Answer:
The cell theory
Explanation:
The explanation of the relationship between the building blocks of life based on the evidence gathered by scientists from studying these building blocks is called the cell theory.
Many scientists study the building blocks. One of the earliest scientists to study these blocks gave them the name 'cells'. Thereafter, several other scientists studied different aspects of the cell and, eventually, the cell theory was propounded. There are three aspects to the theory:
All living organisms are made up of cells.The cell is the basic unit of life.Cells arose from preexisting cells by cell division.A moving sidewalk has a velocity of 1.3 m/s north. If a man walks south on the sidewalk at a speed of 0.9 m/s, how long does it take him to travel 20 m relative to a stationary observer? O A. 21.9 s B. 15.4 s O C. 33.3 O D. 50.0 S
help please!!!
Answer:
D: 50 s
Explanation:
We are told that the sidewalk has a velocity of 1.3 m/s north.
Also, we are told that the man walks south on the sidewalk at a speed of 0.9 m/s.
Thus, it means they are moving in opposite directions. The net velocity of the man will be;
v_net = 1.3 - 0.9
v_net = 0.4 m/s
We want to find how long does it take him to travel 20 m relative to a stationary observer,thus;
We we know that;
Time = distance/speed
Time = 20/0.4
Time = 50 s
On a particle level, when does the least amount of thermal conduction occur
in a liquid?
A. When particles stop moving
B. When the average speed of particles is the same throughout the
liquid
C. When slow particles sink to the bottom
D. When fast particles rise to the top
Answer:
B. When the average speed of particles is the same throughout the liquid
Henrietta manages to swing at a softball that was pitched very low - it almost hit the home
plate! Starting from very near the ground, the ball is launched upward at an angle with
amazing speed. 30 m/s upwards and 20 m/s across. 100m away from home plate is the outfield fence that's 24m tall. Will
Hentrietta get a home run?
a) How long will the ball take to get to the top?
b) How far from home plate will the ball be, once it's at the top?
c) Did the ball reach the fence yet, when it gets to the top?
d) How high up is the softball when it's at the top?
e) how long in seconds will it take for the ball to get 100m away from home plate?
F) How high above the ground is the ball when it’s 100m away from home plate?
G) finally, when the ball is 100m away from home plate, how high above the ground is it?
Answer:
a) The time it takes the ball to reach maximum height is approximately 3.06 seconds
b) The distance of the ball from the home plate once it is at the top is approximately 38.78 m
c) No
d) The height of the ball when it is at the top is approximately 45.92 m
e) The time it takes the ball to travel 100 m horizontally is 5 seconds
F) The height of the ball when it is 100 m away from the home plate is 27.5 m
G) The height of the ball above the ground when it 100 m away from the home plate, is 27.5 m
The height of the ball above the wall at 100 m from home plate is 3.5 m
Explanation:
The given parameters for the motion of the ball are;
The upward (vertical) velocity of the ball, [tex]u_y[/tex] = 30 m/s
The across (horizontal) velocity of the ball, uₓ = 20 m/s
The distance from the home plate to the outfield fence = 100 m
The height of the outfield fence = 24 m
a) The time, '[tex]t_{mh}[/tex]', it takes the ball to reach maximum height is by the following kinematic equation of motion;
[tex]v_y[/tex] = [tex]u_y[/tex] - g·t
Where;
[tex]u_y[/tex] = 30 m/s
g = The acceleration due to gravity ≈ 9.8 m/s²
At maximum height, we have;
[tex]v_y[/tex] = 0 m/s, t = [tex]t_{mh}[/tex]
∴ 0 m/s = [tex]u_y[/tex] - g·[tex]t_{mh}[/tex]
[tex]u_y[/tex] = g·[tex]t_{mh}[/tex]
[tex]t_{mh}[/tex] = [tex]u_y[/tex]/g
∴ [tex]t_{mh}[/tex] = [tex]u_y[/tex]/g = (30 m/s)/(9.8 m/s²) = 150/49 s ≈ 3.06 seconds
The time it takes the ball to reach maximum height, [tex]t_{mh}[/tex] ≈ 3.06 seconds
b) The horizontal distance travelled by the ball, when it is at maximum height, [tex]x_{mh}[/tex], is given as follows;
[tex]x_{mh}[/tex] = uₓ × [tex]t_{mh}[/tex] = 20 m/s × 150/49 s
[tex]x_{mh}[/tex] = 20 m/s × 150/49 s = 3000/49 m
[tex]x_{mh}[/tex] = 3000/49 m
