Given that,
Speed = 3.5 m/s
Magnetic field = 50μT
Angle = 60°
(A). We need to find the direction of magnetic force
Using formula of magnetic force
[tex]\vec{F}=q(\vec{v}\times\vec{B})[/tex]
Here, [tex](\vec{v}\times\vec{B})[/tex]= down
But , charge is negative.
So, the direction of magnetic force will be up.
(B). We need to calculate the magnetic electric field
Using formula of magnetic force
[tex]F=qvB\sin\theta[/tex]
[tex]qE=qvB\sin\theta[/tex]
[tex]E=vB\sin\theta[/tex]
Where, v = speed
B = magnetic field
Put the value into the formula
[tex]E=3.5\times50\times10^{-6}\sin60[/tex]
[tex]E=0.000151\ N/C[/tex]
[tex]E=1.5\times10^{-4}\ N/C[/tex]
Hence, (A). The direction of magnetic force is UP
(c) is correct option
(B). The magnetic electric field is [tex]1.5\times10^{-4}\ N/C[/tex]
(b) is correct option
A uniform disk, a uniform hoop, and a uniform solid sphere are released at the same time at the top of an inclined ramp. They all roll without slipping. In what order do they reach the bottom of the ramp
Answer:
sphere, disk, hoop
Explanation:
See attached file
In a Michelson interferometer, in order to shift the pattern by half a fringe, one of the mirrors at the end of an arm must be moved by:
Answer: Options not given.
The correct option is one quarter wavelengths.
Here are the options.
a. one wavelength
b. half a wavelength
c. one-quarter wavelength
d. it depends on the wavelength
e. it depends on which mirror is moved
It must be moved by one quarter wavelength
Explanation:
The standard way to use oMichelson apparatus is to first measure the wavelength of the incident light. One of the mirrors is moved nearer or farther away while observing the fringe pattern. one of the mirrors at the end of an arm must be moved by one quarter wavelength in order to shift the pattern by half a fringe,
A ballast is dropped from a stationary hot-air balloon that is at an altitude of 576 ft. Find (a) an expression for the altitude of the ballast after t seconds, (b) the time when it strikes the ground, and (c) its velocity when it strikes the ground. (Disregard air resistance and take ft/sec2.)
Answer:
a) [tex]S = \frac{1}{2}gt^2\\[/tex]b) 6secsc) 192ftExplanation:
If a ball dropped from a stationary hot-air balloon that is at an altitude of 576 ft, an expression for the altitude of the ballast after t seconds can be expressed using the equation of motion;
[tex]S = ut + \frac{1}{2}at^{2}[/tex]
S is the altitude of the ballest
u is the initial velocity
a is the acceleration of the body
t is the time taken to strike the ground
Since the body is dropped from a stationary air balloon, the initial velocity u will be zero i.e u = 0m/s
Also, since the ballast is dropped from a stationary hot-air balloon, the body is under the influence of gravity, the acceleration will become acceleration due to gravity i.e a = +g
Substituting this values into the equation of the motion;
[tex]S = 0 + \frac{1}{2}gt^2\\ S = \frac{1}{2}gt^2\\[/tex]
a) An expression for the altitude of the ballast after t seconds is therefore
[tex]S = \frac{1}{2}gt^2\\[/tex]
b) Given S = 576ft and g = 32ft/s², substituting this into the formula in (a);
[tex]576 = \frac{1}{2}(32)t^2\\\\\\576*2 = 32t^2\\1152 = 32t^2\\t^2 = \frac{1152}{32} \\t^2 = 36\\t = \sqrt{36}\\ t = 6.0secs[/tex]
This means that the ballast strikes the ground after 6secs
c) To get the velocity when it strikes the ground, we will use the equation of motion v = u + gt.
v = 0 + 32(6)
v = 192ft
5) what is the weight of a
if its weight
is 5N in moon?
body in the earth,
Answer:
Weight of object on moon is 5N ,as we know. Weight of object on moon is 1/3 the of object on earth,so
let weight of object on earth = X
5N= X/3
X = 3×5 = 15N
Hence the weight of the object on earth will
be 15N
What is the relationship between the magnitudes of the collision forces of two vehicles, if one of them travels at a higher speed?
