The energy level diagram shown below represents a fictional gas. What is the energy of a photon that would move an electron from level 2 to level 5?
A. 5.8 eV
B. 4.8 eV
C. 4.2 eV
D. 2.65 eV

The Energy Level Diagram Shown Below Represents A Fictional Gas. What Is The Energy Of A Photon That

Answers

Answer 1

The energy of a photon that would move an electron from level 2 to level 5 : B. 4.8 eV

Further explanation

The electron energy at the nth shell can be formulated:

En = -Rh / n²

Rh = constant 2.179.10⁻¹⁸ J

So the electron transfer energy (ΔE)

ΔE = E final- E initial

energy at n=2(level 2) = -5.3 eV

energy at n=5(level 5) = -0.5 eV

So the energy absorbed :

[tex]\tt \Delta E=-0.5-(-5.3)=-0.5+5.3=4.8`eV[/tex]

Answer 2

The energy required to move an electron from level 2 to level 5 is 4.8 eV.

According to the Bohr model of the atom, an electron moves from a lower to a higher energy level when it absorbs energy. The same energy is released when the atom returns to ground state.

When an electron from level 2 to level 5, the energy of the photon required is;

ΔE = E5 - E2 = -0.5eV - (-5.3eV)

ΔE = 4.8eV

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Related Questions

A 13.8 g of zinc is heated to 98.8 c in boiling water and then dropped onto a beaker containing 45.0 g of water at 25.o °C .when the water and metal come to thermal equilibrium the temperature is 27.1°C .what is the specific heat capacity

Answers

Answer:

[tex]C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Explanation:

Hello!

In this case, by considering thermodynamics and the temperature of zinc, we can infer it is hot while water is cold, it means that the heat lost by the zinc is gained by the water and we can write:

[tex]Q_{Zn}=-Q_{water}[/tex]

In terms of mass, specific heat and temperatures we can write:

[tex]m_{Zn}C_{Zn}(T_{eq}-T_{Zn})=-m_{water}C_{water}(T_{eq}-T_{water})[/tex]

In such a way, by solving for the specific heat capacity of the zinc we write:

[tex]C_{zinc}=\frac{-m_{water}C_{water}(T_{eq}-T_{water})}{m_{Zn}(T_{eq}-T_{Zn})}[/tex]

Thus, by plugging in the given values we obtain:

[tex]C_{zinc}=\frac{-45.0g*4.184\frac{J}{g\°C}* (27.1\°C-98.8\°C)}{13.8g*(27.1\°C-98.8\°C)}\\\\C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Best regards!

If the net force acting on an object is 0 N, the forces are

Answers

There won’t be any force since if the net force acting on an object is 0 N, inertia causes it to stay still, having no motion

Since the forces equal to 0, it's balanced because the object isn't moving.

How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?

Answers

Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³

Further explanation  

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :

[tex]\tt N=1.4\times 6.02\times 10^{23}\\\\N=8.428\times 10^{23}[/tex]

in which beakers are the particles moving the most slowly

Answers

Answer:

A and D

Explanation:

if you a boy answer this question because............. idk

Answers

Answer:

no

Explanation:

How many Stars are In the Milky way Galaxy

Answers

Answer:

100 thousand million stars

Explanation:

Answer:

100 to 400 billion stars

What are three ways that we can identify when a chemical reaction is occurring?

Answers

Three ways (out of the many) are:

Change of temperature
Color change
Formation of gas

Hope this helps!! (:

How do you know your cell's are working

Answers

are you alive? then your cells are working

Robert was changing the oil in his truck. He dumped the used oil on the ground in his yard. He didn't know it, but Robert was hurting the environment because the oil-
HELP FAST

Answers

oil is toxic and harmful to plants and animals

Answer:

goes deep into the ground and pollutes the groundwater.

how many atoms does sodium hypochlorite have?

Answers

Answer:

NaClO; the contained elements ae Na, Cl, O.

Which statement describes how phase changes can be diagrammed as a substance is heated?

The phase is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the phase is on the x-axis.

The time is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the time is on the x-axis.

Answers

Answer:

The temperature is on the y-axis and the time is on the x-axis.

Explanation:

Which statement describes how phase changes can be diagrammed as a substance is heated? (D is the answer)

The phase is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the phase is on the x-axis.

The time is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the time is on the x-axis.

Which statement describes the appearance of a temperature-vs.-time graph? (C is the answer)

A horizontal line shows that the temperature increases at a constant rate over time.

A vertical line shows that the temperature decreases at a constant rate over time.

Horizontal lines where the temperature is constant during phase changes connect upward-sloping lines where the temperature increases.

Horizontal lines where the temperature increases are connected by upward-sloping lines where the temperature is constant for each phase.

