Answer: 6700m/s^2 E
Explanation:
Given the following :
Velocity of ball before being hit by a racquet = initial velocity(u) = 55m/s W
Velocity of the ball after being hit = final Velocity (v) = 45m/s E
Time of contact between ball and racquet (t) = 1.5 × 10^-2
The acceleration of a body is the change in Velocity of a body with time. It given by:
Acceleration (a) = [final Velocity(v) - initial velocity(u)] / time(t)
The westward direction is towards the left and thus Velocity takes a negative value, similarly, if it's towards the right, Velocity takes a positive value.
Therefore,
a = [45 - (-55)] / 1.5×10^-2
a = [45 + 55] / 0.015
a = 100 / 0.015
a = 6666.6666 m/s^2
a = 6700m/s^2 E
Since the value of acceleration is positive, the direction is towards the East (acceleration is in the direction of the ball's final Velocity).
calculate the wavelength of a wave if 5 complete waves occupy a length of 20m
The wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.
What is wavelength?Wavelength is defined as the space between waves' crests, particularly between electromagnetic or sound wave points. A recurring event's frequency is measured by how many times it occurs in a unit of time. To underline the difference from spatial frequency, it is also occasionally referred to as temporal frequency.
There is an inverse relationship between the frequency and the wavelength of the waves as the wavelength increases the frequency decreases and if the wavelength decreases the frequency increases.
Given that a wave has 5 complete waves occupying a length of 20m. The wavelength of the wave will be calculated as below:-
λ = Distance / frequency
λ = 20 / 5
λ = 4 meters
Therefore, the wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.
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What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon.
Answer:
The jug drowns because the density of the jug is more than that of the density of water.
Answer:
it gets force upwards .
as there is presence of atmospheric pressure in it which causes upthrust and push upwards.
why is urbanization a contribution to pollution?
Answer:
people in urban areas strip the soil of nutrition and makes it difficult to grow crops. people of urban areas consume more energy,food,and water. people in urban areas remove minerals and metals from the ground so, urbanization is a contribution to pollution .
Explanation:
it may help you and give me brainliest
Answer:
pollution and loss of trees not to mention how much electricity we use which doesnt benefit the world.
Explanation: because when we urbanize things we get rid of natural resources around us
Differences Between light year and astronomical unit in two points .
Answer:
A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.
Answer: A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc
Explanation:
Swamp coolers are effective because _____.
A. the water is colder than the air.
B. the water pulls heat from the room to undergo a phase change.
C. the thermal energy of the water is decreasing.
D. the water's latent heat of vaporization is being pulled from the air.
Answer:
D. the water's latent heat of vaporization is being pulled from the air.
Explanation:
A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.
In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.
Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.
The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.
The swamp coolers are typically made up of the following essential components, these are;
1. Float.
2. Blower.
3. Pump.
4. Evaporative pad.
5. Water supply valve.
Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.
Answer:
B and D
Explanation:
What is the magnitude of these two vectors: 101 m 60.0 degrees 85.0 m
Answer:
85.0 please I don't understand
A boy of mass 45kg sits 109cm to the left of seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?
Answer:
[tex]d_{2}[/tex] = 169 cm
Explanation:
Mass 1 = 45 kg => Force = 450 N
Mass 2 = 29 kg => Force = 290 N
According to principle of moments:
=> [tex]F_{1}d_{1} = F_{2}d_{2}[/tex]
Where [tex]F_{1}[/tex] = 450 N, [tex]d_{1}[/tex] = 109 cm and [tex]F_{2}[/tex] = 290 N
=> (450)(109) = 290[tex]d_{2}[/tex]
=> 49050 = 290[tex]d_{2}[/tex]
Dividing both sides by 290
=> [tex]d_{2}[/tex] = 169 cm
A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?
Answer:
we have to measure distances and time, possibly with an automated system since the values are very small
Explanation:
For this exercise we can use the relationship between momentum and momentum
I = ∫ F dt = Δp
F t = m [tex]v_{f}[/tex] - mv₀
In the exercise they indicate that the final speed is zero
F t = - m v₀
F = -m v₀ / t
With this equation we can find what measurements should be carried out.