The distance of the ball from the home plate, 'd', once it is at the top (maximum height), is given as follows;
d = 100 m - [tex]x_{mh}[/tex]
∴ d = 100 m - 3000/49 m = 1900/49 m ≈ 38.78 m
The distance of the ball from the home plate once it is at the top = d ≈ 38.78 m
c) The ball is yet to reach the fence when it gets to the top
The ball has approximately 38.78 meters to reach the fence
d) The height of the ball, [tex]h_{max}[/tex], when it is at the top is given by the following kinematic equation
[tex]h_{max}[/tex] = [tex]u_y[/tex]²/(2·g)
Where;
[tex]u_y[/tex] = 30 m/s
g = The acceleration due to gravity ≈ 9.8 m/s²
∴ [tex]h_{max}[/tex] = (30 m/s)²/(2×9.8 m/s²) = 2,250/49 m ≈ 45.92 m
The height of the ball when it is at the top, [tex]h_{max}[/tex] ≈ 45.92 m
e) The time, t₁₀₀, it will take the ball to get 100 m from home plate is found from the following relationship;
Velocity, u = Distance, x/(time, t)
∴ Time = Distance/(Velocity)
t = x/v
The given distance is the horizontal distance, therefore, we use the horizontal component of the velocity as follows;
v = Horizontal velocity of the softball = uₓ = 20 m/s
x = The given horizontal distance travelled by the ball = 100 m
t₁₀₀ = The time it takes the ball to travel 100 m horizontally
∴ t₁₀₀ = x/(uₓ) = 100 m/(20 m/s) = 5 s
The time it takes the ball to travel 100 m horizontally, t₁₀₀ = 5 seconds
F) The height of the ball above ground when it is 100 m away from the home plate is given as follows;
When the ball is 100 m from the home plate, the time, t₁₀₀ = 5 seconds
The height of the ball at 100m, [tex]h_{t_{(100 \, m)}}[/tex], is given according to the kinematic equation of motion for vertical height reached by an object as follows;
h = [tex]u_y[/tex]·t - 1/2·g·t²
∴ [tex]h_{t_{(100 \, m)}}[/tex] = [tex]u_y[/tex]·t₁₀₀ - 1/2·g·t₁₀₀²
Plugging in the known values gives;
[tex]h_{t_{(100 \, m)}}[/tex] = 30 m/s × 5 s - 1/2 × 9.8 m/s × (5 s)² = 27.5 m
The height of the ball when it is 100 m away from the home plate, [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m.
G) The height of the ball above the ground when it 100 m away from the home plate, is [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m
The height of the ball above the wall at 100 m from the home plate = The height of the ball when it is 100 m away from the home plate - The height of the wall at 100 m away from the home plate
∴ The height of the ball above the wall at 100 m from home plate = 27.5 m - 24 m = 3.5 m.
here is it u can see it
Answer:
The first one is true.
Explanation:
Here it is
What happens to sediment as a result of erosion and deposition?
(Basically what happens when Erosion or Deposition occur I think. Pls tell me if I was right along with your answer.)
Answer:
In the explanation
Explanation:
After erosion and eruptions which is a primary occuration for sediments, this will create heat and tough pressure leading the sediment to be extremely stable and Hard.
Josie has a bag of ice that weighs 5 pounds. she left it in a sealed container and it melted. how much does the resulting water weigh? how do you know this?
A potential difference of 12Voltage is applied across a resistor of 120resistance the current in the circuit is
Answer:
the current flowing in the circuit is 0.1 A.
Explanation:
Given;
potential difference, V = 12 V
resistance of the circuit, R = 120 ohms
The current flowing in the circuit is calculated as;
V = IR
I = V/R
where;
I is the current flowing in the circuit
I = 12 / 120
I = 0.1 A
Therefore, the current flowing in the circuit is 0.1 A.
A shearing of 50N is applied to an aluminum rod with a length of 10m a cross sectional area of 1.0×10-5 and a shear modulus of 2.5×1010 as result the rod is sheared through a distance
Answer:
0.002 m or 2 mm
Explanation:
Given that:
Force, F = 50N
Area = 1 * 10^-5
Length, L = 10m
Shear modulus, = 2.5 * 10^10
Using the relation ;
D = (50 ÷ 1*10^-5) ÷ (2.5 * 10^10 ÷ 10)
D = 5000000 ÷ 2.5 * 10^9
D = 5 * 10^6 ÷ 2.5 * 10^9
D = (5/2.5) * 10^(6-9)
D = 2 * 10^-3
D = 0.002 m
1m = 1000 mm
0.002m = (1000 * 0.002) = 2 mm
Which of the following is NOT accelerating?
A ball being juggled.
A women walking at a constant speed of 2.5 m/s along a straight path.
A rocket taking off.
A car slowing down toward a stop sign.
