Answer:
9.74 m/s²
Explanation:
g = GM / r²
g = (6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / (6.4×10⁶ m + 8848 m)²
g = 9.74 m/s²
How many exercises are there?
Answer:
There are 4 exresise ;endurance, strength, balance, and flexibility. Each one has different benefits.
Explanation:
Endurance activities, often referred to as aerobic, increase your breathing and heart rates.
Your muscular strength can make a big difference. Strong muscles help you stay independent and make everyday activities feel easier, like getting up from a chair, climbing stairs, and carrying groceries.
Balance exercises help prevent falls, a common problem in older adults that can have serious consequences.
Stretching can improve your flexibility. Moving more freely will make it easier for you to reach down to tie your shoes or look over your shoulder when you back your car out of the driveway.
hope this can help you...
A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Answer:
0.109 m/s
Explanation:
The calculation of the volume flow rate of the water is shown below:-
Av = Velocity ([tex]\pi[/tex])(Radius)^2
= 0.87([tex]\pi[/tex])(0.2)^2
= 0.135258 m^3 / sec
= 0.109371429 m/s
or
= 0.109
So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come
How does a fuse differ from a circuit breaker?
O A. A fuse must be replaced after use, but a circuit breaker can be
reset.
OB. A fuse works by flipping open, while a circuit breaker melts.
O C. A fuse opens the circuit to stop current, but a circuit breaker
closes the circuit.
O D. A fuse works when it detects a high resistance, but a circuit
breaker works when it detects a high voltage.
Answer:
A. A fuse must be replaced after use, but a circuit breaker can be
reset.
Explanation:
A fuse works by actually melting, so there is physical damage that interrupts conduction of current due to lack of conductive material.
The circuit breaker is a switch operated automatically when there is excess flow of current. It interrupts that way the flow of current, but can simply get reset (back to its original close position) once the problem that caused the overflow of current in the circuit is found.
This better agrees with answer A in the list of possible choices.
how does gravitational pull affect planets with the same mass but different distance from the sun?
Answer:
it just pulls them at the same time
Explanation:
Write one or two sentences to compare the internal energy of a molecular gas with the internal energy of a monatomic gas.
1-D Kinematics
A car starts at a position of -153 m
and undergoes a displacement of
512 m. What is its final position?
(Unit = m)
Answer:
hope it helps you...........
Two resistors connected in series (R1, R2) are connected to two resistors that are connected in parallel (R3,R4). The series-parallel combination is connected to a battery. Each resistor has a resistance of 10.00 Ohms. The wires connecting the resistors and battery have negligible resistance. A current of 2.00 A runs through resistor R1. What is the voltage supplied by the voltage source?
Explanation:
R1=R2=R3=R4=10 ohms
V=IR
V=2.10
V=20v
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
A 0.675 kg mass is attached to a
spring of spring constant 42.4 N/m,
pulled, and released. What is the
frequency of the resulting
oscillation?
(Unit = Hz)
Answer:
1.26
Explanation:
f=1/(2pi) square root k/m
f=1/(2pi) square root 42.4/.675
f=1.26 I just did this question and found this right
If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.
Answer:
a. It would shrink
b. It would expand
Explanation:
a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out
b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out
A 2,100-kg pile driver is used to drive a steel beam into the ground. The pile driver falls 5.00 m before coming into contact with the top of the beam, and it drives the beam 12.0 cm farther into the ground before coming to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.
Answer:
858375 N of force is exerted on the pile driver by the beam.
Explanation:
mass of the pile driver m = 2100 kg
distance of fall = 5 m
distance through which the beam is driven = 12 cm = 0.12 m
weight of the pile driver = mg
where g = acceleration due to gravity = 9.81 m/s^2
weight of pile driver = 2100 x 9.81 = 20601 N
work done by gravity in bringing the pile driver done the 5 m height is
work = weight x distance = 20601 x 5 = 103005 J
This work by gravity is also used to do work in driving the beam into the 12 cm depth.
The force exerted by the beam on the pile driver will be proportional to the force used to do the work in driving the beam through the 12 cm depth.
equating the works, we have
103005 = F x 0.12
F = 103005/0.12 = 858375 N of force
The vibrations of a string fixed at both ends are represented by y=16sin(πx/15 )cos(96πt). Where x and y are in cm and t in seconds. Then the phase difference between the points at x=13cm and x=16 in radian
Answer:
Explanation:
y = 16 sinπx/15 cos(96πt)
When t = 0
y = 16 sinπx/15
here πx/15 is phase of the point at x
if x = 13
Phase = 13π/15
if x = 16
Phase = 16π/15
Phase difference
= 16π/15 - 13π/15
= 3π/15
= π/5 radian .
A 2.2 kW stove burner operates on a 240 V household circuit.
Answer:
I = 9.17 A
Explanation:
We have,
Power of a stove is 2.2 kW
Voltage on which it operates is 240 V
Let us assume that it is required to find the current flowing in the circuit. Electric power is given by :
[tex]P=IV\\\\I=\dfrac{P}{V}\\\\I=\dfrac{2.2\times 10^3}{240}\\\\I=9.17\ A[/tex]
So, the current in the stove burner is 9.17 A.
The Enterprise goes into orbit around a mysterious planet. The ship moves at 4200 m/s in a circle of radius 4.91 x 10^7 m. What is the mass of the
planet?
Answer:
M = 1.3*10^25 Kg
Explanation:
Answer:
Explanation:
im not saying this bc of the person on top but its 1.3 and then 10^25 i done physics on acellus and i passed with an 90% and i have all of my notes and so the person on top of me was right :)
A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity
Answer:
[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 10 seconds
To Find:
Final velocity (v)
Explanation:
[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?
0.66 N
9.2 N
13 N
180 N
Answer is 9.2 N
Answer: Magnitude of the force exerted on the egg by the ground is 9.2N
Explanation:
Given the following :
Mass of egg (m) = 150g = 0.15kg
Height(h) from which egg is dropped = 3m
velocity of egg before hitting the ground (u) = 4.4m/s
Final velocity of egg (V) = 0
Time taken (t) = 0.072s
Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:
Momentum = mass × velocity
From Newton's second law:
Force = mass × change in Velocity with time ;
That is
F = m * ΔV / t
Inputting our values
F = 0.15 * (4.4 - 0) / 0.072
F = 0.15 × (4.4 / 0.072)
F = 0.15 × 61.11
F = 9.16N
F = 9.2N
Answer:
9.2 N
Explanation:
Just took practice quiz
Which object has the most gravitational potential energy?
O A. A 5 kg book at a height of 2 m
B. An 5 kg book at a height of 3 m
C. An 8 kg book at a height of 3 m
O D. A 8 kg book at a height of 2 m
SUBARU
Answer:
D
Explanation:
its the heaviest so i would assume its D
A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)
Options:
a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.
b) An arrow of magnitude 6.50 N points down the slope of the hill.
c) An arrow of magnitude 78.5 N points down the slope of the hill.
d) An arrow of magnitude 852.6 N points straight down.
Answer:
d) An arrow of magnitude 852.6 N points straight down.
Explanation:
The total mass of the two riders, m = 87.0 kg
The free body diagrams of the situation described are drawn and contained in the files attached to this solution.
Note that the weight of the toboggan will act directly downwards.
Therefore, the weight of the toboggan, W = mg
W = 87 * 9.8
W = 852.6 N
Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.
Is it necessary to convert time in its S.I unit while solving acceleration and velocity numericals
Answer:
yes
Explanation:
In any calculation, we make sure we use all quantity in it simplest s.i unit
for better understandingfor a clearer work analysisHope this will help
what are laws of newton
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction
Explanation:
Answer:
Newton's Law of Motion
1- Every object persists in its state of rest or uniform motion - in a straight line unless it is compelled to change that state by forces impressed on it.
2- Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration.
3- For every action, there is an equal and opposite reaction.
What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?
WILL GIVE BRANLIET PLS HELP!!!!! AT LEAST TAKE A LOOK!!!!! I REALLY COULD USE THE HELP!!! SHARE YO SMARTNESSS!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.
Answer:
λ = 6,108 10⁻⁷ m = 610.8 nm
λ = 5.513 10⁻⁷ m = 551.3 nm
Explanation:
Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression
d sin θ = m λ
where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference
In this exercise they give us several conditions
The first
the angle is 1.12º to the maximum m = 8
the distance between the slits d = 0.000250 m
of the initial equation
λ = d sin θ / m
λ = 0.000250 sin 1.12 / 8
λ = 6,108 10⁻⁷ m = 610.8 nm
The second
the distance from the slits to the screen is L = 302.0 cm = 3.020 m
the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5
in this case we use that the angle in the experiment is small
tan θ = y / L
tan θ = sin θ / cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
λ = d y / L m
we calculate
λ = 0.000250 0.0333 / (3,020 5)
λ = 5.513 10⁻⁷ m = 551.3 nm
The dimensional formula for specific latent heat is
Answer:
The dimensional formula for specific latent heat is L²/T²
Explanation:
The unit of specific latent heat is J/kg
an object experiences buoyant force of 15.9 n when immersed in a fluid of density 917 kg/m^3. what is the volume of the object?
Answer:
0.00176
Explanation:
Credit to the person above.
What is the formula for calculating the efficiency of a heat engine? Answers:
Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.
Answer:
6.67×10⁻⁸ cm³/g/s²
Explanation:
6.67×10⁻¹¹ Nm²/kg²
= 6.67×10⁻¹¹ (kg m/s²) m²/kg²
= 6.67×10⁻¹¹ m³/kg/s²
= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)
= 6.67×10⁻⁸ cm³/g/s²
help fast I want the correct answer please does spectral diffusion cause light to scatter
Answer: No
Explanation:
Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.
Scattering of light occurs when light passes through a rough path or a diffused surface.
But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.
Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.
Fluctuation in frequency does not mean diffraction of light or particles
Therefore, spectral diffusion does not cause light to scatter.
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
Would this be 5.58 g or 5.58 kg?
Answer:
Kg
Explanation:
Answer:
5.58 kg
Explanation:
The SI unit for mass is kg. A Newton is defined as:
N = kg m/s²
So the answer would be 5.58 kg.
A football player kicks a ball at a 30o angle from the ground with an initial velocity of 15 m/s. What is the final velocity of the ball when it hits the ground?
Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
[tex]T=\dfrac{2u\sin\theta}{g}[/tex]
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
[tex]T=\dfrac{2\times15\sin30}{9.8}[/tex]
[tex]T=1.5\ sec[/tex]
We need to calculate the final velocity of the ball
Using equation of motion
[tex]v=u+gt[/tex]
[tex]v=15+9.8\times1.5[/tex]
[tex]v=29.7\ m/s[/tex]
Hence, The final velocity of the ball is 29.7 m/s.