To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.
During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.
In summary we have to measure distances and time, possibly with an automated system since the values are very small
Two straight, parallel wires a and b carry currents in opposite directions, and are separated by a distance d. The magnitude of the force exerted by each wire on a segment of length L of the other wire is F. The vector sum of these forces is
Answer:
Zero
Explanation:
The magnetic field due to the first wire on the second wire with current i₁ in the first wire at a distance d from the second wire is B₁ = μ₀i₁/2πd.
The magnetic force due to this field on the second wire of length segment, L and current i₂ is F₁ = Bi₂L = (μ₀i₁/2πd)i₂L = μ₀i₁i₂L/2πd = F
The magnetic field due to the second wire on the first wire with current i₂ in the first wire at a distance d from the second wire is B₂ = μ₀i₂/2πd.
The magnetic force due to this field on the first wire of length segment, L and current i₁ is F₂ = Bi₁L = (μ₀i₂/2πd)i₁L = μ₀i₁i₂L/2πd = F
Since their magnetic fields are in opposite directions, according to the right hand rule, their forces would also be in opposite directions.
So F₁ = F and F₂ = -F
So their vector sum F₁ + F₂ = F +(-F) = F - F = 0
HELPPPP!!!!!
At which point does the satellite have the most gravitational potential energy?
O A. Point A
O B. Point B
O C. Point
OD. Point D
Answer:
Since gravitational potential is generally defined to be zero at infinity
and gravity does work as an object moves from infinity in a gravitational field,
(the potential becomes more negative) the farther the satellite is from the attractive force the greater is its gravitational potential. Since point E is most distant from the attractive force it has the most gravitational potential.
The Gravitational potential energy connected to a planet's position within the gravitational field of a central object, such as a star or a larger planet, is referred to as its gravitational energy.
The gravitational potential energy is given by:
PE = -G × (M × m) ÷ r
Here, (G) is the gravitational constant, (M) is the mass of a planet, (m) is the mass of a planet, and distance (r).
From the given figure, points E and A are the farthest.
Hence, at points E and A satellite have the most gravitational potential energy
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Please someone to help me with this will be very grateful In a light bulb, how is electrical energy transformed into light? and in an LED, will it be the same?
Answer:
LED;
The energy of photons emitted by an LED is dictated by the band gap of the semiconductor used – the energy required to make an electron–hole pair. When an electron and hole recombine in a radiative process, a photon carries away the extra energy.
BULB
In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. ... 1, chemical potential energy is converted to electrical energy, which is immediately converted to light energy and heat energy
This flow of charge converts chemical potential energy into electrical energy. In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. bulb have a fillament but LED have no filament they produce energy through clod process but bulb have a filament and they produce energy through hot process
Explanation:
This progression of charge changes over substance expected vitality into electrical vitality. In the light, the progression of charge through the fiber warms it up and makes it shine. Along these lines, the light believers electrical vitality to warm vitality and light vitality.
hope soo u can understand my point
The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration. A. 0.24 g
Answer:
Magnitude of the acceleration(g) = 9.7 meters/second²
Explanation:
Given:
Height of tower = 56 meter
Time taken = 3.4 second
Final velocity (v) = 33 meters/second
Initial velocity (u) = 0 meters/second
Find:
Magnitude of the acceleration(g)
Computation:
Using first equation of motion:
v = u + at
Magnitude of the acceleration(g)
v = u + gt
33 = 0 + g(3.4)
g = 33 / 3.4
g = 9.7 meters/second²
Magnitude of the acceleration(g) = 9.7 meters/second²
Which vector has an x-component with a length of 4?
Answer:
C.) vector C
Explanation:
From the graph provided:
Four vectors are present :
Vectors a, b, c and d.
The x-component of the vector is its magnitude along the x-axis.
Taking the coordinate of each vector:
Vector a = (1,4) : length of x- component = 1
Vector b = (1, 1) : length of x- component = 1
Vector c = (4, -4) : length of x- component = 4
Vector d = (-3, 4) : length of x- component = - 3
Therefore, vector c has an x-component length of 4
magnetic moment is scaler or vector??
