The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.53 m and 1.06 m, respectively. The respective rotational speeds are 443 rev/min and 4,120 rev/min. Calculate the speeds of the tips of both rotors. Compare these speeds with the speed of sound, 343 m/s.

Answers

Answer 1

Answer:

Main motor= 174.66 m/s

Tail motor=228.66 m/s

Explanation:

✓Main motor

Diameter of the main motor= 7.53 m

rotational speeds = 443 rev/min

The speed of the trip= rotational speed × radius

Radius of the main rotor= diameter/ 2

= 7.53 /2=3.765 m

The speed of the trip= (443 ×2π ×3.765)

= 10479.69 meter per minutes

We can convert to metre per seconds as

10479.69/ 60

= 174.66 m/s( less than speed of sound)

✓ Tail motor

Diameter of the main motor= 1.06 m

rotational speeds = 4120 rev/min

The speed of the trip= rotational speed × radius

Radius of the main rotor= diameter/ 2

= 1.06/2

= 0.53m

The speed of the trip= (4120 ×2π ×0.53)

= 13719.96 meter per minutes

We can convert to metre per seconds as

13719.96/ 60

= 228.66 m/s( less than speed of sound)


Related Questions

A toaster has a resistance of 30 ohms. It draws 2A of current from the outlet. What is the potential difference ?
A. 60v
B. 2v
C. 15v
D.30v

Answers

Answer:

60V

Explanation: . V = IR = 1

30*2=60

Can anyone help me with the Wet Lab Guide - Coulomb's Law report? I'm really having trouble with it. I have attached the worksheet

Answers

Answer:

Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.

Explanation:

Besides gravity, what factor keeps the moon and Earth in orbit?

force
inertia
mass
distance

Answers

Answer:

interna

Explanation:

please mark as brainllest

Answer is inertia
Good Luck ;)

A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis through its center, how large is the torque acting on the cylinder? With work please

Answers

Answer:

0.011 N-m

Explanation:

Given that

The mass of a solid cylinder, m = 30 kg

The radius of the cylinder, r = 0.18 m

The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]

It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :

[tex]\tau=I\alpha[/tex]

Where

I is the moment of inertia of the cylinder,

For cylinder,

[tex]I=\dfrac{mr^2}{2}[/tex]

So,

[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]

So, the required torque on the cylinder is 0.011 N-m.

What is the IMA of an inclined plane that is 5m long and 2m high?
A. 0.4
B. 2.5
C. 0.4m
D. 2.5m

Answers

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

What is mechanical advantage of inclined plane ?

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

Learn more about mechanical advantage here:

https://brainly.com/question/16617083

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You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment building. You travel in the elevator 22.0 m upward to your floor, walk 12.0 m north to the door of your apartment, and then walk 6.0 m due east to your balcony that overlooks the street. Your friend is standing where you left her.
Now how far are you from your friend?
Express your answer with the appropriate units.

Answers

Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

= 26.3 m

Net displacement from starting point = 26.3 m .

can someone help me :(​

Answers

Answer:

1. This is a speed graph.

2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.

3. Increasing, kind of rapidly going up since the slope is rising not falling.

A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.

Answers

Answer:

ΔQ = 4896 KJ

Heat Flux = 57407.55 W/m²

Cost = $ 0.176

Explanation:

The amount of heat dissipated in two hours can be given as:

[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]

where,

P = Power of Iron = 800 W

t = time taken = 2 hrs

η = Conversion efficiency = 85% = 0.85

[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]

ΔQ = 4896 KJ

Now, for heat flux:

[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]

Heat Flux = 57407.55 W/m²

Now, for total heat energy in KWhr in two hours:

[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]

Cost = $ 0.176

If a large number of waves pass by a certain point in a given time, the waves have a low frequency. none of the above. a high frequency. it doesn't affect frequency.

Answers

Answer:

Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz

The floor on a dance hall can take a pressure of 3.5MPa before getting damaged. A lady of mass 60kg wears high heeled shoes. What is the smallest area of the sole of a heel she could wear such that it won't permanently damage the floor

Answers

Answer:

smallest area of the heel is 0.000168  m^2

Explanation:

Recall that pressure is defined as: Force / area. Therefore to reach a pressure of 3,500,000 Pa using a force: m * g = 60 kg * 9,8 m/s^2 = 588 N, one needs:

Area = 588 / 3500000 m^2 = 0.000168  m^2

Which equation will tell you the acceleration of the object?

Answers

Answer:

In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2

Explanation:

Water boils to power a steam engine. Which statement best describes the changes in the water as it boils?

Answers

Option B

kskmsnsnsmjsjsn

Answer:

C. The potential energy of the particles increases as the intermolecular forces are overcome

Explanation:

Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 mm apart and are emitting 1700-HzHz sound waves into a room where the speed of sound is 340 m/sm/s . Consider a point 4.0 mm in front of speaker 1, which lies along a line from speaker 1, that is perpendicular to a line between the two speakers. Is this a point of maximum constructive interference, a point of perfect destructive interference, or something in between

Answers

Answer:

The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

Explanation:

Given data in the question;

first we find the wavelength of the sound λ

Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.

wavelength λ  = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m

L1 = 4 m

L2 = √(4² +2² ) m

delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m

x = deltaL / λ

If the result is nearly an integer, the waves reinforce at the point.

If it is nearly an integer + 0.5, the waves interfere destructively at the point.

If it is neither, the point is "something in between".

so we solve for  x

x = 0.472 m / 0.2m

x = 2.36

since its not an integer, it is not point maximum constructive interference

delta L = ( 2x + 1 ).λ/2

x = ((2deltaL/λ) - 1)/2

x = (((2×0.472)/0.2) - 1)/2

x = 3.72 / 2

x = 1.86

Here also, it is not an integer, so it is not a point perfect destructive interference.

Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answers

This question is incomplete, the complete question is;

A positive charge of magnitude Q1 = 6.5 nC is located at the origin.

A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answer:

the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C    

Explanation:

Given the data in the question;

Q1 = 6.5 nC, Q2 = -3.5 nC

from the image below, to get our angle ∅

tan∅ = opp/adj

tan∅ = 10.5 / 16.5

tan∅ = 0.636363

∅ = tan⁻¹( 0.636363 )

∅ = 32.47°

also, r1 = √( 16.5² + 10.5²)

r1 = √( 272.25 + 110.25 )

r1 = √382.5

r1 = 19.55 cm = 0.1955 m

Now, the x-component of the electric field at point P due to charge Q1 will be;

Ex = E2cos32.47°

= (kQ1/r1²)cos32.47°

we know that;  k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²

Q1 = 6.5 nC = 6.5 × 10⁻⁹ C

so we substitute

= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°

= (58.5 / 0.03822025) × 0.843672

= 1291.33 N/C

Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2
Solution:

Answers

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]

So, the magnitude of the electrostatic force is 36 N.

Which of the following examples, would best represent the input energy and then
'wasted energy forms when watching TV.
A. Chemical, and then heat and electrical.
B. Chemical, and then heat, kinetic, sound
C. Electrical, and light, sound, heat
D. Electrical, and then sound and heat

Answers

Answer:

I think the answer is c electrical, and light , sound hewt

I need help with this question

Answers

Option 3) a Soccer Ball

will travel the farthest distance.

Answer:

a bowling ball

pls follow me and Mark as brainliest and follow me to get free thanks to all your answers

1) The cause of magnetism is
A. atoms forming “domains” that are arranged randomly
B. atoms forming "domains” that are arranged uniformly
C. atoms forming "dolomites” that are arranged randomly
D. atoms forming “dolomites” that are arranged uniformly

Answers

Answer:

I think it's A, I'm not sure though

Suppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 43 cm. (a) How much work is needed to stretch the spring from 33 cm to 38 cm

Answers

Answer:

Workdone = 0.67 Joules

Explanation:

Given the following data;

Workdone = 6J

Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m

The workdone to stretch a string is given by the formula;

Workdone = ½ke²

Where;

k is the constant of elasticity.

e is the extension of the string.

We would solve for string constant, k;

6 = ½*k*0.15²

6 = ½*k*0.0225

Cross-multiplying, we have;

12 = 0.0225k

k = 12/0.0225

k = 533.33N/m

a. To find the workdone when e = 33, 38.

Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m

Workdone = ½*533.33*0.05²

Workdone = 266.67 * 0.0025

Workdone = 0.67 Joules

Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.

Please answer this question correctly

Answers

20 push ups

hope thats correct^^

What distance will a car cover while uniformly accelerating from 12 m/s to 26 m/s in 14 seconds?

Answers

Answer:

266 m

Explanation:

Why won’t anyone help me please anybody help me I really need help .

