The graph below compares the total amounts of greenhouse gas emissions expected for future mid-size cars, including emissions that
occur when moving fuels from their original source to fueling stations where people can buy the fuels for their cars. Amounts are shown in
grams of CO2 (or equivalent greenhouse gas) per mile driven by the mid-size car.

Which vehicles are the best choices for environmentally friendly cars?
A. Fuel cell Electric and battery electric
B. Hybrid electric and plug-in hybrid electric
C. Conventional internal combustion and hybrid electric
D. Conventional internal combustion and battery electric

Explanation:

To show - from E=mc²=hv show that wavelength=h/mv​

Proof -

Given that,

E = mc²

E = hν

By equating both the equations, we get

mc² = hν

Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).

mv² = hν

Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.

mv² = hv/λ

⇒λ = hv/mv²

⇒λ = h/mv

Hence showed.

Answer:

A B D

Explanation:

Answer:  A: Being the power source of stars

                B: Forming heavier elements from light elements

                D: Being used in thermonuclear weapons

Explanation: (Edmentum)

Answer:

D

Explanation:

Answer:

D

Explanation:

Because it is true

Answer:

540,000 (5.4X10^5)

Explanation:

kj means Kilojoules, while we are converting to joules.

- Kilo, or k, represents our base value, Joules, multiplied by 10^3. To convert to joules, we would simply multiply by 10^3 (which is 1000)

Answer:

The molar mass of the unknown gas is 128g/mol

Explanation:

The rate of effusion of 2 different gases follows the equation:

Rate gas A / Rate gas B = √MM gas B / √MM gas A

Where rate is the speed of effusion of each gas and MM the molar mass of each gas

If gas A is oxygen and gas B the unknown:

Rate gas A / Rate gas B = 2 = √MM gas B / √32g/mol

11.134 = √MM gas B

128g/mol = MM gas B

The molar mass of the unknown gas is 128g/mol

Answer:

pH = 10.95

Explanation:

To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:

pKb dimethylamine:

Based on the equilibrium:

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)

Kb is defined as:

Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]

Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:

[OH-] = [(CH3)2NH2⁺]

And: [(CH3)2NH] = 0.457M

[OH-] can be obtained from pH as follows:

14 -pH = pOH

14-12.2 = 1.8 =pOH

10^-pOH = [OH-] = 0.01585M

Replacing:

Kb = [0.01585M] [(0.01585M] / [0.457M]

Kb = 5.50x10⁻⁴

pKb = -logkb = 3.26

pH of the buffer:

Using H-H equation for bases:

pOH = pKb + log [conjugate acid] / [weak base]

pOH = 3.26 + log [0.280M] / [0.457M]

pOH = 3.05

pH = 14 - pOH

Answer: Fats and oils are composed of molecules known as triglycerides, which are esters composed of three fatty acid units linked to glycerol. An increase in the percentage of shorter-chain fatty acids and/or unsaturated fatty acids lowers the melting point of a fat or oil.

Explanation:

Answer:

ummm u ok?

Explanation:

Answer:

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Explanation:

Let's consider the balanced chemical equation (molecular equation) for the reaction between hydrochloric acid and sodium hydroxide. This is a neutralization reaction.

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻ ⇒ Na⁺(aq) + Cl⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Answer:

m = 4.58 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

[tex]PV=nRT[/tex]

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]

Regards!

Answer:

Can you translate it on English so we can understand

E= hf

so shorter lambda = larger f= more energy

Answer is A

The wavelength of an EM wave related to its energy as "The shorter the wavelength of a wave, the higher its energy".

Electromagnetic radiation is a type of energy that is all around us and takes many forms, such as radio waves, microwaves, X-rays and gamma-rays. Sunlight is also a form of electromagnetic energy, but visible light is only a small portion of the electromagnetic spectrum, which contains a broad range of wavelengths.

In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. In order from highest to lowest wavelength, the series is just opposite.

Electromagnetic radiations don't require any medium to travel and also travel in speed of light. They have Electric field vector and magnetic field vector that is perpendicular to each other and also are perpendicular to the direction of propagation.

Therefore, the wavelength of an EM wave related to its energy as "The shorter the wavelength of a wave, the higher its energy".

Learn more about EM wave, here:

https://brainly.com/question/18729221

#SPJ7

Answer:

whats the question?

Explanation:

Answer:

????

Explanation:

Answer:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]

For the reaction between ethanoic acid and butanol; and therefore, the products side is:

[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

It means that the overall equation is:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

And the ester product is butyl ethanoate.

Regards!

Atomic number = The number of proton in an atom or ion so the right answer is 5!

Answer:

a.

Explanation:

electromagnetism

Answer:

Metal oxide + acid —> salt + water

Explanation:

Answer:

36.16 amu

Explanation:

From the question given above, the following data were obtained:

1st Isotope:

Mass of 1st isotope = 35.01 amu

Abundance of 1st isotope = 35%

2nd isotope:

Mass of 2nd isotope = 36.01 amu

Abundance of 2nd isotope = 15%

3rd isotope:

Mass of 3rd isotope = 37.02 amu

Abundance of 3rd isotope = 50%

Atomic mass of element A =?

