Assume we have two lists, list A and list B. List A contains the numbers [20,10,20], while list B contains the numbers [40,10,30,20,40,30]. We choose one number from list A randomly and one number from list B randomly. What is the chance that the number we drew from list A is larger than or equal to the number we drew from list B

Answer:

Print 4 + 4

Explanation:

If you're writing this in the programming language called BASIC, this is how you would add any two numbers.

Answer:

In computer programming, a return statement causes execution to leave the current subroutine and resume at the point in the code immediately after the instruction which called the subroutine, known as its return address. The return address is saved by the calling routine, today usually on the process's call stack or in a register. Return statements in many languages allow a function to specify a return value to be passed back to the code that called the function.

An expression that returns a value is known as a​ function. Check more about function  below.

A function is often seen as a kind of expression or rule, or law that often tells more about a relationship.

Conclusively, a function is known to often returns a value back to the instruction that is known also to be the function. This is regarded as the differences that exist between a method and a function.

Learn more about function  from

https://brainly.com/question/20476366

Answer:

The answer is below

Explanation:

The correct process for setting up a recurring project for the same client in Quickbooks Online Accountant is as follows:

1. Go to Work, then select create a project

2. Select the Repeat button, then set the frequency and duration

3. Formulate the project and save it.

4. Reopen the project

5. And select the Duplicate button for the proportion of times you want it to recur. This includes assigning the interval, day of the recurrence, and end time.

6. Then select Save.

Firstly, invent a separate project, then pick the repeat button on the right of the screen, specify the frequency and duration. Its frequency can indeed be weekly, biweekly, monthly, and so on.

Therefore, the answer is "first choice".

Learn more:

brainly.com/question/24356450

Answer:

e. All of the above.

Explanation:

An instruction set architecture (ISA) can be defined as series of native memory architecture, instructions, addressing modes, external input and output devices, virtual memory, and interrupts that are meant to be executed by the directly.

Basically, this set of native data type specifies a well-defined interface for the development of the hardware and the software platform to run it.

The two (2) main types of architectural design for the central processing unit (CPU) are;

I. Complex instruction set computing (CISC): it allows multi-step operation or addressing modes to be executed within an instruction set. Thus, many low-level operations are being performed by an instruction.

II. Reduced instruction set computing (RISC): it allows fixed length instructions and simple addressing modes that can be executed within a clock cycle.

All of the following statements are true about RISC (Reduced instruction set computing) because they are its advantages over complex instruction set computing (CISC);

a. RISC (Reduced instruction set computing) architecture has a set of instructions, so high-level language compilers can produce more efficient code.

b. It allows freedom of using the space on microprocessors because of its simplicity.

c. Many RISC processors use the registers for passing arguments and holding the local variables.

d. RISC functions use only a few parameters, and the RISC processors cannot use the call instructions, and therefore, use a fixed length instruction which is easy to pipeline.

The options that are true about RISC (Reduced instruction set computing) is; E: all of the above

Read more about instruction set computing at; https://brainly.com/question/17493537

Answer:

In absolute cell reference, the reference of a cell does not change. 

Answer:

What Language? Once you respond with a comment, I will be happy to write the code for you. I write code 24/7 (Because I have nothing better to do), so I will wait for you to comment. Also is there any pre-existing code?

Explanation:

Answer: drafting

Explanation:

Answer:

yes and

Explanation:

why do you need to know about a buildings security are you going to rob it ???

Answer:

D. Plot

Explanation:

The plot is how the story develops, unfolds and move through time.

Answer:

I believe that the answer is C.

Explanation:

Answer:

think the answer is:

the responsible person or organization, date accessed, and URL

Explanation:

have a nice day

Answer:

Throughout the clarification below, the description of the query is mentioned.

Explanation:

Answer:

no

Explanation:

Answer:

no

Explanation:

if u can still pay for using phones, computers, etc. then we will still have technology

Answer: number 2 is the correct way to do it

Explanation:

Answer:

2 newWord = word1 + word2

Explanation:

Answer: Resolution or DPI, deliverables, and file types are important technical and visual demands to consider when planning a project.