Answers

Answer:

1➡️ this is the method of decomposition

2➡️ H2 and O2

3➡️ b

sorry if I am wrong

A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest

Answers

Answer:

[tex]m=90.1kg[/tex]

Explanation:

From the question we are told that

Force F=39400

Initial speed [tex]V_1=35m/s[/tex]

Distance[tex]d=1.4m[/tex]

Generally the equation for acceleration is mathematically given by

[tex]a=\frac{V^2-U^2}{2d}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=-437.5m/sec^2[/tex]

Generally the equation for mass is mathematically given by

[tex]F=ma\\m=F/a[/tex]

[tex]m=\frac{-39400}{-437.5}[/tex]

[tex]m=90.1kg[/tex]

A rocket has a mass of 156,789 kg and is traveling at 45.6 m/s. How much kinetic energy does the rocket
possess?

Answers

Explanation:

K.E =1/2 mv^2

=1/2(156789)(45.6)^2

=78,394.5 × 2,079.36

=163,010,387.52 kg m/s

This should be your answer.

A very long, solid cylinder with radius R has positive charge uniformly distributed throughout it, with charge per unit volume r. (a) Derive the expression for the electric field inside the volume at a distance r from the axis of the cylinder in terms of the charge density r. (b) What is the electric field at a point outside the volume in terms of the charge per unit length l in the cylinder

Answers

Answer:

Explanation:

From the given information.

The charge density of the cylinder can be computed as:

[tex]\rho = \dfrac{Q_t}{V_t}[/tex]

where:

[tex]Q_t[/tex] = total charge on cylinder

[tex]\rho[/tex] = density of the cylinder

[tex]V_t =[/tex] net volume on cylinder

Considering the charge enclosed by the Gaussian surface; we have:

Q = ρV

Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

Here;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:

[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]

By rearrangement;

[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]

[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]

(b)

Using the same formula:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

where;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;

Then:

[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]

[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]

Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].

From above [tex]\lambda[/tex] = the charge per unit length

[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]

Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes to an A-note at 440 Hz while the Boston Symphony Orchestra tunes to 442 Hz. If the speed of sound is constant at 343 m/s, find the magnitude of difference between the wavelengths of these two different A-notes. (Enter your answer in m.)

Answers

Answer:

Δλ = 3*10⁻³ m.

Explanation:

At any wave, there exists a fixed relationship between the speed of  the wave, the wavelength, and the frequency, as follows:

       [tex]v = \lambda* f (1)[/tex]

       where v is the speed, λ is the wavelength and f is the frequency.

Rearranging terms, we can get λ from the other two parameters, as follows:

       [tex]\lambda = \frac{v}{f} (2)[/tex]

Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:

        [tex]\lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m (3)[/tex]

        [tex]\lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m (4)[/tex]

The difference between both wavelengths, is just the difference between (3) and (4):

       [tex]\Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)[/tex]

       ⇒ Δλ = 3*10⁻³ m.

Explain how to identify a starting position on a line.

Answers

Answer:

We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

Position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system

Position vectors start at the origin and terminate at any arbitrary point.

In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.

In terms of direction of the line, the direction of the position vector points from the starting point of  the coordinate system towards the given point.

Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system.

Learn more here: https://brainly.com/question/20451639

what did classical physics predict would happen to the light given of by an object as its tempurtare increased

Answers

When the temperature of an object that is giving off light is increased, the particles in the object will move at a faster rate and there will be increased vibration of these molecules. This will makes the object to emit more light and to shine more brightly.

Answer:

The energy of the light would increase from visible light into the ultraviolet range.

Explanation:

blah blah blah, blah blah BLAH

A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show work

Answers

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85  = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x  5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788  x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

Suppose that the air resistance a car encounters is independent of its speed. When the car travels at 15 m/s, its engine delivers 20 hp to its wheels. What is the power delivered to the wheels when the car travels at 30 m/s

Answers

Answer:

22.5 hp

Explanation:

The power delivered to an object is given by :

[tex]P=F\times v[/tex]

Where

F is force and v is velocity of the car.

For the same force, power is directly proportional to the velocity.

So,

[tex]\dfrac{P_1}{P_2}=\dfrac{v_1}{v_2}\\\\P_2=\dfrac{P_1v_2}{v_1}\\\\P_2=\dfrac{15\times 30}{20}\\\\P_2=22.5\ hp[/tex]

So, the new power is 22.5 hp.

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