The mass of 1/2pint of milk is 303 g.
1 pint is 0.568 litres
1000 cm3 = 1 litre
Work out the density of the milk. Give your answer in g/cm3

Answer:8n-4

Step-by-step explanation:

Answer:

n=1/2

Step-by-step explanation:

Step1: 2n-n-4+7n

Step2: 8n-4

Step3: 8n=4

Step4: n=4/8

Step5: n=1/2

Answer:

Step-by-step explanation:

new height is ¼ of original height

new width = ¼×8 = 2 inches

Answer:

2 inches

Step-by-step explanation:

To find the new width, find the scale factor that was used to reduce the photo.

Since 16 divided by 4 is 4, 4 is the scale factor.

To find the new width, divide 8 by 4:

8/4

= 2

So, the new width is 2 inches

Answer:

im doing that too </3 plz

Step-by-step explanation:

Answer:

60 meters, see explanation.

Step-by-step explanation:

We know that the ratio of length : width is 10 : 6. So for every 10 meters of length, we also have 6 meters of width. This problem is much easier since we are given the P = 160 meters.

You can see that if we multiply the ratio by ten, we get 100 : 60, where 100 + 60 = 160 total meters. From here, it is clear that the width would be 60 meters.

Answer:

Interest wil be 10% of 100  which is 10

So,  interest will be Rs.10

And total amount to be payed will be 100+10 which is Rs.110

Answer:

Interest= Rs. 10

Step-by-step explanation:

Interest of Rs.100 on 10 p.c.p.a is 10% of 100

i.e., 100*10/100 = 10

Thus we have 10 as the interest

Answer:

16.67% less

or

she only made 83% of her anticipated $18,000

Step-by-step explanation:

3000/18000 = 0.1666 or 16.67% less

15000/18000 = 0.8333 or 83%

Answer:

The last one

Step-by-step explanation:

Answer: 50%

Step-by-step explanation:

In 2010 the percentage of fatal accidents was 16%.

This is 34% less than it was in 2000 because the text says that the 2010 percentage was 16% after being reduced by 34% from 2010.

The percentage of fatal accidents in 2000 is therefore:

= 2010 fatal percentage + Percentage reduced from 2000

= 16% + 34%

= 50%

Step-by-step explanation:

The Answer is 46

The measure of Arc PRQ is 268. Another part of the arc is PQ. PRQ+PQ forms a full circle In which a circle has 360 degrees. Using that

[tex]268 + x = 360[/tex]

[tex]x = 92[/tex]

Since we are asked to the measure of PRQ and it is inscribed in arc PQ. It is half of PQ so the answer is

[tex]92 \div 2[/tex]

which is 46.

Answer:

2,548

Step-by-step explanation:

First, we have to find out the rule. The rule is multiply the previous number by 3 to get the next number.

7x3=21

21x3=63

So, we would continue this pattern until we have the first 6 numbers which are 189, 567, and 1701.

The questions is asking for the SUM of the 6 numbers so you would add the those numbers and do this equation:

7+21+63+189+567+1701= 2548

Hope this helps! :)

Answer →→→→ 12

Hope this helps you

God bless

Answer:

59

Step-by-step explanation:

Given

f(x) = 2x² + 9

f ( -5) = 2 * ( -5)² + 9

= 25 * 2 + 9

= 50 + 9

= 59

════════ ∘◦❁◦∘ ════════

════════════════════

f(x) = 2x² + 9

════════════════════

f(-5) = ?

════════════════════

#as you the x inside the (x) changed into (-5) it means that you need to change the x into -5.

f(-5) = 2(-5)² + 9

= 2 × 25 + 9

= 50 + 9 = 59

#So f(-5) = 59

════════════════════

Answer:

Exact Form:

x = ln ( 64 )/ ln ( 5 )

Decimal Form:

x = 2.58405934 …

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

Step-by-step explanation:

Start by dividing both sides by 3

5^x = 192/3

5^x = 64

Now take the log of both sides

log(5^x) = log(64)

Bring down the power

x log(5) = log(64)

Find the logs

x * 0.69897 = 1.8062

Divide

x = 1.8062 / 0.69897

x = 2.5841

Step-by-step explanation:

[tex] \tt{(5 {x}^{3} - 3x + 6) - (2 {x}^{2} - 4x + 8)}[/tex]

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ [tex] \tt{5 {x}^{3} - 3x + 6 - 2 {x}^{2} + 4x - 8}[/tex]

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶ [tex] \tt{5 {x}^{3} - 3x + 4x + 6 - 8 - 2 {x}}^{2} [/tex]

⟶ [tex] \tt{5 {x}^{3} + x - 2 - 2 {x}^{2} }[/tex]

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

[tex] \red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \tt{5 {x}^{3} - 2 {x}^{2} + x - 2}}}}}}[/tex]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

I'm the smartest person in my math class.

Step-by-step explanation:

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ 5x³-3x +6-2x²+4x-8

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶   5x³-3x+4x+6-8-2x²

⟶  5x³+x-2-2x²

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

9514 1404 393

Answer:

  1 : 14

Step-by-step explanation:

The scale factor model/real = (6 in)/(84 in) simplifies to 1/14.

Answer:

29

Step-by-step explanation:

Answer: Depends on the number of grades

Step-by-step explanation:

School has up to 6th grade: 15

School has up to 7th grade: 12

School has up to 8th grade: 11

School has up to 9th grade: 10

School has up to 10th grade: 9

Need more grades? Comment please

Answer:

okie

Step-by-step explanation:

Answer:

Ok

Step-by-step expl

Part A:

I got the number of kids in the survey which is 130 and I found 70 which is the amount of kids who like playing on a pc/console. I took 130 and 70 and converted it into a fraction 70/130, I simplified it to 7/13 and used a calculator to get my percentage which I rounded and got 53%

Part B:

I drew a table and just focused on column two. I looked at how many people don't like phone or pc and I found that 10 is how many people like phone and not pc, 30 is people who dont like phone or pc, together its 40, so you need to find what the percentage 30 is of 40, or 3/4, I used a calculator and converted it into a percentage and I got 75%

Answer:

4

9/8

Step-by-step explanation:

Given the fraction a/b, the reciprocal is expressed as 1/(a/b) = b/a

For 1/4;

1/4

= 1÷1/4

= 1 * 4/1

= 4

Hence the reciprocal is 4

b) 8/9

= 1 ÷ 8/9

= 1 * 9/8

= 9/8

Hence the reciprocal of 8/9 is 9/8

Answer:

tienes que hacer cuadritos

-8

Step-by-step explanation:

you subtract all for numbers to get your solution

Answer:

Area of shaded region is 18π square unit

Step-by-step explanation:

Please mark brainliest

Answer:

18π cm²

Step-by-step explanation:

The shaded region is calculated as

A = area of circle × fraction of circle

   = πr² × [tex]\frac{80}{360}[/tex] ( r is the radius of the circle )

   = π × 9² × [tex]\frac{2}{9}[/tex]

   = 81π × [tex]\frac{2}{9}[/tex]

   = 9π × 2

   = 18π cm²

Answer:

p(8p + 7)

Step-by-step explanation:

Factorise is when you find the product of the question before taking away the brackets.

so, if you go p(8p + 7), you times p with everything inside the brackets giving you 8p^2 + 7

therefore, the answer is p(8p + 7)

Hope this helped :)

Answer:

Ambitious Ambitious Ambitious Ambitious

Answer:

15%?  i think im wrong sorry.

Step-by-step explanation:

Find the product:-

[tex] \tt \dfrac{18}{30} \times \dfrac{5}{4} [/tex]

[tex] = \tt \dfrac{18 \times 5}{30 \times 4} [/tex]

[tex] = \tt \cancel\dfrac{18 \times 5}{30 \times 4} = \boxed{\tt\dfrac{ \: \: 3 \: \: }{4}} \: \: \: \: \: \: \: \: \: [/tex]

Multiply:-

[tex] \tt4 \: \dfrac{1}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt \dfrac{25}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt\dfrac{25}{8} \times \dfrac{1}{9} [/tex]

[tex] = \tt \cancel\dfrac{25 \times 1}{8 \times 9} = \cancel{ \tt\dfrac{ \: \: 25 \: \: }{72}} [/tex]

[tex] = \boxed{\tt\dfrac{ \: \: 1 \: \: }{3 }} [/tex]

Find the product:-

[tex] \tt \dfrac{15}{18} \times \dfrac{6}{9} \times \dfrac{27}{21} [/tex]

[tex] = \tt \cancel\dfrac{15 \times 6 \times 27}{18 \times 9 \times 25} [/tex]

[tex] = \boxed{\tt \dfrac{ \: \: 5 \: \: }{7}} [/tex]

Multiply:-

[tex] \tt \: 3 \: \dfrac{7}{70} [/tex]

[tex] = \tt \cancel\dfrac{3 \times 7}{1 \times 70} = \boxed{ \tt\dfrac{ \: \: 3 \: \: }{10}} [/tex]

Solve:-

[tex] \tt(6 \times \dfrac{1}{4}) \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt \cancel{( \dfrac{3 \times 1}{1 \times 2} )} \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt(\dfrac{3}{ \: \: 2 \: \: }) \times \dfrac{1}{2} \times \dfrac{1}{2} [/tex]

[tex] = \tt\dfrac{3}{ 2 } \times \dfrac{1}{2} \times \dfrac{1}{2} \: \: \: \: \: \: \: \: = \boxed{ \tt \dfrac{ \: \: 3 \: \: }{8}} [/tex]

Answer:

If the shipping is for all books then the total cost is 164.95

Answer:

One solution, x=-18/11.

Step-by-step explanation:

y=1/2x-7

y=6x+2

---------------

1/2x-7=6x+2

1/2x-7-6x=2

1/2x-6x=2+7

1/2x-12/2x=9

-11/2x=9

x=9/(-11/2)

x=(9/1)(-2/11)

x=-18/11

Answer:

1,100

Step-by-step explanation:

Wow that's a lot of students. Anyway, 25% is one fourth of the 100%, so we multiply 275 by 4 and we get 275.