Which of the following covalent bonds is the most polar (i.e., highest percent ionic character)?
A) Al  I
B) Si  I
C) Al  Cl
D) Si  Cl
E) Si  P

Answers

Answer:

answer d is correct that works

answer d that’s correct it works

Which of these mixtures would NOT be separated by using simple distillation?

Ink and water

Salt and water

Sand and water

Answers

Salt and water because salt is transparent and will dissolve into the water

There is a golden role of solubility, polar solute dissolve in polar solvent and non polar solute dissolve in non polar solvent. Therefore, the correct option is option B that is Salt and water.

What is solution?

Solutions are a homogeneous mixture of two or more substances. A solution is a homogeneous mixture of solvent and solute molecules. Solvent is a substance that is in large amount in solution. solute is the substance which is in small amount in a solution. There are two types of mixture that is homogeneous and heterogeneous. Solution is a homogeneous solution.

Salt and water because salt is transparent and will dissolve into the water among given solute, salt NaCl is a polar solute which will dissolve in polar solvent that is water.

Therefore, the correct option is option B that is Salt and water.

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Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of Cl2 loss is 4.64 × 10-2 M/s, what is the rate of formation of NOCl? 2 NO(g) + Cl2(g) → 2 NOCl(g)

Answers

Answer:

[tex]r_{NOCl}=9.28x10^{-2}M[/tex]

Explanation:

Hello!

In this case, given the balanced chemical reaction:

[tex]2 NO(g) + Cl_2(g) \rightarrow 2 NOCl(g)[/tex]

Since there is 1:2 mole ratio between chlorine and NOCl, based on the rate proportions, we can write:

[tex]\frac{1}{-1}r_{Cl_2} =\frac{1}{2}r_{NOCl}[/tex]

It means that for the formation of NOCl, we obtain:

[tex]r_{NOCl}=\frac{2}{-1}r_{Cl_2} \\\\r_{NOCl}=\frac{2}{-1}(-4.64x10^{-2}M)\\\\r_{NOCl}=9.28x10^{-2}M[/tex]

Notice that chlorine is disappearing, which means its rate is negate.

Best regards!

A 50.0 mL solution of Ba(OH)2 is combined with a 150 mL solution of 0.20 M HCl. If the resulting solution has a hydroxide ion concentration of 0.12 M, what was the concentration of Ba(OH)2 in the original solution?

Answers

Answer:

0.54M of Ba(OH)2

Explanation:

When Ba(OH)2 reacts with HCl, BaCl2 and H2O are produced as follows:

Ba(OH)2 + 2HCl → BaCl2 + 2H2O

The remanent hydroxide ion is because not all Ba(OH)2 reacts. Thus, we need to find moles of Ba(OH)2 that doesn't react and moles of Ba(OH)2 that reacts. The ratio between total moles and volume of the Ba(OH)2 solution = 0.050L is the molarity of the original solution

Moles of Ba(OH)2 that doesn't react:

50mL + 150mL = 0.200L * (0.12 mol OH- / L) = 0.024 moles OH-

2 moles of OH- are in 1 mole of Ba(OH)2:

0.024 moles OH- * (1mol Ba(OH)2 / 2 mol OH-) = 0.012 moles Ba(OH)2

Moles of Ba(OH)2 that react:

0.150L * (0.20mol / L) = 0.030 moles HCl

2 moles of HCl react per mole of Ba(OH)2:

0.030 moles HCl * (1mol Ba(OH)2 / 2 mol HCl) = 0.015 moles Ba(OH)2

Total moles:

0.012mol + 0.015mol = 0.027mol Ba(OH)2 in 50mL

0.027mol Ba(OH)2 / 0.0500L =

0.54M of Ba(OH)2

which have
different numbers of electrons?

Answers

Answer:

These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses. Mass is the word for how much substance (or matter) something has.

how fast is a formula 1 car? (For my chemistry project)

Answers

Answer:

it's 200 mph fast........

1. A baseball pitcher won 75% of the games he pitched. If he pitched 43 ballgames, how many games

did he win?

Answers

Answer:

He won 32 games.

Explanation:

Another way of expressing 75% is 75/100.

To calculate how many games the baseball pitcher won, we multiply the total of games played (43, in this case) by the percent won:

43 * 75/100 = 32.25 ≅ 32

So the baseball pitcher won 32 games.

Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)

Answers

Explanation:

C3H8+5O2----->3CO2+4H2O

Answer:

C3H8+5O2----->3CO2+4H2O

Explanation:

Which of these lead (II) salts will dissolve to the greatest extent in water?

a. PbSO4, Ksp = 1.7x10^-8
b. PbI2, Ksp = 6.5x10^-9
c. PbCrO4, Ksp = 1.8x10^-14
d. PbS, Ksp = 2.5x10^-27
e. Pb3(AsO4)2, Ksp = 4.0x10^-36

Answers

Answer:

a. PbSO4, Ksp = 1.7x10^-8.

Explanation:

Hello!

In this case, since the solubility product indicates how likely a solid is able to ionize and consequently dissolve in water, we can infer that the larger the solubility product Ksp, the more ions are able dissolve in water; therefore the proper answer goes with the largest Ksp, which is a. PbSO4, Ksp = 1.7x10^-8 since the power goes closer to 1 than the other options.

Best regards!

DO NOT TROLL AND ANSWER WITHOUT THE CORRECT ANSWER! I EXPECT THE CORRECT ANSWER NOT A TROLL SO IF YOU DONT HAVE THE ANSWER DO NOT WRITE ANYTHING. IF YOU TROLL I WILL REPORT YOU

A weather balloon with a volume of 3.40774 L

is released from Earth’s surface at sea level.

What volume will the balloon occupy at an

altitude of 20.0 km, where the air pressure is

10 kPa?

Answer in units of L.

Answers

Answer:  The volume occupied at an altitude of 20.0 km is 34.5289 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]     (At constant temperature and number of moles)

where,

[tex]P_1[/tex] = initial pressure of gas = 101.325 kPa ( sea level)

[tex]P_2[/tex] = final pressure of gas = 10 kPa

[tex]V_1[/tex] = initial volume of gas = 3.40774 L

[tex]V_2[/tex] = final volume of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

[tex]101.325\times 3.40774=10\times V_2[/tex]

[tex]V_2=34.5289L[/tex]

Therefore, the volume occupied at an altitude of 20.0 km is 34.5289 L

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READ!!!!! p.s. i have a fly ride T rex and more! also, STAY ON THE PAGE SO I COULD RESPOND AND WE COULD PLAY! yay!! :) :)

Answers

Answer:

I play!!!!!!!!

Explanation:

A 2kg metal cylinder is supplied with 1600J of energy to heat it from 5*C to 13*C. What is the SHC of the metal?

Answers

Answer:

100Jkg/°C

Explanation:

Given parameters:

Mass of metal  = 2kg

Amount of heat energy  = 1600J

Initial temperature  = 5°C

Final temperature = 13°C

Unknown:

Specific heat capacity of the metal  = ?

Solution:

Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.

  H  = m x C x (T₂ - T₁ )

H is the amount of heat

m is the mass

C is the unknown specific heat capacity

T is the temperature

     Insert the parameters and solve;

  1600 = 2 x C x (13 - 5)

   1600  = 16C

        C = 100Jkg/°C



Describe the potential energy of a chemical reaction and how the energy is accessed?

Answers

Explanation:

The energy released due to breakage of bond or we can say that protons and electrons go from a structure of higher potential energy to lower potential energy. During this change, potential energy is converted to kinetic energy in form of heat.

Generally chemical potential energy is accessed in form heat, which the difference between the potential energies of reactant and product.

what is the mass of 16.6 x 10^23 molecules of barium nitrate

Answers

It is fact that
6.023
×
10
23
formula units of barium nitrate have a mass of
16.6*10^23

g
. This is what we specify when we say molar mass. And thus the mass of
5.30
×
10
22
formula units of barium nitrate is the quotient multiplied by the molar mass:
5.30
×
10
22
6.023
×
10
23
m
o
l
×
16.6*10^23

g

m
o
l

1

The mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g

The number of moles of a substance can be calculated by dividing the mass by its molar mass. That is;

no. of moles = mass(g) ÷ molar mass (g/mol)

no. of moles of Ba(NO3)2 = 16.6 × 10²³ ÷ 6.02 × 10²³

no. of moles = 2.75 × 10⁰

no. of moles = 2.75moles.

Molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 2.75

Mass of Ba(NO3)2 = 718.7g

Therefore, the mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g.

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What is the difference between Mega and Milli symbols?

Answers

Gg
B o)))!hb. I I am Gn I’m ok
Lolkk lol h o
Look?ioooookonjj kk kkkkkkkkk has has always always always have s$$&&9999

Noooo I Ik ion ddxd
O
O
Sw n nun. Kkj

Answer:

Mega = 10^6

Milli = 10^-3

Explanation:

Mega is whatever times 10 to 6th power.

Milli is whatever times 10 to the -3rd power.

A container holds 3.41×10−3mol of carbon dioxide (CO2). After the addition of 8.41×10−4mol of carbon dioxide, the volume of the container increases to 95.2mL, with the temperature and pressure remaining constant. What was the initial volume of the container?

Answers

Answer:

76.366

Explanation:

Knewton answer is 76.4

Answer:

76.4mL

Explanation:

First, calculate the final number of moles of carbon dioxide (n2) in the container.

n2 = n1+n added = 3.41×(10^-3) mol+8.41×(10^-4) mol = 4.25×(10^-3) mol

Rearrange Avogadro's law to solve for V1.