Answer:
3 of them are not accelerating . only one of them is and that one is the rocket taking off because its speed increases
Answer:
Second Option
Explanation:
The answer is the second option or "a women walking at a constant speed of 2.5 m/s along a straight path." Remember that constant means always staying the same so if a women is walking at a constant speed of 2.5 miles per hour on a straight path, she will remain at her current speed at 2.5 mils per hour which isn't acceleration.
Hope this helps.
Can we always see the same amount of the illuminated side of the Moon from Earth? Explain. Thanks so much for everyone's help! :)
Answer:
Nope.
Explanation:
No. The Moon rotates on its own axis at the same rate that it orbits around Earth. That means we always see the same side of the Moon from our position on Earth. The side we don't see gets just as much light, so a more accurate name for that part of the Moon is the "far side."
No, we can't see the similar quantity of the illuminated side of the Moon from the planet (Earth).
The gravitation of the moon somewhat distorts the form of our entire globe as well as provides us tidal waves. Earth also taps upon that moon, generating a stony and high-threshold "bulge" that faces us.It finished functioning like something of brakes and slowed right down the moon's rotation to the common material, and therefore high moonlight tide confronts us constantly.
Thus the above answer is correct.
Learn more:
https://brainly.com/question/11606610
Plzzz what is the theory of relativity????? i know the basics but it is just soooo confusingggg....
Answer:
heyyyyyyy
Explanation:
Serena is mixing a material into a beaker filled with a liquid. She notices that the material seems to disappear into the liquid. What physical property of the material is Serena most likely observing? solubility conductivity magnetism density
Answer:
Solubility
Explanation:
Material becomes soluble in solvent and disappears.
The physical property of the material is Serena most likely observing is solubility.
Explanation:
Solubility is defined as the property of a substance to get dissolve in another substance. A small amount of substance is termed as solute and a substance in a larger amount is called a solvent.
Intermolecular interaction of solute particles with solvent particles results in the dissolving of a solute in the solvent.
Conductivity is the property of the substance to conduct heat, electric current, or sound through them.
magnetism is a physical phenomenon that arises due to the motion of electric current through a conductor resulting in the production of a magnetic field.
Density is a measure of the mass of a substance present in the unit volume of the substance.
So, when Serena observed the disappearance of a material into a beaker filled with liquid she is observing the property of solubility of that material.
Learn more about solubility here:
brainly.com/question/13620168?referrer=searchResults
brainly.com/question/3110135?referrer=searchResults
When released from rest: Potential energy = 100 J and Kinetic Energy would equal?
Answer:
0J
Explanation:
The kinetic energy would be zero. An object just released from rest will have no kinetic energy but the potential energy will be maximum.
Kinetic energy is the energy due to the motion of a body
Potential energy is the energy due to the position of a body.
The kinetic energy at the start will therefore be zeroAll the energy is stored as potential energy.Therefore, the kinetic energy is zero
can a physical quantity have different dimensions in different systems of units?
Answer:
yes.
Explanation:
becausehjjkvfdssaajkkbcsssddhkkgddd
2. Suppose your car has a maximum braking acceleration of -5 m/s2. Calculate the stopping distance for an initial speed of 25 m/s.
Answer:
s=62.5m
Explanation:
Use the equation v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.
0²=25²+2(-5)s
10s=625
s=62.5m
What happens to an object when there are no forces acting on it or all the forces acting on it are balanced?
Answer:
It stays and remains at rest
Explanation:
When no forces acts on an object or all the forces on it are balanced, the body stays at rest or remains stationary.
This is based on the Newton's law of inertia which states that "an object will remain in a state of uniform motion or at rest unless an external force acts on it".
If the forces acting on a body is balanced, the object will perpetually remain and keep at rest
determine the gravitational attraction between Earth (6.0 x 10^24 kg) and a 2,500 kg car if the car is 6.38 x 10^6 m from Earth's center.
Answer:
The gravitational attraction between Earth and a 2,500 kg car is 24,592.49 N.
Explanation:
The law of universal gravitation, or simply the law of gravity, establishes the force with which two bodies attract each other simply because they have mass. This law was developed by Sir Isaac Newton.
This law describes the gravitational interaction between massive bodies, and establishes a proportional relationship of the gravitational force with the mass of the bodies.
The Universal Law of Gravitation states that all objects attract each other with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
This means that any two bodies attract each other with a greater or lesser force depending on their mass is greater or less, and according to the distance between them.
The fundamental formula of the Law of Universal Gravitation is as follows:
[tex]F=\frac{G*m1*m2}{d^{2} }[/tex]
Where:
F is the force of attraction between two masses. G is the universal constant of gravitation (6.673484*10⁻¹¹ N.m²/kg²). m1 is the mass of one of the bodies. m2 is the mass of another of the bodies. d is the distance that separates them.In this case:
m1: 6*10²⁴ kgm2: 2,500 kgd: 6.38*10⁶ mReplacing:
[tex]F=\frac{6.673484*10^{-11}\frac{N*m^{2} }{kg^{2} } *6*10^{24} kg*2,500 kg}{(6.38*10^{6} m)^{2} }[/tex]
Solving you get:
F= 24,592.49 N
The gravitational attraction between Earth and a 2,500 kg car is 24,592.49 N.
What are the characteristics of stars on
the main sequence of the Hertzsprung-
Russell diagram?
Answer:
The main sequence stretching from the upper left (hot, luminous stars) to the bottom right (cool, faint stars) dominates the HR diagram. It is here that stars spend about 90% of their lives burning hydrogen into helium in their cores. Main sequence stars have a Morgan-Keenan luminosity class labelled V.
Explanation:
A weightlifter slowly lifts a large amount of weight with a force of 500 N and an acceleration
m/s2. What is the amount of weight being lifted in grams?
Explanation:
Given parameters:
Force = 500N
Acceleration =
Unknown:
Weight can be used to this problem = ?
Solution:
Weight is the vertical force on a body;
Weight = mass x acceleration
So from this we can find the mass and then convert to the second wealth.
During a car crash, why are airbags useful? 0.They decrease the amount of impulse applied to the you.
0.They increase the amount of impulse applied to you.
0.They increase the time it takes to slow you down, which decreases the force applied to you.
0.They decrease the time it takes to slow you down, which increase the force applied to you. 1
Answer:
They increase the time it takes to slow you down, which decreases the force applied to you.
Explanation:
Hope it helps :)))
Answer:
They increase the time it takes to slow you down, which decreases the force applied to you.
Explanation:
Air bags can only deploy at around 8-14mph
true or false
A clue that a chemical change had occurred is that heat is given off.
Answer:
true
Explanation:
Hierarchy of the universe this is due today pls help me
Answer:
what is the question.
Explanation:
A 98 N ball is suspended from a cable so that it hangs 3.5 m above the earth. Find the mass of the ball and the
gravitational PE of the ball.
Answer:
Yes
Explanation:
Charge flows from low potential to high potential.
O True
or
O False
Answer:
False
Explanation:
Think of the electric potential in terms of potential energy. If you imagine a place with high elevation (A) and another one at sea level (B), a ball will roll from high potential to low potential (A-->B).
Everything in our universe wants to reach a lower state of energy if no external force is acted upon it. Every object tends to slow down (friction), a radioactive element dissipates energy (an unstable element releases energy to get to a stable state), water in the clouds comes down to the ground (rain experiencing difference in potential energy).
Electric potential is exactly the same, you just can't see it! It flows from higher voltage (which is a synonym for electric potential) to lower voltage.
HELP PLZZZ!!!
An archer pulls back the string of the bow (spring constant of 250 N/m) a distance of 1 meter. How much elastic energy is stored?
Answer:
im soo sad brainly wouldnt let me in the account that asked this question now i have to start everything over
Explanation:
HELP QUICK WILL MARK AS BRAINLEST!!!
Which of the following elements must be joined only by a covalent bond? The Atomic numbers are in parentheses.
O A. Mg (12) and C (6)
O B. LI (3) and CI (17)
OC. N (7) and C (6)
O D. Al (13) and CI (17)
What is the energy transfer that takes place in a coal burning power plant?
HELP NEEDED
A 1600kg cannon fires a 5kg cannonball horizontally. The exit velocity of the cannonball is 80m/s and the barrel length is 2m. What is the average acceleration of the cannonball before it leaves the barrel?
Answer:
a = 1600 m / s²
Explanation:
For this exercise we use the kinematics relations,
v² = v₀² + 2 a x
where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m
a = [tex]\frac{v^2}{2x}[/tex]
let's calculate
a = [tex]\frac{80^2}{2 \ 2}[/tex]
a = 1600 m / s²
Which is true about using energy? There is an unlimited amount of energy in the universe. When energy is used, it disappears forever. When energy is used, it can transform to new types but can never disappear. A falling object increases its total energy.
Answer:
3. When energy is used, it can transform to new types but can never disappear.
Explanation: it can transform into heat, light, ect and will never disapear unlessed turned of.
When you pick something up do you do work to it
Answer:
Simple answer: Yes
Explanation:
Even if you touch an item with a stick you re still doing work to it, most of the time something sitting on a table not being disturbed is having work done to it. Everything has the force of gravity working on it to essentially keep the items from floating away so workis being done to it.
Work done can be something so small (e.g) a pencil sitting on a table) or as big as an earthquake or kicking a ball through a window and smashing the glass.