The data is shown below:
91, 48, 86, 49, 77, 86, 64, 78
What is the median?

a. 72.37
b. 74
c. 86

Answer:

uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math

Step-by-step explanation:

Answer:

x=-2

Step-by-step explanation:

[tex]\sqrt{x+3}+4=5[/tex]

subtract 4 from each side

[tex]\sqrt{x+3} +4-4=5-4[/tex]

square both sides

[tex]\sqrt{x+3}^2=1^2[/tex]

so we have

[tex]x+3=1[/tex]

subtract 3 from each side

[tex]x+3-3=1-3[/tex]

so our answer is [tex]x=-2[/tex]

Answer:

yes

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. 2

2. 3

3. 6

4. 2

5. 4

Answer:

3 1/4 + 4 2/5 + 6 1/2 = 14.15 hours

Step-by-step explanation:

Answer:

(11+X)/2-(9x-3)/4 x=3

subsititute 3 into all x

(11+3)/2-(9*3)-3)/4

first solve the first diviision

2-(9 times 3)-3/4

=2-(27-3)/4

=2-(24)/4

since the "2-" is there, you have to subtract it from 24 before you dividewhich would then be

22/4=5.5(in decimal form)

DON'T forget you have another bracket waiting for you since you were given 3 brackets. bring the first bracket down

2-(9x-3)/4 was solved and we got 5.5, so basically we are "substituting 5.5 into that part of the question)

11+x/5.5

11+3/5.5

14/5.5

=2.54 which is your final answer

Sorry if I went overboard lol.

Step-by-step explanation:

yes, the answer is 2.54 I believe.

Answer:

4(9 – c)

36 – 4c

Step-by-step explanation:

An example of two equivalent expressions includes the general expression and then the one that is factored.

Answer:180(D)

Step-by-step explanation: First, do 72/x=40/100. Then, cross muliply which is 7200 and 40*x. do 7200/40. The answer should be 180.

Answer:

The answer is C(180) on edg 2021

Answer:

2) 523.3 in²

Steps:

the given polygon is a heptagon

a regular heptagon's area = 7/4 × s² × cot(180°/7)

for the given heptagon

A = 7/4 × 12² × cot(180/7) ≈ 523.28 in² = 523.3 in² (rounded)

Step-by-step explanation:

i d like to help but i fon knoeww

Answer:

B) 60.21 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

You can‘t used mixed measurements (feet and inches), so you have to convert each length to inches

8’6”=102’

14’2”=170’

Now find the area

1/2 x 102 x 170 = 8670 in²

This is one of the answers, but the quetion asks how many quart feet you need.

So, convert it back to feet.

8670 x 0.06944444444 = 60.2083333

(You could also have converted the two lengths to feet. 8’6” = 8.5 ft.  14’2” = 14.16666666.  This way would probably have been faster.

1/2 x 8.5 x 14.166666 = 60.20833333)

Answer:

⚠️DO NOT RELY ON ME⚠️ But, just by doing It in my head i think it's 236.685, but I don't really know just my thought process and mental math

Answer:

4 5/12 feet tall

Step-by-step explanation:

All you have to do is subtract 1/3 from 4 and 3/4 in order to get this answer.

Answer:

Leon is 53/12 feet or 4 & 5/12 or 4.4167 (same answer different forms)

Step-by-step explanation:

Leon older brother is 19/4 feet tall or 57/12.

Leon is 1/3 or 4/12 foot shorter than his brother.

57/12-4/12= 53/12

Answer:

6

Step-by-step explanation:

this is the answer. have a great day.

Answer:

Just explain why you chose mia..

Step-by-step explanation: Why do you think mias right?

Answer:

Mia is right

Step-by-step explanation:

But the reason is because y=4+6x mark is going over the line and he needs to make sure its accross.

Answer:

yes

Step-by-step explanation:

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]

If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.

⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]

☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]

Hope I helped ! ♡

⋆ Have a wonderful day / night ! ♪

Let me know if you have any questions regarding my answer! ツ

[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

On the dive boat deck

Step-by-step explanation:

This is above the water level and water level is considered to be 0

pls love me <3

The probability that a student has a dog given they do not have a cat is 0.1333.

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Total number of students = 30

[tex]n(s)=30[/tex]

Number of students have cat = 16

Number of students have dog = 15

Number of students have a cat and a dog = 11

The event is the probability that a student has a dog given they do not have a cat,

[tex]n(e)=15-11[/tex]

⇒ [tex]4[/tex]

Thus the probability that a student has a dog given they do not have a cat is

⇒ [tex]P(e)=\frac{n(e)}{n(s)}[/tex]

⇒ [tex]P(e)=\frac{4}{30}[/tex]

⇒ [tex]P(e)=0.1333[/tex]

Hence we can conclude that the probability that a student has a dog given they do not have a cat is 0.1333.

Learn more about probability here

https://brainly.com/question/16484393

#SPJ2

Answer:

Yes, because it crosses through (-2) at a rate of 1/3

Answer:

3

Step-by-step explanation:

If you count the units its three units away from each other.

Answer:

[tex]ADC = 70[/tex]

Step-by-step explanation:

Given

[tex]BCA = 50[/tex]

[tex]DCA = 60[/tex]

See attachment for parallelogram and complete question

Required

Find ADC

From the attachment:

[tex]BCD = BCA + DCA[/tex]

[tex]BCD = 50+60[/tex]

[tex]BCD = 110[/tex]

Adjacent angles add up to 180.

So:

[tex]ADC + BCD = 180[/tex]

[tex]ADC = 180-BCD[/tex]

[tex]ADC = 180-110[/tex]

[tex]ADC = 70[/tex]

Answer:

The percentage increase in [tex]T[/tex] is 20 %.

Step-by-step explanation:

Let be [tex]T = \frac{k\cdot x}{y}[/tex], whose initial parameters are [tex]k = k_{o}[/tex], [tex]x = x_{o}[/tex] and [tex]y = y_{o}[/tex]. If these three parameters are increased by 20 %, then initial and final values of [tex]T[/tex] are, respectively:

Initial value

[tex]T_{i} = \frac{k_{o}\cdot x_{o}}{y_{o}}[/tex] (1)

Final value

[tex]T_{ii} = \frac{(1.2\cdot k_{o})\cdot (1.2\cdot x_{o})}{1.2\cdot y_{o}}[/tex]

[tex]T_{ii} = \frac{1.2\cdot k_{o}\cdot x_{o}}{y_{o}}[/tex] (2)

(1) in (2):

[tex]T_{ii} = 1.2\cdot T_{i}[/tex]

And the percentage increase in T is:

[tex]\%T = \frac{T_{ii}-T_{i}}{T_{i}}\times 100\,\%[/tex] (3)

[tex]\%T = \frac{1.2\cdot T_{i}-T_{i}}{T_{i}}\times 100\,\%[/tex]

[tex]\%T = 20\,\%[/tex]

The percentage increase in [tex]T[/tex] is 20 %.

Answer:

Step-by-step explanation:

Lets subsitute k, x and y as  100 to make it easier for us

So k = 100, x = 100, y = 100

Step 1 :-   T = kx/y

- T = 100 * 100 / 100 = 100

Step 2 :- Increase by 20% = 100 * 20% = 20,    100 + 20 = 120

Step 3 :- Percentage Increase = Increased value OVER original calue          MULTIPLIED by 100%

SO = ( 120 - 100 ) ,,,,   20/100 * 100% = 0.2* 100 = 20%

Answer:

the answer is C.

Step-by-step explanation:

Answer:

y=9

Step-by-step explanation:

Answer:

4 sq un

Step-by-step explanation: