The hybrid orbital set used by the central atom in no3- is_____ and why?

a. sp
b. sp3
c. SP2
d. sp3d2
e. sp3d

Answer:

The pressure of the gas is kept constant. If the Kelvin temperature of the gas is doubled, the volume of the gas is. O 1.

The energy of a photon that would move an electron from level 2 to level 5 : B. 4.8 eV

The electron energy at the nth shell can be formulated:

Rh = constant 2.179.10⁻¹⁸ J

So the electron transfer energy (ΔE)

ΔE = E final- E initial

energy at n=2(level 2) = -5.3 eV

energy at n=5(level 5) = -0.5 eV

So the energy absorbed :

[tex]\tt \Delta E=-0.5-(-5.3)=-0.5+5.3=4.8`eV[/tex]

The energy required to move an electron from level 2 to level 5 is 4.8 eV.

According to the Bohr model of the atom, an electron moves from a lower to a higher energy level when it absorbs energy. The same energy is released when the atom returns to ground state.

When an electron from level 2 to level 5, the energy of the photon required is;

ΔE = E5 - E2 = -0.5eV - (-5.3eV)

ΔE = 4.8eV

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Answer:

B. LZAQD

A. Younger than A but older than Q

Explanation:

To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.

According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.

Explanation:

To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. ... The halogens tend to be very reactive, while the noble gases are in no way reactive and don't bond easily, if at all.

Answer:

c

Explanation:

Answer:

66.7%

Explanation:

The reaction for the titration of the excess ferrous ion is:

We calculate the moles of Fe⁺² from the used moles of KMnO₄:

Then we substract those 0.30 mmol from the original amount used:

The reaction between ferrous ammonium sulfate and MnO₂ is:

So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:

Then we convert MnO₂ to Mn₃O₄, using the reaction:

Finally we convert Mn₃O₄ moles to grams:

And calculate the percent

Answer:

the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

Explanation:

The computation of the full efficiency in kilometers per liter is shown below:

39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles)  × (1 gallon ÷ 3.79 L)

Now cut the opposite miles and gallons

So, the fuel efficiency would be

= 16.561 kilometers per liter

Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

Answer:

Option A. The carbocation accepts a pair of electrons.

Explanation:

A carbocation is defined as a positively charged carbon, which is bound to 3 substituents. Since it has no electrons  nonbonding, it only has six electrons in its valence shell. With only six electrons in its valence shell, a carbocation is a powerful electrophile (and Lewis acid) and can react with any nucleophile that is found.

Carbocations are proposed as intermediates in many  organic reactions. They also work like free radicals, which are electron-deficient species.

Same as free radicals, the carbocations are stabilized by alkyl substituents.

Answer:

See image attached

Explanation:

The reaction of toluene with alkaline potassium permanganate in the presence of heat leads to the oxidation of the -CH3 to give benzoic acid.

Reaction benzoic acid with HNO3/H2SO4 yields the nitronium ion (NO2+).

Recall that -COOH is a metal director and deactivated the ring towards electrophilic substitution hence the m-nitrobenzoic acid is formed.

Reaction with FeBr3/Br2 yields the product shown in the image attached.

Explanation:

Generally, temperature increases the rate of any chemical reaction considerably.

In a dissolution process, the solute is solvated in the solvent. Solutes are usually the solids or liquids being dissolved in the solution.

Answer:

the solid materials will disappear after mixing with a liquid material

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Answer: go fk your dad you fkin whor

Suppose of sodium chloride is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Be sure your answer has the correct number of significant

Answer:

1.9 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the balloon

According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.

V₁ / n₁ = V₂ / n₂

V₂ = V₁ × n₂ / n₁

V₂ = 2.5 L × 3.0 mol / 4.0 mol

V₂ = 1.9 L

The cellular respiration process, which generates ATP as the final result, employs oxygen and sugar as reactants. So, the correct option is A.

Cellular respiration is the process by which organisms combine oxygen with food molecules, channeling the chemical energy from those resources into life-sustaining activities while eliminating carbon dioxide and water as waste.

Both oxygen and glucose are reactants in the mobile respiratory system. ATP is the primary component of mobile respiration; waste products include carbon dioxide and water.

Oxygen might be present or absent while cells are respiring. Nonetheless, the activity is essentially known as "cellular respiration" because the cell seems to "respire" by consuming molecular oxygen (as an acceptor of electron) and exhaling carbon dioxide (as an end product).

Therefore, the correct option is A.

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Your question is incomplete, most probably the complete question is:

The process shown in the diagram produces oxygen and sugar. Which

process uses oxygen and sugar as reactants?

Chloroplast

Mitochondrion

Sugar

CO, +H,0

ATP

Heat

Respiration

A. Cellular respiration

B. Water cycle

c. Transpiration

D. Photosynthesis

The internal energy of a system : 21.9 kJ

The laws of thermodynamics 1 state that energy can be changed but cannot be destroyed or created  

The equation is:  

ΔU=Q+W    

Energy owned by the system is expressed as internal energy (U)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

The system absorbs 14.73 kJ⇒Q=+14.kJ

The system compressed⇒work done on the gas⇒W=+

W=-PΔV

[tex]\tt W=-1.54(1-5.720)\\\\W=7.2688[/tex]

[tex]\tt internal~energy(\Delta U)=Q+W\\\\\Delta U=14.73+7.2688\\\\\Delta U=21.9[/tex]

Answer:

H3PO4 + 3NaOH ==> Na3PO4 + 3H2O

The balanced equation for the given reaction is [tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization.

