Answer: frequency is the answer to this question
Answer:
frequency
Explanation:
c a n v a s / a p e x :))
How did the angel of the pendulum affect the period
Answer:The starting angle of a pendulum does not affect its period for .
Explanation: however, the period increases with increasing . The starting angle of a pendulum does not affect its period for.
When a forklift raises an object, is it doing positive or negative work on the object? Which type of work is the force of gravity doing on the object? a)The forklift is doing negative work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing positive work on the object because it is acting opposite to the direction of motion. b)The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion. c)The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing positive work on the object because it is acting opposite to the direction of motion. d)The forklift is doing negative work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion.
Answer: B
The forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion.
Explanation: The work done in lifting an object up is positive when the direction of the displacement and the force applied are in the same direction.
The work will be negative if force and direction of the motion are opposite to each other.
Also, force of gravity is considered positive when an object is moving toward the gravity. That is coming downward. Otherwise, it's negative when it's moving in the opposite direction.
When a forklift raises an object, the forklift is doing positive work on the object because the direction of force and the direction of motion are the same. The force of gravity is doing negative work on the object because it is acting opposite to the direction of motion.
The forklift is doing positive work on the object because the direction of
force and the direction of motion are the same. The force of gravity is
doing negative work on the object because it is acting opposite to the
direction of motion.
When a forklift is used to raise an object , it exerts a force which acts in the
same direction with its motion which signifies that it is doing a positive
work.
The force of gravity on the other hand is doing a negative work as it acts
opposite to the direction of the force and motion.
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What is the net displacement of the particle between 0 seconds and 80 seconds?
Velocity (m/s)
chhi NSON WAO
20
40
80
280
100
Кузорил
Time (s)
OA.
160 meters
OB.
80 meters
OC.
40 meters
OD.
20 meters
OE.
0 meters
Answer: 80
Explanation:
The question is incomplete, There is no specific time for the specific velocity, which is not provided in this question instead of giving the total time interval from 0sec to 80 sec. According to my assumption, I think the net displacement will be 20 m. The correct answer will be option D.
What is net displacement?Net displacement is the total change in the position of an object, taking into account both the magnitude and direction of its motion. It is a vector quantity and is expressed in terms of distance and direction.
In other words, it is the final position of an object relative to its initial position, irrespective of the path taken. It is calculated by finding the vector difference between the final and initial positions of the object.
For example, if an object moves 10 meters to the east and then 5 meters to the north of its starting position, then its net displacement would be the vector sum of these two displacements, which is the diagonal distance between its starting and final positions.
Here in the Question,
To calculate the net displacement of the particle between 0 seconds and 80 seconds based on the given options, we can use the fact that the net displacement is the same as the final position minus the initial position.
Let's assume that the initial position is zero.
Option A. If the net displacement is 160 meters, the final position would be 160 meters. However, looking at the velocities given, we can see that the particle goes back and forth, so it does not make sense for the net displacement to be larger than the maximum displacement in one direction.
Option B. If the net displacement is 80 meters, the final position would be 80 meters. This option could be possible if the particle moves in one direction for a while and then moves back to its initial position. This is incorrect.
Option C. If the net displacement is 40 meters, the final position would be 40 meters. This option is also possible if the particle moves in one direction for a shorter period of time. This is not relevant to the question.
Option D. If the net displacement is 20 meters, the final position would be 20 meters. This option could be possible if the particle moves in one direction for a very short period of time. This is most relevant to the Question.
Option E. If the net displacement is 0 meters, the final position would be the same as the initial position, which is zero. This option could be possible if the particle moves back and forth such that the positive displacements cancel out the negative displacements.
Therefore, based on the given options, the correct answer for the net displacement of the particle between 0 seconds and 80 seconds is option D: 20 meters.
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A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are
the total distance and total displacement of the boat?
OA. The total distance is 105 kilometers and the total displacement is 45 kilometers east.
OB. The total distance is 60 kilometers and the total displacement is 60 kilometers east.
OC. The total distance is 105 kilometers and the total displacement is 15 kilometers east.
OD. The total distance is 60 kilometers and the total displacement is 45 kilometers east.
Answer:1) the total distance is the sum of the two distances
60 km + 45 km = 105 km
2) The displacement is the net movement, or the difference between the initial position and the final position
Call x the initial position, then the final position is x + [60km - 45km]
And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km
Explanation:
I WILL CHOOSE YOU AS BRAINLIEST , PLEASEE HELP ME IT URGENT!!!!!!!!!!!!
Relate acceleration qualitatively to a change in speed and/or direction as a result of a net force
Answer:
Over Here
Explanation:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
When light passes from a slower medium into a faster medium, which of the following explains what will occur?
A. Light will not be refracted.
B. Light will be refracted toward a line drawn perpendicular to the point of refraction.
C. Light will be refracted away from a line drawn perpendicular to the point of refraction.
Answer:
C
Explanation:
Answer:
anser is c i just took test
Explanation:
How much momentum will a dumbbell of mass 10kg transfer to the floor if it falls from a height of 80cm (assume that the dumbbell stops after hitting the ground) ? Take g=10m/s^2
(Point stealers will be reported so better dont do it)
Answer: momentum = 40kgm/s
Explanation:
Given that the
Mass M = 10kg
Height H = 80 cm = 0.8m
g = 10m/s^2
The velocity of the dumbbell as it fall can be calculated by using the formula;
V^2 = U^2 + 2gH
Since the dumbbell fell from rest, initial velocity U = 0
Substitute g and H to get final velocity V
V^2 = 0 + 2 × 10 × 0.8
V^2 = 16
V = sqrt(16)
V = 4 m/s
Momentum is the product of mass and velocity. That is,
Momentum = MV
Substitute mass M and V into the formula
Momentum = 10 × 4 = 40kgm/s
Therefore, 40 kgm/s momentum will be transferred as the dumbbell fall to the floor.
May I please get some help?
A unicorn running on a beach at 8 m/s changes speed at a constant rate of 2.7
m/s2 over a period of 2 seconds. What is the unicorn's velocity at the end of this
time?
Answer:
13.4 m/s
Explanation:
Write down what you have, so:
V0=8 m/s
a=2.7 m/s^2
t=2 seconds
We are trying to find final velocity, so we will use vf = v0 + at
From there, we plug in the given values.
vf = 8 m/s + (2.7 m/s^2 x 2 seconds)
vf = 13.4 m/s
Answer:
about 13s
Explanation: