Answer:
the correct answer is: The magnitude of the current varies with time.
Explanation:
The movement of a filament by a current is due to the electric force when electrons accumulate on one side attract positively charged nuclei.
In this case the voters in a period of time are on one side, let's call it forward and in another period of time it accumulates on the other side, let's call it back, this explains the very small movement of the filament, therefore we have a current that varies over time.
The other two options are not correct because turning off the current the filament goes to the central position and does not go back, the other explanation the current goes in one direction or another, the voters are always on the same side therefore the filament only goes in a sense.
Consequently the correct answer is: The magnitude of the current varies with time.
This figure shows a sinusoidal wave that is traveling from left to right, in the +x-direction. Assume that it is described by a frequency of 57.1 cycles per second, or hertz (Hz).
7.60 cm4.80 cm
A sinusoidal wave lies on an unlabeled coordinate system. One of the wave's maxima lies on the vertical axis. The horizontal distance from the first maximum to the first minimum is labeled 4.80 cm and the vertical distance between a maximum and a minimum is labeled 7.60 cm.
(a)
What is the wave's amplitude (in cm)?
cm
(b)
What is the wavelength (in cm)?
cm
(c)
Calculate the wave's period (in s).
s
(d)
Compute the speed of this wave (in m/s).
m/s
Answer:
a) A = 3.80 cm, b) λ = 9.60 cm, c) T = 1.75 10⁻² s, d) v = 5.48 m / s
Explanation:
The wave is a way of transporting energy and moment without the need to transport the material. They are described by expressions of the type
x = A sin (kx - wt)
where the amplitude A is the distance from the point of zero intensity to the maximum.
Frequency is the number of times the wave oscillates per unit of time
the wavelength is the distance necessary for the wave to start repeating.
a) In the exercise it tells us that the vertical distance from a machismo to a minimum that is worth 7.60 cm
when checking the definition of amplitude is from zero to a maximum, therefore the value given is twice the amplitude
2A = 7.60
A = 3.80 cm
b) the distance between a minimum and the next maximum is 4.80 cm
Using the definition of wavelength the given value corresponds to half wavelength
λ/ 2 = 4.80
λ = 9.60 cm
c) frequency and period are related
f = 1 / T
T = 1 / f
we calculate
T = 1 / 57.1
T = 0.0175 s
T = 1.75 10⁻² s
d) the speed of the wave is related to the frequency and the wavelength
v = λ f
v = 0.0960 57.1
v = 5.48 m / s
A wet towel spread out and hung outside on a day without wind dries faster than an identical wet towel left rolled up in a plastic bag.
Explain why.
Even without wind the sun help evaporate the water so it would dry faster. The other towel is in a bag so the moist and water has nowhere to go, therefor staying in the towel.
Where do animals such as snakes and frogs, which do not make their own body heat, usually get their heat?
fuel
the sun
hot lava
friction
plssssssss answer correctly
The answer to this question is the Sun.
As im writing this, 12,826 people vote the Sun.
animals such as snakes and frogs, which do not make their own body heat. They usually get their heat from the sun. Hence option B is correct.
What is Cold-blooded animals ?A body temperature that is only slightly higher than the ambient temperature. This condition differentiates cold-blooded, or homoiothermic, animals from fishes, amphibians, reptiles, and invertebrates (birds and mammals). Due of their reliance on external warmth for metabolic activity, terrestrial cold-blooded species are restricted to locations with temperatures ranging from 5-10° to 35-40° C (41-50° to 95-104° F).
Cold-blooded creatures cannot create their own body heat, but they may control it by modifying their surroundings. Alligators and other reptiles frequently lay in the sun to warm up. They, on the other hand, cool off by swimming, going into a burrow in the earth, or moving inside the sade of a rock.
Hence option B is correct.