In a water reaction, neutralization means that there is no excess of hydrogen or hydroxide ions in the solution.

A neutralization reaction occurs when an acid and a base react to form water and a salt through the combination of H+ ions and OH- ions. The pH of neutralization of a strong acid and a strong base is 7.

Three moles of sodium hydroxide are required for one mole of phosphoric acid. The balanced equation tells us the following: 1 mol of H3PO4 reacts with 3 mol of NaOH.

It can be written as

[tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

Thus, this is the balanced equation for the given neutralizing reaction.

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Answer:

4

Explanation:

The Balmer series refers to a series of spectral emission lines of the hydrogen atom arising from electronic transitions from any higher level and terminating at the the energy level n= 2.

Using the relation;

1/λ = 1.09737*10^7 (1/2^2 -1/n^2initial)

We now have;

1/486 *10^-9 = 1.09737*10^7 (1/2^2 -1/n^2initial)

0.1875 = 1/2^2 -1/n^2initial

1/n^2initial = 1/2^2 - 0.1875

1/n^2initial = 0.0625

n^2initial = 16

ninitial = 4

Answer:

Crystalline solids have well-defined edges and faces, diffract x-rays, and tend to have sharp melting points. In contrast, amorphous solids have irregular or curved surfaces, do not give well-resolved x-ray diffraction patterns, and melt over a wide range of temperatures.

Explanation:

Hope this helped!

Answer:

Crystalline solids have well-defined edges and faces, diffract x-rays, and tend to have sharp melting points. In contrast, amorphous solids have irregular or curved surfaces, do not give well-resolved x-ray diffraction patterns, and melt over a wide range of temperatures.

Explanation:

Answer:

Mercury Chloride

Explanation:

Trust me, this answer is correct.

Answer:

Fire, Air, Water.

Explanation:

Matter is anything that has mass and occupies space. However, not all form of matter are visible. Air is an example of invisible matter.

Note, electricity does not have mass or does not occupy space. Therefore, electricity is not a matter.

Answer:

Fire, Air, Water

Explanation:

Electricity is the of charged particles conducting medium. However, it is the electrons that are matter, not their movement.

Matter is anything that has mass and occupies space. The flame itself is a mixture of gases and so is matter. The light and heat produced are energy not matter.

Like solids and liquids, air is matter. It has a weight and it takes up space.

Water is a liquid and liquids are one of the four fundamental states of matter.

Answer:

yes and thats all i know

Explanation:

Answer:

47900 cm

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

0.479 km

Step 2: Identify Conversions

1 km = 1000 m

1 m = 100 cm

Step 3: Convert

[tex]0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} )[/tex] = 47900. cm

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

47900. cm ≈ 47900 cm

Answer:

There are:

Explanation:

First calculate the percentage of Cu and S in the compound:

These percentages will remain the same no matter how much of the compound we analyze.

Now we calculate the grams of Cu and S in 3801 kg of the compound:

Answer:

96.72 m/min

Explanation:

The following data were obtained from the question:

Time (t) = 56.7 s

Distance (d) = 100 yard

Rate (R) =?

Next, we shall convert 56.7 s to minutes. This can be obtained as follow:

60 s = 1 min

Therefore,

56.7 s = 56.7 s × 1 min /60 s

56.7 s = 0.945 min

Next, we shall convert 100 yard to metre (m). This can be obtained as follow:

1 yard = 0.914 m

Therefore,

100 yard = 100 yard × 0.914 m /1 yard

100 yard = 91.4 m

Finally, we shall determine the rate of the swimmer as follow:

Time (t) = 0.945 min

Distance (d) = 91.4 m

Rate (R) =?

R = d/t

R = 91.4/0.945

R = 96.72 m/min

Thus the rate of the swimmer is 96.72 m/min

Answer:

C I belive

Explanation:

The higher lattice energy in option a is for LiF. Similarly, MgS have higher lattice energy that NaCl and  MgO have higher lattice energy than RbI.

Lattice energy of a compound is the energy required to convert one mole of that compound into its constituent gaseous ions. Lattice energy increases as the size of the ion decreases. As well as, higher the charge of the ions higher will be the lattice energy.

In LiF and KBr, Li and F are the smaller ions and is having higher lattice energy. In the case of NaCl and MgS, Mg and S are having +2 charge and are smaller causes MgO higher in lattice energy.

Similarly in the case of MgO and RbI the same concept can be applied. Rb⁺ and I⁻ are bigger ions where as Mg²⁺ and O²⁻ are comparatively smaller and have higher charge result in higher lattice energy.

Thus compound which have higher lattice energy in option a is LiF, in option b is MgS and in option C is MgO.

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Answer:

the contrasting sides of human nature

Explanation:

I took the test

Answer:

combining 2 grams of copper and 4 grams of sulfur to make 6 grams of copper sulfate

Explanation:

The Law of Conservation of Mass states that matter cannot be created or destroyed in chemical reactions. It posits that the mass of a substance remains unchanged after undergoing a chemical process.

Therefore, according to the question, the procedure that best demonstrates the law of conservation of mass after the chemistry student conducted different procedures is option D.

This is because, the mass of copper and sulfate did not change but merely combined to form a compound.

Answer:

Because only regular-shaped objects have a consistent length, width, height, and shape.

Explanation:

Because only regular-shaped objects have a consistent length, width, height, and shape. When dealing with an object composed of differing shapes, your must calculate each portion separately and then add them.