Explanation:
The collision forces are equal and opposite. Therefore, the magnitudes are equal.
what is thermodynamic?
Answer:
Thermodynamics is a branch of physics which deals with the energy and work of a system. It was born in the 19th century as scientists were first discovering how to build and operate steam engines. Thermodynamics deals only with the large scale response of a system which we can observe and measure in experiment.
Answer:
thermodynamics is the branch of physics which deals with the study of heat and other forms energy and their mutual relationship(relation ship between them)
Explanation:
i hope this will help you :)
describe the relation among density, temperature, and volume when the pressure is constant, and explain the blackbody radiation curve
Answer:
in all cases with increasing temperature the density should decrease.
Black body radiation is a construction that maintains a constant temperature and a hole is opened, this hole is called a black body,
Explanation:
Let's start for ya dream gas
PV = nRT
Since it indicates that the pressure is constant, we see that the volume is directly proportional to the temperature.
The density of is defined by
ρ = m / V
As we saw that volume increases with temperature, this is also true for solid materials, using linear expansion. Therefore in all cases with increasing temperature the density should decrease.
Black body radiation is a construction that maintains a constant temperature and a hole is opened, this hole is called a black body, since all the radiation that falls on it is absorbed or emitted.
This type of construction has a characteristic curve where the maximum of the curve is dependent on the tempera, but independent of the material with which it is built, to explain the behavior of this curve Planck proposed that the diaconate in the cavity was not continuous but discrete whose energy is given by the relationship
E = h f
a 1000 kg car accelerates from 0 to 15 m/s in 5.0 s with negligible friction and air resistance. what is the average power delivered by the engine
Answer:
30.16 hp
Explanation:
Given :
m= 1000 kg
v=15 m/s
t=5.0 s
The average power delivered by the engine can be determined by using the given formula
[tex]Average\ power\ =\ \frac{0.5*m*v^2\ }{t}[/tex]
where m=,mass, v=velocity and t=time
Now putting the value of m,v and t in the previous equation we get
[tex]Average \ power\ =\ \frac{0.5*1000*15*15}{5} \\Average \ power\ =\ 22,500\ w\\Average \ power\ =\frac{22,500}{746} \\Average \ power\ =30.16\ hp[/tex]
To convert w to hp we divide by 746
Therefore 30.16 hp is the answer.
The friends spend some time thinking about a beam of light traveling from one medium to another medium with higher index of refraction, which strikes the boundary obliquely. Which of Tristan's statements is correct
Answer:
"When light moves from a material in which its speed is high to a material in which its speed is lower, the angle of refraction θ2is less than the angle of incidence θ1and the ray is bent toward the normal."
Explanation:
Refraction is a phenomenon that occurs when light rays change direction after passing through a surface or medium. This is also known as 'bending'. Snell's law provides the relationship between the angle of incidence and refraction in the equation below:
n₁sinФ₁ = n₂sinФ₂
where n1 and n2 represent the two media and theta refers to the angles formed. When light hits a medium with a high refractive index, the speed of light becomes slower.
So, Tristan is right when he says that, "When light moves from a material in which its speed is high to a material in which its speed is lower, the angle of refraction θ2is less than the angle of incidence θ1and the ray is bent toward the normal."