Explanation: Keep in mind whether or not the project will be published in print or on the Web.

Answer:

supercomputer, mainframe, personal computer, minicomputer

Explanation:

Answer:

See attachment for complete solution

Explanation:

The program in your question is unreadable.

So, I started from scratch (see attachment for complete solution)

Using the attached file as a point of reference.

The program has 15 lines

Line 1: Prompt the user for highway number (as an integer)

Line 2: Convert the user input to string

Line 3: Check if highway number is outside 1-999

Line 4: If line 3 is true, print a notice that the input is outside range

Line 5: If line 3 is not true

Line 6: Check if the number of highway digits is 2.

Line 7: If true, Check if highway number is an even number

Line 8: If even, print that the highway is primary and heads east/west

Line 9: If highway number is odd number

Line 10: Print that the highway is primary and heads north/south

Line 11: If the number of highway digits is 3

Line 12: Check if highway number is an even number

Line 13: If even, print that the highway is auxiliary and heads east/west

Line 14: If highway number is odd number

Line 15: Print that the highway is auxiliary and heads north/south

See attachment for complete program

Answer:

In Python:

import os.path

from os import path

fname = input("Filename: ")

if path.exists(fname):

with open(fname) as file_in:

 lines = []

 for line in file_in:

  lines.append(line.rstrip('\n'))

f = open("stat.txt","r+")

f.truncate(0)

f = open("stat.txt", "a")

f.write("Names\tTotal\tSubjects\tAverage\n")

for i in range(len(lines)):

 rowsum = 0; count = 0

 nm = lines[i].split()

 for j in nm:

  if (j.isdecimal()):

   count+=1

   rowsum+=int(j)

 average = rowsum/count

 f.write(nm[0]+"\t %3d\t %2d\t\t %.2f\n" % (rowsum, count, average))

f.close()

else:

print("File does not exist")

Explanation:

See attachment for explanation where comments were used to explain each line

For each student, the sum of the marks, total tests were taken and the average of marks is calculated and is stored in an output file, for example, stats.txt.

The code in Python asks the user for an input file name. If the input file is not found an error is printed else the data in the file is processed further.

Try:

  # take input file name

  file = input('Enter name of the data file: ')

# open the input file

  ip = open(file, 'r')

# store the lines from input file in a list

  lines = ip.readlines()

  # close the file

  ip.close()

# open the output file

  op = open('stats.txt', 'w')

# iterate over each line

  for line in lines:

 # split data using space as delimiter

      data = line.split()

 # get name

   name = data[0]

 # get marks and convert them to integer

      marks = list(map(int, data[1:]))

# get sum of marks

      total = sum(marks)

# get number of tests

      length = len(marks)

# calculate average of marks

      avg = total/length

# add the data to output file

      op.write('{} {} {} {:.2f}\n'.format(name, total, length, avg))

# close the output file

  op.close()

print('Stats have been save in the output file')

# catch FileNotFoundError

except FileNotFoundError:

# print error

  print('Error: that file does not exist. Try again.')

Learn more about the topic python code:

https://brainly.com/question/14492046

Answer:

Explanation:

When your elecronic devices screen is positioned upright or the way a photo is taken

If you want an example look up portrait mode on go0gle or safar1

Answer:

Explanation:

[tex]\text{This is a math function that is integrated using a trapezoidal rule } \\ \\[/tex]

[tex]\text{import math}[/tex]

def [tex]\text{trapezint2(f,a,b):}[/tex]

      [tex]\text{midPoint=(a+b)/2}[/tex]

       [tex]\text{return .5*((midPoint-a)*(f(a)+f(midPoint))+(b-midPoint)*(f(b)+f(midPoint)))}[/tex]

[tex]\text{trapezint2(math.sin,0,.5*math.pi)}[/tex]

[tex]0.9480594489685199[/tex]

[tex]trapezint2(abs,-1,1)[/tex]

[tex]1.0[/tex]

In this exercise we have to use the knowledge of computational language in python to write the code.

the code can be found in the attachment.

In this way we have that the code in python can be written as:

   h = (b-a)/float(n)

   s = 0.5*(f(a) + f(b))

   for i in range(1,n,1):

       s = s + f(a + i*h)

   return h*s

from math import exp  # or from math import *

def g(t):

   return exp(-t**4)

a = -2;  b = 2

n = 1000

result = Trapezoidal(g, a, b, n)

print result

See more about python at brainly.com/question/26104476

Answer:

In Python:

import random

p1name = input("Player 1: "); p2name = input("Player 2: ")

p1score = 0; p2score = 0

playerTurn = 1

print(p1name+" starts the game")

roll = True

while(roll):

   if playerTurn == 1:

       p1 = random.randint(1,6)

       print(p1name+"'s roll: "+str(p1))

       if p1 == 1:

           playerTurn = 2

           roll = True

       else:

           p1score+=p1

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

   else:

       p2 = random.randint(1,6)

       print(p2name+"'s roll: "+str(p2))

       if p2 == 1:

           playerTurn = 1

           roll = True

       else:

           p2score+=p2

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

   if p1score >= 50 or p2score >= 50:

       roll = False

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Explanation:

Note that the dice rolling is simulated using random number whose interval is between 1 and 6

This imports the random module

import random

This line gets the name of both players

p1name = input("Player 1: "); p2name = input("Player 2: ")

This line initializes the scores of both players to 0

p1score = 0; p2score = 0

This sets the first play to player 1

playerTurn = 1

This prints the name of player 1 to begin the game

print(p1name+" starts the game")

This boolean variable roll is set to True.

roll = True

Until roll is updated to False, the following while loop will be repeated

while(roll):

If player turn is 1

   if playerTurn == 1:

This rolls the dice

       p1 = random.randint(1,6)

This prints the outcome of the roll

       print(p1name+"'s roll: "+str(p1))

If the outcome is 1, the turn is passed to player 2

       if p1 == 1:

           playerTurn = 2

           roll = True

If otherwise

       else:

Player 1 score is updated

           p1score+=p1

This asks if player 1 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 2, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

If player turn is 2

   else:

This rolls the dice

       p2 = random.randint(1,6)

This prints the outcome of the roll

       print(p2name+"'s roll: "+str(p2))

If the outcome is 1, the turn is passed to player 1

       if p2 == 1:

           playerTurn = 1

           roll = True

If otherwise

       else:

Player 2 score is updated

           p2score+=p2

This asks if player 2 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 1, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

If either of both players has scored 50 or above

   if p1score >= 50 or p2score >= 50:

roll is updated to False i.e. the loop ends

       roll = False

This prints the name and scores of each player

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Answer:

of a bad product

Explanation:

Answer:

iron

Explanation:

Answer:

See Explanation

Explanation:

The question is incomplete as the cells that contains donation and streaming revenues are not given

So, I will make the following assumption:

H4 = Donations

G4 =  Streaming Revenues

So, the profit will be:

Enter the following formula in cell I4

=(G4 - H4)

To get the actual solution in your case, replace G4 and H4 with the proper cell names

Answer:

Hopes this helps if not comment and I'll change it

Explanation:

import simplegui

import random

def draw_handler(canvas):

for i in range (0, 1000):

x = random.randint(1, 600)

y = random.randint(1, 600)

r = random.randint(0, 255)

g = random.randint(0, 255)

b = random.randint(0, 255)

color = "RGB( " + str(r) + "," + str(g) + "," + str(b) + ")"

canvas.draw_point((x, y), color)

frame = simplegui.create_frame('Points', 600, 600)

frame.set_canvas_background("Black")

frame.set_draw_handler(draw_handler)

frame.start()

Answer in python:

import random

money = 10

winnings = 0

def main():

global winnings

global money

dice_num = random.randrange(1,6)

input_str = "Guess the dice number. You have $"+str(money)+" > "

input_num = input(input_str)

if int(input_num) == dice_num:

 money = money + 10

 winnings = winnings + 10

else:

 money = money - 1

if money < 0:

 print("You lose. You won "+str(winnings)+" times. Press enter to try again")

 useless_variable = input()

 main()

else:

 main()  

main()

Explanation:

Answer:

Its b) Ctrl+Q. Hope it helps.

Explanation:

Answer:

ctrl r

Explanation:

ctrl r is redo

Answer:

In Python

print("Instruction: 1. Rock, 2. Paper or 3. Scissors: ")

p1 = int(input("Player 1: "))

p2 = int(input("Player 2: "))

if p1 == p2:

   print("Tie")

else:

   if p1 == 1: # Rock

       if p2 == 2: #Paper

           print("P2 wins! Paper covers Rock")

       else: #Scissors

           print("P1 wins! Rock smashes Scissors")

   elif p1 == 2: #Paper

       if p2 == 1: #Rock

           print("P1 wins! Paper covers Rock")

       else: #Scissors

           print("P2 wins! Scissors cuts Paper")

   elif p1 == 3: #Scissors

       if p2 == 1: #Rock

           print("P2 wins! Rock smashes Scissors")

       else: #Paper

           print("P1 wins! Scissors cuts Paper")

Explanation:

This prints the game instruction

print("Instruction: 1. Rock, 2. Paper or 3. Scissors: ")

The next two lines get input from the user

p1 = int(input("Player 1: "))

p2 = int(input("Player 2: "))

If both input are the same, then there is a tie

if p1 == p2:

   print("Tie")

If otherwise

else:

The following is executed if P1 selects rock

   if p1 == 1: # Rock

If P2 selects paper, then P2 wins

       if p2 == 2: #Paper

           print("P2 wins! Paper covers Rock")

If P2 selects scissors, then P1 wins

       else: #Scissors

           print("P1 wins! Rock smashes Scissors")

The following is executed if P1 selects paper

   elif p1 == 2: #Paper

If P2 selects rock, then P1 wins

       if p2 == 1: #Rock

           print("P1 wins! Paper covers Rock")

If P2 selects scissors, then P2 wins

       else: #Scissors

           print("P2 wins! Scissors cuts Paper")

The following is executed if P1 selects scissors

   elif p1 == 3: #Scissors

If P2 selects rock, then P2 wins

       if p2 == 1: #Rock

           print("P2 wins! Rock smashes Scissors")

If P2 selects paper, then P1 wins

       else: #Paper

           print("P1 wins! Scissors cuts Paper")

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   double quiz1, quiz2, quiz3, exam1, exam2, finalexam,quiz;

   cout<<"Quiz 1: "; cin>>quiz1;

   cout<<"Quiz 2: "; cin>>quiz2;

   cout<<"Quiz 3: "; cin>>quiz3;

   cout<<"Exam 1: "; cin>>exam1;

   cout<<"Exam 2: "; cin>>exam2;

   cout<<"Final Exam: "; cin>>finalexam;

   if(quiz1<=quiz2 && quiz1 <= quiz3){        quiz=(quiz2+quiz3)/2;    }

   else if(quiz2<=quiz1 && quiz2 <= quiz3){        quiz=(quiz1+quiz3)/2;    }

   else{         quiz=(quiz1+quiz2)/2;     }

   int weight = 0.20 * quiz + 0.30 * ((exam1 + exam2)/2) + 0.50 * finalexam;

   cout<<"Average Weight: "<<weight<<endl;

   if(weight>=91 && weight<=100){        cout<<"Letter Grade: A";    }

   else if(weight>=81 && weight<=90){        cout<<"Letter Grade: B";    }

   else if(weight>=70 && weight<=80){        cout<<"Letter Grade: C";    }

   else{        cout<<"Letter Grade: F";    }

   return 0;

}

Explanation:

See attachment for complete program where comments were used to explain difficult lines

Answer:

The reason that a satellite must have a distinct uplink and downlink set of frequencies is because they help avoid any type of interference that may occur. The uplink receives the signal and amplifies it so that it can be transmitted to another frequency (downlink).