The molar nuclear mass of boron-10 is 10.12937 g/mol. The molar mass of a proton is 1.007825 g/mol. The molar mass of a neutron is. Calculate the binding energy (in) Calculate the energy released (per mole of tritium consumed) for the following fusion reaction, given the following molar masses of nucleons and nuclei. (e = 2.998 times 10^m/s)

Answer:The parent nuclide that initially underwent decay to form Lead-210 is Polonium-218.

Explanation: Polonium-218 undergoes a series of decays in which it emits two alpha-particles and two beta-particles, resulting in the formation of Lead-210. The decay series is as follows:

Polonium-218 → (alpha decay) → Lead-214 → (beta decay) → Bismuth-214 → (alpha decay) → Polonium-210 → (alpha decay) → Lead-206 → (beta decay) → Bismuth-206 → (beta decay) → Polonium-206 → (alpha decay) → Lead-202 → (beta decay) → Thallium-202 → (beta decay) → Lead-202 → (alpha decay) → Mercury-198 → (beta decay) → Gold-198 → (beta decay) → Mercury-198 → (alpha decay) → Lead-194 → (beta decay) → Bismuth-194 → (beta decay) → Polonium-194 → (alpha decay) → Lead-190 → (beta decay) → Bismuth-190 → (alpha decay) → Thallium-186 → (beta decay) → Lead-186 → (beta decay) → Bismuth-186 → (beta decay) → Polonium-186 → (alpha decay) → Lead-182 → (beta decay) → Bismuth-182 → (alpha decay) → Thallium-178 → (beta decay) → Lead-178 → (alpha decay) → Polonium-174 → (alpha decay) → Lead-170 → (beta decay) → Bismuth-170 → (beta decay) → Polonium-170 → (alpha decay) → Lead-166 → (beta decay) → Bismuth-166 → (beta decay) → Polonium-166 → (alpha decay) → Lead-162 → (beta decay) → Bismuth-162 → (alpha decay) → Thallium-158 → (beta decay) → Lead-158 → (beta decay) → Bismuth-158 → (beta decay) → Polonium-158 → (alpha decay) → Lead-154 → (beta decay) → Bismuth-154 → (alpha decay) → Thallium-150 → (beta decay) → Lead-150 → (alpha decay) → Polonium-146 → (alpha decay) → Lead-142 → (beta decay) → Bismuth-142 → (beta decay) → Polonium-142 → (alpha decay) → Lead-138 → (beta decay) → Bismuth-138 → (beta decay) → Polonium-138 → (alpha decay) → Lead-134 → (beta decay) → Bismuth-134 → (alpha decay) → Thallium-130 → (beta decay) → Lead-130 → (beta decay) → Bismuth-130 → (beta decay) → Polonium-130 → (alpha decay) → Lead-126 → (beta decay) → Bismuth-126 → (alpha decay) → Thallium-122 → (beta decay) → Lead-122 → (beta decay) → Bismuth-122 → (beta decay) → Polonium-122 → (alpha decay) → Lead-118 → (beta decay) → Bismuth-118 → (alpha decay) → Thallium-114 → (beta decay) → Lead-114 → (alpha decay) → Polonium-110 → (alpha decay) → Lead-106 → (beta decay) → Bismuth-106 → (beta decay) → Polonium-106 → (alpha decay) → Lead-102 →

lean more about decay

https://brainly.com/question/31880538?referrer=searchResults

#SPJ11

The pH of the solution being titrated and involved in titration with a strong base will equal the pka of the weak acid at the halfway point of the equivalence volume of titrant being added.

This is because at this point, the concentration of the weak acid and its conjugate base are equal, resulting in the pH being equal to the pKa according to the Henderson-Hasselbalch equation. At this point, half of the weak acid has been converted to its conjugate base and the pH is equal to the pka of the weak acid. However, it is important to note that the exact point at which the pH equals the pKa may vary slightly depending on the specific pka value of the weak acid being titrated.

Learn more about titration : https://brainly.com/question/186765

#SPJ11

ΔS°rxn = 127.1 J/(mol·K), ΔG°rxn = -16.7 kJ/mol

To calculate the standard entropy change, ΔS°rxn, we use the standard molar entropies of the reactants and products. ΔS°rxn = ΣS°(products) - ΣS°(reactants). The standard enthalpy of the reaction, ΔH°rxn, is given as -44.2 kJ/mol. From these values, we can calculate the standard Gibbs free energy of the reaction, ΔG°rxn = ΔH°rxn - TΔS°rxn, where T is the temperature in Kelvin (25°C = 298 K).