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A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of 29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track
Answer: [tex]2.27\ m/s^2[/tex]
Explanation:
Given
Length of the race track [tex]L=200\ m[/tex]
the radius of curvature of the track [tex]r=29.5\ m[/tex]
time taken to run on track is [tex]t=24.4\ s[/tex]
Speed of runner is
[tex]\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s[/tex]
Centripetal acceleration is
[tex]\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2[/tex]
How much Work is done when a 5 kg object is picked up a distance of 8 m.
Answer:
392J?
Explanation:
An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go inside. Recalling your recent physics class, you decide to try setting up standing-wave resonances inside the tunnel. Using your subsonic amplifier and loudspeaker, you find resonances at 5.0 Hz and 6.4 Hz , and at no frequencies between these. It's rather chilly inside the tunnel, so you estimate the sound speed to be 333 m/s .
Answer:
L = 116.6 m
Explanation:
For this exercise we approximate the tunnel as a tube with one end open and the other closed, at the open end there is a belly and at the closed end a node, therefore the resonances occur at
λ = 4L 1st harmonic
λ = 4L / 3 third harmonic
λ = 4L / 5 fifth harmonic
General term
λ = 4L / n n = 1, 3, 5,... odd
n = (2n + 1) n are all integers
They indicate that two consecutive resonant frequencies were found, the speed of the wave is related to the wavelength and its frequency
v = λ f
λ = v / f
we substitute
[tex]\frac{v}{f} = \frac{4L}{n}[/tex]
L = [tex]n \frac{ v}{4f}[/tex]
for the first resonance n = n
L = (2n + 1) [tex]\frac{v}{4f_1}[/tex]
for the second resonance n = n + 1
L = (2n + 3) [tex]\frac{v}{4f_2}[/tex]
we have two equations with two unknowns, let's solve by equating
(2n + 1) \frac{v}{4f_1}= (2n + 3) \frac{v}{4f_2}
(2n + 1) f₂ = (2n +3) f₁
2n + 1 = (2n + 3) [tex]\frac{f_1}{f_2}[/tex]
2n (1 - \frac{f_1}{f_2}) = 3 \frac{f_1}{f_2} -1
we substitute the values
2n (1- [tex]\frac{5}{6.4}[/tex]) = 3 [tex]\frac{5}{6.4}[/tex] -1
2n 0.21875 = 1.34375
n = 1.34375 / 2 0.21875
n = 3
remember that n must be an integer.
We use one of the equations to find the length of the Tunal
L = (2n + 1) \frac{v}{4f_1}
L = (2 3 + 1) [tex]\frac{333}{4 \ 5.0}[/tex]
L = 116.55 m
Which two options are forms of kinetic energy?
A. Thermal energy
OO
O B. Nuclear energy
c. Sound energy
O D. Gravitational energy
O E. Chemical energy
Answer:
Themal energy is the best answer from you
Which molecules are in put in photosynthesis
Answer:
During the process of photosynthesis, cells use carbon dioxide and energy from the Sun to make sugar molecules and oxygen. These sugar molecules are the basis for more complex molecules made by the photosynthetic cell, such as glucose.
Explanation:
yes.
Answer:
Sunlight, Carbon Dioxide, and Water
Explanation:
Technically minerals are in there too but when I learned this it was just Sunlight, Carbon Dioxide, and Water
Your friend said that the star in this picture with the highest apparent magnitude must definitely have the highest absolute brightness as well.
