Answer:
Fahrenheit ⇒ 847.4 °FKelvin ⇒ 726.15KExplanation:
To convert Celsius to Fahrenheit, use the following formula;
= (°C * 9/5) + 32
= (453 * 9/5) + 32
= 847.4 °F
To convert Celsius to Kelvin, use the following;
= °C + 273.15
= 453 + 273.15
= 726.15K
Suppose that you wanted to use either conservation of momentum or conservation of kinetic energy to predict the outcome when a large car collides with a smaller car in a demolition derby. Which of the two quantities would be more appropriate for your calculation? Explain please.
Answer:
Conservation of momentum
Explanation:
Out of the two options given, the more appropriate one is the law of conservation of momentum. This is particularly so because momentum deals with the velocity or speed of the car while considering its mass. So, if a large car is to collide with another car, small one, then the momentum is what is considered. Energy on the other hand is talking about the work that is done, while the momentum considers the mass of the car while it is moving and considering its speed also
You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic friction is .4, how far will it move in 3 seconds?
Answer:
Explanation:
Force of friction acting on the body = μ mg cosθ
= .4 x 70 x 9.8 x cos30
= 237.63 N
component of weight = mgsinθ
= 70 x 9.8 x sin30
= 343 N
Net upward force = 600 - mgsinθ - μ mg cosθ
= 600 - 343 - 237.63
= 105.37 N
acceleration in upward direction = 105.37 / 70
= 1.5 m /s²
s = ut + 1/2 a t²
= 0 + .5 x 1.5 x 3²
= 6.75 m .
The crate will move at a distance of 1.215 m in 3 seconds.
How do you calculate the distance of motion?Given that the mass m of the crate is 70 kg and the angle above the horizontal is 30°. External force F on the crate is 600 N and the coefficient of friction is 0.4.
The friction force applied to the crate is calculated as given below.
Friction force = [tex]\mu mgcos \theta[/tex]
Where [tex]\mu[/tex] is the friction constant, g is the gravitational acceleration and [tex]\theta[/tex] is the angle above the horizontal.
Friction Force = [tex]0.4\times 70\times 9.8\times cos30^\circ[/tex]
Friction force = 237.63 N.
There is a force applied on the crate due to its weight is calculated as given below.
Force (weight component) = [tex]mgsin\theta[/tex]
Force (weight component) = [tex]70\times 9.8\times sin 30^\circ[/tex]
Force (weight component) = 343 N.
The net force applied to the crate is given below.
Net force = External force - friction force - force (weight component)
Net force F' = [tex]600 - 237.63 - 343[/tex]
Net force F' = 19.37 N.
The acceleration of the crate can be calculated as given below.
[tex]a = \dfrac {F'}{m}[/tex]
[tex]a =\dfrac {19.37}{70}[/tex]
[tex]a = 0.27 \;\rm m/s^2[/tex]
Hence the distance traveled by the crate in 3 seconds is calculated by the formula given below.
[tex]s = ut + \dfrac {1}{2} at^2[/tex]
Where, s is the distance, u is the initial velocity, a is the acceleration and t is the time of motion of the crate.
[tex]s = 0\times 3 + \dfrac {1}{2} \times 0.27 \times 3^2[/tex]
[tex]s = 1.215[/tex]
Hence we can conclude that the crate will move a distance of 1.215 m in 3 seconds.
To know more about the force, follow the link given below.
https://brainly.com/question/26115859.
A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy potential store
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If you had to choose one device to use with the battery, what would it be? Do you think such a battery could be invented
someday? Explain
Answer:
I would choose refrigerator.
Explanation:
In my opinion, such a battery could be invented by changing the device as a low power mode. Plus, it is a must in order to decrease the CFC gas spreading through the atmosphere. That's all, thank you.
It takes 10 lb of force to stretch a spring 2 in. What is the stiffness (spring constant) of the spring
Answer:
875.59 N/m
Explanation:
From the question given above, the following data were obtained:
Force (F) = 10 lb
Extention (e) = 2 in
Spring constant (K) =?
Next, we shall convert 10 lb to Newton (N). This can be obtained as follow:
1 lb = 4.448 N
Therefore,
10 lb = 10 lb × 4.448 N / 1 lb
10 lb = 44.48 N
Thus, 10 lb is equivalent to 44.48 N
Next, we shall convert 2 in to metre (m). This can be obtained as follow:
1 in = 0.0254 m
Therefore,
2 in = 2 in × 0.0254 m / 1 in
2 in = 0.0508 m
Thus, 2 in is equivalent to 0.0508 m.
Finally, we shall determine the spring constant i.e the stiffness of the spring as follow:
Force (F) = 44.48 N
Extention (e) = 0.0508 m.
Spring constant (K) =?
F = Ke
44.48 = K × 0.0508
Divide both side by 0.0508
K = 44.48 / 0.0508
K = 875.59 N/m
Therefore the spring constant i.e the stiffness of the spring is 875.59 N/m
Two masses sit at the top of two frictionless inclined planes that have different angles,__deleted9917f34947e1359b5705bbac0d9227f8ec5df862078213a2db19c72f00189109deleted__ 0N86-C1-52-40-A837-22820 50% Part (a) What can be said about the speeds of the two masses at the bottom of their respective paths
Answer:
v = [tex]\sqrt{2gh}[/tex]
the speed in the two planes will be the same since it does not depend on the angle of the same
Explanation:
In this exercise we are told that the two inclined planes have no friction force, so we can apply the conservation of energy for each one, we will assume that the initial height in the two planes is the same
starting point. Highest part of each plane
Em₀ = U = m g h
final point. Lowest part of each plane
[tex]Em_{f}[/tex] = K = ½ m v²
as there is no friction, the mechanical energy is preserved
Em₀ = Em_{f}
mg h = ½ m v²
v = [tex]\sqrt{2gh}[/tex]
As we can see, the speed in the two planes will be the same since it does not depend on the angle of the same
9. Two moving objects will change their motion if which of the following is true? a.There is no friction on the objects. b. The objects collide with each other. c.One object is heavier than the other. d.The objects are moving in space.
Answer:
lol
Explanation:
lolllll i need points sorry
Hydropower is alternative source of energy
Answer:
Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.Answer:
because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.
Explanation:
please mark as brainlest
2. What do pitch and loudness have in common?
Both are measured in decibels, or dB.
Both depend on a wave's frequency.
Both are subject to a person's interpretation.
Answer:
Both are subject to a persons interpretation
Explanation:
We hear people describe this when somebody is making an irresistible sound. usually people say the baby has a pitch scream.
A car is being driven down a level track with no net force on it. This motion is best described as
A)Linear motion
B)circular motion
C) periodic motion
D) projectile motion
A)Linear motion
If there is not net force on the car, then by the Newton Second Law, the acceleration is zero, and the only valid option for zero acceleration is A).
Hooke's law describes a certain light spring of unstretched length 32.1 cm. When one end is attached to the top of a doorframe and a 7.94 kg object is hung from the other end, the length of the spring is 42.4 cm. (a) Find its spring constant. .7554 Correct: Your answer is correct. kN/m (b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 178 N. Find the length of the spring in this situation. .7923 Incorrect: Your answer is incorrect.
Answer:
[tex]0.75623\ \text{kN/m}[/tex]
[tex]55.6\ \text{cm}[/tex]
Explanation:
m = Mass of object = 7.94 kg
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
x = Change in length of the spring = [tex](42.4-32.1)\ \text{cm}[/tex]
F = Force on the spring
Force of gravity on the object and the force on the spring will be equal
[tex]mg=kx\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{7.94\times 9.81}{0.424-0.321}\\\Rightarrow k=756.23\ \text{N/m}[/tex]
The spring constant is [tex]756.23\ \text{N/m}=0.75623\ \text{kN/m}[/tex]
F = 178 N
Force on spring is given by
[tex]F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{178}{756.23}\\\Rightarrow x=0.235\ \text{m}=23.5\ \text{cm}[/tex]
The length of the spring will be [tex]32.1+23.5=55.6\ \text{cm}[/tex].