The open-loop transfer function of a unit-negative-feedback system has the form of
G(s)H(s) = 1 / s(s+1).
Please determine the following transient specifications when the reference input is a unit step function:
(1) Percentage overshoot σ%;
(2) Peak time tp;
(3) 2% Settling time t.

Answers

Answer 1

For the given open-loop transfer function 1 / (s(s+1)), the transient specifications when the reference input is a unit step function can be determined by calculating the percentage overshoot, peak time, and 2% settling time using appropriate formulas for a second-order system.

What is the percentage overshoot?

To determine the transient specifications for the given open-loop transfer function G(s)H(s) = 1 / (s(s+1)) with a unit step reference input, we need to analyze the corresponding closed-loop system.

1) Percentage overshoot (σ%):

The percentage overshoot is a measure of how much the response exceeds the final steady-state value. For a second-order system like this, the percentage overshoot can be approximated using the formula: σ% ≈ exp((-ζπ) / √(1-ζ^2)) * 100, where ζ is the damping ratio. In this case, ζ = 1 / (2√2), so substituting this value into the formula will give the percentage overshoot.

2) Peak time (tp):

The peak time is the time it takes for the response to reach its maximum value. For a second-order system, the peak time can be approximated using the formula: tp ≈ π / (ωd√(1-ζ^2)), where ωd is the undamped natural frequency. In this case, ωd = 1, so substituting this value into the formula will give the peak time.

3) 2% settling time (ts):

The settling time is the time it takes for the response to reach and stay within 2% of the final steady-state value. For a second-order system, the settling time can be approximated using the formula: ts ≈ 4 / (ζωn), where ωn is the natural frequency. In this case, ωn = 1, so substituting this value into the formula will give the 2% settling time.

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