Which kind of image can never be projected and forms where light rays appear to originate?
virtual
real
inverted
enlarned
Answer:
a) virtual
Explanation:
This is a lens problem, in this case the equation that describes the process is the constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length, weights the distance to the object and qq the distance to the image
In a projection system the image that we see is q, which can have several characteristics
a) virtual It can never be projected, since this image is formed by the extensions of the light rays, therefore it is not real but a construction of the brain that interprets where the rays must come from.
b) Real. This image can be projected since light rays pass through the image
c) Inverted. Inverted images are real so they can be projected, so rays pass through the image
d) expanded. In this case the image is greater than the object, this occurs when the object the distance to the image is greater than the distance to the object, therefore the distance q is negative, therefore this image is straight and is formed by the extensions from the rays and you can't project
Answer:
option A) virtual
Explanation:
hope this helps :)
When you are told that the wind has a "Small Coriolis force" associated with it, what is that "small force" exactly
Answer:
Coriolis force is a type of force of inertia that acts on objects that is in motion within a frame of reference that rotates with respect to an inertial frame. Due to the rotation of the earth, circulating air is deflected result of the Coriolis force, instead of the air circulating between the earth poles and the equator in a straight manner. Because of the effect of the Coriolis force, air movement deflects toward the right in the Northern Hemisphere and toward the left in the Southern Hemisphere, eventually taking a curved path of travel.
5. Sandor fills a bucket with water and whirls it in a vertical circle to demonstrate that the
water will not spill from the bucket at the top of the loop. If the length of the rope from his
hand to the centre of the bucket is 1.24 m, what is the minimum tension in the rope (at the
top of the swing)? How slow can he swing the bucket? Explain your answer.
Given that,
radius = 1.24 m
According to question,
The rope cannot push outwards. It must always have some slight tension or the bucket will fall.
We need to calculate the tension in the rope
At the top the force of gravity is
[tex]F=mg[/tex]
The force needed to move the bucket in a circle is centripetal force.
So, if mg is ever greater than centripetal force then the bucket and the contents will start to fall.
The rope have a tension of less than zero.
We need to calculate the velocity of swing bucket
Using centripetal force
[tex]F=\dfrac{mv^2}{r}[/tex]
[tex]mg=\dfrac{mv^2}{r}[/tex]
[tex]g=\dfrac{v^2}{r}[/tex]
[tex]v^2=gr[/tex]
[tex]v=\sqrt{gr}[/tex]
Put the value into the formula
[tex]v=\sqrt{9.8\times1.24}[/tex]
[tex]v=3.49\ m/s[/tex]
Hence, The minimum tension in the rope is less than zero .
The bucket swings with the velocity of 3.49 m/s.
A stone is thrown towards a wall with an initial velocity of v0=19m/s and an angle = 71 with the horizontal, as illustrated in the figure below. The stone reaches point A at the top of the wall, t=3.5s after being thrown. Determine (a) the height h of the wall, (b) the maximum height H of the path of the stone, (c) the horizontal distance between the launching point and point A and (d) the horizontal reach of the stone if the wall did not exist
Answer:
(a) 2.85 m
(b) 16.5 m
(c) 21.7 m
(d) 22.7 m
Explanation:
Given:
v₀ₓ = 19 cos 71° m/s
v₀ᵧ = 19 sin 71° m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
(a) Find Δy when t = 3.5 s.
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (19 sin 71° m/s) (3.5 s) + ½ (-9.8 m/s²) (3.5 s)²
Δy = 2.85 m
(b) Find Δy when vᵧ = 0 m/s.
vᵧ² = v₀ᵧ² + 2 aᵧ Δy
(0 m/s)² = (19 sin 71° m/s)² + 2 (-9.8 m/s²) Δy
Δy = 16.5 m
(c) Find Δx when t = 3.5 s.
Δx = v₀ₓ t + ½ aₓ t²
Δx = (19 cos 71° m/s) (3.5 s) + ½ (0 m/s²) (3.5 s)²
Δx = 21.7 m
(d) Find Δx when Δy = 0 m.
First, find t when Δy = 0 m.
Δy = v₀ᵧ t + ½ aᵧ t²
(0 m) = (19 sin 71° m/s) t + ½ (-9.8 m/s²) t²
0 = t (18.0 − 4.9 t)
t = 3.67
Next, find Δx when t = 3.67 s.
Δx = v₀ₓ t + ½ aₓ t²
Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²
Δx = 22.7 m
The specific heat of water is about 4200 J/(kg·oC). To heat a cup of water of 0.25 kg from 10 oC to 50 oC, at least how much heat is required?
Answer:
heat required = mass × specific heat × change in temperature
Explanation:
0.25 × 4200 × 40
=42000 J
When an old LP turntable was revolving at 3313 rpm, it was shut off and uniformly slowed down and stopped in 5.5 seconds. What was the magnitude of its angular acceleration (in rad/s2) as it slowed down?
Answer:
-0.63 rad/s²
Explanation:
Given that
Initial angular velocity of the turntable, w(i) = 33 1/3 rpm
Final angular velocity of the turntable, w(f) = 0 rpm
Time taken to slow down, t = 5.5 s
The calculation is attached in the photo below
What is the average acceleration? Please show work!
Answer:
Explanation:
Average acceleration
= (final velocity - initial velocity) /time
= (50-0)km/h /30 s
= 50 * 1000 / 3600 m/s /s
= 13.89 m/s^2
Calculate the moment of inertia of a skater given the following information.
(a) The 60.0-kg skater is approximated as a cylinder that has a 0.110-m radius.
(b) The skater with arms extended is approximately a cylinder that is 74.0 kg, has a 0.150 m radius, and has two 0.750 m long arms which are 3.00 kg each and extend straight out from the cylinder like rods rotated about their ends.
Answer:
(a) I = 0.363 kgm^2
(b) I = 1.95 kgm^2
Explanation:
(a) If you consider the shape of the skater as approximately a cylinder, you use the following formula to calculate the moment of inertia of the skater:
[tex]I_s=\frac{1}{2}MR^2[/tex] (1)
M: mass of the skater = 60.0 kg
R: radius of the cylinder = 0.110m
[tex]I_s=\frac{1}{2}(60.0kg)(0.110m)^2=0.363kg.m^2[/tex]
The moment of inertia of the skater is 0.363 kgm^2
(b) In the case of the skater with his arms extended, you calculate the moment of inertia of a combine object, given by cylinder and a rod (the arms) that cross the cylinder. You use the following formula for the total moment of inertia:
[tex]I=I_c+I_r\\\\I=\frac{1}{2}M_1R^2+\frac{1}{12}M_2L^2[/tex] (2)
M1: mass of the cylinder = 74.0 kg
M2: mass of the rod = 3.00kg +3.00kg = 6.00kg
L: length of the rod = 0.750m + 0.750m = 1.50m
R: radius of the cylinder = 0.150
[tex]I=\frac{1}{2}(74.0kg)(0.150m)^2+\frac{1}{12}(6.00kg)(1.50m)^2\\\\I=1.95kg.m^2[/tex]
The moment of inertia of the skater with his arms extended is 1.95 kg.m^2
In a fixed-target experiment positrons are fired at a target of electrons at rest. What positron energy is required to produce a Z (mZ = 91.188 GeV)?
Answer:
Explanation:
electron rest mass = 0.511MeV/C²
postion rest mass = 0.511MeV/C²
boson rest mass = 91.188GeV/C²
= 91188 MeV/C²
A heavier car is always safer in a crash than a lighter car.
Answer:
not true because the mass from the heavy car will cause it to damage more
Explanation:
Answer: answer on edmentum is false your welcome
Explanation:
It is false because it's more heavy so more damage l.