Therefore, ΔS°rxn = 127.1 J/(mol·K) and ΔG°rxn = -44.2 kJ/mol - (298 K) * (127.1 J/(mol·K)) = -16.7 kJ/mol. The negative value of ΔG°rxn indicates that the reaction is spontaneous and thermodynamically favorable under standard conditions at 25°C.

In summary, the standard entropy change of the reaction is positive, indicating an increase in the disorder of the system. The standard Gibbs free energy change is negative, indicating that the reaction is spontaneous and thermodynamically favorable.

Learn more about enthalpy here:

https://brainly.com/question/16720480

#SPJ11

The pH and the fraction of the association of the 0.026 m NaOCl is the 10 ans 0.0035.

The chemical equation is :

NaOCl  --->  Na⁺      +  OCl⁻

0.026           0.026    0.026

OCl⁻      +    H₂O   ⇄      HOCl      +    OH⁻

0.026-x                             x                  x

The Kb is as :

Kb = 10⁻¹⁴ /  3 × 10⁻⁸

Kb = 3.3 x 10⁻⁷

x² / 0.026 - x =   3.3 x 10⁻⁷

x = 9.2 × 10⁻⁵

[OH⁻] = [HClO] = 9.2 × 10⁻⁵

[OCl⁻ ] = 0.026

pOH = -log [OH⁻]

pOH = - log (9.2 × 10⁻⁵)

pOH = 4.0

pH = 14 - 4

pH = 10

The fraction of the association is as :

α = [HOCl] / [OCl⁻ ]

α = 9.2 × 10⁻⁵ / 0.026

α = 0.0035

To learn more about pH here

https://brainly.com/question/15289714

#SPJ4

The pH of the solution is approximately 1.22 when rounded to two decimal places.

To find the pH of the solution, we need to use the concentration of the HNO3 and the volume of the solution. First, we need to calculate the new concentration of the solution after it has been diluted. We can use the equation: C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

To calculate the pH of the diluted solution, first determine the moles of HNO3 present, then calculate the concentration of HNO3 in the diluted solution, and finally use the pH formula.
1. Moles of HNO3 = (Volume × Concentration)
Moles of HNO3 = (15.0 mL × 4.00 M HNO3) × (1 L / 1000 mL) = 0.060 moles HNO3
2. Concentration of HNO3 in the diluted solution:
New concentration = Moles of HNO3 / New volume
New concentration = 0.060 moles / 1.00 L = 0.060 M
3. Calculate pH using the formula: pH = -log[H+]
Since HNO3 is a strong acid, it dissociates completely in water, so [H+] = [HNO3]. Therefore:
pH = -log(0.060)

To know more about solution visit :-

https://brainly.com/question/30665317

#SPJ11

The emf of this concentration cell is -0.076 V.The emf of a concentration cell can be calculated using the Nernst equation. In this case, the cell has two half-cells, one with a higher concentration of Mg2+ ions and the other with a lower concentration.

The Mg2+ ions will move from the higher to lower concentration side to balance the concentration gradient, creating a potential difference between the two electrodes.

Using the Nernst equation, we can calculate the emf of this concentration cell:

emf = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant, T is the temperature, n is the number of electrons transferred, F is Faraday's constant, and Q is the reaction quotient.

For this concentration cell, the standard cell potential is 0.00 V (since both electrodes are made of the same metal), n is 2 (since Mg2+ gains 2 electrons to form Mg), and Q can be calculated using the concentrations given:

Q = [Mg2+ (0.70 M)] / [Mg2+ (0.32 M)] = 2.19

Plugging in the values and solving for emf, we get:

emf = 0.00 V - (0.0257 V/K)(298 K/2)(ln 2.19) = -0.076 V

Therefore, the emf of this concentration cell is -0.076 V.

To know more about  emf visit:

brainly.com/question/15121836

#SPJ11

To determine the moles of oxygen produced when 60.1 g of potassium chlorate (KClO3) completely decomposes, first find the moles of KClO3, then use the balanced chemical equation to find the moles of oxygen (O2).

The balanced equation for the decomposition of potassium chlorate is:

2 KClO3 → 2 KCl + 3 O2

Now, calculate the moles of KClO3:

Molar mass of KClO3 = 39.10 (K) + 35.45 (Cl) + 3 * 16.00 (O) = 122.55 g/mol

moles of KClO3 = mass / molar mass = 60.1 g / 122.55 g/mol ≈ 0.490 moles

Using the stoichiometry from the balanced equation:

moles of O2 = (3/2) * moles of KClO3 = (3/2) * 0.490 moles ≈ 0.735 moles

When 60.1 g of potassium chlorate completely decomposes, approximately 0.735 moles of oxygen gas are formed.

learn more about moles

https://brainly.in/question/15416344?referrer=searchResults

#SPJ11

To determine ℰ° for the given voltaic cell, use the formula ℰ°(cell) = ℰ°(cathode) - ℰ°(anode). The resulting ℰ° for the voltaic cell is 0.71 V.

