We have seasons primarily because of how tilted the Earth is on its axis.
SUMMER: The Earth revolves around the sun, and the hemisphere that is tilted toward the sun receives the most sunlight. This is summer, when there is more sunlight.
WINTER: Because of the tilt of the earth's axis, days are shorter and less bright in the hemisphere that faces away from the sun. Winter is the result of the weather getting colder.
24-HOUR DARKNESS: Due to the tilt of the Earth, it is possible for darkness to last 24 hours a day at the North Pole of earth.
It is more frequently exposed to sunlight near the equator. Because of this, it is always much hotter at the equator. There is less variation between seasons because it is hotter for longer periods of time.
Direct sunlight strikes the Earth at the equator. In contrast, the sun's rays barely reach the poles where it is located.
More specifically, it's not because the equator is nearer the sun. But the reason is that the equator is being directly illuminated by the sun.
Because of this, the equator is home to some of the planet's warmest ecosystems, including tropical rainforests and deserts.
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Match each term with its definition.MorphemePhonemeGrammarSyntax1)smallest units of sound that carry meaning on their own2)smallest units of sound that make a difference in meaning3)combined set of rules that govern use of a particular language4)rules for forming speech sounds into phrases and sentences
All the terms are related to languages.
Morpheme - smallest units of sound that carry meaning on their own
Phoneme -smallest units of sound that make a difference in meaning
Grammar - a combined set of rules that govern the use of a particular language
Syntax - rules for forming speech sounds into phrases and sentences
The smallest linguistic unit capable of meaning modification is the phoneme.
Morphemes are divided into two distinct types, bases (or roots) and affixes.
Most people think of grammar as a set of rules that help us form sentences.It covers a variety of language-related topics, such as Parts of speech (verbs, adjectives, nouns, adverbs, prepositions, conjunctions, modifiers, etc.) Clauses (e.g. independent, dependent, compound) (e.g. independent, dependent, compound)
The sequence of grammatical elements like subjects, verbs, direct and indirect objects, etc. is determined by syntax in English.
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what eyepiece focal length will give the microscope an overall angular magnification of 250? assume a length ll
The eye piece focal length is fe = -0.19 m where, fe= focal length of eye ,
What is the focal length?What Is Focal Length? Focal length is the distance (measured in millimeters) between the point of convergence of your lens and the sensor or film recording the image. The focal length of your film or digital camera lens dictates how much of the scene your camera will be able to capture.
Briefing : According to the question we assume ,
let The focal length is F(o) =5.5 mm = -.00055m and distance between objective and eyepiece = 19 cm
This negative sign shows the the microscope is diverging light
The angular magnification is m=250
The distance between the objective and the eyepieces lenses is z=19cm=0.19m
Generally the magnification is mathematically represented as
m={z-fe/fe}{0.25/f(o)}
Where fe is the eyepiece focal length of the microscope
Now making fe the subject of the formula,
fe=z/{(1-1{M-fo)/0.25}
then : fe=0.19/([tex]1-(\frac{250+ - 0.0055}{.25} )[/tex])}
= fe = -0.19 m
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Complete Question : The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .What eyepiece focal length will give the microscope an overall angular magnification of 250?
Two strings are made of the same material and have waves of equal speed. String 1 is thick; string 2 is thin.
Is the tension in string 1 greater than, less than, or equal to the tension in string 2?
greater than the tension in string 2
equal to the tension in string 2
less than the tension in string 2
PART B
Choose the best explanation from among the following:
Equal wave speeds implies equal tensions.
String 1 must have a greater tension to compensate for its greater mass per length.
String 2 will have a greater tension because it is thinner than string 1.
The tension in string 1 is lesser than to the tension in string 2.
What is meant by tension in a string?
It is possible to refer to tension as the action-reaction pair of forces acting at each end of the aforementioned elements. Tension is defined as the pulling force transmitted axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other comparable three-dimensional object.
The tension in the string has a square root relationship with wave speed, while the linear density of the wire has a square root relationship with wave speed. v=sqrt(T/u)
A larger thickness suggests a higher linear density (mass per length. Thus, the speed would be slower. The wave in string 1 moves slower than the wave in string 2, and vice versa.
According to a thick string, there is a lot of mass per length and the wave speed is slow.