In an experiment to measure the acceleration due to gravity g, two independent equally reliable measurements gave 9.67 m/s2 and 9.88 m/s2. Determine (i) the percent difference of the measurements (ii) the percent error of their mean. [Take the theoretical value of g to be 9.81 m/s2]
Answer and Explanation:
a. The computation of the percent difference between the measurements is shown below:-
The first value of g is 9.67 and the second value is 9.88
So, difference = 9.88 - 9.67
= 0.21
Percentage difference in measurement is
[tex]= \frac{0.21}{9.88}\times100[/tex]
= +/-2.13
Percent difference with 9.88
Difference = 9.88 - 9.81
= 0.07
[tex]= \frac{0.07}{9.81}\times100[/tex]
= +/-0.71%
b. The Computation of percent error of their mean is shown below:-
Mean of two values is
= [tex]\frac{9.67 + 9.88}{2}[/tex]
= 9.775
Difference = 9.81 - 9.775
= 0.035
Percentage difference is
[tex]= \frac{0.035}{9.81}\times 100[/tex]
= +/- 0.36%
A ball is thrown from the ground with nonzero horizontal and vertical initial velocities. While the ball is in the air, assuming that only the force of gravity acts on it, which of the following statements is true? a. Both the horizontal and vertical components of momentum are constant. b. Only the horizontal component of momentum is constant. c. Neither the horizontal nor the vertical components of momentum are constant.
Answer:
B
Explanation:
Solution:-
- Take a coordinate system as follows:
x: Directed along the ground
y: Directed vertical to ground
- We will assume that the initial vertical and horizontal non-zeroes velocities are given as follows:
[tex]v_x_i = v_o_x\\\\v_y_i = v_o_y\\[/tex]
- After a ball is thrown it continues a path of parabolic projectile. The motion of the ball can be analyzed in each coordinate system. We will assume that effects of air-resistance are negligible.
- Therefore, only gravity acts on the ball in the vertical direction. We can use kinematic equation of motions to determine the velocity of ball in either ( x-y ) direction at any instant of time ( t ).
- Use first kinematic equation of motion in both x and y directions.
[tex]v_x_f = v_o_x + a_x*t\\\\v_y_f = v_o_y + a_y*t\\[/tex]
- The accelerations ( ax and ay ) in the direction of each axis are to be determined. We know that the gravity acceleration ( g ) acts in vertical direction or along y-axis ( ay ) and always directed downwards while velocity is directed up. Since, we neglected the effects of air-resistance there is no acceleration in the x-direction ( ax = 0 ) .
[tex]v_x_f = v_o_x\\\\v_y_f = v_o_y - gt\\[/tex]
- We see that the horizontal velocity of the ball ( vxf ) at any point in time remains equal to the initial horizontal velocity; hence, it is constant throughout the journey.
- However, the velocity of the ball in vertical direction( vyf ) is changing for every unit of time ( t ) under the influence of gravitational acceleration. Hence, it is not constant throughout the journey
A certain dam generates 120 MJ of mechanical (hydroelectric) energy each minute. If the conversion from mechanical to electrical energy is then 15% efficient, what is the dam's electrical power output in W?
Answer:
electric energy ( power ) = 300000 W
Explanation:
given data
mechanical (hydroelectric) energy = 120 MJ/min = 2000000 J/s
efficiency = 15 % = 0.15
solution
we know that Efficiency of electric engine is expression as
Efficiency = Mechanical energy ÷ electric energy ......................1
and here dam electrical power output is
put here value in equation 1
electric energy ( power ) = Efficiency × Mechanical energy ( power )
electric energy ( power ) = 0.15 × 2000000 J/s
electric energy ( power ) = 300000 W
A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed of vi, and the coefficient of kinetic friction between the carton and the surface is μk.
(a) Use energy considerations to find an expression for the distance the carton moves before it stops. (Use any variable or symbol stated above along with the following as necessary)
(b) What if the initial speed of the carton is increased by a factor of 3, determine an expression for the new distance d the box slides in terms of the old distance.