The atomic mass of element A can be obtained as follow:

Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]

= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]

= 12.25 + 5.40 + 18.51

= 36.16 amu

Thus, the atomic mass of element A is 36.16 amu

Answer: There are 1.53 moles present in [tex]9.23 \times 10^{23}[/tex]  molecules of water in a beaker.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] molecules present in 1 mole of a substance.

So, number of moles present in [tex]9.23 \times 10^{23}[/tex] molecules are calculated as follows.

[tex]Moles = \frac{9.23 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.53 moles[/tex]

Thus, we can conclude that there are 1.53 moles present in [tex]9.23 \times 10^{23}[/tex]  molecules of water in a beaker.

Answer:

By measuring out 3.9 grams of cobalt (II) chloride up to a volume of 1.0 L of solution.

Explanation:

Hello there!

In this case, considering this question about molarity, it turns out possible for us to calculate the required mass of cobalt (II) chloride by firstly compute the moles present in 1.0L of the given 0.03-M solution:

[tex]M=\frac{n}{V} \\n=V*M\\\\n=1.0L*0.03\frac{molCoCl_2}{L}\\\\n=0.03molCoCl_2[/tex]

Next, since the molar mass of cobalt (II) chloride is 129.84 g/mol, we compute the grams we need to measure out in order to prepare this solution:

[tex]m_{CoCl_2}=0.03molCoCl_2*\frac{129.84gCoCl_2}{1molCoCl_2} \\\\m_{CoCl_2}=3.9gCoCl_2[/tex]

Regards!

Answer:

Incomplete question. You didn't give the volume of HNO3

Answer:

C, energy cannot be created nor destroyed.

Explanation:

Answer:

Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.

The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.

Explanation:

answer of this question is [Ar]3d8 4s2

Answer: [Ar] 3d8 4s2

Explanation: Wikipedia

Answer:

New volume = 105.6 mL

Explanation:

Given that,

Temperature, T = 240.0 K

Pressure, P = 670 mm Hg

Volume, V = 128 mL

New temperature = -75°C = 198 K

We need to find the new volume. Let it is V'. The relation between volume and the temperature is given by :

[tex]V=kT\\\\\dfrac{V}{V'}=\dfrac{T}{T'}\\\\V'=\dfrac{VT'}{T}\\\\V'=\dfrac{128\times 198}{240}\\\\V'=105.6\ mL[/tex]

So, the new volume is equal to 105.6 mL.

Answer:

The answer is "212.5 ml"

Explanation:

Please find the complete question in the attached file.

In 2 ml of [tex]35\%[/tex] SDS it makes 120 ml of [tex]7\%[/tex] SDS.

To mix x ml of [tex]35\%[/tex] SDS

[tex]\to V_1S_1 = V_2S_2\\\\\to V_1 = x \ ml\\\\\to V_2 = 120\ ml\\\\\to S_1 = 35\% \\\\ \to S_2 = 7\%\\\\\to V_1 = \frac{V_2S_2}{S_1}\\\\[/tex]

          [tex]= \frac{(120 \times 7)}{35}\\\\=24 \ ml\\\\[/tex]

added water [tex]= 120-24 = 96\ ml[/tex]

So we have to add 24ml from [tex]35\%[/tex] SDS and add 96ml water to male 120ml [tex]7\%[/tex] SDS.

1500ml of 40% Tris Buffer solution  

Let us assume we have to mix y ml of 40% Tris buffer solution  

[tex]\to V_1S_1 = V_2S_2\\\\\to V_1 = y \ ml\\\\\to V_2 = 250\ ml\\\\\to S_1 = 40\% \\\\ \to S_2 = 6\%\\\\\to V_1 = \frac{V_2S_2}{S_1}\\\\[/tex]

        [tex]= \frac{(250 \times 6)}{40}\\\\= 37.5\ ml[/tex]

added water [tex]= 250-37.5 = 212.5\ ml[/tex]  

So we have to add 37.5 ml from 40% Tris Buffer and add 212.5 ml water to male 250 ml 6% Tris Buffer.

Answer:

Explanation:

1500ml of 40% Tris Buffer solution

Let us assume we have to mix y ml of 40% Tris buffer solution

We know,

[tex]V_1S_1 = V_2S_2[/tex]

where,

[tex]V_1 = y ml\\\\V_2 = 150 ml\\\\S_1 = 40\% and S_2 = 8\%[/tex]

So,

[tex]V1 = \frac{V_2S_2}{S_1}\\\\V_1 = \frac{150*8}{40}\\\\V_1 = 30 ml[/tex]

So water we have to add

[tex]= 150-30\\\\= 120 ml[/tex]

So we have to add 30 ml from 40% Tris Buffer and add 120 ml water to male 250 ml 6% Tris Buffer.

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