Answer:
A white dwarf, also called a degenerate dwarf
Explanation:
sorry if im wrong im kind of du-m
The parallel plates in a capacitor, with a plate area of 9.30 cm2 and an air-filled separation of 4.50 mm, are charged by a 7.80 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 9.60 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
Answer:
a) ΔV ’= 1.66 10¹ V= 16.6 V, b) U = 55.64 10⁻¹² J, c) U_f = 1.18 10⁻¹⁰ J
d) W = 6.236 10⁻¹¹ J
Explanation:
Capacitance can be found for a parallel plate capacitor
C = ε₀ [tex]\frac{A}{d}[/tex]
Let's reduce the magnitudes to the SI system
A = 9.30 cm² (1 m / 10² cm) 2 = 9.30 10⁻⁴ m²
c = 4.50 mm (1 m / 1000 mm) = 4.50 10⁻³ m
Co = 8.85 10⁻¹² 9.30 10⁻⁴ /4.50 10⁻³
Co = 1.829 10⁻¹² F
when the plates separate at d = 9.60 10⁻³ m, the capcitance changes to
C = ε₀ \frac{A}{d_1}
C = 8.85 10⁻¹² 9.30 10⁻⁴/9.60 10⁻³
C = 8.57 10⁻¹³ F
a) the potential difference
C =
since the capacitor is not discharged, let's look for the initial charge
Co = \frac{Q}{ \Delta V}
Q = C₀ ΔV
Q = 1.829 10⁻¹² 7.80
Q = 14.2662 10⁻¹² C
when the condensate plates are separated
C = \frac{Q}{ \Delta V' }
ΔV ’= Q / C
ΔV ’= 14.266 10⁻¹² / 8.57 10⁻¹³
ΔV ’= 1.66 10¹ V= 16.6 V
b) the stored energy is
U = ½ C ΔV²
for initial separation
U = ½ C₀ ΔV²
U = ½ 1.829 10⁻¹² 7.80²
U = 55.64 10⁻¹² J
c) The energy for end separation;
U_f = ½ C DV’2
U_f = ½ 8.57 10⁻¹³ 16,6²2
U_f = 1.18 10⁻¹⁰ J
d) The work
as there are no losses, the work is equal to the variation of the energy
W = ΔU = U_f -U₀
W = 1.18 10⁻¹⁰ - 55.64 10-12
W = 6.236 10⁻¹¹ J
what happens to the loudness of the sound as the amplitude increases
it increases and gets louder
and it amplifies the noise
Consider identical spherical conducting space ships in deep space where gravitational fields from other bodies are negligible compared to the gravitational attraction between the ships. Construct a problem in which you place identical excess charges on the space ships to exactly counter their gravitational attraction. Calculate the amount of excess charge needed. Examine whether that charge depends on the distance between the centers of the ships, the masses of the ships, or any other factors. Discuss whether this would be an easy, difficult, or even impossible thing to do in practice.
Answer:
q = 8.61 10⁻¹¹ m
charge does not depend on the distance between the two ships.
it is a very small charge value so it should be easy to create in each one
Explanation:
In this exercise we have two forces in balance: the electric force and the gravitational force
F_e -F_g = 0
F_e = F_g
Since the gravitational force is always attractive, the electric force must be repulsive, which implies that the electric charge in the two ships must be of the same sign.
Let's write Coulomb's law and gravitational attraction
[tex]k \frac{q_1q_2}{r^2} = G \frac{m_1m_2}{r^2}[/tex]
In the exercise, indicate that the two ships are identical, therefore the masses of the ships are the same and we will place the same charge on each one.
k q² = G m²
q = [tex]\sqrt{ \frac{G}{k} }[/tex] m
we substitute
q = [tex]\sqrt{ \frac{ 6.67 \ 10^{-11}}{8.99 \ 10^{9}} }[/tex] m
q = [tex]\sqrt{0.7419 \ 10^{-20}}[/tex] m
q = 0.861 10⁻¹⁰ m
q = 8.61 10⁻¹¹ m
This amount of charge does not depend on the distance between the two ships.
It is also proportional to the mass of the ships with the proportionality factor found.
Suppose the ships have a mass of m = 1000 kg, let's find the cargo
q = 8.61 10⁻¹¹ 10³
q = 8.61 10⁻⁸ C
this is a very small charge value so it should be easy to create in each one
Which type of biological molecule would contain fats?
A) Amino Acids.
C) Nucleic Acids.
B) Lipids.
D) Carbohydrates.
B
Explanation:
lipids contains fat
hope it helps
What is the wavelength of microwaves with a frequency of 3x10^10 Hz?
Answer:
0.01 m
Explanation:
Since the speed of light is 3.0×10^8 m/s
Use the equation,
Wavelength = speed ÷ frequency
Wavelength = 3.0×10^8 ÷ 3×10^10
Wavelength = 0.01m
Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader
Answer:
7.55 g
Explanation:
Given that:
Heat of fusion = 333kj/kg
Heat capacity, c = 4190 j/kg /k
The Number of grams of ice that will melt can be represented as y:
Number of grams of ice that will melt * heat of fusion = specific heat capacity * temperature change
y * 333 * 10^3 J = (4190) * (6 - 0)
333000y = 25140
y = 25140 / 333000
y = 0.0754954 kg
y = 0.0754954 * 100
y = 7.549 g
Hence, Number of grams of ice that will melt = 7.55 g
Score
A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break, also the track can be stoped
in 7.6 m\s if the driver hit the wall.
a. What is the Impulse Excerted on the Vehicle?
b. Whta is the Averge force is exeted on the Track in each stops ?
Answer:
(a) J = 10560 kg-m/s (b) 251.42 N
Explanation:
Given that,
Mass, m = 4400 kg
Initial speed, u = 5.2 m/s
Final speed, v = 7.6 m/s
Time, t = 42 s
(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :
J = m(v-u)
J = 4400 (7.6-5.2)
J = 10560 kg-m/s
(b) Impulse = Force × t
[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N[/tex]
Hence, this is the required solution.
3. The car's mass is 400 kg. It moves at a velocity of 20 m/s. Calculate the car's momentum. *
(10 Points)
0.05 kg.m/s
8000 kg.m/s
80,000 kg.m/s
20 kg.m/s
Answer:
momentum=mass×velocity
momentum =400kg×20m/s=8000kg.m/s
Which type of land usage would increase as the population increases?
Answer:
If the population were to INCREASE land use would also INCREASE, if the human population DECREASED so would land use because there wouldn’t be as many people to using it. hope i helped
Answer:
D. Urban use
Explanation:
It shows here on this graph that overtime urban use is rising as the population is increasing! The other answers that are on this graph does not show it increasing!
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 ×102 T, what is the number of turns per meter for this solenoid?
Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
[tex]B =\mu_o I(\frac{N}{L} )\\\\B = \mu_o I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m[/tex]
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Can someone please help
ummmmmmmmmmm thats confusing
. An object 8.5 cm high is placed 28 cm from a converging lens. The focal length of the lens is 12 cm. Calculate the image distance, di. Calculate the image height, hi.
The converging lens is also called a concave lens. The height of the image formed by the lens is 2.55 cm.
Using the lens formula;
1/f = 1/u + 1/v
f = focal length of the lens
u = object distance
v = image distance
Note that the focal length of a converging lens is positive
Substituting values;
1/12 = 1/28 + 1/v
1/v = 1/12 - 1/28
v = 8.4 cm
Magnification= image height/object height = image distance/object distance
image height = ?
object height = 8.5 cm
image distance = 8.4 cm
object distance = 28 cm
So
image height/8.5 = 8.4/28
image height = 8.5 × 8.4/28
image height = 2.55 cm
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a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?
Answer:
25 miles per hour
Explanation:
It was 20 miles per hour the next day. We don't have enough information to calculate the average speed for the whole trip.
When an object is moving on a surface with a lot of texture, how does this affect the amount of friction created?
A. The friction is stopped.
B. Less friction is created.
C. More friction is created.
D. The amount of friction is the same
Answer:
b) less friction is created
Answer:
B
Explanation:
what is the quantum and its types?
Answer:
It is the physics that explains how everything works, the nature of the particles that make up matter and the forces with which they interact.
Its types: Electromagnetism, the strong nuclear force, and the weak nuclear force.