Answer and Explanation:
Data provided in the question
Carbon mass = m
Initial speed = v_i
Coefficient = μk
Based on the above information, the expressions are as follows
a. By using the energy considerations the expression for the carton moving distance is
As we know that
[tex]Fd = \frac{1}{2} m (v_i^2- v_f^2)[/tex]
where,
[tex]v_f = 0[/tex]
[tex]F = u_kmg[/tex]
[tex](\mu_kg) d = \frac{1}{2} m v_i^2[/tex]
[tex]d = \frac{\frac{1}{2}v_i^2}{\mu_kg}[/tex]
[tex]d = \frac{v_i^2}{2 \mu_kg}[/tex]
b. The initial speed of the carton if the factor of 3 risen, so the expression is
[tex]v_i^1 = 3v_i[/tex]
[tex]d^i = \frac{(3v_i^2)}{2\mu_kg}[/tex]
[tex]= \frac{9v_i^2}{2\mu_kg}[/tex]
[tex]d^i = 9(d)[/tex]
A spring hangs vertically. A 250 g mass is attached to the spring and allowed to come to rest. The spring stretches 8 cm as the mass comes to rest. What is the spring constant of the spring
Answer:
spring constant = 31.25N/m
Explanation:
spring constant = force/extension
mass = 250g = 0.25kg
extension = 8cm = 0.08m
force = mg = 0.25 x 10 = 2.5N
spring constant = 2.5/0.08 = 31.25N/m
A 25-coil spring with a spring constant of 350 N/m is cut into five equal springs with five coils each. What is the spring constant of each of the 5-coil springs
1750N/m
Explanation:
According to Hooke's law, the spring constant (k) of an elastic material is the ratio of the force (F) applied to the material to the extension (x) of the material caused by this force. i.e
k = F / x --------------(i)
From the question, the elastic material (spring) of 25 coils has a spring constant of 350N/m. This means that for every 350N force applied to the spring, the spring extends by 1m.
Now if the spring is cut into five equal parts each with five coils, imagine they are attached together such that the same force of 350N is applied to still cause a total extension of 1m. Each spring contributes 1/5 of this extension.
Therefore, the extension caused by each spring is 1/5 of 1m = 0.2m
Since the same force of 350N is applied, substitute F = 350N and x = 0.2m into equation (i) as follows;
k = 350 / 0.2
k = 1750N/m
Therefore, the spring constant of each of the 5-coil spring is 1750N/m
The spring constant of each of the 5-coil springs is 1,750 N/m.
The given parameters;
spring constant, k = 350 N/mnumber of coils, N = 25The total spring constant of the 25 coils is calculated as follows;
[tex]K_t = 25 \times 350 \ N/m\\\\K_t = 8,750 \ N/m[/tex]
The spring constant of each of the given 5 coils is calculated as follows;
[tex]K = \frac{8,750 }{5} \\\\K = 1,750 \ N/m[/tex]
Thus, the spring constant of each of the 5-coil springs is 1,750 N/m.
Learn more here:https://brainly.com/question/22499689
Un autocar que circula a 81 km/h frena uniformemente con una aceleración de -4,5 m/s2.
a) Determina cuántos metros recorre hasta detenerse.
b) Representa las gráficas v-t y s-t.
Answer:
a) [tex]\Delta x=56.25 m[/tex]
b) imagen adjunta
Explanation:
a) Primero debemos hacer la conversión de 81 km/h a m/s, esto es 22.5 m/s.
Ahora, usando la ecuacion cinemática, en un movimiento acelerado tenemos:
[tex]v_{f}^{2}=v_{0}^{2}+2a \Delta x [/tex]
Queremos encontrar la posición hasta detenerse, osea vf = 0.
[tex]\Delta x=\frac{-v_{0}^{2}}{2a}[/tex]
[tex]\Delta x=\frac{-22.5^{2}}{-2*4.5}[/tex]
[tex]\Delta x=56.25 m[/tex]
b) Para este caso el gráfico se encuentra adjunto.
Espero que te sirva de ayuda!
To understand the standard formula for a sinusoidal traveling wave.
One formula for a wave with a y displacement (e.g., of a string) traveling in the x direction is
y(x,t)=Asin(kxâÏt).
