Answer:
1.99×10¯¹⁴ M
Explanation:
We'll begin by writing the balanced dissociation equation of pyridine. This is illustrated below:
C₅H₅N + H₂O <=> C₅H₆N⁺ + OH¯
From the balanced equation above,
1 mole of C₅H₅N produced 1 mole of OH¯.
Therefore, 0.502 M C₅H₅N will also produce 0.502 M OH¯.
Finally, we shall determine the concentration of hydronium ion, H₃O⁺ in the solution. This can be obtained as follow:
Concentration of Hydroxide ion [OH¯] = 0.502 M
Concentration of hydronium ion [H₃O⁺] =?
[H₃O⁺] [OH¯] = 1×10¯¹⁴
[H₃O⁺] × 0.502 = 1×10¯¹⁴
Divide both side by 0.502
[H₃O⁺] = 1×10¯¹⁴ / 0.502
[H₃O⁺] = 1.99×10¯¹⁴ M
Thus, the concentration of hydronium ion, H₃O⁺ in the solution 1.99×10¯¹⁴ M
When lava cools outside the Earth, ____ igneous rocks are formed
Answer:The rock forms large crystals
Explanation:
list 5 island in the Philippines
Answer:
Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.
Explanation:
I hope this helps.
coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....
Can some one help I'm lost iam being timed:( Show using two conversion factors how you would convert from 0.020 kg into mg
Answer:
20000 Mg
Explanation:
A continuously stirred tank reactor is designed to remove the hazardous waste compound trichloroethylene (TCE) from industrial wastewater. The tank is 3250 liters. The wastewater flows into the tank at 200 L/min with a TCE concentration of 25 mg/L. The reactor decays TCE at a reaction rate of 0.20 min-1 . What is the steady-state concentration of TCE in the treated water leaving the reactor
Answer:
the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Explanation:
Given that;
Tank volume v = 3250 liters
wastewater flows into the tank Q = 200 L/min
TCE concentration Co= 25 mg/L
reactor decays TCE at a reaction rate K = 0.20 min-1
mass balance
we know that;
Accumulation = inflow - outflow ± generation
⇒dc/dt = QCo - Qc ± rc.V
now at a steady state; dc/dt = 0
so
0 = QCo - Qc + rcV
where rc = -kc
0 = QCo - Qc - kcV
Qc + kcV = QCo
c(Q + kV) = QCo
c = QCo / (Q + kV)
so we substitute
c = (200 × 25) / (200 + (0.2×3250))
c = 5000 / 850
c = 5.88 mg/L
Therefore, the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Richard sketched models of two different neutral isotopes of oxygen. If the
isotope models are accurate, which statement might be true? (Refer to the
periodic table if necessary.)
A. One shows 7 protons, and one shows 9.
B. One shows 8 neutrons, and one shows 9.
C. One shows 8 electrons, and one shows 9.
D. One shows 8 protons, and one shows 7.
Answer:
its b
Explanation:
just did the test on A P E X
If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.
What is isotope?A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.
The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
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What causes lightning?
A. Build up of electric charges in the clouds
B. Flow of electric charges among clouds
C. Light energy created in the clouds
D. Reflection of light by the clouds
Answer:
B.
Explanation:
Not sure if this is correct if not sorry.
Surface tension is a force that affects....
A. Gases
B. Plasmas
C. Solids
D. Liquids
Answer:
option A iis the right answer
what is its molar concentration?
Answer:
The correct answer is - the number of moles of solute per liter of solution.
Explanation:
The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:
M = n/v
Where n is the number of moles of the solute and,
v is the volume of solution (in liters normally)
It is worldwide used measurment for the concentration.
1. How would you describe what red cabbage juice is?*
(1 Point)
Acid
Neutral
Alkali
Indicator
Salt
Just like cans of soup, atoms of the same element often have different masses. These different varieties are called isotopes. In the Average Atomic Mass Gizmo, you will learn how to find the average mass of an element using an instrument called a mass s
Answer:
ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
Explanation:
This question is all about the way in which mass spectroscopy works. Mass spectroscopy Is one of the techniques in spectroscopy which is used in the identification of chemical compounds.