Hope this help :)
An angry physics student releases a wrecking ball as shown. The wrecking ball is just about to hit the building at the final time. Neglect loss. Identify the energy types present at each time for the highlighted object or system relative to the reference
level shown. Also identify if loss occurs and/or work is done by a non-conservative force between each time
(if necessary).
Answer:
the force between the building and the ball is non-conservative (friction-type force)
Explanation
Explanation:For this exercise the student must create an impulse to move the ball towards the building, in this part he performs positive work since the applied force and the displacement are in the same direction.
When the ball moves it has a kinetic energy and if its height increases or decreases its potential energy also changes, but the sum of being must be equal to the initial work.
When the ball arrives and collides with the building, non-conservative forces, of various kinds; rubbing, breaking, etc. It transforms this energy into a part of heat and another in mechanical energy that the building must absorb, let us destroy its wall
Consequently, the force between the building and the ball is non-conservative (friction-type force
when an object slides over a smooth horizontal surface, how does the force of friction depend on the surface area of blocks that's are in contact with the table?
Answer: with a greater surface area, there will be a greater force of friction
Explanation:
Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass = 1.5. Calculate the angle of refraction inside glass if angle of incidence in the water is 32 degrees
Answer:
28°
Explanation:
Snell's Law and equation
Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? It would point up. It would point east. It would point down. It would point west.
Answer:
It would point up.
Explanation:
Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.
Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.
So, the compass would point up.
How many electron flow through a light bulb each second if the current flow through the light bulb 0.75A.The electric charge of one electron is 1.6 x 10-19C
Answer:
[tex]n=4.68\times 10^{18}[/tex]
Explanation:
The current through the bulb, I = 0.75 A
We need to find the number of electrons flowing per second. We know that the electric current is given by :
[tex]I=\dfrac{ne}{t}\\\\n=\dfrac{It}{e}\\\\n=\dfrac{0.75\times 1}{1.6\times 10^{-19}}\\\\n=4.68\times 10^{18}[/tex]
So, there are [tex]4.68\times 10^{18}[/tex] electrons flowing per second.
There are "[tex]4.68\times 10^{18}[/tex]" electron flowing per second.
Electric charge:Whenever retained inside an electric as well as the magnetic field, this same basic physical attribute of matter which thus permits it to perceive a force, is considered as Electric charge.
According to the question,
Current flow, I = 0.75 A
Electric charge of one electron, e = 1.6 x 10⁻¹⁹ C
As we know the relation,
Current, I = [tex]\frac{ne}{t}[/tex]
or,
→ n = [tex]\frac{It}{e}[/tex]
By substituting the given values in the above formula, we get
= [tex]\frac{0.75\times 1}{1.6\times 10^{-19}}[/tex]
= [tex]4.68\times 10^{18}[/tex]
Thus the approach above is appropriate.
Find out more information about electric charge here:
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d. Two point charges, q1 = +25 nC and q2 = -75 nC, are separated by a distance of 3.0 cm. Find the magnitude and direction of; i. the electric force q1 exerts on q2 [5] ii. the force that q2 exerts on q1 [4] (take k = 9.0 x 109 N.m2 /C2 )
Answer:
a) F₂₁ = 0.02 N, attracting.
b) F₁₂ = 0.02 N, attracting.
Explanation:
a)
The magnitude of the force that q₁ exerts on q₂ (F₂₁) is given by Coulomb's Law, as follows:[tex]F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)[/tex]
Since q₁ and q₂ have opposite signs, the force between them will be always attractive, i.e., from q₂ towards q₁, along the line that joins both charges.b)
The magnitude of the force on q₁ due to q₂ can be obtained applying Newton's 3rd Law, or using (1), because all parameters are the same, so F₁₂ (in magnitude) = F₂₁ = 0.02 NAs we have already said, it must be opposite to the one found in a) so it must go from q₁ towards q₂, it is an attracting force also.