The electron concentration in silicon at T = 300 K is given by
n(x) = 10^16exp(-x/18) cm^-3
where x is measured in μm and is limited to 0 ≤ x ≤ 25 μm. The electron diffusion coefficient is Dn = 25 cm2/s and the electron mobility is μn = 960 cm2/V-s. The total electron current density through the semiconductor is constant and equal to Jn = -40 A/cm2. The electron current has both diffusion and drift current components. Determine the electric field as a function of x which must exist in the semiconductor.

Answers

Answer 1

Answer:

[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]

Explanation:

From the question we are told that:

Temperature of silicon [tex]T=300k[/tex]

Electron concentration [tex]n(x)=10^{16}\exp (\frac{-x}{18})[/tex]

                                        [tex]\frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})[/tex]

Electron diffusion coefficient is [tex]Dn = 25cm^2/s \approx 2.5*10^{-3}[/tex]

Electron mobility is [tex]\mu n = 960 cm^2/V-s \approx0.096m/V[/tex]

Electron current density [tex]Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2[/tex]

Generally the equation for the semiconductor is mathematically given by

[tex]Jn=qb_n\frac{dn}{dx}+nq \mu E[/tex]

Therefore

[tex]-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E[/tex]

[tex]E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}[/tex]

[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]


Related Questions

This String method removes beginning and ending spaces of the given string.
Solactone​

Answers

Answer:

The trim() method will remove both leading and trailing whitespace from a string and return the result. The original string will remain unchanged. If there is no leading or trailing whitespace to be removed, the original string is returned. Both spaces and tab characters will be removed.

This is very useful when comparing user input with existing data. A programmer often racks his brain for hours trying to figure out why what he enters is not the same as a stored string, only to find out that the difference is only a trailing space. Trimming data prior to comparison will eliminate this problem.

Answer:

String result = str. trim(); The trim() method will remove both leading and trailing whitespace from a string and return the result.

Explanation:

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