The distance a freely falling object falls from rest is one-half second is?

Answers

Answer 1

Answer:

[tex]s = ut + \frac{1}{2}a {t}^{2} \\ = \frac{1}{2} \times 9.81 \times ({ \frac{1}{2} })^{2} \\ s = 1.22m[/tex]


Related Questions

Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
metals?

Answers

Answer:

Metals that do not contain traces or large proportions of iron in them are called Non-Ferrous metals.

Non-Ferrous metals because they do not contain iron while those that contain iron are called ferrous metals

Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9520c as measured in the laboratory. What is the magnitudeof the velocity of one particle relative to the other

Answers

Answer:

the magnitude of the velocity of one particle relative to the other is 0.9988c

Explanation:

Given the data in the question;

Velocities of the two particles = 0.9520c

Using Lorentz transformation

Let relative velocity be W, so

v[tex]_r[/tex] = ( u + v ) / ( 1 + ( uv / c²) )

since each particle travels with the same speed,

u = v

so

v[tex]_r[/tex] = ( u + u ) / ( 1 + ( u×u / c²) )  

v[tex]_r[/tex] = 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )  

we substitute

v[tex]_r[/tex] = 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )  

v[tex]_r[/tex] = 1.904c / ( 1 + 0.906304 )

v[tex]_r[/tex] = 1.904c / 1.906304

v[tex]_r[/tex] = 0.9988c

Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c

You have two flashlights that have 0.500-A currents flowing through them. One flashlight has a single 1.50-V battery in its circuit, and the second flashlight has three 1.50-V batteries connected in a chain that provides 4.50 V. How much power is the battery in the first flashlight providing

Answers

Answer: 0.75 W

Explanation:

Given

Current flowing [tex]I=0.5\ A[/tex]

The first flashlight has a single 1.5 V battery

The second flashlight has three 1.5 V batteries connected to provide 4.5 V

Power is the product of voltage and current.

For the first flashlight

[tex]\Rightarrow P=1.5\times 0.5\\\Rightarrow P=0.75\ W[/tex]

Thus, the first flashlight providing 0.75 W of power.

Atoms are composed of protons, ______, and electrons.​

Answers

Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅

The [tex]\sf\blue{protons}[/tex] (positively charged) and the [tex]\sf\pink{neutrons}[/tex] (no charge) are in the centre of the atom, making up the nucleus.[tex]\sf\red{Electrons}[/tex] (negatively charged) are present in the outermost shell of the atom.

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

At what speed does light travel through water. n=1.33

Answers

Answer:

"In water, the speed of light is v01.33=2.26 x 108 m/s."

Explanation:

What is the speed of a wave if it has a wavelength of
42 m and a frequency of 7 hertz?

Answers

Answer:

♕ [tex]\large{ \red{ \tt{Step - By - Step \: Explanation}}}[/tex]

☃ [tex] \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} : [/tex]

Frequency ( f ) = 7 HertzWavelength ( λ ) = 42m

♨ [tex] \underline {\underline{ \orange{ \large{ \tt{T \: O \: \: F \: I \: N\: D}}}} }: [/tex]

Wave velocity ( v )

☄ [tex]\underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}: [/tex]

✧ [tex] \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}[/tex]

~Plug the known values and then multiply!

↦ [tex] \large{ \tt{7 \times 42}}[/tex]

↦ [tex] \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}[/tex]

☥ [tex] \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}} [/tex]

---------------------------------------------------------------

❁ [tex] \underline{ \large{ \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \: \: I\: N \: F \: O}}}} : [/tex]

Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

# KILL : Excuses

KISS : Opportunities

MARRY : Goals

♪ Hope I helped! ♡

☂ Have a wonderful day / night ! ツ

✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✔

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

A 5.0-m radius playground merry-go-round with a moment of inertia of 1,630 kg m2 is rotating freely with an angular speed of 1.6 rad/s. Two people, each having a mass of 69.5 kg, are standing right outside the edge of the merry-go-round and step on it with negligible speed. What is the angular speed of the merry-go-round right after the two people have stepped on

Answers

Answer:

The right solution is "0.511".

Explanation:

Given:

Initial moment of inertia,

= 1630 kg.m²

Radius,

= 5 m

Angular speed,

= 1.6 rad/s

Now,

The moment of inertia after stepping on will be:

= [tex]1630+2\times (69.5\times (5)^2)[/tex]

= [tex]1630+2\times (69.5\times 25)[/tex]

= [tex]5105 \ Kg.m^2[/tex]

hence,

As per the question, the angular speed is conserved, then

⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]

            [tex]2608=5105\times \omega'[/tex]

                [tex]\omega'=\frac{2608}{5105}[/tex]

                     [tex]=0.511[/tex]

A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor

Answers

Answer:

E = 124.7 N / C

Explanation:

Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.

