}[/tex]
[tex]D_g =0.67 \ m [/tex]
The distance light travels in cubic zirconia is mathematically represented as
[tex]D_c = \frac{c}{n_g} * t[/tex]
Here n_c is the refractive index of cubic zirconia with value 2.15
So
[tex]D_c = \frac{3.0*10^{8}}{2.15} * 3.33*10^{-9}[/tex]
[tex]D_c =0.46 \ m [/tex]
An external reward is known as extrinsic motivation.
ОА.
True
OB. False
URGENT URGENT DUE SOON!!
Which statement describes a question that can guide the design of a
scientific investigation?
A. It asks about a cause-and-effect relationship between two
variables.
B. It asks about the preferred outcome of the investigation.
C. It asks about whether a controlled variable is necessary.
D. It asks about how the observations will be organized.
Answer:
A.
Explanation:
Im just guessing because it sounds like it describes a hypothesis the most and you said its urgent
what would the answer be ?
Answer:
im going between 2 of them b and c but i would have choose b
5. A projectile is fired in Earth's gravitational field with a horizontal velocity of y = 9.00 m/s.
b. How far does the projectile fall in the vertical direction in 0.550 s?
Answer:
4.13mExplanation:
Given
Horizontal velocity = 9.00m/s
time taken = 0.550 s
Required
How far does the projectile fall in the vertical direction
Using the formula for finding the maximum height of the projectile
H = U²sin²θ/2g where;
U = 9.00m/s
θ = 90° (object launched in the vertical direction)
g = 9.81m/s²
Substituting the given parameters into the formula;
H = 9²sin²90/2(9.81)
H = 81(1)/19.62
H = 81/19.62
H = 4.128 m
H ≈ 4.13m
Hence the distance that the projectile fall in the vertical direction is 4.13m
Newtons third law of motion states that if a force is exerted on an object, another force occurs that, A. is equal in speed and opposite direction
B. is equal in side an opposite in direction
C. is in the same direction and speed
D. is in the same direction and size.
Answer:
Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.
Explanation:
Newtons third law of motion states that if a force is exerted on an object, another force occurs that is equal in side an opposite in direction.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.
Newtons third law of motion states that if a force is exerted on an object, another force occurs that is equal in side an opposite in direction.
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An atom’s emission of light with a specific amount of energy confirms that
atoms must have a dense central mass surrounded by electrons at a distance.
electrons emit and absorb energy based on their position around the nucleus.
electrons can only be found within predicted areas surrounding the nucleus.
atoms are made of positive and negative charges.
The correct answer is B. Electrons emit and absorb energy based on their position around the nucleus.
Explanation:
In general, an atom's emission of photons (light) is the result of electrons, which are the negative charge particles that orbit the nucleus. Moreover, the emission of light is likely to occur if the electron is located at a specific energy level (position in the atom) and it moves to a lower level as this requires the loss of energy in the form of photons. Also, the electron can absorb the photons and as a result gain enough energy to move to a higher level. This implies the atom's emissions of light shows the relationship between electrons emitting and absorbing energy and their position or energy level.
Answer:
The correct answer is B. Electrons emit and absorb energy based on their position around the nucleus.
On edge :)
Explanation:
For any object in projectile motion, the vertical velocity is independent of gravity?
Answer:
the y axis, every moment is subjected to a vertical acceleration directed towards the center of the Earth, which is called the acceleration of gravity
Explanation:
In projectile launching, the movement is separated into two movements, one on the x-axis and the other on the y-axis, related through time.
In horizontal movement, the speed is constant, because there is no acceleration in this axis, the effect of air friction is almost always eliminated.
In the other movement on the y axis, every moment is subjected to a vertical acceleration directed towards the center of the Earth, which is called the acceleration of gravity.
This value of the eceleration of gravity is constant for small distances
compared to the radius of the Earth, for higher altitudes an expansion in beings of the distance is used, giving a linear dependence.
What was the current annual rate of inflation in 2009?
pls help !
Answer:
The 2009 inflation rate was -0.36%. The current year-over-year inflation rate (2019 to 2020) is now 0.99%
Explanation:
What is the frequency in Hz of a wave that travels at 2,500 m/s with a wavelength of 100 m?
Answer:
f = 25 Hz
Explanation:
We know that :
[tex]v = f*d\\=> f = \frac{v}{d}[/tex] where f = frequency ; v = speed & d = wavelength
Here in the question ,
Speed = 2500 m/s
Wavelength = 100 m
Using the above formula ,
Frequency = [tex]\frac{2500}{100} = 25 Hz[/tex]
What is the total electric charge of 2.5 kg of (a) electrons and (b) protons?
Answer:
a
[tex]Q_e = -4.39 *10^{11} \ C [/tex]
b
[tex]Q_p = + 2.395*10^{-8} \ C [/tex]
Explanation:
Generally the number of electron in the given mass is mathematically evaluated as
[tex]N_e = \frac{2.5}{m_e }[/tex]
Here m_e is the mass of electron with value [tex]m_e = 9.11 * 10^{-31} \ kg[/tex]
=> [tex]N_e = \frac{2.5}{ 9.11 * 10^{-31} }[/tex]
=> [tex]N_e =2.74 *10^{30} \ electrons [/tex]
The total electric charge is mathematically represented as
[tex]Q_e = N_e * e[/tex]
Here e is the charge on a single electron with value [tex]e = 1.60 *10^{-19} \ C[/tex]
So
[tex]Q_e = -2.74 *10^{30} * 1.60 *10^{-19} [/tex]
[tex]Q_e = -4.39 *10^{11} \ C [/tex]
The negative sign is because we are considering electron
Generally the number of protons in the given mass is mathematically evaluated as
[tex]N_p = \frac{2.5}{m_p }[/tex]
Here m_p is the mass of electron with value [tex]m_e = 1.67 * 10^{-27} \ kg[/tex]
=> [tex]N_p = \frac{2.5}{ 1.67 * 10^{-27} }[/tex]
=> [tex]N_p =1.497 *10^{27} \ protons [/tex]
The total electric charge is mathematically represented as
[tex]Q_p = + N_p * e[/tex]
Here p is the charge on a single proton with value [tex]p = 1.60 *10^{-19} \ C[/tex]
So
[tex]Q_p = +1.497 *10^{27} * 1.60 *10^{-19} [/tex]
[tex]Q_p = + 2.395*10^{-8} \ C [/tex]
Convert 580 g to kg.
The Answer Is - 0.58 Kilogram's
Hope This Help's
• Answer:
0.58 kg
• Explanation:
1 kg = 1000 g
580 g = 0.58 kg
Fossil fuels like gasoline or coal are examples of
Answer:
Nonrenewable Resources
Answer:
fossil fuels
Explanation:
How much work must be done to stop a 1150 kg car traveling at 120 km/h?
Answer:
The work to be done is 638,761.12 J
Explanation:
Given;
mass of the car, m = 1150 kg
velocity of the car, v = 120 km/h = 33.33 m/s
Apply work energy theorem;
W = K.E
where;
W is the work done
K.E is the kinetic energy
W = ¹/₂mv²
W = ¹/₂ (1150)(33.33)²
W = 638,761.12 J
Therefore, the work to be done is 638,761.12 J
Each insulated beaker contains equal amounts of the same fluid. The starting temperature of beaker A was 100.0 degrees Celsius and the starting temperature of beaker B was 0 degrees Celsius. At 5 minutes, the temperature of Beaker A was 82 and the temperature of Beaker B was 18. Assuming no heat was lost, what is the best estimate for the temperature of each beaker at 10 minutes?
Answer:
Correct Answer: B. Beaker A will be 72 °C and beaker B will be 28 °C.
This one is actually right!
why is evidence good for practice
Answer:
HEYO BRO! (my bad for da caps)
Explanation:
Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.
Happy to Help From, Adam
What acceleration would a 18 kg box have if we pushed it with a force of 250 N across a surface that
has a coefficient of friction of 0.8?
N
Answer:
[tex]a=0.08\ m/s^2[/tex]
Explanation:
Given that,
Mass of a box, m = 18 kg
It is pushed with a force of 250 N
The coefficient of friction is 0.8
We need to find the acceleration of the box.
Normal force acting on the box,
N = mg
M = 18 × 10
N = 180 N
The force acting on the force in terms of coefficient of friction is given by :
[tex]F=\mu mg\\\\\text{or}\\\\ ma=\mu mg\\\\a=\dfrac{\mu }{g}\\\\a=\dfrac{0.8}{10}\\\\a=0.08\ m/s^2[/tex]
So, the acceleration of the box is [tex]0.08\ m/s^2[/tex]
Please answer the question on the bottom
Answer:
the one with 2 batteries
An oil pump is drawing 44kW while pumping oil with a density of 860 kg/m3 at a rate of 0.1 m3/s. The inlet and outlet diameters of the pipe are 8cm and 12cm, respectively. If the pressure increases by 500kPa going through the pump and the motoreffi ciency is 90%, determine the mechanical efficiency of the pump
Answer:
The mechanical efficiency of the pump is 91.8 %
Explanation:
Given;
input power, p = 44 kw
density of oil, ρ = 860 kg/m³
motor efficiency, η = 90 %
inlet diameter, d₁ = 8 cm
outlet diameter, d₂ = 12 cm
volume flow rate, V = 0.1 m³/s
pressure rise, P = 500kPa
output power = motor efficiency x input power
output power = 0.9 x 44 = 39.6 kW
Thus, the mechanical input power = 39.6 kW
The mechanical output power is given by change in mechanical energy;
[tex]E = mgh + \frac{m}{2} (v_2^2 - v_1^2) \\\\E = \rho V g h + \frac{\rho V}{2} [(\frac{V_2}{\pi r_2^2} )^2 - (\frac{V_1}{\pi r_1^2})^2]\\\\E = PV + \frac{\rho V^3}{2\pi^2} [\frac{1}{ r_2^4} - \frac{1}{ r_1^4}]\\\\E = (500 *10^3)(0.1) + \frac{(860)(0.1)^3}{2\pi^2} [\frac{1}{ 0.06^4} - \frac{1}{ 0.04^4}]\\\\E = 50000 -13653.51\\\\E = 36346.48 \ W\\\\E = 36.347 \ kW[/tex]
The mechanical efficiency is given by
η = mechanical output power / mechanical input power
η = 36.347 / 39.6
η = 0.918
η = 91.8 %
Therefore, the mechanical efficiency of the pump is 91.8 %