In order to determine the standard cell potential (ℰ°) for a voltaic cell using the provided half-reactions, we first identify the cathode and anode half-reactions. The cathode reaction is the reduction half-reaction with the more positive ℰ° value, while the anode reaction is the oxidation half-reaction with the less positive ℰ° value. In this case, Al3+ + 3e- → Al(s) with ℰ° = -1.66 V is the cathode, and Mg2+ + 2e- → Mg(s) with ℰ° = -2.37 V is the anode. Using the formula ℰ°(cell) = ℰ°(cathode) - ℰ°(anode), we get ℰ°(cell) = -1.66 V - (-2.37 V) = 0.71 V. Thus, the standard cell potential for this voltaic cell is 0.71 V.

To know more about the voltaic cell visit:

https://brainly.com/question/16815411

#SPJ11

The wavelength of the electron with a speed of 1.68 x 10^8 m/s is approximately 4.325 x 10^-12 meters. This calculation demonstrates the wave-particle duality of matter, showing that particles like electrons can exhibit wave-like characteristics, and their wavelength can be determined using the de Broglie equation.

To determine the wavelength of an electron given its speed, we can use the de Broglie wavelength equation, which relates the wavelength of a particle to its momentum. The de Broglie wavelength equation is λ = h / p, where λ is the wavelength, h is the Planck's constant (approximately 6.626 x 10^-34 J·s), and p is the momentum of the particle.

The momentum of an electron can be calculated using the equation p = m·v, where m is the mass of the electron and v is its velocity.

The mass of an electron is approximately 9.109 x 10^-31 kg. Given the speed of the electron as 1.68 x 10^8 m/s, we can calculate the momentum using p = (9.109 x 10^-31 kg) * (1.68 x 10^8 m/s).

Once we have the momentum, we can use the de Broglie wavelength equation to find the wavelength of the electron. Substituting the values into the equation λ = (6.626 x 10^-34 J·s) / p, we can calculate the wavelength.

Let's perform the calculations to determine the wavelength of the electron.

Given:

Mass of electron (m) = 9.109 x 10^-31 kg

Speed of electron (v) = 1.68 x 10^8 m/s

Planck's constant (h) = 6.626 x 10^-34 J·s

1. Calculate the momentum of the electron:

p = m * v

p = (9.109 x 10^-31 kg) * (1.68 x 10^8 m/s)

p ≈ 1.530 x 10^-22 kg·m/s

2. Use the de Broglie wavelength equation to find the wavelength:

λ = h / p

λ = (6.626 x 10^-34 J·s) / (1.530 x 10^-22 kg·m/s)

λ ≈ 4.325 x 10^-12 m

Learn more about de Broglie wavelength here:

https://brainly.com/question/30404168

#SPJ11

The wavelength of the photon produced when an electron in a Bohr model hydrogen atom jumps from the 2nd to the 4th energy level is approximately 1.22 x 10^-7 meters.

To calculate the wavelength of the photon, we need to find the energy difference between the two energy levels and use the formula E = hf, where E is the energy, h is Planck's constant, and f is the frequency.

The energy difference between energy levels in a hydrogen atom is given by the formula: ΔE = 13.6 * (1/n1^2 - 1/n2^2) eV. In our case, n1=2 and n2=4.

Calculating ΔE, we get approximately -3.03 eV. Converting this to joules, we have ΔE ≈ -4.85 x 10^-19 J.

Now, we use the formula E = hf, where h is Planck's constant (6.63 x 10^-34 Js), and the speed of light c = 3 x 10^8 m/s. By substituting the values and solving for the wavelength λ, we get λ ≈ 1.22 x 10^-7 meters.

Learn more about photon here:

https://brainly.com/question/31591565

#SPJ11

The mass of KCl needed to prepare 1000 ml of a 1.50 M solution is 173.65 grams.

To compute the mass of KCl needed, we need to use the formula:
mass (in grams) = moles x molar mass
First, we need to calculate the number of moles of KCl required for a 1.50 M solution:
1.50 mol/L x 1 L = 1.50 moles
The molar mass of KCl is 74.55 g/mol.

Using this information, we can calculate the mass of KCl needed:
mass = 1.50 moles x 74.55 g/mol = 173.65 grams
Therefore, 173.65 grams of KCl is required to prepare 1000 ml of a 1.50 M solution.

Learn more about moles here:

https://brainly.com/question/31597231

#SPJ11

The electron configuration of Cu2+ is [Ar]3d9.

This occurs because when copper loses two electrons to form the Cu2+ ion, one electron is removed from the 4s1 subshell and one from the 3d10 subshell, leaving the configuration [Ar]3d9.

The electron configuration of an atom or ion describes how electrons are distributed among its energy levels or subshells. Copper (Cu) has an atomic number of 29, indicating that it has 29 electrons in its neutral state.

The electron configuration of neutral copper (Cu) is: 1s2 2s2 2p6 3s2 3p6 4s1 3d10. This configuration represents the arrangement of electrons in the different energy levels or subshells of the atom.

The numbers and letters represent the principal energy levels (1, 2, 3, etc.) and the subshells (s, p, d, f) within those energy levels.

When copper forms a +2 ion (Cu2+), it loses two electrons. The electrons that are removed first come from the highest energy level, which is the 4s subshell, before they are removed from the 3d subshell. The reason for this is related to the stability and energy levels of the subshells.

To learn more about energy, refer below:

https://brainly.com/question/1932868

#SPJ11

Atoms of selenium (Se) with six electrons in its outer orbit will tend to form negatively charged ions. The ionic charge of the ions formed by selenium will be -2.

Selenium belongs to Group 16 of the periodic table, also known as the oxygen family or chalcogens. Elements in this group typically have six valence electrons. Valence electrons are the electrons in the outermost energy level of an atom, and they play a significant role in determining the reactivity and chemical behavior of an element.

To achieve a stable electron configuration, atoms of selenium will gain two electrons to fill their outer orbit and achieve a full valence shell of eight electrons. By gaining two electrons, selenium will form negatively charged ions. The ionic charge of these ions will be -2, indicating an excess of two electrons compared to the number of protons in the nucleus.

It is important to note that the tendency to form ions and the resulting ionic charge depend on the number of valence electrons and the octet rule, which states that atoms tend to gain, lose, or share electrons to achieve a stable electron configuration with eight valence electrons (except for hydrogen and helium, which follow the duet rule).

Learn more about chalcogens here: https://brainly.com/question/29220016

#SPJ11

To ensure that there is enough water for everyone during the seven-day journey, we need to calculate the amount of water required per person per day and then multiply it by the number of people and the number of days.

Let's assume there are "n" people in the group.

The total water required for one person per day can vary depending on factors like climate, activity level, and individual needs. On average, a person needs about 2-3 liters of water per day to stay properly hydrated.

Let's take the middle range of 2.5 liters per person per day. Multiply this by the number of people (n) to get the total water required per day for the group.

Total water required per day = 2.5 liters/person/day * n people

Now, multiply the total water required per day by the number of days (7) to get the total water required for the entire journey.

Total water required for the journey = Total water required per day * number of days

Once you have the total water required for the journey, you can check if the 150-gallon water container is sufficient.

1 gallon is equivalent to approximately 3.785 liters. Therefore, the 150-gallon water container can hold:

150 gallons * 3.785 liters/gallon = 567.75 liters

Compare the total water required for the journey with the capacity of the 150-gallon water container. If the container can hold more water than what is required, you have enough water for the journey. Otherwise, you may need to consider additional water sources or containers.

As for the 12 empty soda cans, they are not a suitable option for storing water for a journey of this length and number of people. They are not designed for long-term storage or transportation of water and may not provide an adequate volume of water. It is recommended to use appropriate water containers or bottles for storing water during the journey.

To learn more about water click here:

brainly.com/question/32195714

#SPJ11

The balanced chemical equation for the reaction between nitrogen (N₂) and hydrogen (H₂) to form ammonia (NH₃) is:

[tex]N₂ + 3H₂ → 2NH₃[/tex]

To determine the limiting reactant, we need to compare the amount of each reactant with their respective stoichiometric coefficients in the balanced equation. The molar mass of nitrogen is approximately 28 g/mol, and the molar mass of hydrogen is approximately 2 g/mol. By converting the given masses to moles, we find that 5.65 g of nitrogen is approximately 0.202 moles and 1.15 g of hydrogen is approximately 0.575 moles.

Using the stoichiometry of the balanced equation, we find that for every 1 mole of nitrogen, 3 moles of hydrogen are required. Therefore, the 0.202 moles of nitrogen would require 0.606 moles of hydrogen.

Since we only have 0.575 moles of hydrogen, which is less than the required amount, hydrogen is the limiting reactant.

To calculate the amount of ammonia formed, we use the stoichiometric ratio between hydrogen and ammonia, which is 3:2. Thus, for every 3 moles of hydrogen, 2 moles of ammonia are produced.

Considering that we have 0.575 moles of hydrogen, we can calculate the amount of ammonia formed:

[tex](0.575 moles H₂) × (2 moles NH₃ / 3 moles H₂) ≈ 0.383 moles NH₃[/tex]

Therefore, approximately 0.383 moles of ammonia (NH₃) are formed when 5.65 g of nitrogen reacts with 1.15 g of hydrogen.

Learn more about hydrogen (H₂) here:

https://brainly.com/question/22876328

#SPJ11

Benzene reacts with CH₃COCl in the presence of AlCl₃ to give (D) C₆H₅COCH₃ by Friedel-Crafts acylation.

When benzene (C6H6) reacts with CH₃COCl (acetyl chloride) in the presence of a catalyst, AlCl₃ (aluminum chloride), it undergoes a reaction known as Friedel-Crafts acylation. This reaction results in the formation of an aromatic ketone.

In this reaction, AlCl₃ is a Lewis acid, acting as a catalyst.

In this specific case, the product formed is C₆H₅COCH₃, which is known as acetophenone. Acetophenone is an aromatic ketone, and it has a phenyl group (C₆H₅) attached to the carbonyl group (C=O).

To summarize, when benzene reacts with acetyl chloride in the presence of an aluminum chloride catalyst, the product formed is acetophenone (C₆H₅COCH₃) through the Friedel-Crafts acylation reaction.

To know more about Friedel-Crafts acylation, refer here:

https://brainly.com/question/31107543#

#SPJ11

The solubility of SbOCl in water is relatively low, and the concentration of the product is not high enough to form a visible precipitate due to which the solution of antimony(iii) chloride have no visible precipitate in it.

Although the equilibrium equation shows that SbCl3 reacts with water to form insoluble SbOCl, the solution of antimony(III) chloride has no visible precipitate in it due to several reasons. Firstly, the solubility of SbOCl in water is relatively low, and the concentration of the product is not high enough to form a visible precipitate.

Additionally, the formation of SbOCl depends on the concentration of hydroxide ions, which may not be present in sufficient quantities to drive the reaction to completion. Furthermore, SbCl₃ can exist in different forms, including monomers, dimers, and trimers, which can affect its solubility in water.

Finally, the presence of other ions in the solution, such as chloride or hydrogen ions, can also affect the solubility of SbOCl. Overall, these factors can contribute to the absence of a visible precipitate in the solution of antimony(III) chloride.

To know more about solubility here

https://brainly.com/question/31493083

#SPJ4

The final pH of the solution is 5.00.

First, we need to write the balanced chemical equation for the reaction between the weak acid (HA) and the strong base (NaOH):

HA + NaOH → NaA + H2O

where NaA is the sodium salt of the weak acid.

Since 0.500 mol of NaOH is added to 1.00 mol of HA, the amount of HA remaining after the reaction is (1.00 - 0.500) = 0.500 mol.

To calculate the pH of the solution, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where [A-] is the concentration of the conjugate base (NaA) and [HA] is the concentration of the weak acid (HA).

We can find [A-] by multiplying the amount of NaOH added (0.500 mol) by the stoichiometric coefficient ratio of NaA to NaOH (1:1), and then dividing by the total volume of the solution (1.00 L):

[A-] = (0.500 mol NaOH) / (1.00 L) = 0.500 M

To find [HA], we need to use the initial molarity of the acid (1.00 M) minus the amount of acid that reacted with NaOH (0.500 mol), divided by the total volume of the solution (1.00 L):

[HA] = (1.00 mol HA - 0.500 mol NaOH) / (1.00 L) = 0.500 M

Now we can plug in the values for pKa, [A-], and [HA] to solve for pH:

pH = 5.00 + log(0.500/0.500) = 5.00

Therefore, the final pH of the solution is 5.00.

To learn more about molarity, refer below:

https://brainly.com/question/8732513

#SPJ11

To complete and balance the given half-reaction in basic solution:

Cr(OH)3(s) → CrO42-(aq) + 3e-

First, let's balance the Cr atoms by adding 3 Cr(OH)3 on the left-hand side:

3Cr(OH)3(s) → CrO42-(aq) + 3e-

Next, balance the O atoms by adding 6 OH- ions on the right-hand side:

3Cr(OH)3(s) + 6OH-(aq) → CrO42-(aq) + 3e-

To balance the H atoms, we can add 6 H2O molecules on the left-hand side:

3Cr(OH)3(s) + 6OH-(aq) → CrO42-(aq) + 3e- + 6H2O(l)

Finally, to balance the charges, add 3 OH- ions on the left-hand side:

3Cr(OH)3(s) + 9OH-(aq) → CrO42-(aq) + 3e- + 6H2O(l)

The balanced half-reaction in basic solution is:

3Cr(OH)3(s) + 9OH-(aq) → CrO42-(aq) + 3e- + 6H2O(l)

Please note that this is the balanced half-reaction, and it needs to be combined with another half-reaction to form the complete balanced redox equation.