Sound travels at approximately 1,500 m/s in sea water. How far will a sonar pulse travel in 90 s?
Answer:
135,000 m
Explanation:
(1500 m/s) (90 s) = 135,000 m
The distance travelled by sonar pulse will be 135,000 m. Distance is a numerical representation of the distance between two objects or locations.
What is wavelength ?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometers, and other units since it is a distance measurement.
The distance travelled by sonar pulse is found as;
[tex]\rm d = v \times t \\\\ \rm d = 1500\times 90 \\\\ \rm d = 135,000 \ m[/tex]
Hence, the distance travelled by sonar pulse will be 135,000 m.
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A projectile is fired with an initial speed of 60.3 m/s at an angle of 34.2 above the horizontal on a long flat firing range.
Part A: Determine the maximum height reached by the projectile.
Part B: Determine the total time in the air.
Part C: Determine the total horizontal distance covered (this is, the range).
Part D: Determine the speed of the projectile 1.20 s after firing.
Part E: Determine the direction of the projectile 1.20 s after firing.
Answer:
A.) H = 58.6 m
B.) T = 6.92 s
C.) 345.12 m
D.) V = 22.13 m/s
E.) Ø = 32.1 degree
Explanation:
Given that the
initial speed U = 60.3 m/s
Angle Ø = 34.2 degree
A.) At maximum height, final velocity V is equal to zero.
Using the third equation of motion under gravity.
V^2 = U sin Ø^2 - 2gH
Substitute for U and g. Where g = 9.8 m/s^2
0 = (60.3 sin 34.2)^2 - 2 × 9.8 × H
1148.78 = 19.6 H
H = 1148.78/19.6
H = 58.6 m
B.) To Determine the total time in the air, let us use the formula
V = UsinØ - gt
At maximum height, V = 0
t = UsinØ/g
Total time T = 2t
Therefore, T = 2UsinØ/g
T = (2 × 60.3 × sin 34.2)/9.8
T = 67.79/9.8
T = 6.92 s
C.) To determine the total horizontal distance covered which is the range, we will use second equation of motion.
S = UcosØT - 1/2gt^2
Where S = range R
g = 0, since the range is not a vertical distance
T = total time
Substitute all the parameters into the formula
R = 60.3 cos 34.2 × 6.92
R = 345.12 m
D.) After 1.2 s firing,
V = UsinØ - gt
Where t = 1.2 s
Substitute into the formula
V = 60.3 × sin34.2 - 9.8 × 1.2
V = 33.89 - 11.76
V = 22.13 m/s
Therefore the speed of the projectile 1.20 s after firing is 22.13 m/s
E.) The direction will be determined by using the formula
t = VsinØ/ g
Cross multiply
VsinØ = gt
Make SinØ the subject of formula
SinØ = gt/V
SinØ = (9.8×1.2)/22.13
Sin Ø = 11.76/22.13
Sin Ø = 0.53
Ø = sin^-1( 0.53 )
Ø = 32.1 degree
the dimension of relative density and tension
Answer:
Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.
Explanation:
The dimension of relative density:-
Relative Density of a Substance (R.D.) = Substance Density / Water Density.
Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.
For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).
Tension:- Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.
Please!!! I need some help!!! I will give Brainliest To anyone who truly helps.
Determine the net force charge acting at q1 (+ 2.0 × 10-5C), caused by q2 (-4.0 × 10-5 C) and q3 (-4.0 × 10-5 C). Be sure to include a free body diagram representing the force acting at q1 in your solution. Determine the net electric field acting at q1.
Answer:
Please INCLUDE a picture.
Explanation:
You did not include a picture, so there is no way to tell how the charges will interact with each other.
Please INCLUDE a picture.
The net force acting on q1 is 3.2 N to the right.