The electric field of the standing wave is

            I = E²

            E =√I

where I is the intensity of the radiation.

What is it

             I = P / A

where P is the effective emission power, almost all the power of the microwave and A is the area of ​​the cavity, in the most used microwaves

P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²

             I = 700 / 0.045

             I = 15555.56 W/m²

let's calculate the electric field

            E = √15555.56

            E = 124.7 N / C

what is the transfer of heat energy by direct contact. A . convection b. radiation c. thermal or heat and d. conduction ​

Answers

Answer:

d. conduction ​

Explanation:

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.

In conclusion, conduction typically involves the transfer of heat energy by direct contact between two or more conductors such as a pot and electric cooker.

Answer:

d. conduction ​

Explanation:

Conduction is the transfer of energy from one molecule to another by direct contact.

ADHD is triggered ________ by genetic and neurological factors and ________ by social or environmental ones.
A. less; more
B. somewhat; somewhat
C. little; mostly
D. more; less

Answers

Answer:

D More: Less

Explanation:

ADHD is triggered more by genetic and neurological factors and less by social or environmental ones.

What is ADHD?

ADHD is one of the most common neurodevelopmental disorders of childhood. It is usually first diagnosed in childhood and often lasts into adulthood. Children with ADHD may have trouble paying attention, controlling impulsive behaviors (may act without thinking about what the result will be), or be overly active.

Moreover, ADHD tends to run in families and, in most cases, it's thought the genes you inherit from your parents are a significant factor in developing the condition. Research shows that parents and siblings of someone with ADHD are more likely to have ADHD themselves.

Therefore, adults with attention deficit hyperactivity disorder (ADHD or ADD) lead anxious lives. The nature of ADHD often makes day-to-day life stressful, creating situations and environments fraught with uncertainty – anxiety's primary fuel.

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During forced exhalation, such as when blowing up a balloon, the diaphragm and chest muscles create a pressure of 72.0 mm Hg between the lungs and chest wall. What force in newtons does this pressure create on the 605 cm2 surface area of the diaphragm

Answers

Answer:

F = 580.75 N

Explanation:

The force can be calculated through the following formula:

[tex]F = PA[/tex]

where,

F = Force = ?

P = Pressure = (72 mm Hg)(133.322 Pa/1 mm Hg) = 9599.18 Pa

A = Area = (605 cm²)(1 m²/10⁴ cm²) = 0.0605 m²

Therefore,

[tex]F = (9599.18\ Pa)(0.0605\ m^2)[/tex]

F = 580.75 N

Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulley without slipping. The mass of block A is 2.1 kg and the mass of block B is 4.1 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 358 J/m2. What is the angular frequency (in rad/s) of oscillations of this system

Answers

Answer:

[tex]F=1.159[/tex]

Explanation:

From the question we are told that:

Mass of pulley [tex]M=1kg[/tex]

Radius [tex]r=12cm[/tex]

Mass of block A [tex]M_a=2.1kg[/tex]

Mass of block B [tex]m_b=4.1kg[/tex]

Spring constant[tex]\mu= 358 J/m2[/tex]

Generally the equation for Torque is mathematically given by

Since [tex]\sumF=ma[/tex]

At mass A

 [tex]T_2-f_3=2.1a[/tex]

At mass B

 [tex]4.8-T_1=4.1a[/tex]

At  Pulley

 [tex]R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}[/tex]

 [tex]R(T_1-T_2)=0.55a[/tex]

Therefore the equation for total force F

At mass A+At mass B+At  Pulley

 [tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a[/tex]

 [tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a[/tex]

 [tex]-f_3+4.1=6.75a[/tex]

 [tex]-f_3=6.75a+4.8[/tex]

Since From above equation

[tex]M_{eff}=6.7kg[/tex]

Therefore

[tex]T=2\pi \sqrt{{\frac{M_{eff}}{k}}[/tex]

[tex]T=2\pi \sqrt{{\frac{6.75}{\mu}}[/tex]

[tex]T=0.862s[/tex]

Generally the equation for frequency is mathematically given by

[tex]F=\frac{1}{T} \\F=\frac{1}{0.862}[/tex]

[tex]F=1.159[/tex]

An electron that has an instantaneous velocity of is moving through the uniform magnetic field (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity

Answers

Answer:

Explanation:

From the given information:

The missing value are as follows:

The velocity  [tex]v ^{\to} = (2.0 \times 10^6 \ m/s) \hat i + (3.0 \times 10^6 \ m.s) \hat j[/tex]

The uniform magnetic field [tex]B^{\to} = (0.030 T)\hat i -(0.15 T) \hat j[/tex]

The force on electron as a result of the Magnetic field is:

[tex]F^\to = q(v^\to \times B^\to)[/tex]

here;

Change of electron [tex]q = -1.6 \times 10^{-19} C[/tex]

Then,

[tex]v^{\to} \times B^{\to} = \left|\begin{array}{ccc}2\times10^6&3\times 10^6&0\\0.03&-0.15&0\end{array}\right|[/tex]

[tex]= \hat i(0-0) -\hat j ( 0-0) +\hat k (-3\times 10^5 -0.9\times 10^5) \\ \\ =-3.9 \times 10^5 \ k[/tex]

[tex]F^\to = q(v^\to \times B^\to)[/tex]

[tex]F^{\to} = -1.6 \times 10^{-19} \times -3.9 \times 10^5 \\ \\ F^{\to} = 6.24 \times 10^{-14 } \ N[/tex]

For the proton with the same velocity:

[tex]q = 1.6 \times 10^{-19 } \ C \\ \\ F = q (v^\to * B^\to) \ \\ \\ F^\to = q(-3.9 \times 10^5) \\ \\ F = (1.6 \times 10^{-19}) (-3.9 \times 10^5) \\ \\ \mathbf{F ^{\to} = -6.24 \times 10^{-14} \ N}[/tex]

In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt/pi including the background correction.

Answers

Answer:

The answer is "[tex]15.38\%[/tex]"

Explanation:

Background[tex]= 13 \ mv\\\\[/tex]

corrected signal[tex]= 91 \ mv-13\ mv= 78\ mv\\\\[/tex]

with attenuator[tex]=25\ mv-13\ mv= 12\ mv\\\\[/tex]

[tex]\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%[/tex]

At the Olympics, high-diving competition,a diver from the top board curves her body in order to?
A. Dive clearly into the water
B. Spin more
C. Increase her energy
D. Spin more slowly
E. Increase her speed​

Answers

E increase her speed

The correct option is E. Increase her speed​

High-diving is the process or way in which a person jump into water  or swimming pool from a higher heights.

A Diver  is a person who dive or Fall into a water from a top board or diving board .

Therefore she was curving her body from the top board in order to Increase her speed​ which will enable her to spin or flip more faster.

Inconclusion The correct option is E. Increase her speed.

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An old fashioned string of 80 Christmas lights is wired in series. Each bulb has a resistance of 2 Ohms and the entire string is plugged into a 120V outlet. What is the current passing through each of the bulbs?

Answers

The sum of the resistance = 2 ohms x 80 lights = 160 ohms.

Current = Total voltage / total resistance:

Current = 120V / 160 ohms

Current = 0.75 Amps

Which of the following is form of energy:
a) Power
b) Light
C) pressure
d) None​

Answers

Answer:

Explanation:

b) light

A sound wave with a frequency of 700 Hz and a wavelength of 5 m travels through a liquid. How fast does sound travel through the liquid?

A.
140 m/s
B.
0.007 m/s
C.
3500 mHz
D.
3500 m/s

Answers

Answer:

It’s D, 3500 m/s
It’s D 3500 m/s in most cases

Please helpppppppppp!!!!!!!!!!!

Answers

37N is the answer.

Also pls mark me brianliest!!


5. Stopping a fast-moving object is harder than stopping a slow-moving
one.
True
False

Answers

true because well it’s moving fast lol sometimes ur eyes have a hard time following its speed
True because it’s fast

There are three 20.0 Ω resistors connected in series across a 120 V generator

Answers

Answer:

That is equal to R1 + R2. If three or more unequal (or equal) resistors are connected in series then the equivalent resistance is: R1 + R2 + R3 +…, etc. One important point to remember about resistors in series networks to check that your maths is correct.

A bullet with a mass of 12 g moving horizontally strikes a fixed block of wood and penetrates a distance of 5.2 cm. The speed of the bullet just before the collision is 640 m/s. What is the average force that the wood exerted on the bullet

Answers

Answer:

F = 47261.5 N = 47.26 KN

Explanation:

First, we will calculate the deceleration of the bullet by using the third equation of motion:

[tex]2as = v_f^2-v_i^2[/tex]

where,

a = deceleration = ?

s = distace covered = 5.2 cm = 0.052 m

vf = final speed = 0 m/s

vi = initial speed = 640 m/s

Therefore,

[tex]2(a)(0.052\ m) = (0\ m/s)^2-(640\ m/s)^2\\\\a = -\frac{409600\ m^2/s^2}{0.104\ m}\\\\a=-3938461.5\ m/s^2[/tex]

negative sign shows deceleration.

Now for the force, we will use Newton's Second Law of Motion:

F = ma

where,

F = Force = ?

m = mass of bullet = 12 g = 0.012 kg

Therefore,

F = (0.012 kg)(3938461.5 m/s²)

F = 47261.5 N = 47.26 KN

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order

Answers

Answer:

377 nm

Explanation:

Number of lines per meter is, [tex]N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}[/tex]

Grating element is, [tex]d=\frac{1}{N}[/tex]

[tex]=1.8868 \times 10^{-6} \mathrm{~m}[tex]

Order is, n=5

Condition for maximum intensity is, [tex]d \sin \theta=n \lambda[/tex]

 [tex]\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}[/tex]

Steel Usually forms a
magnet that keeps its magnetism when moved away from a
magnetic source. What one word completes the sentence?

Answers

Answer:

Permanent magnetism (of the steel)

make me brainliestt :))

4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?​

Answers

Force = area * pressure
F = 0.0025 m * 200000 pa
F = 500 N

paano matutugunan o matutulungan ng pamahalaan at ng mga guro yubg mga estudyanteng nakararanas nag stress at anxiety.

Answers

Answer: how the government and teachers can address or help students experiencing stress and anxiety.

Explanation:

An irrigation canal has a rectangular cross section. At one point where the canal is 18.2 m wide and the water is 3.55 m deep, the water flows at 2.55 cm/s . At a second point downstream, but on the same level, the canal is 16.3 m wide, but the water flows at 11.6 cm/s . How deep is the water at this point

Answers

Answer:

Explanation:

Rate of volume flow at two points will be same at two points .

A₁ V₁ = A₂V₂

A₁ and A₂ are area of cross section at two points and V₁ and V₂ are velocities .

A₁ = 18.2 x 3.55 = 64.61 m²

V₁ = 2 .55 x 10⁻² m/s

A₂ = 16.3 x d = 16.3 d  m²

d is depth at second point .

V₂ = 11.6 x 10⁻² m/s

64.61 m² x 2 .55 x 10⁻² m/s = 16.3 d  m² x 11.6 x 10⁻² m/s

d = .87 m

so canal is .87 m deep.

Why is it important for equipment for sport to be strong? To protect us

Answers

Answer:

To protect us.

Explanation:

For ex. your dunking on a basketball hoop if that wasn't strong you would fall on your back and get injured.

A closed loop conductor that forms a circle with a radius of 2.0 m is located in a uniform but changing magnetic field. If the maximum emf Induced in the loop is 5.0 V what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies

Answers

Answer:

The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.

Explanation:

Given;

radius of the circular loop, r = 2.0 m

maximum induced emf, E = 5.0 V

The emf induced in a magnetic field is given as;

[tex]emf = \frac{d\phi}{dt} \\\\\phi = AB\\\\emf = A\frac{dB}{dt} \\\\\frac{dB}{dt} = \frac{emf}{A} \\\\where;\\A \ is \ the \ area \ circular \ l00p = \pi r^2 = \pi (2)^2 = 4\pi \ m^2\\\\\frac{dB}{dt} = \frac{5}{4\pi} \\\\\frac{dB}{dt} = 0.398 \ T/s[/tex]

Therefore, the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.

which statement describes the molecules and a reaction once it reaches equilibrium
A. They maintain stable concentrations
B. They stop moving
C. They consist mainly of reactant molecules
D. They react only if they are disturbed

Answers

Answer:

They maintain stable concentrations

Explanation:

Just took the test.

The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is option A as the When a chemical reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.

What is equilibrium?

Equilibrium is a dynamic state, meaning that the reaction is still ongoing but the rates of the forward and reverse reactions are equal. This means that molecules are still reacting with each other, but at a constant rate, so that the concentrations of the reactants and products remain stable. When a reaction is not at equilibrium, the concentrations of the reactants and products change as the reaction progresses. However, once equilibrium is reached, the concentrations of the reactants and products no longer change, but the individual molecules are still moving and reacting with each other.

Hence, The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is an option. A 

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