All the questions in this problem refer to this formula and to the wave it describes.
1) What is the phase Ï(x,t) of the wave?
Express the phase in terms of one or more given variables ( A, k, x, t, and Ï) and any needed constants like Ï
Ï(x,t)=
2) What is the wavelength λ of the wave?
Express the wavelength in terms of one or more given variables ( A, k, x, t, and Ï) and any needed constants like Ï.
λ=
3) What is the period T of this wave?
Express the period in terms of one or more given variables ( A, k, x, t, and Ï) and any needed constants like Ï.
T=
4) What is the speed of propagation v of this wave?
Express the speed of propagation in terms of one or more given variables ( A, k, x, t, and Ï) and any needed constants like Ï.
v=
Answer:
1) Φ=zero
2) λ = 2π / k
3) T = 2π / w
4) v = w / k
Explanation:
The equation of a traveling wave is
y = A sin (ka - wt + Ф)
Let's answer using this equation the different questions
1) we see that the equation given in the problem the phase is zero
2) wavelength
k = 2π /λ
λ = 2π / k
3) The perido
angular velocity is related to frequency
w = 2π f
frequency and period are related
f = 1 / T
w = 2 π / T
T = 2π / w
4) the wave speed is
v = λ f
λ = 2π / k
f = w / 2π
v = 2π /k w /2π
v = w / k
ou are using a hydrogen discharge tube and high quality red and blue light filters as the light source for a Michelson interferometer. The hydrogen discharge tube provides light of several different wavelengths (colors) in the visible range. The red light in the hydrogen spectrum has a wavelength of 656.3 nm and the blue light has a wavelength of 434.0 nm. When using the discharge tube and the red filter as the light source, you view a bright red spot in the viewing area of the interferometer. You now move the movable mirror away from the beam splitter and observe 146 bright spots. You replace the red filter with the blue filter and observe a bright blue spot in the interferometer. You now move the movable mirror towards the beam splitter and observe 122 bright spots. Determine the final displacement (include sign) of the moveable mirror. (Assume the positive direction is away from the beam splitter.)
Answer:
Explanation:
In interferometer , when the movable mirror is moved away by distance d , there is fringe shift on the screen . If n be number of fringes shifted
2 d = n λ
where λ is wavelength of light
Applying this theory for first case when no of fringes shifted is 146
2 d₁ = 146 x 656.3 nm
d₁ = 47909.9 x 10⁻⁹ m
= .048 x 10⁻³ m
= .048 mm
For second case n = 122
2d₂ = 122 x 434 x 10⁻⁹
d₂ = 26474 x 10⁻⁹ m
= .026 mm
So in the second case , mirror must have been moved towards the beam splitter by .048 - .026 = .022 mm
So movement = - 0 .022 mm ( negative displacement )
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.9 rad/s in 2.98 s.
(a) Find the magnitude of the angular acceleration of the wheel.
(b) Find the angle in radians through which it rotates in this time interval.
Explanation:
(a) Find the magnitude of the angular acceleration of the wheel.
angular acceleration = angular speed /timeangular acceleration = 12.9/2.98 = 4.329rad/s²(b) Find the angle in radians through which it rotates in this time interval.
angular speed = 2x3.14xf12.9rad = 2 x3.14rad = 6.28/12.9rad = 0.487Now we convert rad to angle
1 rad = 57.296°0.487 = unknown angleunknown angle =57.296 x 0.487 = 27.9°The angle in radians = 27.9°
A boat develops a leak and, after its passengers are rescued, eventually sinks to the bottom of a lake. When the boat is at the bottom, what is the force of the lake bottom on the boat?
Answer:
Explanation:
The force of the lake bottom on the boat = force the boat exerts on the bottom
force the boat exerts on the bottom = weight of the boat - buoyant force on the boat
so
The force of the lake bottom on the boat = weight of the boat - buoyant force on the boat
So
The force of the lake bottom on the boat will be less than its weight .