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the velocity of a wave with a wavelength of 4.700 m and frequency of 54.00 hz is (5 points) 25.38 m/s 33.85 m/s 114.9 m/s 253.8 m/s
The velocity of this wave is 253.8 m/s.
Wavelength is the distance of the starting point of a wave till its ending point. The length of the wave is known as wavelength. The waves will interact via constructive interference, which is possible only when the wavelength and phase of the waves are the same.
Frequency is the number of waves that pass a fixed point.
Given,
Wavelength = 4.7 m
Frequency = 54 Hz
Velocity of any wave is given by a formula,
Velocity = wavelength * frequency
Velocity = 4.7 * 54
Velocity = 253.8 m/s
Therefore, the velocity of this wave is 253.8 m/s
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An ideal gas is initially in a state that corresponds to point 1 on the graph above, where it has pressure P1 volume V1, and temperature T1. The gas undergoes an isothermal process represented by the curve shown, which takes it to a final state 3 at temperature T3. If T2 and T4 are the temperatures the gas would have at points 2 and 4, respectively, which of the following relationships is true? a. t1
b. t1
c. t1
d. t1=t2
e. t1=t4
The following relationship is true T1 < T2.
An ideal gas is defined as a gas in which all collisions between atoms or molecules are perfectly elastic and no intermolecular attractive forces occur. It can be thought of as a collection of perfectly rigid spheres that collide but do not interact.
The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. Gas particles undergo perfectly elastic collisions without losing energy. This is the relationship between four variables and describes the state of the gas.
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a particle with charge +4.20 nc is in a uniform electric field e⃗ directed to the left. the charge is released from rest and moves to the left; after it has moved 6.00 cm, its kinetic energy is +2.20×10−6 j.
(a) The work done is 1.50 x 10^-6 J
(b) The potential of the starting point with respect to the endpoint is 357.14 V.
(c) The magnitude of E is 5952.38 N/C.
Given that,
Charge = 4.20 nC
Distance = 6.00 cm
Kinetic energy K.E = 1.50 x 10^-6 J
The particle start from rest. So, the initial kinetic energy i zero.
(A) We need to calculate the work by the electric force
Using formula of work done
W = ∆K.E
W = K.Ef - K.Ei
Put the value into the formula
W = 1.50 × 10^-6 - 0
W = 1.50 x 10^-6 J
The work done is 1.50 x 10^-6 J
(B). We need to calculate the potential of the starting point with respect to the endpoint
We know that.
Change in potential energy = change in kinetic energy
∆P.E = ∆K.E
So, U = 1.50 x 10^-6
Using formula of potential
V = U/q
Put the value into the formula
V = 1.50 × 10^-6/4.20 x 10^-9
V = 357.14 V
The potential of the starting point with respect to the endpoint is 357.14 V
(C) We need to calculate the magnitude of E
Using formula of work done
W = F x r (1)
Using formula of force
F = qE
Put the value in the equation (1)
W = qE x r
E = W/q x r
Put the value into the formula
E = 1.50 x 10^-6/4.20 x 10^-9 x 6.00 x10^-2
E = 5952.38 N/C
Hence, The magnitude of E is
5952.38 N/C
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what is the greatest average speed ????v of blood flow at 37∘c37∘c in an artery of radius 2.25 mm2.25 mm if the flow is to remain laminar? take the density of blood to be 1025 kg/m3,1025 kg/m3, and the viscosity to be 2.084×10−3 pa·s.
Average speed of blood flow is given by:
V = n*Re/(rho*d)
n = viscosity of blood = 2.084*10^-3 Pa.s
Re = max reynolds number for which flow remains laminar = 2000
rho = density of blood = 1025 kg/m^3
d = diameter of artery = 2*radius = 2*2.50 mm = 5.0*10^-3 m
So,
V = 2.084*10^-3*2000/(1025*5.0*10^-3)
V = 0.813 m/sec
A painter (of mass 79 kg) needs to reach out from a scaffolding to paint the side of a building, so he lays a plank across two bars of the scaffolding, and puts a heavy bucket of mass 23 kg directly over one of the bars (see figure). You can assume the plank is massless, and is long enough to reach to the other building. Show answer no attempt if the bars are separated by a distance 2. 9 m, how far, d, from the bar on the the right can the painter walk before the plank starts to fall?