Learn more about balancing redox reactions in basic solution

https://brainly.com/question/3471295?referrer=searchResults

#SPJ11.

To determine the new concentration of Fe3+ when 3.00 mL of 0.00200 M iron(III) nitrate is diluted to a total volume of 10.00 mL, we can use the concept of dilution.

First, we need to calculate the number of moles of Fe3+ in the initial 3.00 mL of 0.00200 M iron(III) nitrate. The number of moles can be calculated using the formula:

moles = concentration × volume

moles = 0.00200 M × 0.00300 L

moles = 0.000006 mol

Next, we determine the final volume of the solution, which is 10.00 mL.

Now we can use the dilution formula to find the final concentration:

C1V1 = C2V2

C1 = initial concentration

V1 = initial volume

C2 = final concentration

V2 = final volume

Rearranging the formula:

C2 = (C1V1) / V2

C2 = (0.00200 M × 0.00300 L) / 0.01000 L

C2 = 0.0006 M

Therefore, the new concentration of Fe3+ after dilution is 0.0006 M in a total volume of 10.00 mL.

Learn more about concentration of Fe3+ here

https://brainly.com/question/30886685

#SPJ11

The reagents that can oxidize VO^2+ to VO^2+ but not oxidize Pb^2+ to PbO2 under standard conditions in an acidic solution are Cr2O7^2-, Ag^+, and Co^3+.

To find a reagent that can oxidize VO^2+ to VO^2+ but not oxidize Pb^2+ to PbO2, we need to compare their standard reduction potentials.

From the Standard Reduction Potentials table, we have:

VO^2+ + H2O + 2e^- -> VO^2+ + 2OH^-; E° = +0.34V

Pb^2+ + 2e^- -> Pb; E° = -0.13V

We need a reagent that has a reduction potential between these two values. From the options given, the following have reduction potentials in the required range:

Cr2O7^2- + 14H^+ + 6e^- -> 2Cr^3+ + 7H2O; E° = +1.33V

Ag^+ + e^- -> Ag; E° = +0.80V

Co^3+ + e^- -> Co^2+; E° = +1.82V

Therefore, the reagents that can oxidize VO^2+ to VO^2+ but not oxidize Pb^2+ to PbO2 under standard conditions in an acidic solution are Cr2O7^2-, Ag^+, and Co^3+.

To know more about Standard Reduction Potential, click below.

https://brainly.com/question/30066942

#SPJ11

When 12.0 litres of oxygen at STP (standard temperature and pressure) is heated to [tex]215^0C[/tex] and the pressure is increased to 220 atm, the new volume of gas will be 0.053 L.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. To solve this problem, we can use the formula V2 = (P1 x V1 x T2) / (P2 x T1), where V2 is the new volume, P1 is the initial pressure, V1 is the initial volume, T2 is the new temperature, P2 is the final pressure, and T1 is the initial temperature.

At STP, the temperature is [tex]0^0C[/tex], which is equivalent to 273 K. Therefore, the initial temperature is 273 K, and the initial volume is 12.0 L. Given that the new temperature is [tex]215^0C[/tex], which is equivalent to 488 K, and the final pressure is 220 atm, we can substitute these values into the formula to find the new volume:

V2 = (220 atm x 12.0 L x 488 K) / (1 atm x 273 K)

V2 ≈ 0.053 L

Therefore, the new volume of the gas, when heated to [tex]215^0C[/tex] and under a pressure of 220 atm, is approximately 0.053 L.

Learn more about ideal gas laws here:

https://brainly.com/question/12624936

#SPJ11

When succinic anhydride is heated with ammonium chloride at 200 degree Celsius, it undergoes a nucleophilic attack by the ammonium ion, resulting in the formation of an initially-formed tetrahedral intermediate. This intermediate has four groups bonded to the central carbon atom, which is also bonded to the oxygen of the anhydride group.

The ammonium ion acts as a nucleophile, attacking the carbonyl carbon of the anhydride. This results in the formation of a tetrahedral intermediate, which contains the ammonium group, two carbonyl oxygens, and the carbon atom of the anhydride group. The nitrogen of the ammonium group has a positive charge, while the carbon atom of the anhydride group has a partial negative charge due to the electron-withdrawing nature of the carbonyl groups.
The tetrahedral intermediate is unstable and undergoes a rearrangement to form succinimide, releasing ammonia and carbon dioxide as byproducts. Succinimide is a cyclic imide that contains a five-membered ring with two carbonyl groups and a nitrogen atom.
In summary, the initially-formed tetrahedral intermediate in the reaction between succinic anhydride and ammonium chloride is formed by the nucleophilic attack of the ammonium ion on the carbonyl carbon of the anhydride group. This intermediate is unstable and undergoes a rearrangement to form succinimide.

To know more about Ammonium Chloride visit:

https://brainly.com/question/23387600

#SPJ11

The mass of the reactant during the reaction base on the law of conservation of mass is 27.50 grams

The law of conservation of matter states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another. Thus, the total mass of reactants must equal to the  total mass of the product obtained in a chemical reaction.

Now, we shall obtain the mass of the reactants during the reaction. Details below:

Iron + sulfur -> Iron sulfide

Mass of iron + mass of sulfur = Mass of iron sulfide

Mass of iron + mass of sulfur = 27.50

Thus, we can conclude from the above calculation that the mass of reactants is 27.50 grams

Learn more about law of conservation of matter:

https://brainly.com/question/9434062

#SPJ1

Six substances are strong bases: KOH, [tex]NH_4OH[/tex], Ca(OH)2, Mg(OH)2, Al(OH)3, and NaOH.

Out of the given substances, only six are classified as strong bases.

These include potassium hydroxide (KOH), ammonium hydroxide (NH4OH), calcium hydroxide (Ca(OH)2), magnesium hydroxide (Mg(OH)2), aluminum hydroxide (Al(OH)3), and sodium hydroxide (NaOH).

These substances are characterized by their ability to dissociate completely in water to produce hydroxide ions (OH-), which makes them strong bases.

The other substances listed in the question, including nitrous acid ([tex]HNO_2[/tex]), sodium chloride (NaCl), and sulfuric acid ([tex]H_2SO_4[/tex]), are not bases at all.

Understanding the properties and classifications of substances is crucial in chemistry, as it helps us understand their behavior and how they interact with other substances.

For more such questions on substances, click on:

https://brainly.com/question/29108029

#SPJ11

KOH, Ca(OH)2, Mg(OH)2, and Al(OH)3 are strong bases that dissociate completely in water to produce hydroxide ions, increasing the hydroxide ion concentration. NH4OH and HNO2 are weak bases, while NaCl and H2SO4 are not based.

A strong base is a substance that dissociates completely in water to produce hydroxide ions (OH-) and has a high tendency to accept protons (H+). Potassium hydroxide (KOH), calcium hydroxide (Ca(OH)2), magnesium hydroxide (Mg(OH)2), and aluminum hydroxide (Al(OH)3) are examples of strong bases. These bases dissociate completely in water to form their respective metal cations and hydroxide ions, thereby increasing the concentration of hydroxide ions in the solution. In contrast, ammonium hydroxide (NH4OH) and nitrous acid (HNO2) are weak bases and do not dissociate completely in water to form hydroxide ions. Sodium chloride (NaCl) and sulfuric acid (H2SO4) are not bases at all.

learn more about hydroxide here:

https://brainly.com/question/31820869

#SPJ11

To find out how much of the 18% alcohol solution and how much water must be mixed together to make 10 liters of a 12% alcohol solution, you can use the following steps:

Step 1: Set up the equation

Let x be the amount of 18% alcohol solution, and y be the amount of water to be mixed.

x + y = 10 (total solution volume)

0.18x + 0y = 0.12 * 10 (total alcohol content)

Step 2: Solve for y

y = 10 - x

Step 3: Substitute y in the second equation

0.18x + 0(10 - x) = 1.2

0.18x = 1.2

Step 4: Solve for x

x = 1.2 / 0.18

x = 6.67 liters (approximately)

Step 5: Solve for y

y = 10 - 6.67

y = 3.33 liters (approximately)

In conclusion, to make 10 liters of a 12% alcohol solution, the pharmacist needs to mix approximately 6.67 liters of the 18% alcohol solution with approximately 3.33 liters of water.

