The following half-reaction method is used to balance oxidation-reduction equations.

(1) Determine which atoms change oxidation state from reactant to product in the reaction.
(2) Identify and write half reactions (oxidation and reduction).
(3) Return to the original chemical equation to balance it.
(a) Insert the coefficients from the half reactions first.
(b) Inspect the number of each atom on each side for all elements.

Which important step is missing from this procedure?

Check other reactions similar to this one.
Name the elements that are involved in the reaction.
Make sure the reduction half reaction is identified first.
Balance the half reactions based on the number of electrons.

Answer:

The advantage of the globe is that it promotes visual accuracy. Students need to use a globe frequently if they are to form accurate mental maps. The advantage of the world map is that you can see the entire world at one time. The disadvantage is that world maps distort shape, size, distance, and direction.

Explanation:

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(just make it look like you typed it)

Answer:

The advantage of the globe is that it promotes visual accuracy. Students need to use a globe frequently if they are to form accurate mental maps. The advantage of the world map is that you can see the entire world at one time. The disadvantage is that world maps distort shape, size, distance, and direction.

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Answer:

[tex]\Delta _{fus}H=332 \frac{J}{g}[/tex]

Explanation:

Hello!

In this case, since the heat of fusion of a solid substance stands for the energy required to melt it, which is a phase transition from solid to liquid, we can see that the heat lost by water is that gained by the solid, so we can write:

[tex]Q_{solid}=-Q_{w}[/tex]

Thus, by using the water data and its specific heat (4.184), we obtain:

[tex]Q_{solid}=-m_{w}C_{w}(T_f-T_i)\\\\Q_{solid}=-425g*4.184\frac{J}{g\°C}*(30.0-85.1)\°C\\\\ Q_{solid}=97,978.82J=98.0kJ[/tex]

Next, since the heat of fusion of a substance is usually represented in terms of energy per amount of substance, we use the mass of solid to obtain:

[tex]\Delta _{fus}H=\frac{98.0kJ}{295.5g}\\\\ \Delta _{fus}H=0.332\frac{kJ}{g}=332 \frac{J}{g}[/tex]

Best regards!

The heat of fusion of the solid is 0.332 KJ/g or 332 J/g

We'll begin by calculating the heat loss by the water. This can be obtained as follow:

Mass of water (M) = 425 g

Initial temperature of water (T₁) = 85.1 °C

Final temperature (T₂) = 30 °C

Change in temperature (ΔT) = T₂ – T₁ = 30 – 85.1 = –55.1 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

Q = 425 × 4.184 × –55.1

Q = –97978.82 J

Divide by 1000 to express in KJ

Q = –97978.82 / 1000

Heat loss by water = –97.98 KJ

Heat gained by the solid (Q) = 97.98 KJ

Mass of solid (m) = 295.5 g

Q = m•Hf

97.98 = 295.5 × Hf

Divide both side by 295.5

Hf = 97.98 / 295.5

Learn more: https://brainly.com/question/15563205

Answer:

because it will help u

because it will make u to understand the question very well

Answer:

52.4%

Explanation:

Since a simple cubic unit cell contains only 1 atom. The packing efficiency of the simple cubic cell is 52.4 %

Answer:

25% or 0.25 or 1/4

Explanation:

don't know which form you need so here you have all 3

good luck :)