0.84 m is the distance the painter walk before the plank starts to fall.
What is Torque?Torque is a measure of the force that rotates an object about an axis. A force accelerates an object with linear kinematics. Similarly, torque causes angular acceleration. Therefore, torque can be defined as the rotational equivalent of a linear force. The straight line around which an object rotates is called the axis of rotation. In physics, torque is simply the tendency of a force to twist or twist. Various terms such as moment and moment of force are used interchangeably to describe torque. The distance from the point of force application to the axis of rotation is sometimes called the moment arm or lever arm.
Mass of the painter (m₁) = 79 kg
Weight of painter (w₁) = 79 × 9.8
= 774.2 N
Mass of bucket (m₂) = 74 kg
Weight of bucket (w₂) = 23 × 9.8
= 225.4 N
Distance between them (L) = 2.9 m
Let d be the distance at which the painter can walk before the plank starts to fall.
At distance d, the torque due to painter and bucket is equal to each other:
T₁ = T₂
w₁d = w₂L
d = (w₂L)/w₁
d = (225.4 × 2.9)/774.2
d = 0.84 m
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The solar system is 25,000 light years from the center of our Milky Way galaxy. One light year is the distance light travels in one year at a speed of 3.0 x 108 m/s. Astronomers have determinedthat the solar system is orbiting the center of the galaxy at a speed of 230 km/s.
a. Assuming the orbit is circular, what is the period of the solarsystem’s orbit? Give your answer in years.
b. Our solar system was formed roughly 5 billion years ago. How many orbits has it completed?
c. The gravitational force on the solar system is the net force due to all the matter inside our orbit. Most of that matter is concentrated near the center of the galaxy. Assume that the matter has a spherical distribution, like a giant star. What is the approximate mass of the galactic center?
d. Assume that the sun is a typical star with a typical mass. If galactic matter is made up of stars, approximately how many stars are in the center of the galaxy?
a. The period of the solar system's orbit, assuming the orbit is circular, is [tex]2.05X10^{8} years[/tex].
b. There have been 24.4 completed revolutions.
c. The star has a mass of [tex]1.87X10^{41}[/tex] kg.
d. There are [tex]9.45X10^{10}[/tex] stars in the galaxy's center.
a. Distance equals 25,000 light years.
[tex]3X10^{8}[/tex]m/s equals the speed of light (c)
230 m/s is the astronomers' speed.
Using the time period formula,
[tex]t=\frac{d}{v}[/tex]
[tex]t= \frac{2\pi r}{v}[/tex]
r = distance
t = time, and v = speed.
Fill out the formula with the value
[tex]t = \frac{2\pi * 25000 * 9.46 * 10^{15} }{230 * 10^{3} }[/tex]
[tex]t= 6.460*10^{15} sec[/tex]
Number of years
[tex]t= \frac{6.460*10^{15} }{3.15*10^{7} } \\t= 2.05*10^{8} years[/tex]
Consequently, the solar system's orbit lasts [tex]2.05*10^{8}[/tex].
b. The solar system's average age is Tn=5 billion years, or [tex]5* 10^{9}[/tex] years.
The number of completed revolutions can be computed as
[tex]N=\frac{T^{n} }{T} \\N= \frac{5*10^{9}years }{2.05*10^{8}years } \\N=24.4[/tex]
24.4 revolutions have been completed.
c. The solar system's radius, r=25000 light years
velocity = 230 km/s
We can determine the big star's mass as
[tex]M= \frac{v^2r}{G} \\[/tex]
By substituting values, we obtain
[tex]M= \frac{(230*10^{3})^2* (25000*3*10^{8}*365*24*60*60m) }{(6.67*10^{-11} N/kg^2.m^2)}[/tex]
[tex]M= 1.87*10^{41} kg[/tex]
The star has a mass of [tex]1.87*10^{41} kg[/tex].
d. The sun's mass, [tex]M_{s}[/tex], is [tex]1.99*10^{30} kg[/tex]
The star's number can be computed using
[tex]N=\frac{mass of glactic center}{mass of sun} \\N= \frac{1.88*10^{41} }{1.99*10^{30} } \\N= 9.45*10^{10}[/tex]
There are [tex]9.45*10^{10}[/tex] beginnings, or around 94.5 billion, each year.