To know more about 18% alcohol solution refer here

https://brainly.com/question/14462663#

#SPJ11

1 mole is equal to 6. 022 x 10 23 particles, which is also known as the Avogadro's constant. To compute the amount of moles of any material in the sample, just divide the substance's stated weight by its molar mass.

we first need to determine which reactant is limiting and which is in excess. We can do this by using the mole ratio from the balanced chemical equation:

3 CuO + 2 Al --> 3 Cu + Al2O3

For every 2 moles of Al that react, 1 mole of Al2O3 is produced. Therefore, the maximum number of moles of Al2O3 that can form is:

(3.47 moles Al) / (2 moles Al per 1 mole Al2O3) = 1.735 moles Al2O3

However, we also need to consider the amount of CuO available. For every 3 moles of CuO that react, 1 mole of Al2O3 is produced. Therefore, the maximum number of moles of Al2O3 that can form based on the amount of CuO available is:

(6.04 moles CuO) / (3 moles CuO per 1 mole Al2O3) = 2.013 moles Al2O3

Since we can only produce as much Al2O3 as the limiting reactant allows, the actual yield of Al2O3 will be the smaller of the two values calculated above, which is 1.735 moles Al2O3. Therefore, the answer is e. 1.74 moles.

To solve this problem, we'll use the stoichiometry of the balanced chemical equation: 3 CuO + 2 Al → 3 Cu + Al2O3.

Given: 3.47 moles of Al and 6.04 moles of CuO.

First, determine the number of moles of Al2O3 that can form from Al:
(3.47 moles Al) x (1 mole Al2O3 / 2 moles Al) = 1.735 moles Al2O3

Next, determine the number of moles of Al2O3 that can form from CuO:
(6.04 moles CuO) x (1 mole Al2O3 / 3 moles CuO) = 2.013 moles Al2O3

Since the number of moles of Al2O3 formed from Al (1.735 moles) is less than the number of moles of Al2O3 formed from CuO (2.013 moles), Al is the limiting reactant. Therefore, the maximum number of moles of Al2O3 that can form is 1.735 moles (rounded to 1.74 moles).

Your answer: e. 1.74 moles

To know about moles visit:

https://brainly.com/question/31597231

#SPJ11

Answer:

The order of carbon that cannot undergo SN1 (Syl) reactions is primary carbon.

Explanation:

Primary carbon atoms are not able to undergo SN1 reactions due to their lower stability in forming carbocation intermediates compared to secondary and tertiary carbon atoms.

In this sort of haloalkane chemical reaction, the nucleophile attacks an electron-deficient site and substitutes the halogen or X there.

The electronegative halogen component in alkyl halides will cause electrons to withdraw from the bond and attract electrons towards it, polarizing the bond. As a result, a partial positive charge develops on the carbon atom, making it an electron deficient site.

Now imagine a nucleophile attacking the electron-deficient carbon atom. It will induce the halogen member to leave the complex as a halide ion. The halogen group will leave in the following order: I > Br > Cl > F.

To know more about SN1 reaction, visit:

https://brainly.com/question/31882848

#SPJ11

To determine the reasonableness of the Lewis structure proposed for a molecule that contains AlCl3, we first need to understand the bonding pattern of this compound.

AlCl3 is a covalent compound in which aluminum has a partial positive charge, and each chlorine atom has a partial negative charge. The Lewis structure for AlCl3 should reflect these charges and show how the atoms are bonded together.

One proposed Lewis structure for AlCl3 shows aluminum with a double bond to one chlorine atom and a single bond to the other two chlorine atoms. This structure does not accurately reflect the bonding pattern of AlCl3 since aluminum only forms single bonds with each chlorine atom. Therefore, this Lewis structure is not reasonable.

A more accurate Lewis structure for AlCl3 would show aluminum with a single bond to each chlorine atom, and each chlorine atom would have a lone pair of electrons. This structure reflects the bonding pattern of AlCl3 and shows the partial charges on each atom. This Lewis structure is reasonable.

In conclusion, to determine the reasonableness of a Lewis structure proposed for a molecule containing AlCl3, we need to consider the bonding pattern and ensure that the structure accurately reflects the charges and bonding between the atoms.

To know more about Lewis structure click here:

https://brainly.com/question/4144781

#SPJ11

The electronic transition in a hydrogen atom that is associated with the largest emission of energy is from n = 2 to n = 1.

This is because the energy difference between these two energy levels is the largest, and as the electron transitions from a higher energy level (n = 2) to a lower energy level (n = 1), it releases energy in the form of a photon. This is known as the Lyman series of spectral lines, and the wavelength of the emitted photon can be found using the Rydberg equation. This information can be found on a data sheet or periodic table that includes the energy levels and wavelengths of hydrogen's spectral lines.

The hydrogen atom is the simplest and most well-known atomic system in physics and chemistry. It consists of a single proton in the nucleus and a single electron orbiting around the nucleus. The hydrogen atom is the basis for understanding many principles of atomic and molecular physics, such as electronic structure, spectroscopy, and chemical bonding.

To know more about hydrogen atom:

https://brainly.com/question/29695801

#SPJ11