V1 =(V2×n1)/n2

Substitute in the known values for n1, V2, and n2.

V1 = (95.2mL×(3.41×10^-3 mol))/(4.25×(10^-3) mol)=76.4mL

So the initial volume is 76.4mL.

1. 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g) a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum to produce aluminum sulfate. b. Determine the % yield if 112 g of aluminum sulfate is produced under the above conditions.

Answers

Answer:

a. 167 mL b. 39.27 %

Explanation:

a. From the chemical equation. 2 mole of Al reacts with 3 mole H₂SO₄ to produce 1 mol  Al₂(SO₄)₃.

Now, we calculate the number of moles of Al in 45.0 g Al.

We know number of moles, n = m/M where m = mass of Al = 45.0 g and M = molar mass of Al = 26.98 g/mol.

So n = 45.0 g/26.98 g/mol = 1.668 mol

Since 2 mole of Al reacts with 3 mole H₂SO₄, then 1.668 mole of Al reacts with x mole H₂SO₄. So, x = 3 × 1.668/2 mol = 2.5 mol

So, we have 2.5 mol H₂SO₄.

Now number of moles of H₂SO₄, n = CV where C = concentration of H₂SO₄ = 15.0 M = 15.0 mol/L and V = volume of H₂SO₄.

V = n/C

= 2.5 mol/15.0 mol/L

= 0.167 L

= 167 mL of 15.0 M H₂SO₄ reacts with 45.0 g Al to produce aluminum sulfate.

b. From the chemical reaction, 2 mol Al produces 1 mol Al₂(SO₄)₃

Therefore 1.668 mol Al will produce x mol  Al₂(SO₄)₃. So, x = 1 mol × 1.668 mol/2 mol = 0.834 mol

So, we need to find the mass of 0.834 mol  Al₂(SO₄)₃. Now molar mass  Al₂(SO₄)₃ = 2 × 26.98 g/mol + 3 × 32 g/mol + 4 × 3 × 16 g/mol = 53.96 g/mol + 96 g/mol + 192 g/mol = 341.96 g/mol.

Also number of moles of  Al₂(SO₄)₃, n = mass of  Al₂(SO₄)₃,m/molar mass  Al₂(SO₄)₃, M

n =m/M

So, m = nM = 0.834 mol × 341.96 g/mol = 285.2 g

% yield = Actual yield/theoretical yield × 100 %

Actual yield = 112 g, /theoretical yield = 285.2 g

So, % yield = 112 g/285.2 g × 100 %

= 0.3927 × 100 %

=  39.27 %

The volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum is 166mL and % yield of the reaction is 39.46%.

How do we calculate moles?

Moles of any substance will be calculated by using the below formula as:
n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is :

2Al(s) + 3H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3H₂(g)

Moles of 45g of Al will be calculated as:

n = 45g / 27g/mol = 1.66 mole

From the stoichiometry of the reaction, it is clear that:

1.66 moles of Al = react with 3/2×1.66=2.49 moles of H₂SO₄

By using the formula of molarity we can calculate the volume of H₂SO₄ as:

M = n/V

V = (2.49) / (15) = 0.166L = 166mL

Again from the stoichiometry it is clear that:
1.66 moles of Al = produces 1/2×1.66= 0.83 moles of Al₂(SO₄)₃

Mass of 0.83 moles of Al₂(SO₄)₃ = (0.83mol)(341.96g/mol) = 283.82 g

Given actual yield of Al₂(SO₄)₃ = 112g

% yield will be calculated as:

Percent yield = (Actual yield/Theoretical yield) × 100

% yield = (112/283.82) × 100 = 39.46%

Hence required values are discussed above.

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If 75J of heat are applied to 8.4 L of a gas at 732 mmHg and 298K, what is the final temperature, in K, of the gas? Cp for an ideal gas is 20.79 J/mol*K.

Answers

Answer:

309 K

Explanation:

Step 1: Convert the pressure to atm

We will use the conversion factor 1 atm = 760 mmHg.

732 mmHg × 1 atm/760 mmHg = 0.963 atm

Step 2: Calculate the moles (n) of the ideal gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.963 atm × 8.4 L/0.0821 atm.L/mol.K × 298 K

n = 0.33 mol

Step 3: Calculate the temperature change

We will use the following expression.

Q = n × Cp × ΔT

ΔT = Q/n × Cp

ΔT = 75 J/0.33 mol × 20.79 J/mol.K

ΔT = 11 K

Step 4: Calculate the final temperature

T = 298 K + 11 K = 309 K

3. Theoretically how many grams of magnesium is required to produce to 5.0 g of

Magnesium oxide?

Answers

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

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