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when ashley sat on a rotating stool holding a set of weights close to her body, her rate of rotation changed when she moved the weights away from her body. did her rate or rotation slow down or speed up? why did this occur? did this violate the conservation of energy?
Reduced moment of inertia because of the frictional effects of the Moon-driven tides.
What is conservation of energy?A fundamental law of chemistry and physics stating that despite internal changes, an isolated system's total power remains static. The first conservation of energy is based on this principle, which is far more commonly phrased as the fact that electricity cannot be generated or destroyed. According to the rule of conservation of energy, energy can only be transformed from one type of energy to another and cannot be created or destroyed. This indicates that unless energy is added from the outside, a system constantly has the same quantity of energy.
What is the principle of conserving energy?According to the conservation of energy principle, energy is neither created nor destroyed. It has the capacity to change types. The validity of the conservation of energy principle, like that of mass, depends on experimental observations; as a result, it is an empirical law.
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A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal spring with spring constant of 2. 0 ? 106 n/m. What is the maximum compression of the spring? (neglect the mass of the spring. ).
A 1500-kg car moving around 25 m/s collides with a horizontal spring that is initially uncompressed but has a spring stiffness of 2.0?106 n/m as well as a max compress of x = 0.68 meters.
What is another word for compression?Compress, constrict, contract, inflate, and shrink are a few words that frequently replace the word compress. While all of these phrases refer to "decreasing in bulk or area," compress indicates squeezing over resistance into a constricted area with a certain shape.
Briefing:Considering that,
The automobile weighs 1500 kg.
Vehicle speed, v = 25 m/s
spring's spring constant, k=2×10⁶ N/m
Let x be the greatest distance the spring may compress before breaking,
1/2mv²=1/2kx²
1/2mv²=1/2kx²
x=[tex]\sqrt{mv^{2} /k}[/tex]
x=[tex]\sqrt{1500*25x^{2} /2*10^{6} }[/tex]
x = 0.68 meters
The spring is thereby compressed by 0.68 meters.
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an explosion in a rigid pipe shoots out three pieces. a 6 g piece comes out the right end. a 4 g piece comes out the left end with twice the speed of the 6 g piece. from which end does the third piece emerge?
In an explosion a 6 g piece comes out of the right end and a 4 g piece comes out of the left end at twice the speed of the 6 g piece and the third piece comes out of the right end.
Initially all three balls are at rest so u = 0
Given m1 = 6g and m2=4g where m is the mass of balls
Let v1 be the velocity of the first ball = v(i) (denoted as (i) since the right end points to the positive X axis)
Let velocity v2 of second ball = 2(v)(-i) (denoted as (-i) since left end points negative X axis)
Mass of the third ball m3 = m and its velocity v3 = v'
By applying conservation of momentum
m1(u1) + m2(u2) + m3(u3) = m1(v1) + m2(v2) + m3(v3)
Since all balls are initially at rest u1 = u2 = u3 = u = 0
0 = (6×10⁻³)(v)(i) + (4×10⁻³)(2v)(-i) + m(v')
m(v') = (2×10⁻³)(v)(i)
v’ = (2×10⁻³)(v)(i)/(m)
So positive (i) indicates right end
So the third ball comes from the right end.
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A linear, ideal spring that is stretched by 8. 0 cm has an elastic potential energy of 20 j. What is the elastic potential energy of the same spring when it is stretched by 12 cm?.
The elastic potential energy in the spring at this elongation is 45J.
What is elastic potential energy?
The energy that is stored when a force is used to deform an elastic object is known as elastic potential energy. Until the force is released and the item bounces back to its original shape, doing labor in the process, the energy is retained. The item may be compressed, stretched, or twisted during the deformation.
To solve this problem we need to use the equations related to Elastic Potential Energy, which allows us to know the Energy stored in a spring based on its elastic constant and its respective compression. By definition it is described as
[tex]P E=\frac{1}{2} k x^2[/tex]
Where,
k = Spring constant
x = Displacement
Our values are given as
[tex]x_1=0.08 \mathrm{~m}[/tex]
As we do not know the spring constant but if the energy stored at the compression given then,
[tex]\begin{aligned}& P E=\frac{1}{2} k x^2 \\& 20=\frac{1}{2} k(0.08)^2 \\& k=6250 \mathrm{~N} / \mathrm{m}\end{aligned}[/tex]
In the case of the second compression and understanding that the spring constant is intrinsic to the internal force of the spring, then
[tex]x_2=0.12 m$$[/tex]
Replacing,
[tex]$$\begin{aligned}& P E=\frac{1}{2}(6250)(0.12)^2 \\& P E=45 . J\end{aligned}$$[/tex]
Therefore the elastic potential energy in the spring at this elongation is 45J.