The force on q₁ due to q₂ is:
F1 = k * q₁ * q₂ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₂, which is 0.1 m
Plugging in the values, we get:
F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²
= 6.4 N
The force on q₁ due to q₃ is:
F₂ = k * q₁ * q₃ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₃, which is 0.2 m
Plugging in the values, we get:
F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²
= 16 N
The net force on q₁ is the sum of F₁ and F₂:
Fnet = F₁ + F₂
= 6.4 N + 16 N
= 22 N
The net force on q1 is to the right because both F₁ and F₂ are to the right.
Net electric field
The net electric field acting on q1 is 3.2 N/C to the right.
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Neptune moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the eccentricity is 0.0086. Find the perihelion distance of Neptune from the sun. Round your answer to the nearest kilometers.
Given that,
Eccentricity = 0.0086
Suppose, The length of half of the major axis is [tex]1\times10^{9}\ km[/tex]
We need to calculate the distance from the center to the foci
Using formula of eccentricity
[tex]e=\dfrac{c}{a}[/tex]
[tex]c=e\times a[/tex]
Where, e = eccentricity
a = major axis
c = the distance from the center to the foci
Put the value in to the formula
[tex]c=0.0086\times1\times10^{9}[/tex]
[tex]c=8600000[/tex]
We need to calculate the perihelion distance of Neptune from the sun
Using formula of distance
[tex]d=a-c[/tex]
Put the value into the formula
[tex]d=1\times10^{9}-0.0086\times10^{9}[/tex]
[tex]d=991400000\ km[/tex]
Hence, The perihelion distance of Neptune from the sun is 991400000 km.
A machine can never be 100% efficient because some work is always lost due to which factor?
A.friction
B.gravity
C.static
D.input force
Answer:
A. can never be efficient due to friction
HEY!!
Answer:
A. friction
Explanation:
Now if we obtain output work same as input energy then it is 100% efficient.
but this is only possible when we have no energy loss while it is not possible due to many reasons:
one of the main cause of energy loss is friction
A machine can never be 100% efficient because some work is always lost due to the lack of materials or equipment that would convert work by 100%. but so far, no machine has got 100% efficiency.
So when the machine are working there must be a friction between its working parts due to which the out-input energy is lost in different parts and hence we can never be 100% efficient machine.
HOPE IT HELPS!!
The volume of an object as a function of time is calculated by v = At3+B÷t where t is time measured in seconds and v is in cubic metres. Determine the dimension of the constants A and B.
Answer:
A = m³/s³ = [L]³/[T]³ = [L³T⁻³]
B = m³s = [L³T]
Explanation:
We have the equation:
V = At³ + B/t
where, the dimensions of each variable are as follows:
V = m³ = [L]³
t = s = [T]
substituting these in equation, we get:
m³ = A(s)³ + B/s
for the homogeneity of the equation:
A(s)³ = m³
A = m³/s³ = [L]³/[T]³ = [L³T⁻³]
Also,
B/s = m³
B = m³s = [L³T]
Wood has chemical energy which can be used to generate thermal and radiant energy when burned in a fire place which best explains what happens to the total amount of energy in this scenario
Answer:
c i took the test
Explanation:
The total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.
What happens to the total amount of energy in this scenario?The energy present in the wood change into other forms of energy such as heat and radiant energy. We know that during a reaction, matter is transformed into another form with the release of different types of energy.
So we can conclude that he total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.
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Consider a transition at 5000 Å with a width of 1 Å and a cavity 2 cm3 in volume. How many electromagnetic modes exist in this frequency band for this cavity?
Answer:
total number of modes is 8
Explanation:
attached here is the calculations
Using the free-body diagram, calculate the net force acting on the sled. Is the sled in a state of dynamic equilibrium?
The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.
Explanation:
The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.
Since the net force acting on the sled is zero, the sled is in some state of equilibrium...
Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.
Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.
From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.
So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.
Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.
Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...
EXTRA
Given is that the sled is moving with a constant speed.
No imagine two situations and try to predict what will happen.... Here we go...
Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.
Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...
Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.
Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.
Answer:
yes
Explanation:
edg 2020
Two identical long wires of radius a = 2.80 mm are parallel and carry identical currents of i = 5.00 A in opposite directions. Their center-to-center separation is W = 19.0 cm. Neglect the flux within the wires but consider the flux in the region between the wires. What is the inductance per unit length of the wires?