Mass spectroscopy works based on the principle of ionization. For a mass spectroscopy to start ionization must first occur that is to say this is the first step in the identification of compound in mass spectroscopy.
The following steps are involve in mass spectroscopy;
=> Ionization: the molecules of the sample are first ionized. The ions formed here are positive ions.
=> Acceleration: the ions in step one are accelerated.
=> Deflection: the smaller ions get deflected more than the bigger ions. The magnetic field is used in the deflection of this ions.
=> Detection: the ions are then detected.
Therefore, to answer the question, the ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
There is a 2 percent defect rate at a specific point in a production process. If an inspector is placed at this point, all the defects can be detected and eliminated. The inspector would cost $10 per hour and could inspect units in the process at the current production rate of 48 per hour.
If no inspector is hired and defects are allowed to pass this point, there is a cost of $11 per defective unit to correct the defects later on.
Assume that the line will operate at the same rate (i.e., the current production rate) regardless of whether the inspector is hired or not.
a. If an inspector is hired, what will be the inspection cost per unit? (Round your answer to 3 decimal places.)
Inspection cost per unit _____________$
b. If an inspector is not hired, what will be the defective cost per unit? (Round your answer to 3 decimal places.)
Defective cost per unit _____________$
c. Should an inspector be hired based on costs alone?
Answer:
A) $0.208 per unit
B) $0.220 per unit
C) An inspector should be hired
Explanation:
percentage of defect rate = 2% = 0.02
cost of inspector = $10 per hour
production rate = 48 per hour
cost of not hiring an inspector = $11
A) Determine the inspection cost per unit if an inspector is hired
= cost of inspector / production rate
= 10 / 48 = $0.208 per unit
B) Determine the defective cost per unit if an Inspector is not hired
= cost of not hiring an inspector * percentage of defect rate
= 11 * 0.02
= $0.220 per unit
C) Inspection cost < defective cost i.e. $0.208 < $0.220 hence an inspector should be hired
After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the Run Experiment button at the end or by clicking the Overview tab and returning to the Experiment tab to select Run Experiment. There are nine reactions you can explore on your own. Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much SO2 would you need to completely react with 6.00 g of O2 such that all reactants could be consumed
Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]
[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]
Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex] of [tex]SO_2[/tex]
Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]
Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.
Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
Answer:
If your asking what golds natural state of matter is it's solid.
Explanation:
Answer:
the answer is soild
Explanation:
i did it on edge :)
Determine the mass of AgCl(s) produced when 0.91 g of AgNO3 in an aqueous solution reacts with excess NaCl aqueous solution as shown below: AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) i Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10")
Answer:
0.77 g
Explanation:
Step 1: Write the balanced equation
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
Step 2: Calculate the moles corresponding to 0.91 g of AgNO₃
The molar mass of AgNO₃ is 169.87 g/mol.
0.91 g × 1 mol/169.87 g = 5.4 × 10⁻³ mol
Step 3: Calculate the moles of AgCl produced from 5.4 × 10⁻³ moles of AgNO₃
The molar ratio of AgNO₃ to AgCl is 1:1. The moles of AgCl produced are 1/1 × 5.4 × 10⁻³ mol = 5.4 × 10⁻³ mol.
Step 4: Calculate the mass corresponding to 5.4 × 10⁻³ moles of AgCl
The molar mass of AgCl is 143.32 g/mol.
5.4 × 10⁻³ mol × 143.32 g/mol = 0.77 g
**will give brainlists if correct answer***
Predict all of the products of the incomplete reaction shown below.
K+ Cl2 →
A)KCIO3
B)K2
С)КСІ
D)KCI2
Answer:
C)
Explanation:
tell me how is your life as a youngster
Answer:
ruthless, my style as a juvenile
ran with a gang, slanged in the meanwhile
Explanation:
An unknown compound contains only C , H , and O . Combustion of 5.90 g of this compound produced 11.8 g CO2 and 4.83 g H2O . What is the empirical formula of the unknown compound
Answer:
C₂H₄O
Explanation:
In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.
Moles CO₂ = Moles C:
11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =
3.216g C
Moles H₂O = 1/2 moles H:
4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =
0.537 mol H * (1g/mol) = 0.537g H
Mass O to find moles O:
5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O
Ratio of atoms -Dividing in 0.134 moles-:
C = 0.268mol C / 0.134 mol O = 2
H = 0.537mol H / 0.134 mol O = 4
O = 0.134mol O / 0.134 mol O = 1
Empirical formula is:
C₂H₄OWhat are mand n in the rate law equation?
Rate = k[A]”[B]"
A (they are experimentally determined exponents)
In general chemicals enter Ecosystems through which two spears
Answer:
biosphere and lithosphere
Explanation:
The biosphere is described as the zone of life on Earth. It is a sum of all ecosystems. The biosphere is composed of living organisms and non-living factors.
The lithosphere is the outer part of the Earth such that this part is rocky. The lithosphere is made up of the brittle crust.
In general, chemicals enter Ecosystems through the biosphere and lithosphere.
7. Consider an element with 2
electrons on the 1st shell and 4
electrons on the 2nd shell. What
element is likely to have that Bohr
model?
Answer:
Carbon (C)
Explanation:
The electron configuration of Carbon is 2-4.
What is the normal pH range of a Base?
Answer:
7.35 - 7.45
Explanation:
The pH scale ranges from 0 (strongly acidic) to 14 (strongly basic or alkaline). A pH of 7.0, in the middle of this scale, is neutral. Blood is normally slightly basic, with a normal pH range of about 7.35 to 7.45. Usually, the body maintains the pH of blood close to 7.40.
Hope this helps
Answer:
The normal pH range if a base is more than 7
Explanation:
Basideally the pH range goes from 0-14 in which
Acidic range is :0-7
Neutral :7
Base : 7 - 14
I need help please please
Answer:
B should be the answer, and ur low-key valid lol
Explanation:
Can someone please rephrase this question, I dont understand what it is asking for.
Which disease might have cures developed as a result of their understanding of structure and function of protein?
Answer:
Which infection may have fixes created because of their comprehension of construction and capacity of protein?
HELP!!!! Which of the following substances is a major component in acid rain?
A) KOH
B) NH3
C) SO2
D) NaOH
Answer:
(C) SO2.
SO2 is known as sulfur dioxide.
The below information about acid rain and SO2’s involvement is from epa.gov:
“Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents. The SO2 and NOX react with water, oxygen and other chemicals to form sulfuric and nitric acids. These then mix with water and other materials before falling to the ground.”
Explanation:
DIRECTION: Supply the missing information about the scientist listed in the graphic
organizer.
HELP ME PLEASSEEEE
I'll give you brainliest I promise
Answer:
The missing information or their role in the discovery of the cell is as follows:
Robert Hooke: He was the first scientist to called cells to tiny box-like cavities he saw in cork and illustrated as cells.
A. Leeuwenhoek: he was a microscopist and microbiologist who used microscopes and observed many other living cells. He called animalcules to these single-cell living organisms later used to prove that cells are the fundamental unit of life.
Schwann and Schleiden: They presented the theory that suggested that the cells are basic building blocks of all living things.
Virchow: He observed that the cell dividing and come from pre-existing cells.
How many moles of "02" are in a 192g sample of O2? *
1
2
3
4
5
6
7
Answer: The number of moles of [tex]O_2[/tex] are 6.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
Given mass = 192 g
Molar mass = 32 g/mol
[tex]\text{Number of moles}=\frac{192g}{32g/mol}=6mol[/tex]
The number of moles of [tex]O_2[/tex] are 6.
Convert the volume, nm^3, to liters (L) by using the box dimensions of 4nm x 8.75nm x 10nm. Use the conversion factor of 1 L = 1 dm^3. Do not convert directly from nm^3 to dm^3
Answer:
[tex]V=3.50x10^{-22}L[/tex]
Explanation:
Hello there!
In this case, given the dimensions of the box, we first compute the volume by multiplying each side:
[tex]V=4nm*8.75nm*10nm=350nm^3[/tex]
Next, we apply the following conversion factor in order to obtain the corresponding liters:
[tex]V=350nm^3*(\frac{1m}{10^9nm} )^3*\frac{1000L}{1m^3} \\\\V=350nm^3*\frac{1m^3}{10^{27}nm^3} *\frac{1000L}{1m^3}\\\\V=3.50x10^{-22}L[/tex]
Best regards!
A silver nitrate solution contains 14.77 g of primary standard AGNO3 ( Molecular weight 169.87) in 1.00 L. What volume of this solution will be needed to react with 0.2631 g of NaCl ( Molecular weight 58.44) ?
Answer:
[tex]V=5.2 mL=0.052L[/tex]
Explanation:
Hello!
In this case, since the chemical reaction between silver nitrate and sodium chloride is:
[tex]AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)[/tex]
We can see there is a 1:1 mole ratio between each solution; thus, we first compute the moles of each reactant considering their molar masses:
[tex]n_{AgNO_3}=14.77g*\frac{1mol}{169.87g}=0.087molAgNO_3\\\\ n_{NaCl}=0.2631g*\frac{1mol}{58.44}=0.0045molNaCl[/tex]
Now, since the concentration of the silver chloride solution is 0.087 M, we may assume that the concentration of the NaCl solution is the same, so we can compute the volume as shown below:
[tex]V=\frac{n_{NaCl}}{M}=\frac{0.0045mol}{0.087mol/L}\\\\V=0.052L[/tex]
Or:
[tex]V=5.2 mL[/tex]
Best regards!
The volume of solution needed to react with 0.2631 g of NaCl is 0.052 L.
How we calculate the volume?Volume of the solution will be calculated by using the below formula:
M = n/V, where
M = concentration in terms of molarity
n = no. of moles
V = volume
Given chemical reaction is:
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
First we calculate the moles of given reactants by using the formula:
n = W/M , where
W = given mass
M = molar mass
Moles of AgNO₃ = 14.77g / 169.87g/mole = 0.087 mole
Moles of NaCl = 0.2631g / 58.44g/mole = 0.0045 mole
Concentration of AgNO₃ = 0.087 mole / 1L = 0.087M
From the stoichiometry of the reaction it is clear that mole ration of AgNO₃ & NaCl is 1:1. So, we take the concentration of NaCl is equal to the concentration of AgNO₃ and calculate the volume by using the above formula as:
Volume of NaCl = 0.0045mole / 0.087M = 0.052 L
Hence, 0.052 L is the required volume of NaCl.
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Early chemists, known at the time as alchemists, had a difficult time understanding the Law of Conservation of Mass. Using the burning of wood as an example, what property of matter made this law difficult for early scientists to understand?
The law of conservation of mass states that, for any isolated system, the mass can neither be created nor be destroyed
After burning a log, the remains that are left behind after it burns are lesser than what would initially seem. There is a difference in mass before the burning of the log after the burning of the log. This seems like a violation of the law of conservation of mass, which would have made it difficult for early chemists to understand it. But if we consider the surroundings as a system then we can see that the mass that is lost in burning is actually converted into smoke and energy or forming other forms of substances. Then considering the whole system we can see that the mass and energy are conserved and interrelated.learn more about conservation of mass and energy:
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How many grams of silver nitrate are needed to prepare 0.125 M solution in 250.0 mL of water?*
(1 Point)
AgNO₃
Ag
= 107.868 8
mol
N = 14.0078
mol
8
0 = 15.999
mol
0.313 g
169.872 g
0.0849 g
5.31 g
O 31.3 g
Answer:5.3 grams AgNO3
Explanation:
To solve your problem, take a look at the definition of molality (m):
moles of solute/kg of solvent
You are given the grams of solvent (water) to find the grams of silver nitrate.
First, convert 250 grams to kg:
250 g * 1 kg / 1000g = 0.250 kg
Now that you have the kg of solvent, you can solve for the moles of solute:
kg of solvent * molality = moles of solute
0.250 kg * 0.125 m = 0.03125 mol AgNO3
You can convert the number of moles to grams using the molar mass of AgNO3, which is 169.872 g/mol:
moles of solute * molar mass of solute = grams of solute
0.03125 mol AgNO3 * 169.872 g/mol = 5.3085 g
Because your question provides two significant digits, you must round this number to get the final answer:
5.3 grams AgNO3
I hope this helps!