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a long, straight wire carries a current i (see figure below). which of the following statements is true regarding the magnetic field due to the wire? more than one statement may be correct.
For a long straight wire carrying conductor the magnitude of the magnetic field produced around it is proportional to I/r, and the direction is out of the page at P.
A magnetic field is produced by moving charges. Charges are constantly moving in a conductor carrying current; as a result, magnetic fields are created all around the conductor.
The right-hand thumb rule indicates the direction of this magnetic field. The thumb of the right hand is used in this rule to indicate the current's direction. The direction of the magnetic field surrounding the wire is indicated by the curled fingers.
The magnitude of the magnetic field produced by the current carrying conductor depends on the following factors:
The magnitude of the current flowing through the conductor
The distance to the point where the field value is calculating.
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you observe a galaxy with a hydrogen beta absorption line 496.0 nm. the laboratory wavelength of this line is 486.1 nm. what is the galaxy's distance from us in mega-light years (mly)?
The galaxy with a hydrogen beta absorption of 496 nm then the galaxy's distance from us in mega-light years (mly) will be equal to 277.54 Mly.
What is Wavelength?
The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
As per the given information in the question,
The line's hydrogen laboratory wavelength, λ = 486.1 nm
The galaxy's spectrum's wavelength, λ' = 496.0 nm
Then, the change in wavelength,
Δλ = λ' - λ
Δλ = 9.9 nm
The speed of light, c = 2.998 × 10⁵ km/s
Use the equation of Doppler's effect,
v = c × Δλ/λ
v = 6,105.75 km/s
So, the radial velocity will be 6105.78 km/s.
v = H₀d
Here, v is the velocity of the galaxy, d is the distance between galaxies and H₀ is Hubble's constant.
d = v/H₀
d = 6105.75/22
d = 277.54 Mly
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the motion of a piston in an auto engine is simple harmonic. if the piston travels back and forth (side to side) over a distance of 12 cm, and the piston has a mass of 1.5 kg, what is the maximum speed of the piston and the maximum force acting on the piston when the engine is running at 3 800 rpm?
The maximum speed of the piston is 8.6 m/s and the maximum force acting on the piston when the engine is running at 3 800 rpm is 7 486 N
The given information is that the motion of a piston in an auto engine is simple harmonic. if the piston travels back and forth (side to side) over a distance of 12 cm, and the piston has a mass of 1.5 kg, The maximum speed of the piston is determined by the equation for the simple harmonic motion:
v = (2πfA)^0.5 where f is the frequency of the motion (in this case, 3 800 rpm), and A is the maximum displacement (in this case, 12 cm).
v = (2π(3800)(0.12))^0.5 v = 8.6 m/s.
The maximum force acting on the piston is determined by the equation for the simple harmonic motion:
F = mω^2A, where m is the mass of the piston (in this case, 1.5 kg), ω is the angular velocity (in this case, 2πf = 2π(3800) = 23 883 rad/s) and A is the maximum displacement (in this case, 12 cm).
F = (1.5)(23 883)^2(0.12) F = 7 486 N
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A truck is traveling at 25 m/s on a slippery road. The driver slams on the brakes and the truck starts to skid. If the coefficient of kinetic friction between the tires and the road is 0. 20, how far will the truck skid before stopping?.
If the coefficient of kinetic friction among the tires and the street is 0. 20, 312.5m far will the truck skid before stopping.
What is kinetic friction?
Kinetic friction is defined as a force that acts between moving surfaces. A body moving on the surface experiences a force in the opposite direction of its movement. The magnitude of the force will depend on the coefficient of kinetic friction between the two materials.
m = the mass of the truck
N = normal reaction
g = 9.8 m/s²
μ = 0.2, the coefficient of kinetic friction
The resistive force on the truck is
F = μN = μmg = 0.2*(9.8)m = 1.96m N
The acceleration (actually deceleration) is
a = F/m = -1.96 m/s²
Let d = distance for the truck to come to rest from an initial velocity of u = 35 m/s.
Then
u² + 2ad = 0
(35 m/s)² + 2(-1.96 m/s²)(d m) = 0
d = 35²/3.92 = 312.5 m
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a cd has a mass of 17 g and a radius of 6.0 cm. when inserted into a player, the cd starts from rest and accelerates to an angular velocity of 21 rad/s in 0.52 s. assuming the cd is a uniform solid disk, determine the net torque acting on it.
Assuming the cd is a uniform solid disk, Then the net torque acting on it is τ≈7.4×10⁻⁴ N
The product of an object's moment of inertia and angular acceleration is the torque operating on that item. We must know the CD player's moment of inertia and angular acceleration in order to calculate the torque operating on it.
Angular Acceleration:
α=ω2−ω1/t
α=22 rad/s²−0/0.91
α=24.17582rad/s²
Momemt of inertia:
I=1/2mr²
I=1/2(17×10⁻³ kg)(6.0×10⁻²m)²
I=0.0000306 kg.m²
Now, Torque:
τ=Iα
τ=(0.0000306)(24.17582)
τ=0.000739780092 kg⋅m²/s2
τ≈7.4×10⁻⁴ N
Therefore, Torque≈7.4×10⁻⁴ N
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he purpose of low beam headlights is to provide better visibility to a driver driving in fog, rain and smoke. a) true b) false
Answer: True
Explanation:
Any external force that acts against movement is called __________. A. Gravityb. Efficiencyc. Resistanced. Momentum.
Answer:
the answer is resistance
the velocity function is for a particle moving along a line. find the displacement and the distance traveled by the particle during the time interval . displacement
The displacement and the distance traveled by the particle during the time interval [-2, 5] are -26.83 units and 27.17 units.
Displacement is the straight path between the initial and end positions, whereas distance traveled is the actual length the body covers.
Here, the velocity is given as v(t)=(-t²)+3t-2 and the interval is [-2, 5]. By integrating the given velocity function, we will get the total distance traveled and displacement within the given interval.
The displacement is given as follows,
[tex]\begin{aligned}\int\limits^5_{-2} v(t)dt&=\int\limits^5_{-2} ((-t^2)+3t-2)dt\\&=\left[\frac{-t^3}{3}+\frac{3t^2}{2}-2t\right]^5_{-2}\\&=\left(\frac{5^3}{3}+\frac{3(5)^2}{2}-2(5)\right)-\left(-\frac{(-2)^3}{2}-2(-2)\right)\\&=-\frac{85}{6}-\left(\frac{38}{3}\right)\\&=-\frac{161}{6}\\&=-\mathrm{26.83\;units}\end{aligned}[/tex]
The total distance traveled is given by,
[tex]\begin{aligned}\int\limits^a_b|v(t)|dt&=\int\limits^5_{-2}|(-t^2)+3t-2|dt\\&=\int\limits^1_{-2}(t^2-3t+2)dt+\int\limits^2_1(-t^2-3t+2)dt+\int\limits^5_2(t^2-3t+2)dt\\&=\left[\frac{t^3}{3}-\frac{3t^2}{2}+2t\right]^1_{-2}+\left[-\frac{t^3}{3}+\frac{3t^2}{2}-2t\right]^2_{1}+\left[\frac{t^3}{3}-\frac{3t^2}{2}+2t\right]^5_2\\&=\frac{27}{2}+\frac{1}{6}+\frac{27}{2}\\&=\frac{163}{6}\\&=\mathrm{27.17\;units}\end{aligned}[/tex]
Therefore, the displacement and distance traveled are calculated using the given time interval.
The complete question is -
The velocity function is v(t)=(-t²)+3t-2 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [-2, 5].
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a student has built a 15 cm long pinhole camera for a science fair project. she wants to photograph her 180 cm tall friend and have the image in the film be 5 cm high. how far should the front of the camera be from her friend?
Considering that there is a certain distance between both the student's friend as well as the camera's front, 540 cm or 5.4m
What is distance?
Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting as well as ending point. The term "displacement" refers to a change in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial position to the ending position. For instance, if an object shifts from position A to position B, its position changes. Displacement is the term used to describe this shift in an object's position.
Let d be determined by the separation between the student's friend and the camera's front.
5.0cm/15cm = 180cm/d
d = (15cm)(180cm)/5.0cm
= 540cm or 5.4m
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Hydroelectric power plants are most commonly located nearA. coal-powered plants.B. nuclear-power plants.C. artificial reservoirs.D. estuaries.
Answer:
C. Artificial Resevoirs
Explanation:
For two main reasons; the first is the capacity of water of water they contain, and the second one is for mainteinance purpouse.
in which direction does a first quarter moon rise? a) north b) south c) east d) west e) the moon becomes a first quarter moon only after it has risen and changed phase.
The first quarter moon rises in the East. Option (c) is the right answer.
The first quarter moon occurs halfway between the new moon and the full moon. One-quarter of the moon is visible from Earth, meaning that you see half the daylit side of the moon.
Just like the Sun and the nighttime stars, the Moon's apparent rising in the east and set in the west each day is not from the Moon's orbit around the Earth, it's from the Earth spinning. The lunar orbit is slower and harder to see but you can still spot it.
The moon rises in the east and sets in the west, every day. It has to. The rising and setting of all celestial objects are due to Earth's continuous daily spin beneath the sky.
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the scattering of sunlight by the mixture of gas molecules in air results in the blue color of the sky. calculate the energy (in joules) of a single photon of blue light with a frequency of 7.30 × 10¹⁴ hz. (h
The energy (in Joules) of a single photon of blue light = [tex]4.83 * 10^-^1^9 J[/tex]
What is the energy of photon?
The energy that a single photon carries is known as photon energy. Energy is inversely correlated with electromagnetic frequency of the photon.
The energy of a photon is given by the formula
E = h*v
where,
h = planks constant
v = frequency
Given,
h = [tex]6.626 * 10^-^3^4 J s[/tex]
v = 7.30 × [tex]10^1^4[/tex] Hz
1 Hz = 1 [tex]s^-1[/tex]
v = 7.30 × [tex]10^1^4 s^-1[/tex]
E = [tex]6.626 * 10^-34 * 7.30 * 10^1^4[/tex]
E = [tex]48.36 *10^-^2^0 J[/tex]
E = [tex]4.83 * 10-19 J[/tex]
The energy (in Joules) of a single photon of blue light = [tex]4.83 * 10^-^1^9 J[/tex]
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A solenoidal coil with 30 turns of wire is wound tightly around another coil with 310 turns. The inner solenoid is 20.0 cm long and has a diameter of 2.50 cm. At a certain time, the current in the inner solenoid is 0.150 A and is increasing at a rate of 1700 A/s.
Part A For this time, calculate the average magnetic flux through each turn of the inner solenoid.
Part B For this time, calculate the mutual inductance of the two solenoids.
Part C For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid.
Mutual inductance is the property by which one coil affects the current and voltage of the other coil.
Magnetic flux us the total magnetic field around both the coils.
EMF are invisible energy around the coils, which are mainly referred to as radiation.
How to find mutual inductance, magnetic flux and EMF around two coils?
We know
N = 30 turns
N¹= 310 turns
Inner solenoid length L¹= 20 CM= 0.2m long
Diameter d¹= 2.5 CM= 0.025m
Current i¹= 0.150 A
Rate of increase in current = di¹/dt= 1700A/s
Part A : magnetic flux = ∅¹= B¹A¹
B¹= ûⁿ × n¹ × i¹ = 2.92× 10↑-4T
Thus, ∅= 2.92×10↑-4× π/4×0.025²
= 1.432×10↑-7 Wb
Part B
Magnetic flux in one coil× number of turns in second coil = mutual inductance× current in the first coil
∅¹ × N² = Mi¹
= 1.432×10^-7 ×30
M × 0.150=1.432×10^-7×30
M=2.86×10^-5H
Part C
E = M di¹/dt
= 2.86×10^-5×1700 V
= 0.048 V
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In view of both the given query The inner solenoid's mean flux density per rotation is 1.43 * 10⁻⁷ Wb, or the two solenoids' mutual coupling is 2.86 x 10⁻⁴ H. The induced emf in the exterior loop is 4.86 * 10⁻¹ V.
How do solenoids function?A solenoid operates by creating an electromagnetic field surrounding an armature, which is a moving core. The electromagnetic field causes the armature to move, and when it does, it opens and closing valves or switches, converting mechanical energy into electrical movements and force.
Briefing:Given:
N1 = 310 revolutions in the inner solenoid.
N2 = 30 is the number of revolutions in the outer solenoid.
The inner solenoid's length is 20 cm, or 0.2 meters.
Inner solenoid radius = r = diameter/2 = 2.50/2 = 1.25 cm = 0.0125 m
The inner solenoid's current I is equal to 0.150 A.
1700 A/s is the current growth rate, di/dt.
A). Average magnetic flux across the inner solenoid's turns is equal to BA.
Include the values:
Average magnetic flux via the inner solenoid's turns:
= [4π x 10⁻⁷][310/0.2][0.150]π(0.0125)²
= 1.43 * 10⁻⁷ Wb
B). The two solenoids' mutual inductance is given by M = N2 x (average flux) / current.
= (30 x 1.43 * 10⁻⁷) / 0.150
= 2.86 x 10⁻⁴ H
C). The change in current there in inner solenoid causes an induced emf in the outer magnet that is equal to M*di/dt.
= 2.86 x 10⁻⁴ * 1700
= 4.86 * 10⁻¹ V
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how much work does an elevator motor do to lift a 1500 kg elevator a height of 100 m ? express your answer with the appropriate units.
1.47 MJ work does an elevator motor do to lift a 1500 kg elevator a height of 100 m.
What is work in a physics?In physics, the term "work" refers to the energy transfer that takes place when an item is displaced over a distance by such an external force, at least a portion of which is supplied in the displacement direction. Stimulates into an object to cause some displacement is what is referred to as work. The ability to perform tasks is referred to as energy. The work is consistently the same.
Briefing:Work is simply the result of force multiplied by distance, so:
Work = Force * Distance
In this instance, force is simply equal to the elevator's weight, so:
Work = mass * gravity * distance
Work = 1500 kg * 9.8 m/s^2 * 100 m
Work = 1,470,000 J = 1.47 MJ
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in taking your pulse, you count 67 heartbeats in 1 minmin. part a what is the period of your heart oscillations?
The period of your heart oscillations = 60 / 67 cycles/min.
How do you find the period of oscillation?T = 2(m/k) describes this. We may calculate the period and, thus, the frequency by measuring the length of one full oscillation. Be aware that the period of a pendulum is independent of its mass, but the period of a mass on a spring is independent of the spring's length.Number of oscillations that were completed in the given unit of time. f = 1/T = ω/2π 4. Period of time (T) T = 2 /Section overview. A repetitive oscillation is known as periodic motion. The period T is the length of one oscillation. The frequency f is the number of oscillations per unit of time.Given data :
Time taken for 67 heart beats = 1 min = 1* 60 seconds =60 s The time taken for 1 heart beat = 60 / 67
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A heat engine has a cold reservoir of 250 k and a hot reservoir of 715 k. What is the maximum efficiency of the engine? a. 65. 0% b. 60. 8% c. 73. 6% d. 58. 6% e. 69. 1%.
Answer:
Heat in = 715 K
Heat out = 250 K
Heat converted to work = 715 - 250 = 465 K
Efficiency = 465 / 715 = .65
(a) Maximum efficiency = 65%
an inventor designs a machine that he claims will lift a 30 kg object with the application of only a 25 n force. if the inventor is correct, what is the shortest possible distance through which the force must be applied for each meter that the object is raised?
The shortest possible distance through which the force must be applied must be 0.83 meters.
What is force?
A force is indeed an influence that can alter an object's motion according to physics. A force may cause an object to mass to accelerate when it changes its velocity, such as when it moves away from rest. An intuitive way to describe force is as a push or even a pull. A force is a vector quantity because it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P). The net force acting on an object seems to be equal to the speed that its momentum changes over time, according to Newton's second law in its original formulation.
The shortest possible distance through which the force must be applied for each meter that the object is raised is 0.83 meters.
This is because the force needed to lift the object is 25 N,
and the mass of the object is 30 kg (30 x 9.8 = 294 N).
Therefore, the amount of work done for each meter of lifting is 25 N x 0.83 m = 20.75 Joules (J).
This means that each meter of lifting requires 20.75 J of work, and therefore the shortest possible distance through which the force must be applied must be 0.83 meters.
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