Answer:
Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
Explanation:
Radius of the wire, a = 2.80 mm
Currents carried by each of the wires, i = 5.00 A
Center-to-Center Separation, W = 19.0 cm
The flux in the wires is given by the equation, ∅ = Li
The Net flux of the region between the wires is given by the equation:
[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]
Divide both sides by l to get the net flux per unit length
[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57 The 5-number summary is nothing, nothing, nothing, nothing, and nothing, all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)
Answer:
The 5-number summary is
1. Median = 0.93 W/kg
2. Lower quartile = 0.69 W/kg
3. Upper quartile = 1.16 W/kg
4. Minimum value = 0.54 W/kg
5. Maximum value = 1.42 W/kg
Explanation:
We are given the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones.
1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57
What is 5-number summary?
A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.
These statistical characteristics are:
1. Median
2. Lower quartile
3. Upper quartile
4. Minimum value
5. Maximum value
1. Median:
Arrange the data in ascending order
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
(n+1)/2 gives the median value of the data set.
(11 + 1)/2 = 6th position
Therefore, 0.93 W/kg is the median of the data set.
2. Lower quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The lower quartile is the median of the lower half of the data set.
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
The median is 6/2 = 3rd position
Therefore, the lower quartile of the data set is 0.69 W/kg
3. Upper quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The upper quartile is the median of the lower half of the data set.
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The median is 6/2 = 3rd position
Therefore, the upper quartile of the data set is 1.16 W/kg
4. Minimum value:
The minimum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the minimum value of the data set is 0.54 W/kg
5. Maximum value
The maximum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the maximum value of the data set is 1.42 W/kg
The box plot is illustrated in the attached diagram.
What will be the resistance Rstretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.
Answer:
Hence, the resistance of the stretched wire will be four times that of the original wire.Explanation:
The resistance of a material is expressed as R = ρL/A
Volume of the original material V = Area * Length = A*L
ρ is the resistivity of the material
R is the resistance
A is the cross sectional area
L is the length of the wire.
If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.
This means V = V₂
A*L = = A₂*L₂
A*L = A₂*(2 L)
A = 2 A₂
A₂ = A/2
The new resistance of the material Rf = ρL₂/A₂
R₂ = ρ(2 L)/(A/2)
Rf = 2ρL * 2/A
Rf = 4(ρL/A)
Since R = ρL/A
R₂ = 4R
Hence, the resistance of the stretched wire will be four times that of the original wire.
If the wire is stretched to twice its original length, the new resistance would be quadrupled.
The resistance (R) of a wire is given by:
[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]
Since the wire is stretched, the new length (L₁) is twice its original length, hence:
L₁ = 2L
An increase in length affects the area, the new area (A₁) is:
initial volume = volume after stretch
AL = A₁L₁
AL = A₁(2L)
A₁ = A/2
The resistance of the stretched wire (R₁) is:
[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]
Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.
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Describe your acceleration as you skate down your neighborhood sidewalk.
Answer: when you increase or decrease your speed.
Explanation:
Moving a skate at rest, you need to apply force in order to cause acceleration.
F = ma Where
F = force applied
m = mass of the skate
a = acceleration
The initial velocity u will be equal to zero and the skate will acceleration to a certain velocity.
as you skate down your neighborhood sidewalk, you will accelerate when you increase your speed. Because
Acceleration is the rate of change of velocity. That is,
Acceleration = change in velocity/ time.
And also, you will decelerate when you reduce the speed or velocity down your neighborhood sidewalk.
What is the overall charge of the wall?
Answer:
The overall charge on the wall is zero.
Explanation:
Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.
The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rotated by 90 degrees. Only one of two waves is shown at a time when placing wave in standard wave format.
Answer:
Transverse wave and Longitudinal wave and Electromagnetic wave
Explanation:
An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion. Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion. Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc. Most electromagnetic waves are transverse in nature.Answer:
Transverse wave and Longitudinal wave and Electromagnetic wave
Explanation: